I am trying to pass a file path into a C# Console Application but am having problems with the string being incorrect by the time it reaches the console application.
If I run my application from the command line, with a file path parameter:
MyApp "C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject\"
A windows dialogue pops up and informs me that my application has stopped working, and when I click the Debug option, I can see that the result of args[0] is:
C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject"
Note there is still a trailing quote at the end.
If I pass a second argument:
MyApp "C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject\" "any old string"
I get an error again, and after viewing in debug I see that args[0] is:
C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject" any
I am baffled as to why this is happening. My only guess is that the backslashes in the string are causing some kind of escape sequence from the string? Edit: I notice that the same is happening in the string example above! It seems \" is causing problems here.
I just want to pass in the file path of the current solution directory and am calling my app from a pre-build event using $(SolutionDir), and know that I can get the path of the current solution in other ways. But this is simplest and I am curious as to why it does not work as expected.
Yes, the rules for commandline arguments are a little murky.
The \ is the escape char and you can use it to escape quotes ("). You'll have to escape a backslash but only when it is preceding a quote. So use (note the '\\' at the end):
MyApp "C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject\\"
or, simpler but you'll have to deal with it in C# somehow:
MyApp "C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject"
Also see this question
That's why it's always better to use / in path
"C:/Users/DevDave/Documents/Visual Studio 2012/Projects/MyProject/" "any old string"
take a look: http://en.wikipedia.org/wiki/Path_(computing) , you can use both \ and / in path but if you want any shell compatibility I suggest to use /
Anything that comes after MyApp will be the first argument (args[0]). In your case, the first argument is "C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject\". Also, the quote at the end of the string seems to happen because \" means that you want to want to escape the quote and write it as a string. In this case, the quote is not closing the string. That is the reason that your args[0] is the whole thing that comes after MyApp
If you don't want to scape the quote and have a slash behind it, you should do \\"
You could try this and tell me what happens:
MyApp "C:\Users\DevDave\Documents\Visual Studio 2012\Projects\MyProject\\"
(look at the double slash)
Hope it helps.
Continuation of Henk's answer, and choose to add a \ at the end of the path, then:
If you choose to hack the bug by choosing this code in Henk's answer ("simpler but you'll have to deal with it in C# somehow:"), then you should realize some bugs that will occur:
args[0] will only be set, even if you pass multiple parameters in. The length of args will be equal to 1. So you have to split args[0] into multiple pieces for your hack.
You have to replace any " characters with a \ if they are at the end of the pieces you split.
Related
I have an existing console app that takes option args that don't have the -- in front of them. For example:
./myapp businessDate=20230128 type=charley location=nashville
Currently I parse the args[] array tokens and split them around the "=" to get the key/value
I can't change that, because other programs already call it that way. But it appears that DragonFruit needs to have it this way instead.
./myapp --businessDate=20230128 type=charley --location=nashville
So my question is, can DragonFruit be configured to NOT use the -- prefix on options when I use the equals sign to separate the key from the value the way I currently do it in the example above? I believe the answer is "no", because of the Posix compliance. But maybe I missed something.
What I Tried
I ran the example program here Building your first app with System.CommandLine.DragonFruit And it worked fine when I ran it:
$ dotnet run --int-option=123 --bool-option=true
The value for --int-option is: 123
The value for --bool-option is: True
The value for --file-option is: null
But when I tried it without the --, this way instead, it gave me errors, and I was hoping it would work as above:
$ dotnet run int-option=123 bool-option=true
Unrecognized command or argument 'int-option=123'.
Unrecognized command or argument 'bool-option=true'.
With C/C++, we can get argv[0]:
printf("%s\n",argv[0])
In C#, args begins with argv[1].
Non of bellow API gives exactly argv[0], at least under Linux:
AppDomain.CurrentDomain.FriendlyName: only gives the name, no path
Process.GetCurrentProcess().ProcessName: gives wrong result with symbol link, and no path
Process.GetCurrentProcess().MainModule.FileName: gives wrong result with symbol link, and the path is always absolute
FYI: under Linux with the above C/C++ code (whose result is treated as the golden standard here), it prints the exact path (absolute or relative) that is used to invoke the program, and if you invoke the program through any symbol link, the symbol link's name is printed instead of the real program.
