Linq to XElement Preparation with some condtions - c#

private XElement GetClinicalClientPrice(int invid)
{
using (MyDatabase db = new MyDatabase())
{
return new XElement("CLINICALCLIENTPRICE",
from ccp in db.TblClinicalClientPrice
where ccp.INVENTORY_ID == invid
select new XElement("Record",
new XElement("ITEM_ID",ccp.ITEM_ID),
new XElement("INVENTORY_ID", ccp.INVENTORY_ID),
new XElement("ITEM_DESCRIPTION", ccp.ITEM_DESCRIPTION),
new XElement("SUPPLIER_CAT", ccp.SUPPLIER_CAT),
new XElement("NDC_CODE", ccp.NDC_CODE),
new XElement("ITEM_NUMBER", ccp.ITEM_NUMBER),
new XElement("UOM", ccp.UOM),
new XElement("CONVERSION_FACTOR", ccp.CONVERSION_FACTOR),
new XElement("MANUFACTURER", ccp.MANUFACTURER),
new XElement("SESSION_ID", ccp.SESSION_ID),
new XElement("USERNAME", ccp.USERNAME),
new XElement("ENTRY_TIME", ccp.ENTRY_TIME),
new XElement("COST", ccp.COST),
new XElement("CLIENT_INPUT_ID", ccp.CLIENT_INPUT_ID),
new XElement("MHS_ITEM_ID", ccp.MHS_ITEM_ID),
new XElement("GUID", ccp.GUID),
new XElement("UNIQUE_ID", ccp.UNIQUE_ID),
new XElement("SUPPLIER_CAT_MODIFIED", ccp.SUPPLIER_CAT_MODIFIED),
new XElement("SIZE", ccp.SIZE),
new XElement("STRENGTH", ccp.STRENGTH)
));
}
}
I am getting (DateTime) Null value exception when I am inserting above resulted XElement into data base.
My Example is : stackoverflow.com/a/21163312/3121707

Related

How to add list, with LINQ, in an xml?

I have the following structure in an xml:
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfNO xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<No>
<Id>1</Id>
<Name>txt_1</Name>
<Text>some text</Text>
<Txt_relacionados>
<string>txt_4</string>
<string>txt_4</string>
<string>txt_4</string>
</Txt_relacionados>
<N>0</N>
<X>285</X>
<Y>31</Y>
<Externa>false</Externa>
<EM>false</EM>
<B>false</B>
<K>false</K>
<L1>false</L1>
<L2>false</L2>
<L3>false</L3>
<L4>false</L4>
<L5>false</L5>
<L6>false</L6>
<L7>false</L7>
<L8>false</L8>
<L9>false</L9>
<L10>false</L10>
<L11>false</L11>
<L12>false</L12>
<IP>0</IP>
</No>
I'm having trouble inserting the "Txt_relacionados" element because it contains a list of strings.
In the VO of this element i have the following:
[XmlArray("Txt_relacionados"), XmlArrayItem("string", Type = typeof(String))]
private List<String> txt_relacionados = new List<String>();
public List<String> Txt_relacionados
{
get { return txt_relacionados; }
set { txt_relacionados = value; }
}
What changes should I make in the code below to be able to insert this list?
public void inserir2(VoNo value)
{
RefreshXDoc();
XElement no = XElement.Load(path);
XElement element = new XElement("No",
new XElement("Id", value.Id),
new XElement("Name", value.Name),
new XElement("Text", value.Text),
new XmlArrayAttribute("Txt_relacionados", value.Txt_relacionados),
new XElement("N", value.N),
new XElement("X", value.X),
new XElement("Y", value.Y),
new XElement("Externa", value.Externa),
new XElement("B", value.B),
new XElement("K", value.K),
new XElement("L1", value.L1),
new XElement("L2", value.L2),
new XElement("L3", value.L3),
new XElement("L4", value.L4),
new XElement("L5", value.L5),
new XElement("L6", value.L6),
new XElement("L7", value.L7),
new XElement("L8", value.L8),
new XElement("L9", value.L9),
new XElement("L10", value.L10),
new XElement("L11", value.L11),
new XElement("L12", value.L12),
new XElement("IP", value.IP));
no.Add(element);
no.Save(path);
}
Thanks!!
You need to create Txt_relacionados element before you create new element No and then pass Txt_relacionados at proper place when you are creating No.
Consider following.
public void inserir2(VoNo value)
{
var rels = new XElement("Txt_relacionados");
foreach (var x in value.Txt_relacionados)
{
var elem = new XElement("string", x);
rels.Add(elem);
}
RefreshXDoc();
XElement no = XElement.Load(path);
XElement element = new XElement("No",
new XElement("Id", value.Id),
new XElement("Name", value.Name),
new XElement("Text", value.Text),
rels,
new XElement("N", value.N),
new XElement("X", value.X),
new XElement("Y", value.Y),
new XElement("Externa", value.Externa),
new XElement("B", value.B),
new XElement("K", value.K),
new XElement("L1", value.L1),
new XElement("L2", value.L2),
new XElement("L3", value.L3),
new XElement("L4", value.L4),
new XElement("L5", value.L5),
new XElement("L6", value.L6),
new XElement("L7", value.L7),
new XElement("L8", value.L8),
new XElement("L9", value.L9),
new XElement("L10", value.L10),
new XElement("L11", value.L11),
new XElement("L12", value.L12),
new XElement("IP", value.IP));
no.Add(element);
no.Save(path);
}

