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I am new in the programming and i am looking for a regular expression as
first three characters should be alphanumeric followed by a constant which is a special character and then 1 or more hashes
(3 alphanumeric) (constant) ( one or more hashes)
AB1-#
ABC$##
etc
you can use something like
(\w{3})([^\s])(#+)
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how do i set validation expression using this type of format ###-###-### this is for TIN number(Philippines). if not possible format like 9 numbers and 3 - .
Use this regular expression in RegularExpressionValidator:
\d{3}-\d{3}-\d{3}
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" ** दुनिया की सबसे बेस्ट कंपनी * the zzzz is best company in world "
I have remove/replace Hindi Font in String in mvc c# with regex .
plz Help Me . .
Try:
\p{IsDevanagari}
See it working here (characters are replaced with X).
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What is the formula for converting UPC-E barcodes to UPC-A barcodes? Better yet would be some C# code, C#esque pseudocode, or even just in an "English" expository way.
Ctrl+F for "Converting UPC-A to UPC-E" at http://www.taltech.com/barcodesoftware/symbologies/upc . It explains all the cases in a better format than I can paste here.
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Hi guys I Need Some Help With A Regex:
I Need A Regex:
1. that accepts all type of characters like ą or Э or Ǿ or Я ...
2. which the number of characters is between 3 and 15
3. doesn't contain special characters
I'm guessing you want to match 3 to 15 Unicode letters. For that, you can use
new Regex(#"^\p{L}{3,15}$")
If you also want to allow spaces, you can use a character class:
new Regex(#"^[\p{L} ]{3,15}$")
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I wonder how to get a string (or array of strings) between two known tags.
For example I have this string
string var1="my first video is [video]http://video.com/aaa[/video] and my second is[video id=\"1\" length=\"3\"]http://video.com/bbb[/video]";
How to get these values http://video.com/aaa and http://video.com/bbb?
use this pattern: #"\[video.*?\](.*?)\[/video\]" and then get group 1. I won't post the whole code because I dont want to do your work for you. Read about C# Regexes, Patterns and try to write your code with this pattern.