C# Adding a root to an XDocument - c#

I have a string that contains an XML, lets say like this:
<Novels>
<Book>
<Title>Cat in hat</Title>
<Price>12</Price>
</Book>
</Novels>
I want to make an XDocument that looks like this:
<Booklist>
<Novels>
<Book>
<Title>Cat in hat</Title>
<Price>12</Price>
</Book>
</Novels>
</Booklist>
I can load the xml string into an XDocument using XDocument doc = XDocument.Parse(xmlString);
How would I load the document under a new root. I can think of something like creating a new XDocument with the root I want and then using a for loop to add the nodes as children, but is there an easier way of doing this?

XDocument yourResult = new XDocument(new XElement("Booklist", doc.Root));

var doc = new XDocument(new XElement("Booklist", source.Root));
It does not require any parsing at all. There is a deep copy of XElement made, so there is also no references between old and new documents.

Related

Parsing xml response - Select specific node based on value of another node

I'm new to xml so I'm not sure if I worded the question correctly, but I will do my best to explain.
Basically, I'm trying to parse an xml response in C# such as the one below:
<Premium>
<TotalPremiumAmount>87</TotalPremiumAmount>
<StandardPremium>87</StandardPremium>
<OptionalPremium>0</OptionalPremium>
<StandardTax>0</StandardTax>
<OptionalTax>0</OptionalTax>
<ExtendedTax>0</ExtendedTax>
<ExtendedPremium>0</ExtendedPremium>
<PromotionalPremium>0</PromotionalPremium>
<FeesPremium>0</FeesPremium>
<FeesTax>0</FeesTax>
<StandardFeesPremium>0</StandardFeesPremium>
<OptionalFeesPremium>0</OptionalFeesPremium>
<Tax>0</Tax>
<StandardPremiumDistribution>
<Travelers>
<Traveler>
<TravelerPremium>42</TravelerPremium>
<TravelerTax>0</TravelerTax>
</Traveler>
<Traveler>
<TravelerPremium>45</TravelerPremium>
<TravelerTax>0</TravelerTax>
</Traveler>
</Travelers>
</StandardPremiumDistribution>
<PackagePremiumDistribution>
<Packages>
<Package>
<PackageID>20265</PackageID>
<PackageName />
<PackageTypeID>12</PackageTypeID>
<Premium>87</Premium>
<Fees>0</Fees>
<Tax>0</Tax>
<Travelers>
<Traveler>
<TravelerID>0</TravelerID>
<Premium>42</Premium>
<Tax>0</Tax>
</Traveler>
<Traveler>
<TravelerID>1</TravelerID>
<Premium>45</Premium>
<Tax>0</Tax>
</Traveler>
</Travelers>
</Package>
</Packages>
</PackagePremiumDistribution>
</Premium>
I would like to get the value of the (Traveler) Premium. In the case of only one traveler, I have been using an XMLDocument and the 'SelectSingleNode" function. For example I could do something like:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(xmlResponse);
var premium = xmlDoc.SelectSingleNode("//TravelerPremium").InnerText;
But this wouldn't work when multiple travelers are returned under one plan. For example, I need the premium when TravelerID = 0. How would I go about doing this?
Thanks.
Using XmlDocument:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(xmlResponse);
var premium = xmlDoc.SelectSingleNode("//Premium[../TravelerID = '0']")
You could also iterate through the nodes if multiple could match on this condition like so:
foreach(var premium in xmldoc.SelectNodes("//Premium[../TravelerID = '0']")
{
// do work on each premium node where TravelerID = 0
}
I'd encourage you to look into using LINQ to XML - it's generally easier to work with and will be more performant in most cases. You could even still use XPath expressions, but the following would work:
XDocument xdoc = XDocument.Load(xmlResponse);
var premium = (string)xdoc.Descendants("Traveler").Where(x => (string)x.Element("TravelerID") == "0").Element("Premium");
Assuming your xml looks like that, try something like this:
XmlDocument doc = new XmlDocument();
xmlDoc.Load(xmlResponse);
if (doc.HasChildNodes)
{
foreach (XmlNode node in doc.DocumentElement.ChildNodes)
if (node.Name == "StandardPremiumDistribution")
{
XmlNodeList xnList = node.SelectNodes("//Travelers");
double travelerPremium= xnList.Item(z).FirstChild.InnerText);
}}
Based on this, I think you're gonna do it.
Let's suppose you have a file called XMLFile1.xml with the XML you posted you can iterate through all your TravelerPremium with the following code:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load("XMLFile1.xml");
XmlNodeList premiums = xmlDoc.SelectNodes("//TravelerPremium");
foreach(XmlNode node in premiums)
{
MessageBox.Show(node.FirstChild.InnerText);
}
You can also acces the other elements with similar code.