Nesting XML Tags using Linq with Data From DB

I am trying to build an XML document using Linq, XElement and data from Database,
It's working kinda, but in my XML, I want to close the tag and start a new tag and get the results from the query to populate into for the Tag, it is complaining that my variable r in the tag is unresolved, how can I make this work, or is there a better way of building the XML. All the child elements should be under the parent , having two children and , which has their own set of children.
Here is the code below
public void GenerateXML(int id, string site, string state, string country, string bFn, string bLn, string sFn, string sLn)
{
var results = (from o in _db.Orders
where o.OrderId == id
select o).ToList();
var xmlDoc = new XElement("Order",
from r in results
select
new XElement("OrderHeader",
new XElement("SiteId", site),
new XElement("OrderId", r.OrderId),
new XElement("Time", r.OrderDate.Value),
new XElement("Subtotal", r.SubTotal),
new XElement("Shipping", ""),
new XElement("SalesTax", r.SalesTax),
new XElement("Total", r.Total),
new XElement("PaymentAmount", ""),
new XElement("PaymentMethod", ""),
new XElement("ArchiTypeAcctNum", "20001"),
new XElement("TaxExempt", r.TaxExempt),
new XElement("SpecialInstructions", r.SpecialInstructions),
new XElement("BillTo",
new XElement("BillEmail", r.BillToEmail),
new XElement("FirstName", bFn),
new XElement("LastName", bLn),
new XElement("CompanyName", r.BillCompany),
new XElement("Address1", r.BillToAddress),
new XElement("City", r.BillToCity),
new XElement("State", state),
new XElement("Country", country),
new XElement("Zip", r.BillToZip),
new XElement("Phone", r.BillToPhoneNumber)),
new XElement("ShipTo",
new XElement("FirstName", sFn),
new XElement("LastName", sLn),
new XElement("CompanyName", r.ShipCompany),
new XElement("Address1", r.ShipToAddress),
new XElement("City", r.ShipToCity),
new XElement("State", state),
new XElement("Country", country),
new XElement("Zip", r.ShipToZip),
new XElement("Phone", r.ShipToPhoneNumber))),
new XElement("Items",
from i in r.Items
select new XElement("Item",
new XElement("SKU", i.SkuNumber),
new XElement("PROD_Name", i.ProductName),
new XElement("Description", i.Description),
new XElement("Attributes", i.Attributes),
new XElement("Quantity", i.Quantity),
new XElement("UnitPrice", i.UnitPrice),
new XElement("InkColor", i.InkColor)))
);
xmlDoc.Save(Server.MapPath(#"~/Xml/Orders.xml"));
RedirectToAction("Save");
}
I wrote an extension for same purpose. I think much easier . you can just use as orders.EntityToXml();
public static class XmlExtensions
{
public static bool EntityToXml<T>(this T entity, string filePath)
{
if (string.IsNullOrEmpty(filePath))
{
throw new ArgumentNullException(nameof(filePath));
}
var dir = Path.GetDirectoryName(filePath);
if (string.IsNullOrEmpty(dir))
{
throw new ArgumentNullException(nameof(filePath));
}
if (!Directory.Exists(dir))
{
Directory.CreateDirectory(dir);
}
var serializer= new System.Xml.Serialization.XmlSerializer(typeof(T));
using (var stream = new StreamWriter(filePath))
{
serializer.Serialize(stream , entity);
return true;
}
}
}

