Trying to create a Mandelbrot set, I have been trying to using 8 and 15 digit floating point variables in my program, and have run into an issue: the double approximates to 0. I tried unit testing and wrote this code to isolate the issue. Using the variable viewer, the h and w values both were on 0.0, as opposed to 0.00185185185185 and 0.0015625, yet when I just write double h = 0.0015625, it works.
Many thanks for assistance.
int apparentwidth = 3;
int apparentheight = 2;
int height = 1080;
int width = 1920;
double w = (apparentwidth / width);
double h = (apparentheight / height);
Console.WriteLine(w);
Console.WriteLine(h);
You're dividing two int variables, and the result is an int. You're storing the result in a double, but the scale (portion after the decimal) has already been lost.
Use double throughout:
double apparentwidth = 3;
double apparentheight = 2;
double height = 1080;
double width = 1920;
double w = (apparentwidth / width);
double h = (apparentheight / height);
Or cast one of the variables to a double when dividing:
double w = ((double)apparentwidth / width);
double h = ((double)apparentheight / height);
You are doing integer division on accident.
double w = (double)apparentwidth / (double)width;
double h = (double)apparentheight / (double)height;
Just to provide further explanation to the other answers:
When you do mathematical operations on ints, the result is an int, and this is achieved by effectively truncating the non-integer portion:
3 / 2 == 1
When an operation is performed involving at least one double, the int input is first converted to a double, so the result is a double:
1.0 / 4 == 0.25
4 * 0.25 == 1
And of course, if both inputs are double the result is double and no implicit conversion occurs:
1.0 / 4.0 == 0.25
Related
I am trying to calculate the delta of a number using a formula of bhaskara and delta but it is giving NaN in the message box
//Variables declaration
int a = 800, b = 500, c = 350;
double delta, a1, a2;
//Formulas
delta = (b*b) - (4*a*c);
a1 = (-b + Math.Sqrt(delta)) / (2 * a);
a2 = (-b - Math.Sqrt(delta)) / (2 * a);
//Output
MessageBox.Show(a1.ToString());
MessageBox.Show(a2.ToString());
The value of delta is -870000.
That's not a value you can take the square root of (and get a real number anyway).
From the Math.Sqrt docs:
As Broots said Math.sqrt of negative number will return NaN. There is a Complex struct that should do what you need:
Complex c = Complex.Sqrt(-25); // has a value of approximately 0 + 5i
I have some problems with my code where I think the accuracy is a bit off. I'll take out the declarations of variables from my code, so the code is as small as possible:
int a = Int32.Parse(tb_weight.Text);
double b = 0;
b = (a * 1.03) / 1000;
double g = 0;
g = (1.09 + (0.41 * (Math.Sqrt(50 / b))));
lbl_vertforce.Content = Math.Round((b * g * 9.81), 2);
So, tb_weight is a textbox where the input is made, and lets say the input is 5000, the label lbl_vertforce is showing 119,61 and according to my calculator, it should show 119,74. What is wroing here?
Doubles are not 100% precise and can vary in the least common digits. If you want exact precision you need to use Decimal type which has a bigger memory foot print, but was designed to be very precise. Unfortunately Math.Sqrt is not overloaded for Decimal and only works on doubles. I have provide code I found in another posting discussing the subject of Decimal Square roots: Performing Math operations on decimal datatype in C#?
public void YourCodeModifiedForDecimal()
{
int a = Int32.Parse(tb_weight.Text);
decimal b = 0;
b = (a* 1.03m) / 1000m;
decimal g = 0;
g = (1.09m + (0.41m * (Sqrt(50m / b))));
lbl_vertforce.Content = Math.Round((b* g * 9.81m), 2);
}
public static decimal Sqrt(decimal x, decimal? guess = null)
{
var ourGuess = guess.GetValueOrDefault(x / 2m);
var result = x / ourGuess;
var average = (ourGuess + result) / 2m;
if (average == ourGuess) // This checks for the maximum precision possible with a decimal.
return average;
else
return Sqrt(x, average);
}
You need to round g to 2 decimal places to get 119.74 in the final calculation.
g = Math.Round(1.09 + (0.41 * (Math.Sqrt(50 / b))), 2);
Given two numbers X and Y, how can I compute how many X's can fit into Y?
