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Get Public client IP in C#/.net without external service

How i get public client IP in C# without external api/service
I tried use this code. But, not success.
string ipAddress = Response.HttpContext.Connection.RemoteIpAddress.ToString();
if(ipAddress == "::1")
{
ipAddress = Dns.GetHostEntry(Dns.GetHostName()).AddressList[1].ToString();
}
Console.WriteLine(ipAddress);

on ASP.NET Follow This Method:
Public string GetIp()  
{  
string ip = System.Web.HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];  
if (string.IsNullOrEmpty(ip))  
{  
ip = System.Web.HttpContext.Current.Request.ServerVariables["REMOTE_ADDR"];  
}  
return ip;  
} 
otherwise use below method:
Public string GetIp()  {
string IPAddress = "";
IPHostEntry Host = default(IPHostEntry);
string Hostname = null;
Hostname = System.Environment.MachineName;
Host = Dns.GetHostEntry(Hostname);
foreach (IPAddress IP in Host.AddressList)
{
if (IP.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
IPAddress = Convert.ToString(IP);
}
}
return IPAddress;
}
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How to Get system IP (IPv4) address and convert to string using C# asp.net

On my web application I am using the following function to get System IP
Function
public void SetHostid()
{
try
{
string ip = "";
string strHostName = "";
strHostName = System.Net.Dns.GetHostName();
IPHostEntry ipEntry = System.Net.Dns.GetHostEntry(strHostName);
IPAddress[] addr = ipEntry.AddressList;
ip = addr[1].MapToIPv4().ToString();
HostId = ip;
HttpContext.Current.Session["Hostid"] = HostId;
}
catch (Exception ex)
{
Error_ManagerClass em = new Error_ManagerClass();
em.WriteError(ex);
}
}
It works perfectly because the IP is on the 1 postion of the variable addr (addr[ 1]).
And the problem comes when I try to run the same solution from a different system. function throws an error while trynig to convert IP to string( ip = addr[1].MapToIPv4().ToString(); ) because IP is not in the position number 1.
how can I change the function to work on every computer ??

If you want to get IPv4 only use this code:
var addr = ipEntry.AddressList.Where(ip => ip.AddressFamily == AddressFamily.InterNetwork);
var firstInList = addr.First(); // get first
But you should consider which IP to chose when there are several IP addresses in system.

Getting the ip adress of the user connected to asp application

I'd like to know how to get the IP of the user connected to my application ( asp.net mvc4) .
I tried:
IPHostEntry ipHostEntry = Dns.GetHostByName(Dns.GetHostName());
IPAddress ipAddress = ipHostEntry.AddressList[0];
But it didn't work.
So how can I modify the snippet to get the Ip` or the connected user?

Here's the converted C# code from the similar question #jamieHennerley suggested.
protected string GetIPAddress()
{
System.Web.HttpContext context = System.Web.HttpContext.Current;
string ipAddress = context.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrEmpty(ipAddress))
{
string[] addresses = ipAddress.Split(',');
if (addresses.Length != 0)
{
return addresses[0];
}
}
return context.Request.ServerVariables["REMOTE_ADDR"];
}

How to get IPv4 and IPv6 address of local machine?

I am developing a windows application and I need to find the IPv4 and IPv6 address of local machine. OS can be XP or Windows 7.
I got a solution for getting MAC address like,
string GetMACAddress()
{
var macAddr =
(
from nic in NetworkInterface.GetAllNetworkInterfaces()
where nic.OperationalStatus == OperationalStatus.Up
select nic.GetPhysicalAddress().ToString()
).FirstOrDefault();
return macAddr.ToString();
}
This is working in all OS.
What is the correct way to get IPv4 and IPv6 address that work on XP and WINDOWS 7?

string strHostName = System.Net.Dns.GetHostName();;
IPHostEntry ipEntry = System.Net.Dns.GetHostEntry(strHostName);
IPAddress[] addr = ipEntry.AddressList;
Console.WriteLine(addr[addr.Length-1].ToString());
if (addr[0].AddressFamily == System.Net.Sockets.AddressFamily.InterNetworkV6)
{
Console.WriteLine(addr[0].ToString()); //ipv6
}

To get all IP4 and IP6 address, here is my preferred solution. Note that it also filters the loopback IP addresses like 127.0.0.1 or ::1
public static IEnumerable<IPAddress> GetIpAddress()
{
var host = Dns.GetHostEntry(Dns.GetHostName());
return (from ip in host.AddressList where !IPAddress.IsLoopback(ip) select ip).ToList();
}

