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Remove the biggest value from a linked list

So I've said it in the title, I want to delete the biggest value from a LinkedList, can't get my head around how to exactly do it. I tried this but I get an error.
//Remove n from list 'first'
public static void Remove(Node<int> first, Node<int> n)
{
Node<int> pos = first;
while (pos.GetNext() != n)
pos = pos.GetNext();
pos.SetNext(n.GetNext());
}
public static void DeleteMaxValue(Node<int> first)
{
int max = 0;
Node<int> pos = first;
Node<int> maxNode = null;
while(pos.GetNext() != null)
{
if (pos.GetNext().GetValue() > max)
{
maxNode = new Node<int>(pos.GetNext().GetValue());
}
pos = pos.GetNext();
}
Remove(first, maxNode);
}

imagine this is your Node structure in linked list
public class Node
{
public int data;
public Node next;
}
you can use this function to find the biggest number in the linked list and then remove it.
public int GetMax(Node head)
{
int max = int.MinValue();
while(head != null)
{
if(max < head.data)
max = head.data;
head = head.next;
}
return max;
}

Several issues:
max is never updated. It should be updated when you have found a greater value, otherwise the last positive value is considered the greatest.
maxNode is never a node that is in the list, since it is created as a new node. By consequence the Remove function will not find it and nothing gets deleted.
Your function's signature has no way of deleting the first node, since first is passed by value. There is no way to solve this for all cases, unless you change the design:
Either let first be a member of your class, and then don't pass it as argument, or
Let the function return the (potentially) new value of first, so the caller can adapt its own reference to the head of the list.
max = 0 assumes that your list cannot have negative values. In case this is possible, I would suggest initialising max with the value that is in the first node (after having checked that the list is not empty).
Instead of cycling again through the list with Remove, keep a reference to the node the precedes the node that is to be deleted.
Here is a function that returns the value of first, so the caller can make an update to their own reference in case the first node was deleted:
// Return type changed: the function will return the first node
public static Node<int> DeleteMaxValue(Node<int> first)
{
if (first == null) { // In an empty list there is nothing to delete
return;
}
int max = first.GetValue(); // Don't use 0, values might be negative
Node<int> pos = first;
Node<int> maxNode = first;
Node<int> beforeMaxNode = null; // Have a reference that lags behind
while(pos.GetNext() != null)
{
int val = pos.GetNext().GetValue();
if (val > max)
{
max = val; // Update max
beforeMaxNode = pos; // Don't create a new node
}
pos = pos.GetNext();
}
if (beforeMaxNode == null) { // First node has the maximum
// Now `first` reference will change, so it's important to return
// that new reference, else the caller will not see any change
first = maxNode.GetNext();
} else {
beforeMaxNode.SetNext(maxNode.GetNext());
}
return first;
}

swapping nodes in doubly linked list

Trying to swap the second and third nodes from a doubly linked list in c# with the following method:-
public static void swapNodes(List dblLinkList)
{
Node tempnodeTwo = dblLinkList.firstNode.next; //node two in list
Node tempnodeThree = dblLinkList.firstNode.next.next; //node three in list
Node tempnodeFive = tempnodeTwo.previous;
Node tempnodeSix = tempnodeThree.next;
tempnodeThree.previous = tempnodeFive;
tempnodeThree.next = tempnodeThree;
tempnodeTwo.previous = tempnodeTwo;
tempnodeTwo.next = tempnodeSix;
}
The following shows the output: The first is the original list and the second is the result of the method.
N:19:16 19:16:9 16:9:15 9:15:15 15:15:N
N:19:16 16:16:15 9:15:15 15:15:N
Where am I going wrong?? I have already studied previous questions about this topic which gave me the idea for the code but now stuck!

It seems that you assume tempnodeThree is the third and tempnodeTwo is the second node
of the linked list regardless of the changes you make but this is not the case.
After the initializations what you get is:
tempnodeFive <--> tempnodeTwo <--> tempnodeThree <--> tempnodeSix
And you need is:
tempnodeFive <--> tempnodeThree <--> tempnodeTwo <--> tempnodeSix
So what you have to change from left to right are:
tempNodeFive.next, tempNodeTwo.previous, tempNodeTwo.next, tempNodeThree.previous, tempNodeThree.next, tempNodeSix.previous
Let's go over them following the 2nd linked list representation:
tempNodeFive.next = tempNodeThree;
tempNodeTwo.previous = tempnodeThree;
tempNodeTwo.next = tempnodeSix;
tempNodeThree.previous = tempnodeFive;
tempNodeThree.next = tempnodeTwo;
tempNodeSix.previous = tempnodeTwo;
These six lines are what you need.
PS: You can reconsider variable names for a readable and maintainable code, esp. tempNodeFive and tempnodeSix because five and six does not make any sense as an index and it arises confusion while reading the code.