Add collection of items( xml elements) to XML doc

How to add the collection of items to XML Document ? Something I started trying, but it's wrong! I'll be grateful for the link on the Internet at a good tutorial too. Also, It is assumed that the iteration will be some elements.
Such code:
public static void Create_Interfaces()
{
XDocument Interfaces;
Interfaces = XDocument.Load("Interfaces.xml");
List<string> intf = new List<string>{"em0","em1","em2"};
foreach (var i in intf)
{
Interfaces = new XDocument(
new XElement("Interfaces",
new XElement("Interface",
new XElement("name", i),
new XElement("vlan-tagging", XElement.EmptySequence),
new XElement("unit",
new XElement("vlan-id", "10"),
new XElement("family", new XElement("inet", new XElement("address", new XElement("name", "10.10.1.23/24"))))))));
}
Interfaces.Save("Interfaces.xml");
}
Get your root element add new elements to it then save it:
var rootElement = Interfaces.Root;
foreach (var i in intf)
{
var element = new XElement("Interface",
new XElement("name", i),
new XElement("vlan-tagging", XElement.EmptySequence),
new XElement("unit",
new XElement("vlan-id", "10"),
new XElement("family",
new XElement("inet",
new XElement("address",
new XElement("name", "10.10.1.23/24"))))));
rootElement.Add(element);
}
rootElement.Save("Interfaces.xml");

