This question already has answers here:
Show Console in Windows Application?
(12 answers)
Closed 9 years ago.
I have a Windows forms application that I wont a console extension.
I cant find a way to add a new console and also if there is a way how would i call it?
If you just want to pop up a Console application it is as simple as:
Process cmdProcess = new Process();
cmdProcess.StartInfo.FileName = "cmd";
cmdProcess.Start();
If you want to call an Executable (output of a console application) from WinForms, then as #JeffRSon quoted
Process cmdProcess = new Process();
cmdProcess.StartInfo.FileName = "YourExecutablePath.exe";
cmdProcess.Start();
If you want an application to be run in Command Prompt then the code as:
System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo("cmd.exe");
psi.CreateNoWindow = true;
psi.UseShellExecute = false;
psi.RedirectStandardInput = true;
psi.RedirectStandardOutput = true;
psi.RedirectStandardError = true;
psi.WorkingDirectory = "Path of the Executable";
System.Diagnostics.Process process = System.Diagnostics.Process.Start(psi);
string sCommandLine = string.Format("YourExecutable.exe -{1}", YourParameterValues);
process.StandardInput.WriteLine(sCommandLine);
process.StandardInput.Flush();
process.StandardInput.Close();
process.WaitForExit();
process.Close();
Related
I want to run .exe file from another app, which is console app in .NET Core. When the app is open I want to write input to console from my code. Something like this:
var cmd = System.Diagnostics.Process.Start("myApp.exe");
cmd.StartInfo.RedirectStandardInput = true;
cmd.StartInfo.RedirectStandardOutput = true;
cmd.StartInfo.UseShellExecute = false;
cmd.Start();
cmd.StandardInput.WriteLine("MyName"); // this should be entered in console as username
So I specify username from my code, instead of writing it to console manually. Code above is not working for me. Is there a way to do this?
enter username
You're first starting the Process and then you're manipulating the startup arguments. You need to start the process afterwards.
use something like this instead:
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.UseShellExecute = false; //required to redirect standart input/output
// redirects on your choice
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardError = true;
startInfo.FileName = ...app path to execute...;
startInfo.Arguments = ...argumetns if required...;
Process process = new Process();
process.StartInfo = startInfo;
process.Start();
process.StandardInput.WriteLine(...write whatever you want...);
source
You need redirect standard input. Create ProcessStartInfo structure, then start a process and after process started write to the process standart input
ProcessStartInfo processStartInfo = new ProcessStartInfo
{
FileName = pathToApplication,
RedirectStandardInput = true,
UseShellExecute = false
};
Process process = Process.Start(processStartInfo);
var writer = process.StandardInput;
writer.WriteLine("MyName");
Console.ReadLine();
I am writing an application that calls an external process via the command line. I have coded the external process to not show a command window, but display the output of the external process in a rich text box in another form. This code works on Windows 7. However when I move the application to a Windows 10 machine the command window is visible and the output of the process does not show in my rich text box. Debugging the application on Windows 10 shows that the DeviceReceivedEventHandler is not being triggered. Can anyone explain why this is different between the Operating Systems and how I might be able to fix it?
Here is the method that I am having issues with:
private void commandLineProcess(string cmdArgs)
{
Process process = new Process();
ProcessStartInfo startInfo = process.StartInfo;
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.FileName = "CMD.exe";
startInfo.UseShellExecute = false;
startInfo.RedirectStandardError = true;
startInfo.RedirectStandardInput = true;
startInfo.RedirectStandardOutput = true;
startInfo.CreateNoWindow = true;
startInfo.Arguments = cmdArgs;
if (!cmdArgs.Contains("FindDrive"))
{
Form progress = new Forms.mForceWriteProgress();
progress.Show();
process.OutputDataReceived += new DataReceivedEventHandler((sender, e) =>
{
if (!String.IsNullOrEmpty(e.Data))
{
Forms.mForceWriteProgress.Instance.addToRichTextBox(e.Data);
}
});
}
process.Start();
process.BeginOutputReadLine();
}
I am using a windows application to start a console application for command line parameters configuration.
