Using the following code:
XDocument transformedDoc = new XDocument();
using (XmlWriter writer = transformedDoc.CreateWriter())
{
XslCompiledTransform transform = new XslCompiledTransform();
//transform.Load(XmlReader.Create(new StringReader(HttpContext.Current.Server.MapPath("~/XML/CareLog.xsl"))));
transform.Load(HttpContext.Current.Server.MapPath("~/XML/CareLog.xsl"));
transform.Transform(doc.CreateReader(), writer);
}
I have some strings from a database that contain <br /> for a line return(as used elsewhere). Whatever I replace this with, Environment.NewLine, \n, etc it will never put line breaks in the transformed document.
EDIT
Replaced line breaks with \r\n and changed as per suggestion below:
var xslt = new XslCompiledTransform();
xslt.Load(HttpContext.Current.Server.MapPath("~/XML/CareLogresidenceSummary.xsl"));
var settings = xslt.OutputSettings.Clone();
settings.NewLineChars = "\n";
using (var reader = doc.CreateReader())
{
using (var writer = XmlWriter.Create(HttpContext.Current.Server.MapPath("~/BrowserTemp/CareLogResidenceSummary.xml"), settings))
{
xslt.Transform(reader, writer);
}
}
Still creates transformed document ok, but still does not put anything onto a new line. For reference I am renaming the transformed document with a .doc extension to open in word, the XML has the line breaks but not when opened in Word.
You should use "\r\n" for representing new lines.
There are two ways you can handle the newlines:
Set-up the writer to use specific characters when writing new lines using the NewLineChars option.
Instruct the writer not to modify the new lines using the NewLineHandling option
So you could modify your code as follows to preserve the new lines:
var xslt = new XslCompiledTransform();
xslt.Load(HttpContext.Current.Server.MapPath("~/XML/CareLog.xsl"));
var settings = xslt.OutputSettings.Clone();
settings.NewLineChars = "\n";
settings.NewLineHandling = NewLineHandling.Replace;
using (var reader = XmlReader.Create("example.xml"))
{
using (var writer = XmlWriter.Create("yourDoc.txt", settings))
{
xslt.Transform(reader, writer);
}
}
Note that I haven't run this. The only thing you'll need to do is get your file into the call to "XmlWriter.Create()".
Related
I am writing to the file XML serialization of the object, generated by validator.MatchPossiblyValid(string input)method. First call, serializes and write to the file. However, the second call fails with an exception: System.InvalidOperationException: 'Token StartElement in state EndRootElement would result in an invalid XML document. Make sure that the ConformanceLevel setting is set to ConformanceLevel.Fragment or ConformanceLevel.Auto if you want to write an XML fragment. '
XmlSerializerNamespaces emptyNS = new XmlSerializerNamespaces(new[] { XmlQualifiedName.Empty });
var serializer = new XmlSerializer(typeof(PDPCustomerInfoInvalid));
var settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
//settings.Indent = true;
using (var stream = new System.IO.StreamWriter(args[1], true))
{
using (var writer = XmlWriter.Create(stream, settings))
{
serializer.Serialize(writer, validator.MatchPossiblyValid("STRING FOR PARSING"), emptyNS);
stream.Write(Environment.NewLine);
stream.Flush();
//Line below throws the exception
serializer.Serialize(writer, validator.MatchPossiblyValid("STRING FOR PARSING"), emptyNS);
stream.Write(Environment.NewLine);
stream.Flush();
}
}
You are trying to use a single XmlWriter to create an XML file with multiple root elements. However, the XML standard requires exactly one root element per XML document. Your XmlWriter is throwing the exception to indicate that the XML being created is invalid. (MCVE here.)
