I want to print the contents of a simple TextBox. After I click the print button, PrintDialog is shown.
I found a lot of info but they all use RichTextBoxes. Is there an easy way to do something like this?
This print contents of textbox named textbox1
PrintDocument document = new PrintDocument();
PrintDialog dialog = new PrintDialog();
public Form1()
{
InitializeComponent();
document.PrintPage += new PrintPageEventHandler(document_PrintPage);
}
void document_PrintPage(object sender, PrintPageEventArgs e)
{
e.Graphics.DrawString(textBox1.Text, new Font("Arial", 20, FontStyle.Regular), Brushes.Black, 20, 20);
}
private void btnPrint_Click(object sender, EventArgs e)
{
dialog.Document = document;
if (dialog.ShowDialog() == DialogResult.OK)
{
document.Print();
}
}
Take a look at this: http://answers.yahoo.com/question/index?qid=20081230163003AA4xOaT,
and this: How to print the contents of a TextBox
Also, there is a tutorial on printing in C#: http://www.dreamincode.net/forums/topic/44330-printing-in-c%23/
If, after this, you still cannot print TextBox content from some reason, you can always create a new RichTextBox object and assign your TextBox's Text to its text. Then proceed with printing using the RichTextBox.
Related
in C# Winform, i'm sending an Image to the printer using the PrintDialog... using this code:
private void PrintSnippedImage()
{
PrintDocument pDoc = new PrintDocument();
pDoc.PrintPage += PrintPage;
PrintDialog pDialog = new PrintDialog();
pDialog.ShowHelp = true;
pDialog.AllowSelection = false;
pDialog.AllowSomePages = false;
pDialog.Document = pDoc;
if (pDialog.ShowDialog() == DialogResult.OK)
{
pDoc.Print();
};
}
private void PrintPage(object o, PrintPageEventArgs e)
{
System.Drawing.Image img = Glob.SnippedImage;
Point loc = new Point(10, 10);
e.Graphics.DrawImage(img, loc);
}
I get a popup that shows "Printing... Page 1 of document" with a Cancel button.
it appears in seemingly random locations on one of my monitors.
is there a way to inhibit this popup, or at least force it to appear on the monitor in the general location of the application that called it?
it looks like this:
It should be a case of swapping the PrintController implementation from PrintControllerWithStatusDialog (the default) to StandardPrintController. See https://learn.microsoft.com/en-us/dotnet/api/system.drawing.printing.printdocument.printcontroller?view=dotnet-plat-ext-6.0#system-drawing-printing-printdocument-printcontroller
I have a print function which prints received messages in my application this application is a background process, but as soon as I get a new message, it displays "printing box" for a brief moment, how can I hide this.
PrintDocument DocumentPrint = new PrintDocument();
DocumentPrint.PrintPage += new PrintPageEventHandler(page_print);
DocumentPrint.Print();
private void page_print(object sender, PrintPageEventArgs ev)
{
ev.Graphics.DrawString(strMessagePrint,
clsGlobals.DEFAULT_PRINTER_FONT,
Brushes.Black,
new Point(clsGlobals.DEFAULT_LEFT_MARGIN, clsGlobals.DEFAULT_TOP_MARGIN));
}
Solve the problem to use PrintDocument's PrintController to StandardPrintController should solve this.
PrintDocument printDocument = new PrintDocument();
PrintController printdisable = new StandardPrintController();
printDocument.PrintController = printdisable ;
I found this code to print
// The PrintDialog will print the document
// by handling the document's PrintPage event.
private void document_PrintPage(object sender,
System.Drawing.Printing.PrintPageEventArgs e)
{
// Insert code to render the page here.
// This code will be called when the control is drawn.
// The following code will render a simple
// message on the printed document.
string text = "In document_PrintPage method.";
System.Drawing.Font printFont = new System.Drawing.Font
("Arial", 35, System.Drawing.FontStyle.Regular);
// Draw the content.
e.Graphics.DrawString(text, printFont,
System.Drawing.Brushes.Black, 10, 10);
}
// Declare the PrintDocument object.
private System.Drawing.Printing.PrintDocument docToPrint =
new System.Drawing.Printing.PrintDocument();
private void printButton_Click(object sender, EventArgs e)
{
PrintDialog PrintDialog1 = new PrintDialog();
// Allow the user to choose the page range he or she would
// like to print.
PrintDialog1.AllowSomePages = true;
// Show the help button.
PrintDialog1.ShowHelp = true;
// Set the Document property to the PrintDocument for
// which the PrintPage Event has been handled. To display the
// dialog, either this property or the PrinterSettings property
// must be set
PrintDialog1.Document = docToPrint;
DialogResult result = PrintDialog1.ShowDialog();
// If the result is OK then print the document.
if (result == DialogResult.OK)
{
docToPrint.Print();
}
}
I execute it and the result of the printing is an empty page, my question is where can i put the data to print? and how can i make the printed data as rows each row has label and value.
You create the PrintDocument as a private member:
// Declare the PrintDocument object.
private System.Drawing.Printing.PrintDocument docToPrint =
new System.Drawing.Printing.PrintDocument();
But that makes it hard to attach the event handler at the right moment. I suggest using the constructor:
// Declare the PrintDocument object.
private System.Drawing.Printing.PrintDocument docToPrint;
//= new System.Drawing.Printing.PrintDocument();
public Form1() // the Form ctor
{
InitializeComponents();
docToPrint = new System.Drawing.Printing.PrintDocument();
docToPrint.PrintPage += document_PrintPage; // the missing piece
}
I'm trying to make a program that prints a textbox full text. When I'm generating it to a pdf to see the page before I print it some of the text is missing.
This is my code:
private void Print_Click(object sender, EventArgs e)
{
PrintDialog PD = new PrintDialog();
PrintDocument PDoc = new PrintDocument();
PD.Document = PDoc;
PDoc.PrintPage += new PrintPageEventHandler(PDoc_PrintPage);
DialogResult result = PD.ShowDialog();
if (result == DialogResult.OK)
{
PDoc.Print();
}
}
void PDoc_PrintPage(object sender, PrintPageEventArgs e)
{
Graphics graph = e.Graphics;
graph.DrawString(textBox1.Text,
new Font("Arial", 12), new SolidBrush(Color.Black), 10, 10);
}
This is the text (Just for a test):
hellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohello
hellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohello
hellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohellohello
this is the textbox screenshot:
This is what I get:
as you can see some of the text is missing. I'm not really familiar with printing so I have no Idea how to solve this problem.
It would appear your problem is that you want the text to wrap when printing. Have a look at this previous thread: Automatically Word-Wrapping Text To A Print Page?
while i am trying to implement font menu item in notepad ,
im not getting text changed , is there any mistake in my code
this is my code
private void fontMenuItem_Click(object sender, EventArgs e)
{
FontDialog objFontForm = new FontDialog();
objFontForm.ShowDialog();
}
Here's a really simple example taken from DotNetPearls
//Create FontDialog instance
FontDialog fontDialog1 = new FontDialog();
// Show the dialog.
DialogResult result = fontDialog1.ShowDialog();
// See if OK was pressed.
if (result == DialogResult.OK)
{
// Get Font.
Font font = fontDialog1.Font;
// Set TextBox properties.
this.textBox1.Text = string.Format("Font is: {0}", font.Name);
this.textBox1.Font = font;
}