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How can I generate a 100% random number between 1 and the max of a 32 bit int in C# [closed]

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I would like to generate a random number that populates an int in C#.
I have heard that sometimes random numbers are not reliable. Would this be a problem for me to generate a random number?
Can someone comment on this and suggest a very reliable way to generate a random number between 1 and the max of a 32 bit int?

Random random = new Random();
for(someloop) {
int randomValue = random.Next(0, int.MaxValue) + 1;
}
Be aware that this is only pseudo random. This example is creating an instance of the random outside the loop, so it doesn't keep getting reseeded with the same current time. If you use random extensively, you could even make a singleton wrapper around it and use one instance of random for your entire application (be aware of threading issues of coarse).

Generating a random double number with one number decimal point [closed]

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I have to generate a number between -4.0 and 4.0 including all numbers like 3.4 etc. I have managed to create a random integer but got stuck when creating double - it just returns an integer.

.NET Random class provides a method NextDouble() which can be used in this case. But a workaround for your case would be much easier and faster to implement. Such as:
Dim r As Random = New Random()
Dim d As Double = r.Next(-4, 4) + (r.Next(0, 9) / 10) 'First random next call in desired range, and second is to add the decimal point
Console.WriteLine("Generated Number: {0}", d)

One work around can be that you get a random int between -40 and 40, then divide the result by 10.

Update Array and preserve data [closed]

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i want to update a Global Array that contain 24 data
Decimal[] GolbalInfo = new Decimal[24];
with three different small array containing each one 8 data
Decimal[] TableSwInfo ;
how can i do it please ?

You can use CopyTo. Assuming you have arrays like the following:
//main destination array
Decimal[] GolbalInfo = new Decimal[24];
//smaller source arrays
Decimal[] SmallOne = new Decimal[8];
Decimal[] SmallTwo = new Decimal[8];
Decimal[] SmallThree = new Decimal[8];
You can set the large one using the smaller ones like this:
SmallOne.CopyTo(GolbalInfo, 0);//sets 0 - 7
SmallTwo.CopyTo(GolbalInfo, 7);//sets 8 - 15
SmallThree.CopyTo(GolbalInfo, 15);//sets 16 - 23
I would recommend that you validate the sizes before adding them, although it may be a safe assumption depending on your setup

Print Duplicate Items using LINQ [closed]

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I want to print duplicate items using LINQ.
e.g. I want to print 1 at 10 times.
Here 1 is a string and 10 (Dynamic Number) is the number of times I want to print this string.
How can I do this?

You can use this constructor overload:
int count = 10;
string s = new String('1', count);

If you really wanted to use Linq, you could use Enumerable.Repeat:
int copies = 10;
foreach(var s in Enumerable.Repeat("1", copies))
{
Console.WriteLine(s);
}
But for that matter, a simple for-loop would work too:
int copies = 10;
for(int i = 0; i < copies; i++)
{
Console.WriteLine("1");
}

Math.Round doesn't behave like i want it to. (X.0xxxxx numbers) [closed]

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Quick question.
I'm making a diagram so the numbers i'm passing to the function can be anything (depending on zoom and such). Lets say I want to round the number 3.086948353 to 3 but i still want other numbers like 2.199999999 to round to 2.2.
Currently it just looks like this:
Math.Round(value, 10)

You want to do two things in single shot:
Get the integer value if first digit after decimal is 0
Get the rounded value upto last 2 digits if its first digit after decimal is not 0.
For second option you can use:
newValue = Math.Round(value, 2)
Now comes the first requirement:
Once you get the decimal with 2 digits after decimal, get last two digits:
int decimalValue= (int)((newValue - (int)newValue ) * 100);
if(decimalValue < 10)
{
newValue = Math.Floor(value);
}