I want it to search string like "$12,56,450" using Regex in c#, but it doesn't match the string
Here is my code:
string input="Total earn for the year $12,56,450";
string pattern = #"\b(?mi)($12,56,450)\b";
Regex regex = new Regex(pattern);
if (regex.Match(input).Success)
{
return true;
}
This Regex will do the job, (?mi)(\$\d{2},\d{2},\d{3}), and here's a Regex 101 to prove it.
Now let's break it down a little:
\$ matches the literal $ at the beginning of the string
\d{2} matches any two digits
, matches the literal ,
\d{2} matches any two digits
, matches the literal ,
\d{3} matches any three digits
Now, for the purposes of the demonstration I removed the word boundaries, \b, but I'm also pretty confident you don't need them anyway. See, word boundaries aren't generally necessary for such a finite string match. Consider their definition:
Before the first character in the string, if the first character is a word character.
After the last character in the string, if the last character is a word character.
Between two characters in the string, where one is a word character and the other is not a word character.
You need to escape $ and some other special regex caracters.
try this #"\b(?mi)(\$12,56,450)\b";
if you want you can use \d to match a digit, and use \d{2,3} to match a digit with size 2 or 3.
Related
I have created a Regex Pattern (?<=[TCC|TCC_BHPB]\s\d{3,4})[-_\s]\d{1,2}[,]
This Pattern match just:
TCC 6005_5,
What should I change to the end to match these both strings:
TCC 6005-5 ,
TCC 6005_5,
You can add a non-greedy wildcard to your expression (.*?):
(?<=(?:TCC|TCC_BHPB)\s\d{3,4})[-_\s]\d{1,2}.*?[,]
^^^
This will now also match any characters between the last digit and the comma.
As has been pointed out in the comments, [TCC|TCC_BHPB] is a character class rather than a literal match, so I've changed this to (?:TCC|TCC_BHPB) which is presumably what your intention was.
Try it online
This part of the pattern [TCC|TCC_BHPB] is a character class that matches one of the listed characters. It might also be written for example as [|_TCBHP]
To "match" both strings, you can match all parts instead of using a positive lookbehind.
\bTCC(?:_BHPB)?\s\d{3,4}[-_\s]\d{1,2}\s?,
See a regex demo
\bTCC A word boundary to prevent a partial match, then match TCC
(?:_BHPB)?\s\d{3,4} Optionally match _BHPB, match a whitespace char and 3-4 digits (Use [0-9] to match a digit 0-9)
[-_\s]\d{1,2} Match one of - _ or a whitespace char
\s?, Match an optional space and ,
Note that \s can also match a newline.
Using the lookbehind:
(?<=TCC(?:_BHPB)?\s\d{3,4})[-_\s]\d{1,2}\s?,
Regex demo
Or if you want to match 1 or more spaces except a newline
\bTCC(?:_BHPB)?[\p{Zs}\t][0-9]{3,4}[-_\p{Zs}\t][0-9]{1,2}[\p{Zs}\t]*,
Regex demo
I have the following regex in my c#:
(?<!\w)M20A\w+
Actual code:
string regex = $#"(?<!\w){prefix}\w+";
Notice the prefix var matches strings such as M20A and X50G.
It perfectly matches the following cases:
M20A0820
M20A1234
M20A7U8V
But now I got a new requirement from the business to match, for example:
M20A-SDR
It will be the prefix followed by the exact string "-SDR". Not just a dash followed by 3 alphanumerics, but literally "-SDR". The existing matches need to still work, but prefix + "-SDR" must also be matched.
What would be the regex that would match the following:
M20A0820
M20A1234
M20A7U8V
M20A-SDR
You may use
string regex = $#"(?<!\w){prefix}\w*(?:-SDR)?";
See the regex demo.
Or, to match as a whole word, you may use word boundaries:
string regex = $#"\b{prefix}\w*(?:-SDR)?\b";
See this regex demo
The \b word boundary at the start will work if all the values in prefix start with a word char, a letter, digit or _. The word boundary at the end will make sense if after -SDR, there can be no more word chars.
The (?:-SDR)? will match a -SDR string optonally.
Details
\b - word boundary
M20A - a literal string
\w* - 0+ word chars
(?:-SDR)? - a non-capturing group that matches 1 or 0 times (as there is a ? after it) an -SDR substring
\b - a word boundary.
This is in C#. I've been bugging my head but not luck so far.
So for example
123456BVC --> 123456BVC (keep the same)
123456BV --> 123456 (remove trailing letters)
12345V -- > 12345V (keep the same)
12345 --> 12345 (keep the same)
ABC123AB --> ABC123 (remove trailing letters)
It can start with anything.
I've tried #".*[a-zA-Z]{2}$" but no luck
This is in C# so that I always return a string removing the two trailing letters if they do exist and are not preceded with another letter.
Match result = Regex.Match(mystring, pattern);
return result.Value;
Your #".*[a-zA-Z]{2}$" regex matches any 0+ characters other than a newline (as many as possible) and 2 ASCII letters at the end of the string. You do not check the context, so the 2 letters are matched regardless of what comes before them.
You need a regex that will match the last two letters not preceded with a letter:
(?<!\p{L})\p{L}{2}$
See this regex demo.
Details:
(?<!\p{L}) - fails the match if a letter (\p{L}) is found before the current position (you may use [a-zA-Z] if you only want to deal with ASCII letters)
\p{L}{2} - 2 letters
$ - end of string.
In C#, use
var result = Regex.Replace(mystring, #"(?<!\p{L})\p{L}{2}$", string.Empty);
If you're looking to remove those last two letters, you can simply do this:
string result = Regex.Replace(originalString, #"[A-Za-z]{2}$", string.Empty);
Remember that in regex $ means the end of the input or the string before a newline.
I am looking for a regex to validate input in C#. The regex has to match an arbitrary number of words which are separated with only 1 space character in between. The matched string cannot start or end with whitespace characters (this is where my problem is).
Example: some sample input 123
What I've tried: /^(\S+[ ]{0,1})+$/gm this pattern almost does what is required but it also matches 1 trailing space.
Any ideas? Thanks.
I tried this one and it seems to work:
Regex regex = new Regex(#"^\S+([ ]{1}\S+)*$");
It checks if your string starts with a word followed by zero or more entities of a single white space followed by a word. So trailing white spaces are not allowed.
I want to check whether there is string starting from number and then optional character with the help of the regex.So what should be the regex for matching the string which must be started with number and then character might be there or not.Like there is string "30a" or "30" it should be matched.But if there is "a" or some else character or sereis of characters, string should not be matched.
Sounds like there should be able to be any number of numeric characters at the beginning followed by optional other characters. To match any other character after a series of numbers at the beginning I would use:
\d+.*
To match only alpha numeric characters after the mandatory numeric beginning I would use:
\d+\w*
Note: as pointed out by Dav, if you add a ^ to the start of the expression and a $ to the end of the expression like this ^\d+\w*$ you will ensure the whole string matches. However if you leave those off, you will be able to search the input string for what you need. It just depends on what your needs are.
^\d.*
The ^ matches the start of the string, \d matches a single digit, and then the .* matches any number of additional characters.
Thus, the net result is that it will only match if the string begins with a digit.