well here in these lines
tempnodeThree.next = tempnodeThree;
tempnodeTwo.previous = tempnodeTwo;
you are setting the next of a node to itself and the previous of another to itself.
don't you mean
tempnodeThree.next = tempnodeTwo;
tempnodeTwo.previous = tempnodeThree;
I think you would have an easier time if you used better names.
I also would not implement this function like this -- I'd make the function suit it's name like this:
public static void swapNodes(Node a, Node b)
{
if (a == null) return;
if (b == null) return;
Node afterA = a.next;
Node beforeA = a.previous;
a.previous = b.previous;
if (b.previous != null) b.previous.next = a;
a.next = b.next;
if (b.next != null) b.next.previous = a;
b.next = afterA;
if (afterA != null) afterA.previous = b;
b.previous = beforeA;
if (beforeA != null) beforeA.next = b;
}
// call it like this
swapNodes(dblLinkList.firstNode.next, dblLinkList.firstNode.next.next);

Are you sure it's c#? Looks like java. C# has LinkedListNode<T> class, not Node. And LinkedListNode<T> has Next and Previous properties. With capitals. And they are read only.
Any way c# implementation looks like this:
using System;
using System.Collections.Generic;
namespace LinkedListSwap
{
class Program
{
static void Main(string[] args)
{
var list = new LinkedList<string>(new[] { "1st", "2nd", "3rd", "4th", "5th", "6th", "7th" });
Console.WriteLine(list.ToDisplayString());
list.Swap(2, 3);
Console.WriteLine(list.ToDisplayString());
}
}
static class LinkedListExtensions
{
public static void Swap<T>(this LinkedList<T> list, int firstIndex, int secondIndex)
{
if (firstIndex < 1 || firstIndex > list.Count)
throw new IndexOutOfRangeException($"Index out of range: {nameof(firstIndex)}");
if (secondIndex < 1 || secondIndex > list.Count)
throw new IndexOutOfRangeException($"Index out of range: {nameof(secondIndex)}");
if (firstIndex == secondIndex)
return;
if (firstIndex > secondIndex)
(firstIndex, secondIndex) = (secondIndex, firstIndex);
int i = 0;
var leftNode = list.First;
while (++i < firstIndex)
leftNode = leftNode.Next;
var rightNode = leftNode.Next;
while (++i < secondIndex)
rightNode = rightNode.Next;
list.Replace(leftNode, rightNode);
list.Replace(rightNode, leftNode);
}
public static void Replace<T>(this LinkedList<T> list, LinkedListNode<T> oldNode, LinkedListNode<T> newNode)
{
list.AddAfter(oldNode, new LinkedListNode<T>(newNode.Value));
list.Remove(oldNode);
}
public static string ToDisplayString<T>(this LinkedList<T> list) => string.Join(" ", list);
}
}
Output is:
1st 2nd 3rd 4th 5th 6th 7th
1st 3rd 2nd 4th 5th 6th 7th

fill in delimited sequence

I have a file that contains a list of delimited sequence numbers as a record key. I need to fill in the missing sequence. So if I have
8
8.2
8.3.4.1
I need to add
8.1
8.3
8.3.1
8.3.2
8.3.3
8.3.4
I have come up with a few algorithms but they're all horribly complex and have too many cases. Is there an easy way to do this or do I have to plod through? I'm using c# but Java would do.

Not sure if my solution is easy to understand, but let's try. The idea is that we recursively insert missing sequences between existing ones.
First, you need to parse your file to create a List of items representing existing sequence. Every item should have reference to the next one (linked list idea).
public class Item
{
public int Value { get; set; }
public Item SubItem { get; set; }
public Item NextItem { get; set; }
public Item(int value, Item subItem)
{
Value = value;
SubItem = subItem;
}
public Item CreatePreviousItem()
{
if (SubItem == null)
{
return Value == 1 ? null : new Item(Value - 1, null);
}
return new Item(Value, SubItem.CreatePreviousItem());
}
public bool IsItemMissingPrior(Item item)
{
if (item == null)
{
return false;
}
return
item.Value - Value > 1
|| (SubItem == null && item.SubItem != null && item.SubItem.Value > 1) //edge case
|| (SubItem != null && SubItem.IsItemMissingPrior(item.SubItem));
}
public override string ToString()
{
return Value + (SubItem != null ? "." + SubItem : "");
}
}
Assuming that sequences are delimited by new line symbol, you can use the following Parse method.
private List<Item> Parse(string s)
{
var result = new List<Item>();
var numberLines = s.Split(new[] {Environment.NewLine}, StringSplitOptions.RemoveEmptyEntries);
foreach (var numberLine in numberLines)
{
var numbers = numberLine.Split(new[] {'.'}).Reverse();
Item itemInstance = null;
foreach (var number in numbers)
{
itemInstance = new Item(Convert.ToInt32(number), itemInstance);
}
if (result.Count > 0)
{
result.Last().NextItem = itemInstance;
}
result.Add(itemInstance);
}
return result;
}
Here is a recursive method which inserts missing sequences between two existing ones
private void UpdateSequence(Item item)
{
if (item.IsItemMissingPrior(item.NextItem))
{
var inBetweenItem = item.NextItem.CreatePreviousItem();
inBetweenItem.NextItem = item.NextItem;
item.NextItem = inBetweenItem;
UpdateSequence(item);
}
}
And finally the use case:
var inputItems = Parse(inputString);
foreach (var item in inputItems)
{
UpdateSequence(item);
}
That's it. To see the result, you just need to get the first item from the list and keep moving forward using NextItem property. For example
var displayItem = inputItems.FirstOrDefault();
while (displayItem != null)
{
Console.WriteLine(displayItem.ToString());
displayItem = displayItem.NextItem;
}
Hope it helps.