Getting Country Calling Code in .NET Framework

In my program I need to get currency symbol and country calling code for specific countries.
I can get currency symbol from RegionInfo class
new RegionInfo(abbreviation).CurrencySymbol
But I cannot find a way to get country calling code from .NET Framework.
Years too late for the original poster, but if someone stumbles across this & wants a bit of code to save creating themselves a list of dial codes from Wikipedia, an open source project (of mine) has this C# file:
https://github.com/mcshaz/SimPlanner/blob/master/SP.DTOs/ProcessBreezeRequests/ISO3166.cs
public List<CountryTelCode> TelCodes { get; set; }
//*****************************************************************
public class CountryTelCode
//*****************************************************************
{
public string Pfx { get; set; }
public string Iso { get; set; }
public int Priority { get; set; }
public CountryTelCode(string pfx, string iso, int priority = 0)
{
Pfx = pfx;
Iso = iso;
Priority = priority;
}
}
//-----------------------------------------------------------------
public void InitTelCodes()
//-----------------------------------------------------------------
{
TelCodes = new List<CountryTelCode>
{
new CountryTelCode("+93", "AF"),
new CountryTelCode("+355", "AL"),
new CountryTelCode("+213", "DZ"),
new CountryTelCode("+1-684", "AS"),
new CountryTelCode("+376", "AD"),
new CountryTelCode("+244", "AO"),
new CountryTelCode("+1-264", "AI"),
new CountryTelCode("+672", "AQ"),
new CountryTelCode("+1-268", "AG"),
new CountryTelCode("+54", "AR"),
new CountryTelCode("+374", "AM"),
new CountryTelCode("+297", "AW"),
new CountryTelCode("+61", "AU"),
new CountryTelCode("+43", "AT"),
new CountryTelCode("+994", "AZ"),
new CountryTelCode("+1-242", "BS"),
new CountryTelCode("+973", "BH"),
new CountryTelCode("+880", "BD"),
new CountryTelCode("+1-246", "BB"),
new CountryTelCode("+375", "BY"),
new CountryTelCode("+32", "BE"),
new CountryTelCode("+501", "BZ"),
new CountryTelCode("+229", "BJ"),
new CountryTelCode("+1-441", "BM"),
new CountryTelCode("+975", "BT"),
new CountryTelCode("+591", "BO"),
new CountryTelCode("+387", "BA"),
new CountryTelCode("+267", "BW"),
new CountryTelCode("+55", "BR"),
new CountryTelCode("+246", "IO"),
new CountryTelCode("+1-284", "VG"),
new CountryTelCode("+673", "BN"),
new CountryTelCode("+359", "BG"),
new CountryTelCode("+226", "BF"),
new CountryTelCode("+257", "BI"),
new CountryTelCode("+855", "KH"),
new CountryTelCode("+237", "CM"),
new CountryTelCode("+1", "CA"),
new CountryTelCode("+238", "CV"),
new CountryTelCode("+1-345", "KY"),
new CountryTelCode("+236", "CF"),
new CountryTelCode("+235", "TD"),
new CountryTelCode("+56", "CL"),
new CountryTelCode("+86", "CN"),
new CountryTelCode("+61", "CX"),
new CountryTelCode("+61", "CC"),
new CountryTelCode("+57", "CO"),
new CountryTelCode("+269", "KM"),
new CountryTelCode("+682", "CK"),
new CountryTelCode("+506", "CR"),
new CountryTelCode("+385", "HR"),
new CountryTelCode("+53", "CU"),
new CountryTelCode("+599", "CW"),
new CountryTelCode("+357", "CY"),
new CountryTelCode("+420", "CZ"),
new CountryTelCode("+243", "CD"),
new CountryTelCode("+45", "DK"),
new CountryTelCode("+253", "DJ"),
new CountryTelCode("+1-767", "DM"),
new CountryTelCode("+1-809", "DO"),
new CountryTelCode("+1-829", "DO"),
new CountryTelCode("+1-849", "DO"),
new CountryTelCode("+670", "TL"),
new CountryTelCode("+593", "EC"),
new CountryTelCode("+20", "EG"),
new CountryTelCode("+503", "SV"),
new CountryTelCode("+240", "GQ"),
new CountryTelCode("+291", "ER"),
new CountryTelCode("+372", "EE"),
new CountryTelCode("+251", "ET"),
new CountryTelCode("+500", "FK"),
new CountryTelCode("+298", "FO"),
new CountryTelCode("+679", "FJ"),
new CountryTelCode("+358", "FI"),
new CountryTelCode("+33", "FR"),
new CountryTelCode("+689", "PF"),
new CountryTelCode("+241", "GA"),
new CountryTelCode("+220", "GM"),
new CountryTelCode("+995", "GE"),
new CountryTelCode("+49", "DE"),
new CountryTelCode("+233", "GH"),
new CountryTelCode("+350", "GI"),
new CountryTelCode("+30", "GR"),
new CountryTelCode("+299", "GL"),
new CountryTelCode("+1-473", "GD"),
new CountryTelCode("+1-671", "GU"),
new CountryTelCode("+502", "GT"),
new CountryTelCode("+44-1481", "GG"),
new CountryTelCode("+224", "GN"),
new CountryTelCode("+245", "GW"),
new CountryTelCode("+592", "GY"),
new CountryTelCode("+509", "HT"),
new CountryTelCode("+504", "HN"),
new CountryTelCode("+852", "HK"),
new CountryTelCode("+36", "HU"),
new CountryTelCode("+354", "IS"),
new CountryTelCode("+91", "IN"),
new CountryTelCode("+62", "ID"),
new CountryTelCode("+98", "IR"),
new CountryTelCode("+964", "IQ"),
new CountryTelCode("+353", "IE"),
new CountryTelCode("+44-1624", "IM"),
new CountryTelCode("+972", "IL"),
new CountryTelCode("+39", "IT"),
new CountryTelCode("+225", "CI"),
new CountryTelCode("+1-876", "JM"),
new CountryTelCode("+81", "JP"),
new CountryTelCode("+44-1534", "JE"),