I ask this question since I try to write a wrapper program using C# under Ubuntu, which should pass argv[0] through to be fully transparent in case the wrapped program's behavior depends on argv[0].
Environment.CommandLine and Environment.GetCommandLineArgs() should contain the full and unmodified command line.
The accepted answer doesn't work for me on .NET 5 on Linux, I get $PROJECT_DIRECTORY/bin/Debug/net5.0/$PROJECT_NAME.dll. Further, this doesn't change if symlinks are used.
Instead I have to use this non-portable hack (taken from this comment):
(await File.ReadAllTextAsync("/proc/self/cmdline")).Split('\0')[0]
Result:
$ bin/Debug/net5.0/bpm
argv[0]: bin/Debug/net5.0/bpm
$ ln -s bin/Debug/net5.0/bpm foo
$ ./foo
argv[0]: ./foo
I`m getting an ArgumentException from the following code:
string strPath="C:\somename.xls";
startPath=System.IO.Path.GetDirectoryName(System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName);
filePath = System.IO.Path.Combine(startPath, strPath);
I found this code on Stack Overflow.
Link:
C#:Copy protected worksheet to another excel file
I don't exactly know what it is. Please tell me what it is. This code I'm building into an exe.
Lastly, I need to Copy one worksheet to another file.
What`s wrong am I doing? I deploy this in server.
what that code appears to do, is it gets your working directory(wherever the exe associated with your code is), and combines it with "C:\\somename.xls"(which doesn't make sense.)
I think you might have intended something like
string strPath=#"somename.xls";
so assume you're running your application from
"C:\Users\owner\documents\visual studio 2012\Projects\ConsoleApplication1\ConsoleApplication1\bin\Debug"
what that code would do is set filePath to
"C:\Users\owner\documents\visual studio 2012\Projects\ConsoleApplication1\ConsoleApplication1\bin\Debug\somename.xls"
the first thing I saw was
string filePath="C:\somename.xls";
\ is a special character, for determining other characters. for instance '\n' is a newline. '\\' is the actual backslash.
so, you want to escape your \ with another \
string filePath="C:\\somename.xls";
or make it a literal string by putting a # in front of it.
string filePath=#"C:\somename.xls";
Your code should be:
string filePath = "C:\\somename.xls"
You need double backslashes.
Two problems with the code,
First
string filePath="C:\somename.xls";
\ is a special character, for determining other characters. for instance '\n' is a newline. '\\' is the actual backslash.
Second
filePath contains a root path, C:\\. Path.Combine will just return filePath then, it cannot be combined.
Your main problem is in startPath parameter.
System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName
If you trace your code, in FileName you will see a bad symbol character witch is illegal
I need to escape chars in a string I have, which content is C:\\blablabla\blabla\\bla\\SQL.exe to C:\blablabla\blabla\bla\SQL.exe so I could throw a process based on this SQL.exe file.
I tried with Mystring.Replace("\\", #"\"); and Mystring.Replace(#"\\", #"\"); but none worked.
How could I do this?
EDITED: Corrected type in string.
I very strongly suspect that you are looking this input string in the Visual Studio debugger and fooling yourself that there are actually 2 \ whereas in reality there aren't. That's the reason why attempting to replace \\ with \ doesn't do anything because in the original string there is no occurrence of \\. And since you are looking the output once again in the debugger, you are once again fooling yourself that there are 2 \.
Visual Studio debugger has this tendency to escape strings. Log it to a file or print to the console and you will see that there is a single \ in your input string and you don't need to replace anything.
It looks like you're trying to replace double backslash (#"\\") in a string with single backslash (#"\"). If so try the following
Mystring = Mystring.Replace(#"\\", #"\");
Note: Are you sure that the string even contains double backslashes? Certain environments will print out a single backslash as a double (debugger for example). Your comment mentioned my approach didn't work. That's a flag that there's not actually a double backslash in your string (else it would work).
