I have an OpenFileDialog with the filter set to *.wav. However, when I execute the OpenFileDialog it also shows other files that includes .wav but the true extension is not .wav but e.g. png. Why is that and how can I avoid this?
Right now I take care of it when loading the file(s) for processing but I would like to avoid getting them in the OpenFileDialog list in the first place. Is this a bug in the control or is it me?
Background: I had by accident renamed a picture file to TheFile.wav.png - stupid, true, but these kind of things happens also for other users.
Thanks in advance
Try this to set the file type in the dialog:
OpenFileDialog dialog = new OpenFileDialog();
dialog.Filter = "wav files (*.wav)|*.wav";
dialog.InitialDirectory = #"C:\"; // You may not need this.
if (dialog.ShowDialog() == DialogResult.OK) // Or this; I was just being thorough.
{
// Your code can go here.
}
Just make sure that when using the .Filter property, you follow the pattern I have above, or else it won't work. Also, as was mentioned above, you may want to do some validation after the user selects something.
Related
I have a problem where if you set the filename in the dialog box to a sub directory within the initial directory you set it to and then clicking 'Save', the dialog window doesn't actually save the file but opens the sub directory which I could still interact with.
For example If I set the initial directory for the dialog to 'C:\MainDir' and that directory consists of SubDir1, SubDir2, then in the save file dialog I could see that I am in the initial directory with two sub directories. If I set the filename to SubDir1 (no extension) in the dialog, and then I hit 'Save', what happens is instead of saving the file as 'filename.extension' the dialog opens the directory specified by the file name.
Here's what I currently have:
SaveFileDialog dlg = new SaveFileDialog();
dlg.DefaultExt = ext;
dlg.AddExtension = true;
dlg.FileName = filename;
dlg.Filter = filter;
dlg.FileOk += OnFileDialogOk;
dlg.InitialDirectory = dir;
bool? dlgRes = dlg.ShowDialog();
Is this something that can be easily fixed?
Quick Answer: No.
You cannot override the default save method of Windows OS.
What you can do is perhaps to verify whether the filename you wanted to use (in this instance, SubDir) exists already as a directory. If it does, then you would need to change that name, as that will only manifest the behavior you've already seen.
Side Note: Just imagine you have a very important folder which contains critical files, and Windows would let you save a file that is named with that directory. That is a disaster waiting to happen.
The only ways I can think of doing this are a bit extreme:
You could roll your own dialog
You could modify the functionality of the standard dialog
The answers found here: Customizing OpenFileDialog could help with that.
I guess I should also note that while it may seem helpful to accommodate this kind of input and automatically append the extension, it'll be counter-intuitive to many users who will expect the default behaviour.
In short, I'd probably think twice about this.
VERY VERY new to C Sharp, as it's not part of my study path, but I have to edit small codes in C Sharp in order for my app to work. I'm using Ogama, a open source gaze tracker, which I need for my project. The heatmap, to be more specific. Now, I want to save the heatmap to a directed folder, and managed to find the code. The initial code was
public static bool ExportImageToFile(Image image)
{
SaveFileDialog dlg = new SaveFileDialog();
dlg.Title = "Please enter filename for image...";
dlg.InitialDirectory = Environment.SpecialFolder.MyDocuments.ToString();
So I thought I could change it, by following other tutorials online, and this was my code.
public static bool ExportImageToFile(Image image)
{
SaveFileDialog dlg = new SaveFileDialog();
dlg.Title = "Please enter filename for image...";
dlg.InitialDirectory = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.Personal), "heatmapimages");
But it doesn't work. When I click the save file button, it brings me to where my Ogama projects are. The 'heatmapimages' folder is in my Desktop. Any advice? Thank you in advance.
EDIT: Managed to make it work, by changing Special.Personal to Special.DesktopDirectory. Is there a way to make it autosave the image? Such that I don't need to click save?
You need to set RestoreDirectory true and set InitialDirectory to SpecialFolder.Desktop. Here are all SpecialFolders for your reference.
It restores the current directory to its original value if the user changed the directory while searching for files.
I have an OpenFileDialog and I only want to allow .txt as a valid file for the users.