new CountryTelCode("+962", "JO"),
new CountryTelCode("+7", "KZ"),
new CountryTelCode("+254", "KE"),
new CountryTelCode("+686", "KI"),
new CountryTelCode("+383", "XK"),
new CountryTelCode("+965", "KW"),
new CountryTelCode("+996", "KG"),
new CountryTelCode("+856", "LA"),
new CountryTelCode("+371", "LV"),
new CountryTelCode("+961", "LB"),
new CountryTelCode("+266", "LS"),
new CountryTelCode("+231", "LR"),
new CountryTelCode("+218", "LY"),
new CountryTelCode("+423", "LI"),
new CountryTelCode("+370", "LT"),
new CountryTelCode("+352", "LU"),
new CountryTelCode("+853", "MO"),
new CountryTelCode("+389", "MK"),
new CountryTelCode("+261", "MG"),
new CountryTelCode("+265", "MW"),
new CountryTelCode("+60", "MY"),
new CountryTelCode("+960", "MV"),
new CountryTelCode("+223", "ML"),
new CountryTelCode("+356", "MT"),
new CountryTelCode("+692", "MH"),
new CountryTelCode("+222", "MR"),
new CountryTelCode("+230", "MU"),
new CountryTelCode("+262", "YT"),
new CountryTelCode("+52", "MX"),
new CountryTelCode("+691", "FM"),
new CountryTelCode("+373", "MD"),
new CountryTelCode("+377", "MC"),
new CountryTelCode("+976", "MN"),
new CountryTelCode("+382", "ME"),
new CountryTelCode("+1-664", "MS"),
new CountryTelCode("+212", "MA"),
new CountryTelCode("+258", "MZ"),
new CountryTelCode("+95", "MM"),
new CountryTelCode("+264", "NA"),
new CountryTelCode("+674", "NR"),
new CountryTelCode("+977", "NP"),
new CountryTelCode("+31", "NL"),
new CountryTelCode("+599", "AN"),
new CountryTelCode("+687", "NC"),
new CountryTelCode("+64", "NZ"),
new CountryTelCode("+505", "NI"),
new CountryTelCode("+227", "NE"),
new CountryTelCode("+234", "NG"),
new CountryTelCode("+683", "NU"),
new CountryTelCode("+850", "KP"),
new CountryTelCode("+1-670", "MP"),
new CountryTelCode("+47", "NO"),
new CountryTelCode("+968", "OM"),
new CountryTelCode("+92", "PK"),
new CountryTelCode("+680", "PW"),
new CountryTelCode("+970", "PS"),
new CountryTelCode("+507", "PA"),
new CountryTelCode("+675", "PG"),
new CountryTelCode("+595", "PY"),
new CountryTelCode("+51", "PE"),
new CountryTelCode("+63", "PH"),
new CountryTelCode("+64", "PN"),
new CountryTelCode("+48", "PL"),
new CountryTelCode("+351", "PT"),
new CountryTelCode("+1-787", "PR"),
new CountryTelCode("+1-939", "PR"),
new CountryTelCode("+974", "QA"),
new CountryTelCode("+242", "CG"),
new CountryTelCode("+262", "RE"),
new CountryTelCode("+40", "RO"),
new CountryTelCode("+7", "RU"),
new CountryTelCode("+250", "RW"),
new CountryTelCode("+590", "BL"),
new CountryTelCode("+290", "SH"),
new CountryTelCode("+1-869", "KN"),
new CountryTelCode("+1-758", "LC"),
new CountryTelCode("+590", "MF"),
new CountryTelCode("+508", "PM"),
new CountryTelCode("+1-784", "VC"),
new CountryTelCode("+685", "WS"),
new CountryTelCode("+378", "SM"),
new CountryTelCode("+239", "ST"),
new CountryTelCode("+966", "SA"),
new CountryTelCode("+221", "SN"),
new CountryTelCode("+381", "RS"),
new CountryTelCode("+248", "SC"),
new CountryTelCode("+232", "SL"),
new CountryTelCode("+65", "SG"),
new CountryTelCode("+1-721", "SX"),
new CountryTelCode("+421", "SK"),
new CountryTelCode("+386", "SI"),
new CountryTelCode("+677", "SB"),
new CountryTelCode("+252", "SO"),
new CountryTelCode("+27", "ZA"),
new CountryTelCode("+82", "KR"),
new CountryTelCode("+211", "SS"),
new CountryTelCode("+34", "ES"),
new CountryTelCode("+94", "LK"),
new CountryTelCode("+249", "SD"),
new CountryTelCode("+597", "SR"),
new CountryTelCode("+47", "SJ"),
new CountryTelCode("+268", "SZ"),
new CountryTelCode("+46", "SE"),
new CountryTelCode("+41", "CH"),
new CountryTelCode("+963", "SY"),
new CountryTelCode("+886", "TW"),
new CountryTelCode("+992", "TJ"),
new CountryTelCode("+255", "TZ"),
new CountryTelCode("+66", "TH"),
new CountryTelCode("+228", "TG"),
new CountryTelCode("+690", "TK"),
new CountryTelCode("+676", "TO"),
new CountryTelCode("+1-868", "TT"),
new CountryTelCode("+216", "TN"),
new CountryTelCode("+90", "TR"),
new CountryTelCode("+993", "TM"),
new CountryTelCode("+1-649", "TC"),
new CountryTelCode("+688", "TV"),
new CountryTelCode("+1-340", "VI"),
new CountryTelCode("+256", "UG"),
new CountryTelCode("+380", "UA"),
new CountryTelCode("+971", "AE"),
new CountryTelCode("+44", "GB"),
new CountryTelCode("+1", "US"),
new CountryTelCode("+598", "UY"),
new CountryTelCode("+998", "UZ"),
new CountryTelCode("+678", "VU"),
new CountryTelCode("+379", "VA"),
new CountryTelCode("+58", "VE"),
new CountryTelCode("+84", "VN"),
new CountryTelCode("+681", "WF"),
new CountryTelCode("+212", "EH"),
new CountryTelCode("+967", "YE"),
new CountryTelCode("+260", "ZM"),
new CountryTelCode("+263", "ZW"),
};
}
If you're talking about phone calling codes you have to build a look-up table.
I would recommend looking this list of calling codes: Wikipedia
There's also quite a handy ReST API for this. I'd suggest copying the data locally into a json file or whatever rather than relying on a third-party service.
GET https://restcountries.eu/rest/v2/all