The # character specifies a string as a verbatim literal string, but that is when constructing a string. If you use Mystring.Replace("\\", #"\") then nothing will be replaced, essentially, as the two strings are the same.
If you want a string without the escape characters, then either define it with:
string path = #"C:\Some\Directory\And\File.txt";
Or you can replace the \\ with / like so:
path = path.Replace('\\', '/');
It is worth noting, as mentioned by Darin Dimitrov, that the string containing two \ characters is likely just the display of the string (i.e. when using the debugger) and not the actual value of the string.
i think OP is asking how to escape \\ in File Path, if that in the case, as OP is not mentioning where he's trying to use this. so i'm putting a guess.
Then You use Path.Combine() method to get the FileName path.
Path.Combine() Documentation
where are you looking at this output? because it could be the string is what you expect, but viewing the value through the debugger, output window, etc. is escaping the slash
Use something like:
myStr = myStr.Replace(#"\\", #"\");
Make sure you assign the result of Replace method to myStr. Otherwise it goes into void ;)
Try adding "|DataDirectory|\MyFile.xyz" where you need it. It works with connection strings it might work with something else (I haven't really tried to apply it to something else).
I didn't understand what you want, if you just want do get the file name (escape directory chars) you can try:
string fileName = Path.GetFileName(YourString)
Noloman.... when you concatenate are you perhaps missing a "\" when concatenating the directory.. I am assuming that you are trying to join directory + some sub directory.. #noloman keep in mind that in C# "c:\Temp" is written like this "c:\Temp" or #"c:\Temp" one is Literal the other is how to represent a "\" in the legacy way of coding because the "\" is an escape Char and when dealing with directorys we represent all paths and sub paths with "\"
so perhaps by you replacing the "\" you are truly messing up your own expected process
Mystring = Mystring.Replace(#"\\", #"\");
should work for you unless you are truly meaning to do
Mystring = Mystring.Replace(#"\", "\"); which if you believe that you are expecting a "\" to be used to build the directory.. then of course it will not work.. because you have just in essense replaced the backslash with a return char.. I hope that this makes sense to you..
System.IO.Directory.GetCurrentDirectory(); you are using is also an Issue.. SQL Server is not that application thats running the code.. it's your .NET application so you need to either put the location of the SQL Server into a variable, app.config, web.config ect... please edit your question and paste the code that you are using to do what it is that you want to do inregards to the SQL Server Code.. you would probably want to look at the Are you wanting to do something like Process.Start(....) meaning the file name..?
I have an application that is supposed to aid my project in terms of pre- and post-build event handling. I'm using ndesk.options for command line argument parsing. Which gave me weird results when my project path contains spaces. I thought this was the fault of ndesk.options but I guess my own application is to blame. I call my application as a post-built event like so:
build.exe --in="$(ProjectDir)" --out="c:\out\"
A simple foreach over args[] displays the following:
--in=c:\my project" --out=c:\out"
What happened is that the last " in each parameter was treated as if it was escaped. Thus the trailing backslash was removed. And the whole thing is treated as a single argument.
Now I thought I was being smart by simply escaping the first " as well, like so:
build.exe --in=\"$(ProjectDir)" --out=\"c:\out\"
In that case the resulting args[] look like this:
--path="c:\my
project"
--out="c:\out"
The trailing backslash in the parameters is still swallowed and the first parameter is now split up.
Passing this args[] to ndesk.options will then yield wrong results.
How should the right command line look so that the correct elements end up in the correct args[] slots? Alternatively, how is one supposed to parse command line arguments like these with or without ndesk.options? Any suggestion is welcome.
Thanks in advance
Did you try to escape the last backslash?
build.exe --in="$(ProjectDir)\" --out="c:\out\\"
This works probably only, as long as the ProjectDir ends in \, which should be given.
This is just an idea, but I did not give it a try
EDIT:
I found a comment which suggests to leave out the trailing "
I actually used "." to solve this same problem:
build.exe --in="$(ProjectDir)." --out="c:\out\."
primarily because otherwise it might look like you are trying to escape the second quote...which you're not, you're escaping the final \ (which is hidden).
I also added a REM in the postbuild command describing why I did that.