If you really need to concatenate two XML documents into a single file, you could use separate XmlWriters created with XmlWriterSettings.CloseOutput set to false:
using (var stream = new System.IO.StreamWriter(args[1], true))
{
var settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
//settings.Indent = true;
settings.CloseOutput = false;
using (var writer = XmlWriter.Create(stream, settings))
{
serializer.Serialize(writer, validator.MatchPossiblyValid("STRING FOR PARSING"), emptyNS);
}
stream.Write(Environment.NewLine);
stream.Flush();
using (var writer = XmlWriter.Create(stream, settings))
{
serializer.Serialize(writer, validator.MatchPossiblyValid("STRING FOR PARSING"), emptyNS);
}
//Line below throws the exception
stream.Write(Environment.NewLine);
stream.Flush();
}
Sample fiddle.
Or, better yet, don't do this at all, since an "XML Document" with multiple roots is, as stated above, not valid. Instead, serialize both objects inside some container element.
I'm trying to create an xml file. I already set the document and have a result with Xmlwriter when printing to console but when it comes to having an actual .xml file on my desktop I always end up with empty files. Clearly I'm missing something or forgetting something but can't tell on my own.
Below is the piece of my code where it all happens (not).
public void button1_Click(object sender, EventArgs e)
{
XmlDocument dddxml = new XmlDocument();
//XmlDeclaration xmldecl;
//xmldecl = dddxml.CreateXmlDeclaration("1.0", null, null);
//xmldecl.Encoding = "UTF-8";
//xmldecl.Standalone = "yes";
XmlWriterSettings settings = new XmlWriterSettings();
settings.Encoding = Encoding.UTF8;
settings.Indent = true;
StringBuilder builder = new StringBuilder();
writer = XmlWriter.Create(builder, settings);
writer.WriteStartDocument();
writer.WriteStartElement("root");
BlockSelect(0);
writer.WriteEndElement();
writer.WriteEndDocument();
writer.Close();
Console.WriteLine(builder.ToString());
writer = XmlWriter.Create("DddXml.Xml", settings);
dddxml.Save(writer);
File.Create(path);//declared elsewhere, valid file location string
}
You have created new XmlDocument here:
XmlDocument dddxml = new XmlDocument();
But you haven't populated it in the rest of the code and in fact you're not using it and writing xml to string builder using WriteStartDocument and WriteEndElement methods of XmlWriter.
Thus your dddxml remains empty, so when you're trying to save it like this:
dddxml.Save(writer);
, there is nothing to save and you're getting empty file.
So you have to choose - will you use XmlDocument or XmlWriter to create and save your xml.
As commented by #Charles Mager, File.Create() just makes an empty file.
You can try to write directly to the file instead of using StringBuilder. Here's a sample to directly write to the file using the XmlWriter:
XmlWriter writer = XmlWriter.Create("C:\\ddxml.xml", settings);
writer.WriteStartDocument();
writer.WriteStartElement("root");
writer.WriteEndElement();
writer.WriteEndDocument();
writer.Close();
See that the file is written on C:\ddxml.xml.
If you want you can also use LINQ, it's easier :
XDocument doc = new XDocument();
XNamespace ns = "";
doc.Add(new XElement(ns + "root"));
doc.Save(#"C:\DddXml.Xml");
I'm currently trying to serialize a class into XML to be posted to php web service.
Whenever I did the normal serialization using XMLSerializer, XML declaration is always appear in the first line of the XML document (similar as to <?xml ....?>). I tested the XML and unable to get it working because the endpoint does not accept XML declaration and I can't do anything about it.
I'm unfamiliar with XML Serialization in C# to be honest.
Therefore, I used XMLWriter to do this as below :-
private string SerializeClassToString(GetRiskReport value)
{
var emptyNS = new XmlSerializerNamespaces(new[] { XmlQualifiedName.Empty });
var ser = new XmlSerializer(value.GetType());
var settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
using (var stream = new StringWriter())
{
using (var writer = XmlWriter.Create(stream, settings))
{
ser.Serialize(writer, value, emptyNS);
return stream.ToString();
}
}
}
Result for the Namespace is
<GetRiskReport FCRA=\"false\" ReturnResultsOnly=\"false\" Monitoring=\"false\">
... and I'm able to omit the XML Declaration, however I'm being introduced with 2 new problem.
