I have a PictureBox.
If I right click the PictureBox, my ContextMenuStrip (right click menu) appears.
In that ContextMenuStrip is a ToolStripMenuItem (one of the options in the right click menu).
There is an event on the ToolStripMenuItem that handles what happens if that option is clicked.
We're starting from ToolStripMenuItem's "Clicked" function. I need to somehow get back to the PictureBox programmatically. From there, I can modify the PictureBox.
ToolStripMenuItem -> ContextMenuStrip -> PictureBox
How would I go about this?
If the click event handler for your menu item is named OnToolStripMenuItemClick, the following might be an approach to your problem:
private void OnToolStripMenuItemClick(object sender, EventArgs e)
{
var menuItem = sender as ToolStripMenuItem;
var contextMenu = menuItem.Parent as ContextMenuStrip;
var pictureBox = contextMenu.SourceControl;
}
Of course, don't forget to check for null when accessing properties after conversion with as.
I'm not sure that I really understood your problem, but I guess you want to let users can return to the picturebox when they want to cancel current operation by clicking the right button. In this case, you should not implement your work in click event, because right and left button both can trigger the click event, instead, you should process your work in the event "MouseUp", like this:
private void menuItemBack_MouseUp(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Left)
{
MessageBox.Show("back item is clicked");
}
else
{
MessageBox.Show("I will come back.");
//do your return things here.
}
}
I've just come across this same problem in C#, and the path to the value seems to be something like:
sender.Owner.SourceControl;
However, since sender, Owner and so on are generic classes, I had to cast everything as follows:
PictureBox pb = (PictureBox) ((ContextMenuStrip)((ToolStripMenuItem)sender).Owner).SourceControl;
Ugly, but it works.
Related
Why in every right click, the contextmenustrip pop up,how to enable it in a specify position by controlling the right click event??
Try to remove the default contextmenustrip and create a new one.
With HitTest on a control you can check if the clicked position is on a element
private void MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
if (dataGrid.HitTest(e.X, e.Y).Type == DataGridViewHitTestType.ColumnHeader)
{
new ContextMenuStrip().Show(dataGrid, e.Location);
}
}
}
See: How do I correctly position a Context Menu when I right click a DataGridView's column header?
I want to capture the right click mouse event within the ToolStripDropDownItemClicked Event
private void toolStripDropDownButton1_DropDownItemClicked(object sender, ToolStripItemClickedEventArgs e)
Based on the right click, i display a contextmenu. So, I need to get both the item clicked and mouse click right.
You could use the MouseUp or MouseDown event it knows which button was pressed.
The sender object is the menu item that was clicked. Cast it to the correct type to access it's properties. If you're not sure about the type you could use as and then check if the resulting object is null.
void firstToolStripMenuItem_MouseUp(object sender, MouseEventArgs e)
{
var toolStripMenuItem = (ToolStripMenuItem)sender;
var nullIfOtherType = sender as ToolStripMenuItem;
var right = e.Button == System.Windows.Forms.MouseButtons.Right;
}
How to get a right click mouse event? Changing EventArgs to MouseEventArgs causes an error in Form1Designer?
i have a WPF tab control with two tabs(A, B). Since there is no Clicked Event on the TabItem,therefore i add an previewMouseDown event on the Tab B and a messageBox will show up. However, after i close the messageBox, my application will not navigate to the Tab B. Anyone can help me?
C# code snippet :
private void MyTabB_PreviewMouseDown(object sender, MouseButtonEventArgs e)
{
MessageBox.Show("Please login");
}
You can use the TabControlSelectionChanged event.
Since you know the selected tab for login say index 0, change selected tab after the MessageBox ie something like this
MyTabB_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
TabControl tc= ((TabControl)sender;
if(tc.SelectedIndex == tc.Items.IndexOf(A/*Login tab*/))
{
MessageBox.Show("Login")
tc.SelectedIndex = tc.Items.IndexOf(B);
}
}
This means whenever you select A you will MessageBox will pop up then you login.
Alternatively why not put a button or any control with ClickedEvent in A then when clicked tc.SelectedIndex is changed.
I am trying to show a popup menu on my treeview when users right click - allowing them to choose context sensitive actions to apply against the selected node.
At the moment the user has to left click node and then right click to choose.
Is it possible to make a right click on a node select that node - and if so what is the best method to do this.
Both left and right clicks fire a click event and cause the selection to change. However, in certain circumstances (that I haven't yet bothered to trace down) the selection will change from the node that was right clicked to the originally selected node.
In order to make sure that the right click changes the selection, you can forcibly change the selected node by using the MouseDown event:
treeView.MouseDown += (sender, args) =>
treeView.SelectedNode = treeView.GetNodeAt(args.X, args.Y);
A little better, as one of the other posters pointed out, is to use the NodeMouseClick event:
treeView.NodeMouseClick += (sender, args) => treeView.SelectedNode = args.Node;
yes. Here is processing for NodeMouseClick event:
private void treeView1_NodeMouseClick(object sender, TreeNodeMouseClickEventArgs e)
{
treeView1.SelectedNode = e.Node;
}
Drag a context menu strip onto the form then:
private void treeView1_MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Right)
{
// Display context menu for eg:
ContextMenu1.Show();
}
}
I have a button that I trigger OnClick whenever there is a click on that button. I would like to know which Mouse button clicked on that button?
When I use the Mouse.LeftButton or Mouse.RightButton, both tell me "realsed" which is their states after the click.
I just want to know which one clicked on my button. If I change EventArgs to MouseEventArgs, I receive errors.
XAML: <Button Name="myButton" Click="OnClick">
private void OnClick(object sender, EventArgs e)
{
//do certain thing.
}
You can cast like below:
MouseEventArgs myArgs = (MouseEventArgs) e;
And then get the information with:
if (myArgs.Button == System.Windows.Forms.MouseButtons.Left)
{
// do sth
}
The solution works in VS2013 and you do not have to use MouseClick event anymore ;)
If you're just using the Button's Click event, then the only mouse button that will fire it is the primary mouse button.
If you still need to know specifically whether it was the left or right button, then you can use the SystemInformation to obtain it.
void OnClick(object sender, RoutedEventArgs e)
{
if (SystemParameters.SwapButtons) // Or use SystemInformation.MouseButtonsSwapped
{
// It's the right button.
}
else
{
// It's the standard left button.
}
}
Edit: The WPF equivalent to SystemInformation is SystemParameters, which can be used instead. Though you can include System.Windows.Forms as a reference to obtain the SystemInformation without adversely effecting the application in any way.
You're right, Jose, it's with MouseClick event. But you must add a little delegate:
this.button1.MouseDown += new System.Windows.Forms.MouseEventHandler(this.MyMouseDouwn);
And use this method in your form:
private void MyMouseDouwn(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Right)
this.Text = "Right";
if (e.Button == MouseButtons.Left)
this.Text = "Left";
}