Is it possible to bind the contents of an xml file with a data grid view in c#? Maybe using... LINQ? can I do that? I want to display the contents of an xml file within a grid view, edit, add or delete them there and then save them in the xml file I loaded in the first place. I'd also like to be able to search through the grid and edit multiple items. I am creating a forms application. The xml file is simple it only:
<people>
<person name='John' email='John#email.com'/>
</people>
There can be lots of records of type person.
What's the best way to approach this problem?
The easiest way recommended by MSDN here http://msdn.microsoft.com/en-us/magazine/cc163669.aspx is to load it into a data set.
There is an entire set of code in Vb.Net over at DevX here and a tutorial that might help you with binding DataGridView to XML via data sets. http://www.devx.com/dotnet/Article/28678/1954
Hope this helps. It is in Vb.Net but you will get idea.
Assuming you have loaded your xml into "doc" XDocument
var persons = from item in doc.Descendants("person")
select new
{
Name = item.Element("name").Value,
Mail = item.Element("email").Value
};
myDataboundControl.DataSource = persons;
myDataboundControl.Databind();
first you have to get the path of the XML file .Then create a new data set then bind the data set with the data grid view as your wish. you can also use SQL query to update,delete the XML file.
{
Data Set dd = new Data Set();
dd.ReadXml ("XML Path");
DataTable xm = ds.Tables[0];
}
Related
Currently have a project where I am dumping a result set of data to an excel and creating pivot table with this raw data using Closed XML
I cannot seem to get the report Layout to set and persist as tabular
Below is a sample of the code I am using to implement this
var ptSheet = wb.Worksheets.Add("PivotTable");
var pt = ptSheet.PivotTables.Add("PivotTable", ptSheet.Cell(1, 1), range);
pt.SetLayout(XLPivotLayout.Tabular);
pt.Layout = XLPivotLayout.Tabular;
'SetLayout' & 'Layout' seem to make no changes to the layout of the pivot on save of the excel. Are other settings required to be toggled?
Just adding this solution in case someone has similar issue.
I found adding the following line of code to my above example made the pivot table layout appear as tabular
pt.ClassicPivotTableLayout = true;
Not the most elegant solution but works for my use case
I have XML file of object.I want to get instance of that object.But i dont have class.I must read XML and create dynamically how to say class. How to do?
See this page, it can help but you need .NET 4.
I guess you want to read data from an XML into your class. If so, you can use the following way to read the data from a file.
var records = from r in XElement.Load(#"YourFile.xml").Elements("NodeName")
select r;
I am building a web application where I have to read some values from the config file which I am assuming as nothing but an XML file. So in this process I am able to read the XML document using
XDocument config = XDocument.Load("\\path\to\example.exe.config");
Now I have a textbox in my web page. I want to get a specific value into that textbox where the user can edit and update that value in the textbox.
Can any one guide me to the solution?
Using C#, Linq to XML, Asp.net
Well you have an XDocument, so you can use Linq to XML to query it for the value. Put that in the textbox when the page is rendered. Of course when you POST the value you'll have to load the file a second time, query the XDocument again, and then update the XML element with the new value before saving.
This code
XmlDataDocument xmlDataDocument = new XmlDataDocument(ds);
does not work for me, because the node names are derived from the columns' encoded ColumnName property and will look like "last_x20_name", for instance. This I cannot use in the resulting Excel spreadsheet. In order to treat the column names to make them something more friendly, I need to generate the XML myself.
I like LINQ to XML, and one of the responses to this question contained the following snippets:
XDocument doc = new XDocument(new XDeclaration("1.0","UTF-8","yes"),
new XElement("products", from p in collection
select new XElement("product",
new XAttribute("guid", p.ProductId),
new XAttribute("title", p.Title),
new XAttribute("version", p.Version))));
The entire goal is to dynamically derive the column names from the dataset, so hardcoding them is not an option. Can this be done with Linq and without making the code much longer?
It ought to be possible.
In order to use your Dataset as a source you need Linq-to-Dataset.
Then you would need a nested query
// untested
var data = new XElement("products",
from row in ds.Table["ProductsTable"].Rows.AsEnumerable()
select new XElement("product",
from column in ds.Table["ProductsTable"].Columns // not sure about this
select new XElement(colum.Fieldname, rows[colum.Fieldname])
) );
I appreciate the answers, but I had to abandon this approach altogether. I did manage to produce the XML that I wanted (albeit not with Linq), but of course there is a reason why the default implementation of the XmlDataDocument constructor uses the EncodedColumnName - namely that special characters are not allowed in element names in XML. But since I wanted to use the XML to convert what used to be a simple CSV file to the XML Spreadsheet format using XSLT (customer complains about losing leading 0's in ZIP codes etc when loading the original CSV into Excel), I had to look into ways that preserve the data in Excel.
But the ultimate goal of this is to produce a CSV file for upload to the payroll processor, and they mandate the column names to be something that is not XML-compliant (e.g. "File #"). The data is reviewed by humans before the upload, and they use Excel.
I resorted to hard-coding the column names in the XSLT after all.
Whats the best way to read Xml from either an XmlDocument or a String into a DataGrid?
Does the xml have to be in a particular format?
Do I have to use A DataSet as an intermediary?
I'm working on a client that consumes Xml sent over from a Server which is being developed by one of my colleagues, I can get him to change the format of the Xml to match what a DataGrid requires.
It depends on which version of .NET you are running on. If you can use Linq2Xml then it is easy. Just create an XDocument and select the child nodes as a list of an anonymous type.
If you can't use Linq2Xml then you have a few other options. Using a DataSet is one, this can work well, but it depends on the xml you are receiving. An other option is to create a class that describes the entity you will read from the xml and step through the xml nodes manually. A third option would be to use Xml serialization and deserialize the xml into a list of objects. This can work well as long as you have classes that are setup for it.
The easiest option will be either to create an XDocument or to create a DataSet as you suggest.
Obviously your XML needs to be valid :)
After that, define a dataset, define a datagrid. Use the readXML method on the dataset to fill the dataset with your XML, finish with a dataBind and you are good to go.
DataSet myDataSet = new DataSet();
myDataSet .ReadXml(myXMLString);
myDataGrid.DataSource = myDataSet ;
myDataGrid.DataBind();
You can simply use the XmlDatasource object as the grid's data source. That allows you to set the file and the XPath, in order to choose the XML that is the soure of your data. You can then use the <%# XPath="blah"%> function to write out your data explicitely, if you like.
We have a partial answer to get the data into a dataset but it reads it in as a set of tables with relational links.
DataSet ds = new DataSet();
XmlTextReader xmlreader = new XmlTextReader(xmlSource, XmlNodeType.Document, null);
ds.ReadXml(xmlreader);