I got \r\n for new line and I have escaped double quote such as ReturnResultsOnly=\"false\" Monitoring=\"false\" which is also unable processed by the endpoint.
I would like to ask is that does anyone can give me an idea on how to change the XmlWriterSetting to omit XML Declaration, avoid \r\n and also avoid escaped double quotes \"
Thanks for your advice in advance.
Simon
Try with following settings
settings.NewLineHandling = NewLineHandling.None;
settings.CheckCharacters = false;
private void SerializeClassToString(GetRiskReport value)
{
var emptyNS = new XmlSerializerNamespaces(new[]{XmlQualifiedName.Empty});
var ser = new XmlSerializer(value.GetType());
var settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
string path = 'your_file_path_here'
if (File.Exists(path)) File.Delete(path);
FileStream stream = File.Create(path);
using (var writer = XmlWriter.Create(stream, settings))
{
ser.Serialize(writer, value, emptyNS);
return;
}
}
There was no way to avoid ms bug or thier intensional specification about xmlserializing.It's easier and faster to use filestream object.
I have a function that translates a xml file using a xsl style sheet. It does the job fine; but when I want to delete that transformed file sometimes I get the following error: System.IO.IOException: The process cannot access the file
The function is like this:
XslTransform transform = new XslTransform();
transform.Load('xsl_style_sheet');
transform.Transform('fullpath/xmlfilename','fullpath/transformedFileName')
XElement xEle = XElement.Load('fullpath/transformedFileName');
I do what ever with the xEle and in the end I want to delete the 'fullpath/transformedFileName' but some times i get the dreaded System.IO.IOException: The process cannot access the file
Can any one please help. A million thanks
Use the XslCompiledTranform class (XslTranform is obsolete ) and the overload on Transform that accepts an XmlReader and XmlWriter. You can call Dispose on them, they will take care of closing and disposing the underlying stream.
// Load the style sheet.
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load("xsl_style_sheet");
// Create the writer.
XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;
settings.IndentChars = "\t";
using(XmlWriter writer = XmlWriter.Create("fullpath/transformedFileName", settings))
{
using(XmlReader reader = XmlReader.Create("fullpath/xmlfilename"))
{
reader.MoveToContent();
xslt.Transform(reader, writer);
}
}
using(XmlReader reader = XmlReader.Create("fullpath/transformedFileName"))
{
XElement xEle = XElement.Load(reader);
// do all other stuff you need to do here
// after this the file will be closed
}
I am new to LINQ to XML. After you have built XDocument, how do you get the OuterXml of it like you did with XmlDocument?
You only need to use the overridden ToString() method of the object:
XDocument xmlDoc ...
string xml = xmlDoc.ToString();
This works with all XObjects, like XElement, etc.
I don't know when this changed, but today (July 2017) when trying the answers out, I got
"System.Xml.XmlDocument"
Instead of ToString(), you can use the originally intended way accessing the XmlDocument content: writing the xml doc to a stream.
XmlDocument xml = ...;
string result;
using (StringWriter writer = new StringWriter())
{
xml.Save(writer);
result = writer.ToString();
}
Several responses give a slightly incorrect answer.
XDocument.ToString() omits the XML declaration (and, according to #Alex Gordon, may return invalid XML if it contains encoded unusual characters like &).
Saving XDocument to StringWriter will cause .NET to emit encoding="utf-16", which you most likely don't want (if you save XML as a string, it's probably because you want to later save it as a file, and de facto standard for saving files is UTF-8 - .NET saves text files as UTF-8 unless specified otherwise).
#Wolfgang Grinfeld's answer is heading in the right direction, but it's unnecessarily complex.
Use the following:
var memory = new MemoryStream();
xDocument.Save(memory);
string xmlText = Encoding.UTF8.GetString(memory.ToArray());
This will return XML text with UTF-8 declaration.
Doing XDocument.ToString() may not get you the full XML.