Append New Element in XML VB or C#

I apologize if this question is too easy for you as I am just starting to learn how XML works. What I am trying to do is to append a new element to App/Library and for example I started with this.
<?xml version="1.0" encoding="utf-8"?>
<App>
<Library>
<Count>100</Count>
<Track>
<TrackID>1</TrackID>
<Name>New York</Name>
<Artist>Snow Patrol</Name>
</Track>
</Library>
</App>
what I am trying to do is to add another track to my existing XML.
<Track>
<TrackID>2</TrackID>
<Name>Chasing Cars</Name>
<Artist>Snow Patrol</Name>
</Track>
There are a couple of ways to deal with xml manipulation in .NET. The older style using System.Xml.XmlDocument or using System.Xml.Linq.XDocument approach.
Here is an example on how to do it using XmlDocument:
var xml = "Baz";
var doc = new XmlDocument();
doc.LoadXml(xml); //Load up the original xml string into XmlDocument object
var fooNode = doc.SelectSingleNode("//foo"); //use xpath to get to the top level foo element
var newBar = doc.CreateElement("bar"); //Create a new bar element and assign it's inner text
newBar.InnerText = "Baz2";
fooNode.AppendChild(newBar); //append the newly created bar element to foo
and here is an example on how to do it using XDocument (which is much more simpler):
var xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?><foo><bar>Baz</bar></foo>";
var xdoc = XDocument.Parse(xml); //Load up the original xml string into Linq XDocument object
xdoc.Root.Add(new XElement("bar", "Bar2")); //Add <bar>Bar2</bar> to foo (which is root of the document)
Here is a running example:
https://dotnetfiddle.net/vY7Vag

How to Remove Root Element in C#/

I'm new to XML & C#.
I want to remove root element without deleting child element.
XML file is strudctured as below.
<?xml version="1.0" encoding="UTF-8"?>
<dataroot generated="2013-07-06T20:26:48" xmlns:od="urn:schemas-microsoft-com:officedata">
<MetaDataSection>
<Name>KR04</Name>
<XMLCreationDate>02.05.2013 9:52:41 </XMLCreationDate>
<Address>AUTOMATIC</Address>
<Age>22</Age>
</MetaDataSection>
</dataroot>
I want to root element "dataroot", so it should look like below.
<?xml version="1.0" encoding="UTF-8"?>
<MetaDataSection>
<Name>KR04</Name>
<XMLCreationDate>02.05.2013 9:52:41 </XMLCreationDate>
<Address>AUTOMATIC</Address>
<Age>22</Age>
</MetaDataSection>
Deleting child elements look like easy, but I don't know how to delete root element only.
Below is the code I've tried so far.
XmlDocument xmlFile = new XmlDocument();
xmlFile.Load("path to xml");
XmlNodeList nodes = xmlFile.SelectNodes("//dataroot");
foreach (XmlElement element in nodes)
{
element.RemoveAll();
}
Is there a way to remove root element only? without deleting child elements?
Thank you in advnace.
Rather than trying to actually remove the root element from an existing object, it looks like the underlying aim is to save (or at least access) the first child element of the root element.
The simplest way to do this is with LINQ to XML - something like this:
XDocument input = XDocument.Load("input.xml");
XElement firstChild = input.Root.Elements().First();
XDocument output = new XDocument(new XDeclaration("1.0", "utf-8", "yes"),
firstChild);
output.Save("output.xml");
Or if you don't need the XML declaration:
XDocument input = XDocument.Load("input.xml");
XElement firstChild = input.Root.Elements().First();
firstChild.Save("output.xml");
if you need to do in c# coding means
Solution
foreach (XElement item in Element.Descendants("dataroot").ToList())
{
item.ReplaceWith(item.Nodes());
}

How do I add a document type to an XDocument?