One of the easy ways (though not optimal for some cases) will be maintaining a set of existing keys. For each key in your initial sequence you can add all the preceding keys to that set. This can be done in two loops: in inner loop you add a key to a set and decrease last number of a key by one while the number is more than zero, in outer loop you decrease the length of a key by one.
And then you just need to output the set in sorted order.

Creating custom LinkedList

I am working on creating my own LinkedList. But I can't seem to solve this error. Can anyone help me!
The problem is that I want to insert an object after a particular element. I have created Find method to search for that particular item and return its reference, but I can't seem to solve it.
CustomLinkedList c = new CustomLinkedList();
c.Add(31);
c.Add(45);
c.Add(23);
c.Add(36);
c.PrintList();
Console.WriteLine("\n" + " Process of adding item at a spectifed location");
c.Addafter(66,23);
c.PrintList();
class Node
{
public object Element;
public Node Link;
public Node()
{
Element = null;
Link = null;
}
public Node(object TheElement)
{
Element = TheElement;
Link = null;
}
class CustomLinkedList
{
protected Node header;
protected Node last;
public CustomLinkedList()
{
//header = new Node("header");
}
private Node Find(object Item)
{
Node Current = new Node();
Current = header;
while (Current.Element != Item && Current.Link !=null)
{
Current = Current.Link;
}
return Current;
}
public void PrintList()
{
Node n = new Node();
n = header;
while (n != null)
{
Console.WriteLine(n.Element);
n = n.Link;
}
}
public void Add(object a)
{
Node n = new Node();
n.Element = a;
n.Link = null;
if (last == null)
{
header = n;
last = n;
}
else
{
last.Link = n;
last = n;
}
}
public void Addafter(object newitem, object After)
{
Node current = new Node();
Node newNode = new Node(newitem);
current = Find(After);
newNode.Link = current.Link;
current.Link = newNode;
}
}

The reason why it doesn't work is on this line:
while (Current.Element != Item && Current.Link !=null)
The == and != operators for the object type check for reference equality. If you're using your list with a value type (int for instance), the values will be boxed to distinct objects, and the != operator will always return true (see this article for details about boxing).
Consider this:
object x = 42;
object y = 42;
Console.WriteLine(x == y); // prints False
Console.WriteLine(x.Equals(y)); // prints True
Your current code is working fine with reference types:
var list = new CustomLinkedList();
list.Add("hello");
list.Add("!");
list.Addafter("world", "hello");
list.PrintList();
Output:
hello
world
!
But for value types it never finds the "after" value, so it appends the new item to the end of the list:
var list = new CustomLinkedList();
list.Add(1);
list.Add(3);
list.Addafter(2, 1);
list.PrintList();
Output:
1
3
2
So you need to replace the == operator with a call to Equals:
while (!object.Equals(Current.Element, Item) && Current.Link !=null)

I don't know what you're using for testing but value types won't work the way you think it should because the box values are being compared.
For example this will always return 3 (last element in list)
CustomLinkedList cList= new CustomLinkedList();
cList.Add(1);
cList.Add(2);
cList.Add(3);
Console.WriteLine(cList.Find(2).Element);
but this will work (output 2)
CustomLinkedList cll = new CustomLinkedList();
object a = 1;
object b = 2;
object c = 3;
cll.Add(a);
cll.Add(b);
cll.Add(c);
Console.WriteLine(cll.Find(b).Element);
The same goes for reference types that don't implement the != operators. So strings will work but little else will