In order to get the XML declaration at the start of the XML document as a string, use the XDocument.Save() method:
var ms = new MemoryStream();
using (var xw = XmlWriter.Create(new StreamWriter(ms, Encoding.GetEncoding("ISO-8859-1"))))
new XDocument(new XElement("Root", new XElement("Leaf", "data"))).Save(xw);
var myXml = Encoding.GetEncoding("ISO-8859-1").GetString(ms.ToArray());
Use ToString() to convert XDocument into a string:
string result = string.Empty;
XElement root = new XElement("xml",
new XElement("MsgType", "<![CDATA[" + "text" + "]]>"),
new XElement("Content", "<![CDATA[" + "Hi, this is Wilson Wu Testing for you! You can ask any question but no answer can be replied...." + "]]>"),
new XElement("FuncFlag", 0)
);
result = root.ToString();
While #wolfgang-grinfeld's answer is technically correct (as it also produces the XML declaration, as opposed to just using .ToString() method), the code generated UTF-8 byte order mark (BOM), which for some reason XDocument.Parse(string) method cannot process and throws Data at the root level is invalid. Line 1, position 1. error.
So here is a another solution without the BOM:
var utf8Encoding =
new UTF8Encoding(encoderShouldEmitUTF8Identifier: false);
using (var memory = new MemoryStream())
using (var writer = XmlWriter.Create(memory, new XmlWriterSettings
{
OmitXmlDeclaration = false,
Encoding = utf8Encoding
}))
{
CompanyDataXml.Save(writer);
writer.Flush();
return utf8Encoding.GetString(memory.ToArray());
}
I found this example in the Microsoft .NET 6 documentation for XDocument.Save method. I think it answers the original question (what is the XDocument equivalent for XmlDocument.OuterXml), and also addresses the concerns that others have pointed out already. By using the XmlWritingSettings you can predictably control the string output.
https://learn.microsoft.com/en-us/dotnet/api/system.xml.linq.xdocument.save
StringBuilder sb = new StringBuilder();
XmlWriterSettings xws = new XmlWriterSettings();
xws.OmitXmlDeclaration = true;
xws.Indent = true;
using (XmlWriter xw = XmlWriter.Create(sb, xws)) {
XDocument doc = new XDocument(
new XElement("Child",
new XElement("GrandChild", "some content")
)
);
doc.Save(xw);
}
Console.WriteLine(sb.ToString());
Looking at these answers, I see a lot of unnecessary complexity and inefficiency in pursuit of generating the XML declaration automatically. But since the declaration is so simple, there isn't much value in generating it. Just KISS (keep it simple, stupid):
// Extension method
public static string ToStringWithDeclaration(this XDocument doc, string declaration = null)
{
declaration ??= "<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n";
return declaration + doc.ToString();
}
// Usage
string xmlString = doc.ToStringWithDeclaration();
// Or
string xmlString = doc.ToStringWithDeclaration("...");
Using XmlWriter instead of ToString() can give you more control over how the output is formatted (such as if you want indentation), and it can write to other targets besides string.
The reason to target a memory stream is performance. It lets you skip the step of storing the XML in a string (since you know the data must end up in a different encoding eventually, whereas string is always UTF-16 in C#). For instance, for an HTTP request:
// Extension method
public static ByteArrayContent ToByteArrayContent(
this XDocument doc, XmlWriterSettings xmlWriterSettings = null)
{
xmlWriterSettings ??= new XmlWriterSettings();
using (var stream = new MemoryStream())
{
using (var writer = XmlWriter.Create(stream, xmlWriterSettings))
{
doc.Save(writer);
}
var content = new ByteArrayContent(stream.GetBuffer(), 0, (int)stream.Length);
content.Headers.ContentType = new MediaTypeHeaderValue("text/xml");
return content;
}
}
// Usage (XDocument -> UTF-8 bytes)
var content = doc.ToByteArrayContent();
var response = await httpClient.PostAsync("/someurl", content);
// Alternative (XDocument -> string -> UTF-8 bytes)
var content = new StringContent(doc.ToStringWithDeclaration(), Encoding.UTF8, "text/xml");
var response = await httpClient.PostAsync("/someurl", content);