How do I serialise a List<T> to XML using LINQ to XML?

I've this generic list
List<zil> listKD = new List<zil>
{
new zil{day="Mon",c="1",S1="08:00",S2="08:40",S3="08:47"},
new zil{day="Mon",c="2",S1="08:50",S2="09:30",S3="09:37"},
new zil{day="Mon",c="3",S1="09:40",S2="10:20",S3="10:27"},
new zil{day="Mon",c="4",S1="10:30",S2="11:10",S3="11:17"},
new zil{day="Tue",c="1",S1="08:00",S2="08:40",S3="08:47"},
new zil{day="Tue",c="2",S1="08:50",S2="09:30",S3="09:37"},
new zil{day="Wed",c="1",S1="08:00",S2="08:40",S3="08:47"},
new zil{day="Wed",c="2",S1="08:50",S2="09:30",S3="09:37"},
new zil{day="Thu",c="1",S1="08:00",S2="08:40",S3="08:47"},
new zil{day="Thu",c="2",S1="08:50",S2="09:30",S3="09:37"},
new zil{day="Thu",c="3",S1="09:40",S2="10:20",S3="10:27"},
new zil{day="Fri",c="1",S1="08:00",S2="08:40",S3="08:47"},
new zil{day="Fri",c="2",S1="08:50",S2="09:30",S3="09:37"},
new zil{day="Fri",c="3",S1="09:40",S2="10:20",S3="10:27"},
new zil{day="Fri",c="4",S1="10:30",S2="11:10",S3="11:17"},
};
and I want save,this list xml but I can't like this xml file
alt text http://aliaydin.com.tr/exXml.jpg
this code doesn't work for I want
XElement zXml = new XElement("Days",
from g in listKD
select new XElement("Day",
new XAttribute("id", g.Day),
new XElement("clock",
new XAttribute("id", g.c),
new XElement("s1", g.s1),
new XElement("s2", g.s2),
new XElement("s3", g.s3)
)));
ZXml.Save("abc.xml");
Thanks...
I think you haven't grouped by day; perhaps something like:
var el = new XElement("Days",
from z in listKD
group z by z.day into tmp
select new XElement("Day",
new XAttribute("id", tmp.Key),
from item in tmp
select new XElement("clock",
new XAttribute("id", item.c),
new XElement("s1", item.S1),
new XElement("s2", item.S2),
new XElement("s3", item.S3))
));
string s = el.ToString(); // or save etc
Update re comment; to reverse it, something like:
XElement parsed = XElement.Parse(s);
var newList = (from day in parsed.Elements("Day")
from clock in day.Elements("clock")
select new zil
{
day = (string)day.Attribute("id"),
c = (string)clock.Attribute("id"),
S1 = (string)clock.Element("S1"),
S2 = (string)clock.Element("S2"),
S3 = (string)clock.Element("S3")
}).ToList();
To filter to a specific day:
from day in parsed.Elements("Day")
where (string)day.Attribute("id") == "Mon"
from clock in day.Elements("clock")
...
[XmlArray("Zils"), XmlArrayItem("Zil", typeof(zil))]
public List<zil> listKD = new List<zil>();

Categories