Here's my method for getting all the IPv4 addresses only.
/// <summary>
/// Gets/Sets the IPAddress(s) of the computer which the client is running on.
/// If this isn't set then all IPAddresses which could be enumerated will be sent as
/// a comma separated list.
/// </summary>
public string IPAddress
{
set
{
_IPAddress = value;
}
get
{
string retVal = _IPAddress;
// If IPAddress isn't explicitly set then we enumerate all IP's on this machine.
if (_IPAddress == null)
{
// TODO: Only return ipaddresses that are for Ethernet Adapters
String strHostName = Dns.GetHostName();
IPHostEntry ipEntry = Dns.GetHostEntry(strHostName);
IPAddress[] addr = ipEntry.AddressList;
List<string> validAddresses = new List<string>();
// Loops through the addresses and creates a list of valid ones.
for (int i = 0; i < addr.Length; i++)
{
string currAddr = addr[i].ToString();
if( IsValidIP( currAddr ) ) {
validAddresses.Add( currAddr );
}
}
for(int i=0; i<validAddresses.Count; i++)
{
retVal += validAddresses[i];
if (i < validAddresses.Count - 1)
{
retVal += ",";
}
}
if (String.IsNullOrEmpty(retVal))
{
retVal = String.Empty;
}
}
return retVal;
}
}

Get IPv4 addresses from Dns.GetHostEntry()

I've got some code here that works great on IPv4 machines, but on our build server (an IPv6) it fails. In a nutshell:
IPHostEntry ipHostEntry = Dns.GetHostEntry(string.Empty);
The documentation for GetHostEntry says that passing in string.Empty will get you the IPv4 address of the localhost. This is what I want. The problem is that it's returning the string "::1:" on our IPv6 machine, which I believe is the IPv6 address.
Pinging the machine from any other IPv4 machine gives a good IPv4 address... and doing a "ping -4 machinename" from itself gives the correct IPv4 address.... but pinging it regularly from itself gives "::1:".
How can I get the IPv4 for this machine, from itself?

Have you looked at all the addresses in the return, discard the ones of family InterNetworkV6 and retain only the IPv4 ones?

To find all local IPv4 addresses:
IPAddress[] ipv4Addresses = Array.FindAll(
Dns.GetHostEntry(string.Empty).AddressList,
a => a.AddressFamily == AddressFamily.InterNetwork);
or use Array.Find or Array.FindLast if you just want one.

IPHostEntry ipHostInfo = Dns.GetHostEntry(serverName);
IPAddress ipAddress = ipHostInfo.AddressList
.FirstOrDefault(a => a.AddressFamily == AddressFamily.InterNetwork);

public Form1()
{
InitializeComponent();
string myHost = System.Net.Dns.GetHostName();
string myIP = null;
for (int i = 0; i <= System.Net.Dns.GetHostEntry(myHost).AddressList.Length - 1; i++)
{
if (System.Net.Dns.GetHostEntry(myHost).AddressList[i].IsIPv6LinkLocal == false)
{
myIP = System.Net.Dns.GetHostEntry(myHost).AddressList[i].ToString();
}
}
}
Declare myIP and myHost in public Variable
and use in any function of the form.

public static string GetIPAddress(string hostname)
{
IPHostEntry host;
host = Dns.GetHostEntry(hostname);
foreach (IPAddress ip in host.AddressList)
{
if (ip.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
//System.Diagnostics.Debug.WriteLine("LocalIPadress: " + ip);
return ip.ToString();
}
}
return string.Empty;
}

To find all valid address list this is the code I have used
public static IEnumerable<string> GetAddresses()
{
var host = Dns.GetHostEntry(Dns.GetHostName());
return (from ip in host.AddressList where ip.AddressFamily == AddressFamily.lo select ip.ToString()).ToList();
}

You can get all IPv4 address from the DNS using this code:
IPs[] ipv4Addresses = Array.FindAll(
Dns.GetHostEntry(string.Empty).AddressList,
address => address.AddressFamily == AddressFamily.InterNetwork);

IPv6
lblIP.Text = System.Net.Dns.GetHostEntry(System.Net.Dns.GetHostName).AddressList(0).ToString()
IPv4
lblIP.Text = System.Net.Dns.GetHostEntry(System.Net.Dns.GetHostName).AddressList(1).ToString()