I know I can add a Filter to the OpenFileDialog like so:
var dialog = new OpenFileDialog();
dialog.DefaultExt = ".txt";
dialog.Filter = "Text Files (*.txt)|*.txt";
var result = dialog.ShowDialog();
// Do something with the result
The problem however, is that I can still directly say something like "test.jpg" in the OpenFileDialog and then it opens this uploads this .jpg file. (Obviously it goes wrong somewhere later, but that doesn't matter for now.) I just want to know how I can restrict the user to only add ".txt" files, nothing else? (By directly validation it inside the OpenFileDialog, instead of doing it somewhere later.)
You cant do that only in OpenFileDialog and even if you could its a bad limitation.
Using the *.txt example there are multiple files extensions that are plain text inside, *.bat or all the codding file extensions *.cs, *.js, etc...
You should not limit the user on what file he can put on it.
For more complex file types if your program cant handle the file passed by the user you should show an error not prevent the user from passing the file.
I'm learning C and C#, this question is for C#. I have a app that I want to open files on my C:\ drive. Can I use OpenFileDialog to open any type of file? How is this done?
Here is the code:
case 1:
openSomething();
break;
private static void openSomething()
{
OpenFileDialog open = new OpenFileDialog();
open.Filter = "All Files (*.*)|*.*";
open.ShowDialog();
if (open.ShowDialog() == DialogResult.OK)
{
File.Open(open.FileName); // I want to do something like this
}
}
Is there something like System.Diagnostics.Process.Start on programs for files, so I use openfiledialog to get the filename and then my code opens the file with the default application?
Edit: I answered my own question
private static void openSomething()
{
OpenFileDialog open = new OpenFileDialog();
open.Filter = "All Files (*.*)|*.*";
if (open.ShowDialog() == DialogResult.OK)
{
System.Diagnostics.Process.Start(open.FileName);
}
}
Usually the program tries to limit the kind of files listed by OpenFileDialog using the Filter property, but, if you want to allow the opening of any kind of file you set this property (before calling ShowDialog) with something like this
open.Filter = "All Files (*.*)|*.*";
meaning that every kind of file could be choosen by your user.
Keep in mind that the Filter property is just a facility to give a rapid choice to the end user, by itself the OpenFileDialog can open any kind of files also if you set any specialized filter.
All that your user is required to do is typing the *.* in the filename textbox space and he/she can choose any kind of file (of course only if he/she has the required file/folder access permissions)
After the ShowDialog returns DialogResult.OK you could check if there is something selected in the Filename property, and, if you want to open the file using the default application associated for the file extension then you use Process.Start
if (open.ShowDialog() == DialogResult.OK)
{
if(open.FileName.Trim() != string.Empty)
{
Process.Start(open.FileName);
}
}
Of course this could be problematic if the file choosen has no default program associated (for example what if the user choose a DLL?), so perhaps it is better to apply a filter to select only a subset of well known file types. But this depends on your requirements.
The OpenFileDialog really only serves as a window to let the user select a file or multiple files. It does not open any file. The selected filenames can be retrieved from the FileName or FileNames properties after dialog has been closed. To open and read / edit the file is an independent task.
using openFileDialog will not return a filename in use, I want the filename only I don't care if it's in use
The file will most likely be in use, I just want to be able to find the file and retrieve its name and location to perform a connection.
OpenFileDialog works until I select the file, then it has a popup that says "File in Use". I don't want it to check for that, just return the filename.
It seems that setting the ValidateNames property to false solves the problem (but don't ask why :) ...)
Here's the code I used to try out:
var f=File.OpenWrite(#"C:\test.txt");
var ofd = new OpenFileDialog();
ofd.ValidateNames = false;
ofd.ShowDialog();
f.Close();
Commenting out the third line gave me the described error "file in use".
Try setting ValidateNames to false.
OpenFileDialog fd = new OpenFileDialog();
fd.ValidateNames = false;
I googled and found a thread that suggests this is a bug in the control:
http://social.msdn.microsoft.com/forums/en-US/netfxbcl/thread/56fbbf9b-31d5-4e89-be85-83d9cb1d538c/
The suggested workaround is to call the API directly as found here:
http://www.codeproject.com/KB/dialog/customize_dialog.aspx?print=true