When I am sending the command line parameters through debug mode, the application is working perfect, and all Console.WriteLine is printing to console, but when am starting the process from windows application of that console application it is not showing console output
the way, am starting the process is
ProcessStartInfo procStartInfo = new ProcessStartInfo();
procStartInfo.FileName = EXEName;
procStartInfo.Arguments = FilePath;
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
using (Process process = new Process())
{
process.StartInfo = procStartInfo;
process.Start();
}
You need to set ProcessStartInfo.RedirectStandardOutput to false;
I'm writing a program which creates a PDF at various intervals of time. I'm trying to run a PHP command to generate the PDF using a windows service (C#).
My code works just fine from within a C# windows desktop app, but when I try to use it in a windows service, nothing happens and the exit line appears in output without generating a PDF file.
Here is my code:
ProcessStartInfo cmdStartInfo = new ProcessStartInfo();
cmdStartInfo.FileName = #"cmd.exe";
cmdStartInfo.RedirectStandardOutput = true;
cmdStartInfo.RedirectStandardError = true;
cmdStartInfo.RedirectStandardInput = true;
cmdStartInfo.UseShellExecute = false;
cmdStartInfo.CreateNoWindow = true;
cmdStartInfo.ErrorDialog = false;
cmdStartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmdStartInfo.WorkingDirectory = WorkingDirectory; //refers to directory where php file exist.
Process cmdProcess = new Process();
cmdProcess.StartInfo = cmdStartInfo;
cmdProcess.ErrorDataReceived += cmdProcess_ErrorDataReceived;
cmdProcess.OutputDataReceived += cmdProcess_OutputDataReceived;
cmdProcess.EnableRaisingEvents = true;
cmdProcess.Start();
cmdProcess.BeginOutputReadLine();
cmdProcess.BeginErrorReadLine();
cmdProcess.StandardInput.WriteLine(#"php.exe -c GeneratePDF.php ");
cmdProcess.StandardInput.WriteLine("Exit");
I am trying to create process on a remote machine using using System.Diagnostics.Process class.
I am able to create a process. But the problem is, creating a service is take a long time and console window is displayed.
Another annoying thing is the console window is displayed on top of my windows form and i cant do any other operations on that form.
I have set all properties like CreateNoWindow = true,
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden
but still it shows the console window. even i have redirected output and errors to seperate stream but no luck.
Is there any other way to hide the Console window? Please help me out .
Here is the part of my code i used to execute sc command.
Process proc = new Process();
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.StartInfo.FileName = "sc";
proc.StartInfo.Arguments = string.Format(#"\\SYS25 create MySvc binPath= C:\mysvc.exe");
proc.StartInfo.RedirectStandardError = false;
proc.StartInfo.RedirectStandardOutput = false;
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.Start();
proc.WaitForExit();
I had a similar issue when attempting to start a process without showing the console window. I tested with several different combinations of property values until I found one that exhibited the behavior I wanted.
Here is a page detailing why the UseShellExecute property must be set to false.
http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.createnowindow.aspx
Under Remarks section on page:
If the UseShellExecute property is true or the UserName and
Password properties are not null, the CreateNoWindow property
value is ignored and a new window is created.
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = fullPath;
startInfo.Arguments = args;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardError = true;
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
Process processTemp = new Process();
processTemp.StartInfo = startInfo;
processTemp.EnableRaisingEvents = true;
try
{
processTemp.Start();
}
catch (Exception e)
{
throw;
}
I've had bad luck with this answer, with the process (Wix light.exe) essentially going out to lunch and not coming home in time for dinner. However, the following worked well for me:
Process p = new Process();
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
// etc, then start process
This should work, try;
Add a System Reference.
using System.Diagnostics;
Then use this code to run your command in a hiden CMD Window.
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmd.StartInfo.Arguments = "Enter your command here";
cmd.Start();
This doesn't show the window:
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmd.StartInfo.CreateNoWindow = true;
...
cmd.Start();