Good old division to the rescue!
float x = 16;
float y = 12345;
float howMany = ((float)y)/x; //> 771.5625
int floor = (int)howMany; //> 771
int ceil = (int)(howMany+0.5f);//> 772
Alliteratively, since you leave us guessing, you may want:
int lenX = "16".Length;
int lenY = "12345".Length;
float howMany = (float)lenY/lenX; //> 2.5
There are two ways your question could be interpreted.
(1) How many fractional X's can fit into Y?
In mathematics, the answer to this question is Y / X. In a programming language, if X and Y are integer values, you'll have to take care to cast them to floating point values before performing the division.
When X and Y are integers
int X = 5;
int Y = 17;
double N = (double)Y / (double)X;
// N is 3.4
When X and Y are real numbers
double X = 2.5;
double Y = 11.5;
double N = Y / X;
// N is 4.6
(2) How many whole X's can fit into Y?
In mathematics, the answer to this question is ⌊Y / X⌋, the floor of Y divided by X. In a programming language, if X and Y are integer values, the / operator applied to them will typically perform integer division. Integer division discards the remainder of division, so you don't have to call any floor function.
When X and Y are integers
int X = 5;
int Y = 17;
int N = Y / X;
// N is 3
When X and Y are real numbers
double X = 2.5;
double Y = 11.5;
int N = (int)Math.Floor(Y / X);
// N is 4
in my ASP.NET project i did a survey page that uses Application to save the votes. I have a problem with the making of the percentages amount. I've tried many things. here is the problematic part of my code:
double x = (count / sum) ;
double f = (count1 / sum) ;
double g = (count2 / sum) ;
double h = (count3 / sum) ;
if (sum > 0)
{
a = (int)x * 100;
b = (int)f * 100;
c = (int)g * 100;
d = (int)h * 100;
}
I used breakpoints and figured out that the problem was in the double variables: the (count/sum) equals 0 anyway.
I'm assuming count and sum are integer types.
The result of division of 2 integers is a truncated integer.
You need to cast one side of the division to a double, then the result will be double
So
((double)count)/sum
What are the datatypes of count, count[1-3] and sum? If they are integral types, then integer division is performed. This
int x = 100 ;
int y = 300 ;
double z = x / y ;
yields the value 0.0 for z.
Try something like
double h = (double) ( count3 / sum ) ;
You might also want to move your test for sum > 0 up: as coded, if sum is zero, you'll throw a DivideByZeroException before you get to your test, thus rendering your test moot.
Your count and sum variables are probably integers. Cast one of them to double:
double x = count / (double)sum;
UPDATE:
Actually, if you want the percentage as an integer, you can skip the doubles altogether:
int a = 100 * count / sum;
I can't get this to divide into a decimal. It is rounding to value 0.
private void button24_Click(object sender, EventArgs e)
{
double x = 0;
x = 1 / 2;
ans.Text = x.ToString();
}
When I debug, x is zero before it is sent to the textbox 'ans.'
I tried..and string variable is still zero..
double x = 1/5;
string displayX = x.ToString("0.0000");
It's integer division and those are the expected outputs.
double x = 1.0 / 5; // this will not perform integer division
double x = 1/5; // this does (1/5 = 0).
double x = 1D / 5; // this will not because 1 is treated as a double
You can do one of the follow:
double x = 1;
double y = 1.5;
double ans = x / y;
Replace double x = 1/5 with double x = 1.0/5 and that should fix it. Because both numbers you're dividing are integers, it still processes it as an integer, rather than as a double. When you think through logically, it makes some sense - it does the division in whatever form those numbers are and then saves it to the variable; the variable type is inconsequential to the actual equation.
(I realize there are other answers already, but hopefully this will help you see why the issue exists.)