This question already has answers here:
C# convert int to string with padding zeros?
(15 answers)
Closed 9 years ago.
I need to set “0” at the end of the decimal place dynamically if less integer number found after decimal place.
Suppose we have value: “535.8”
Now I need to set it as “535.800”
I have following code:
string cost = "535.8";
string decplace = "3";
decimal price = decimal.Round(Convert.ToDecimal(cost), Convert.ToInt32(decplace));
Console.WriteLine(price);
Console.ReadLine();
Unable to get 535.800.
How can I achieve this?
You can convert price to string and show upto 3 decimal places with 0's at end.
string cost = "535.8";
string decplace = "3";
decimal price = decimal.Round(Convert.ToDecimal(cost), Convert.ToInt32(decplace));
//string.Format("{0:N2}", price);
Console.WriteLine(string.Format("{0:N3}", price));
price.ToString("N3")
Standard Numeric Format Strings: The Numeric ("N") Format Specifier
So if the number of decimal should be dynamic:
int numDecimalPlaces = 3;
Console.WriteLine(price.ToString("N" + numDecimalPlaces));
You can use string.Format() to make it possible:
Console.WriteLine(string.Format("{0:N3}", d));
So in your code:
string cost = "535.8";
string decplace = "3";
decimal price = decimal.Round(Convert.ToDecimal(cost), Convert.ToInt32(decplace));
Console.WriteLine(string.Format("{0:N" + decplace + "}", price);
Console.ReadLine();
Related
This question already has answers here:
String to decimal conversion: dot separation instead of comma
(8 answers)
Closed 6 months ago.
I need a program that takes two inputs from the user and perform a calculation. Those inputs need to be double datatype.
The problem I'm facing is that: the program receives a decimal value with dot separator, but when converting it to double, it loses the decimal value. For example, input from the user is 2.5, but when converting it becomes 25.
When the user type 2,5 it is correctly converting it to 2.5
Here's my code example:
Console.WriteLine("Var1: ");
string? v1 = Console.ReadLine();
Console.WriteLine("Var2: ");
string? v2 = Console.ReadLine();
double v1Double = Double.Parse(v1);
double v2Double = Double.Parse(v2);
Console.WriteLine($"Var1: {v1Double}");
Console.WriteLine($"Var2: {v2Double}");
Console.WriteLine($"Multiplication: {v1Double * v2Double}");
Here's what I'm getting when with dot separator:
Here's what I'm gettig when comma separator:
Can anyone help me how to address this problem?
You could use NumberFormatInfo for this problem like so:
NumberFormatInfo provider = new NumberFormatInfo();
provider.NumberDecimalSeparator = ".";
provider.NumberGroupSeparator = ",";
double doubleVal = Convert.ToDouble(YOUR_STRING, provider);
This question already has answers here:
How remove decimal part from string?
(3 answers)
Closed 1 year ago.
I want to remove decimal point from string.
I try with this code but not work for me:
string wSpeed = Math.Round(weatherBindingData.WeatherDataCurrent.Wind.Speed) * 3.6 + "km/h";
WindSpeed.Text = wSpeed;
I want to remove the decimal point, but with this code I receive a values with decimal point.
How is the correct way to remove the decimal point?
Use formatting:
string wSpeed = $"{Math.Round(weatherBindingData.WeatherDataCurrent.Wind.Speed) * 3.6:0}km/h";
Or what you more likely want:
string wSpeed = $"{weatherBindingData.WeatherDataCurrent.Wind.Speed * 3.6:0}km/h";
Solved, thanks for the help!
So I got an assignment for school, and no matter how much I search the net or read my books I can't figure out the answer to the question.
I have done programming for about 4 hours, so thats why the question is phrased wierdly, I think.
Console.WriteLine("Enter a number with any number of decimals.");
string input;
input = Console.ReadLine();
decimal myNumber = decimal.Parse(input);
Console.WriteLine("Please specify how many decimals you want to be shown.");
string input2;
input22 = Console.ReadLine();
int myDecimal = int.Parse(input2);
Console.WriteLine(("Your number with the choosen number of decimals: {0:f3}"), myNumber);
So, when I run it and enter 2,1234567 as my number and 5 as my number of decimals, it prints 2,123 instead of 2,12345.
I know it prints 3 decimals because of the 3 after the f, but I can't figure out how to change the 3 into the ammount chosen by the user.
I have tried {0:f(myDecimal)}, {myDecimal:f and {0:f(int = myDecimal)} , none of which I expected to work as I was just testing things out.
The answer is probably really simple, and I'm probably just overthinking things, but help would be very much appriciated!
You need a format-ception here:
// the {{ and }} escapes to { and }
var numberFormat = string.Format("{{0:f{0}}}", myDecimal).Dump();
Console.WriteLine("Your number with the choosen number of decimals: " + numberFormat, myNumber);
You can use ToString too
decimal myNumber = 224323.545656M;
int myDecimal = 4;
Console.WriteLine(String.Format("Your number with the choosen number of decimals: {0} " , myNumber.ToString("F" + myDecimal)));
You could just simply change your last Console.WriteLine() call to this:
Console.WriteLine("Your number with the choosen number of decimals: {0}",
myNumber.ToString("f" + input2));
The part that changes is: myNumber.ToString("f" + input2). What this does is use string concatenation to build your format string from your variable input2.
I made a fiddle here.
Please keep in mind though, the format string you are using ("F") will round to that number of decimal places (i.e 1.236 would become 1.24 with format "F2")
You need to build the format string dynamically. At this point using a substituted string is harder than ToString:
var digits = 3;
var input = 2.123456789;
var format = $"F{digits}";
var output = "Some text {input.ToString(format)} some more text";
how to trim decimal part in given string of a decimal value in C#. im getting 20472.060 desired o/p - 20472
decimal totalamountWithTaxes = pri + result1 + result2 ;
string totalAmountPlusTaxes = totalamountWithTaxes.ToString();
You can simply do it like this:
int number = (int) totalAmountPlusTaxes;
or
string totalAmountPlusTaxes = String.Format("{0:C0}",totalamountWithTaxes);
Int32 Amount = Convert.ToInt32(totalamountWithTaxes.ToString().Substring(0,totalamountWithTaxes.ToString().IndexOf(".")));
Yes the above example is right and also I recommend you to visit:
String.Format Method-MSDN
This question already has answers here:
How do I format a double to a string and only show decimal digits when necessary?
(2 answers)
Closed 9 years ago.
How to hide fractional part of a double or float number if it is all zero. I am converting a floating point number to string and its display Mantissa part even if it is zero. For example:
double number = 123.00;
string strNumber = number.ToString(); // it shows "123.0", what I need is only "123"
double secondNumber = 123.2234;
string strSecondNumber = secondNumber.ToString(); // it shows "123.2234" as needed.
Is there any built-in solution in .NET to get it done?
Thanks
Try using the overload of double.ToString() that takes in a format string, and pass it "R":
double number = 123.00;
string strNumber = number.ToString("R");
double secondNumber = 123.2234;
string strSecondNumber = secondNumber.ToString("R");