Your code has 2 problems
The Find() function is returning the Tail element when the Item is not in the List.
Comparing n.Element and Item is tricky when they are of type object. Make your classes generic to solve that.
...
class CustomLinkedList<T> where T : IEquatable
{
....
private Node Find(object Item)
{
Node Current = header; // null for empty list
//while (Current.Element != Item && Current.Link !=null)
while(Current != null)
{
if (Current.Equals(Item) ) // can't always use ==
break;
Current = Current.Link;
}
return Current;
}
}

Reverse a single chained List

I hope I am using the right terminology.
I have made a single-chained list.
class MyStack
{
public Node Initial { get; set; }
public MyStack()
{
Initial = null;
}
public void Push(int data)
{
var node = new Node { Data = data, Next = Initial };
Initial = node;
}
public int Pop()
{
int res = Initial.Data;
Initial = Initial.Next;
return res;
}
public int Sum()
{
int sum = 0;
Node currentNode = Initial;
while (currentNode != null)
{
sum += currentNode.Data;
currentNode = currentNode.Next;
}
return sum;
}
public int Count()
{
int count = 0;
Node currentNode = Initial;
while (currentNode != null)
{
count++;
currentNode = currentNode.Next;
}
return count;
}
public void PrintAll()
{
Node currentNode = Initial;
while(currentNode != null)
{
Console.WriteLine("tmp.Data = " + currentNode.Data);
currentNode = currentNode.Next;
}
}
}
public class Node
{
public int Data;
public Node Next;
}
Meaning you can do something like this:
var s = new MyStack();
s.Push(5);
s.Push(3);
s.Push(7);
s.PrintAll();
Console.WriteLine("Sum: " + s.Sum());
Console.WriteLine("Count: " + s.Count());
Now, I want to try and make a Reverse method. This seems to be working:
public void Reverse()
{
Node predesesor, location;
location = Initial;
predesesor = null;
while(Initial != null)
{
Initial = Initial.Next;
location.Next = predesesor;
predesesor = location;
location = Initial;
}
Initial = predesesor;
}
I am hardly able to see how it works, and it will be tough to maintain.
It seems more like a hack than anything else.
Can you offer any assistance?

It doesn't seem like a hack to me and I don't see what's there to maintain (it is either correct or not, what else would you do with it?). If you want to figure out how it works, "execute" each step on paper. Draw a list (e.g 1 -> 3 -> 5 -> 7 -> 9 -> NULL), mark out where all Nodes point at any time and start "single-stepping".
I couldn't think of a cleaner way to reverse a singly linked list. You need a reference to the next node (Initial at the beginning of the loop), before you can reverse the link between current node and previous node. You just won't be able to move on in the original list otherwise.
What you could do is fix the spelling of the variables and perhaps not use Initial in the loop itself (use a third variable, so the role of each variable is clearer) and only set Initial to the first Node in the reversed list at the end.
So, all in all:
public void Reverse() {
Node current = Initial, previous = null;
while (current) {
Node next = current.Next;
current.Next = previous;
previous = current;
current = next;
}
Initial = previous;
}

One solution would be to turn it into a doubly-linked list, and then work backwards using the previous node property:
public class Node
{
public int Data;
public Node Next;
public Node Previous;
}
There is already a doubly-linked list in the framework if you want to save yourself some effort.

you can do it recursivly:
a->b->c->d
a->null
b->null
c->null
c<-d
b<-c
a<-b
a<-b<-c<-d
public void Reverse()
{
Reverse(Initial);
}
private void Reverse(Node node)
{
if(node != null && node.Next != null)
{
//go deeper
Reverse(node.Next);
//swap
node.Next.Next = node
node.Next = null;
}
}

Instead of reinventing the wheel you should check, if there is already something you can use something from .Net Framework.
For example i would take here the LinkedList with the LinkedListNode. In other cases you could probably take the Queue or a Stack.

If you call it "nreverse" or "reverse in place" then any developer worth tuppence would recognise it as a classic algorithm rather than a hack.
It shouldn't require much maintenance, except maybe renaming any incorrectly spelled variables.

The following code might be a bit more intuitive:
public void Reverse()
{
MyStack reverse = new MyStack();
while (Initial != null)
{
reverse.Push(this.Pop());
}
Initial = reverse.Initial;
}
(Reverse is a member method of the MyStack class).
Of course, it does require twice the space compared with the original code.

stack s1
s1.push_front(...)
...
s1.push_front(...)
////////////////////////////////////////////////////////
void reverse(stack& to,stack_or_list& s )
while(!s.empty()){
to.push_front(s.pop_front());
}
}
now a series of to.pop_fronts gets you what you want
stack_or_list needs: pop_front empty
to needs: push_front,pop_front