I have an existing XDocument object that I would like to add an XML doctype to. For example:
XDocument doc = XDocument.Parse("<a>test</a>");
I can create an XDocumentType using:
XDocumentType doctype = new XDocumentType("a", "-//TEST//", "test.dtd", "");
But how do I apply that to the existing XDocument?
You can add an XDocumentType to an existing XDocument, but it must be the first element added. The documentation surrounding this is vague.
Thanks to Jeroen for pointing out the convenient approach of using AddFirst in the comments. This approach allows you to write the following code, which shows how to add the XDocumentType after the XDocument already has elements:
var doc = XDocument.Parse("<a>test</a>");
var doctype = new XDocumentType("a", "-//TEST//", "test.dtd", "");
doc.AddFirst(doctype);
Alternately, you could use the Add method to add an XDocumentType to an existing XDocument, but the caveat is that no other element should exist since it has to be first.
XDocument xDocument = new XDocument();
XDocumentType documentType = new XDocumentType("Books", null, "Books.dtd", null);
xDocument.Add(documentType);
On the other hand, the following is invalid and would result in an InvalidOperationException: "This operation would create an incorrectly structured document."
xDocument.Add(new XElement("Books"));
xDocument.Add(documentType); // invalid, element added before doctype
Just pass it to the XDocument constructor (full example):
XDocument doc = new XDocument(
new XDocumentType("a", "-//TEST//", "test.dtd", ""),
new XElement("a", "test")
);
or use XDocument.Add (the XDocumentType has to be added before the root element):
XDocument doc = new XDocument();
doc.Add(new XDocumentType("a", "-//TEST//", "test.dtd", ""));
doc.Add(XElement.Parse("<a>test</a>"));

Read attribute from xml

Can someone help me read attribute ows_AZPersonnummer with asp.net using c# from this xml structure
<listitems
xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
xmlns:rs="urn:schemas-microsoft-com:rowset"
xmlns:z="#RowsetSchema"
xmlns="http://schemas.microsoft.com/sharepoint/soap/">
<rs:data ItemCount="1">
<z:row
ows_AZNamnUppdragsansvarig="Peter"
ows_AZTypAvUtbetalning="Arvode till privatperson"
ows_AZPersonnummer="196202081276"
ows_AZPlusgiro="5456436534"
ows_MetaInfo="1;#"
ows__ModerationStatus="0"
ows__Level="1" ows_ID="1"
ows_owshiddenversion="6"
ows_UniqueId="1;#{11E4AD4C-7931-46D8-80BB-7E482C605990}"
ows_FSObjType="1;#0"
ows_Created="2009-04-15T08:29:32Z"
ows_FileRef="1;#uppdragsavtal/Lists/Uppdragsavtal/1_.000"
/>
</rs:data>
</listitems>
And get value 196202081276.
Open this up in an XmlDocument object, then use the SelectNode function with the following XPath:
//*[local-name() = 'row']/#ows_AZPersonnummer
Basically, this looks for every element named "row", regardless of depth and namespace, and returns the ows_AZPersonnummer attribute of it. Should help avoid any namespace issues you might be having.
The XmlNamespaceManager is your friend:
string xml = "..."; //your xml here
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
XmlNamespaceManager nsm = new XmlNamespaceManager(new NameTable());
nsm.AddNamespace("z", "#RowsetSchema");
XmlNode n = doc.DocumentElement
.SelectSingleNode("//#ows_AZPersonnummer", nsm);
Console.WriteLine(n.Value);
You can also use LINQ to XML:
XDocument xd = XDocument.Parse(xml);
XNamespace xns = "#RowsetSchema";
string result1 = xd.Descendants(xns + "row")
.First()
.Attribute("ows_AZPersonnummer")
.Value;
// Or...
string result2 =
(from el in xd.Descendants(xns + "row")
select el).First().Attribute("ows_AZPersonnummer").Value;
I'd say you need an XML parser, which I believe are common. This looks like a simple XML structure, so the handling code shouldn't be too hard.
Use <%# Eval("path to attribute") %> but you need to load the xml has a DataSource.
Otherwise you can load it using XmlTextReader. Here's an example.

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