inheriting object from another class - c#

So currently I have a RadAutocomplete box. I am able to call that object in the
public MainWindow()
But I want to be able to call it in my viewmodel. If I may get tips and suggestions Would be great.

Never in WPF create UI elements, like in your case telerik objects, from view model.
If you do so, you loose benefits of MVVM.
View model is for binding between UI and business logic itself. You have to define telerik oject in XAML and show/hide it based on model view property.

Related

How to instantiate an object in ViewModel and edit that in another ViewModel or user control

I'm new to c# and mvvm.
I have a class that has many properties, and because of that, it is not possible to present every property to user in one page. Therefore, I decided to break the UI into 4 different part. I designed one user control for each of these parts.
As of now, I have 4 different user controls which are presented to user with the help of a side bar selection.
However, I still have one object to work with and it is not possible to break the object too.
The problem is I cant access to object from user controls' code behind. It means that I can bind object with UI but I'm not able to change parameters in code behind.
Welcome to SO!
On one hand you talk about MVVM and data-binding, but then on the other hand you talk about modifying changing parameters in code-behind. These are antithetical design patterns. Pick one!
If you are implementing MVVM then, as you know you have the View (UI e.g. Page1.xaml) in XAML, with code behind (Page1.xaml.cs) these then use a ViewModel (e.g. Page1ViewModel.cs) as their data context, i.e. where they can access the Model.
You do not have to have a one-to-one correlation of Views, ViewModels and Models.
You can have more than one View use the same ViewModel as its data context and you can have a ViewModel contain yet more ViewModels and a ViewModel can reference several Models if required.
So in your situation I'd have several pages reference the same ViewModel.

ViewModel into View

Currently I'm learning C# with WPF. My mainapproach is to use the MVVM pattern the best I can but now I'm a bit confused.
In my Application for all my views I have a viewmodel:
private DruckviewViewModel ViewModel { get; set; }
public Druckview()
{
ViewModel = new DruckviewViewModel();
DataContext = ViewModel;
InitializeComponent();
}
Is this the suggested way to implement the ViewModel into the View or are there better ways to do it?
MVVM doesn't mean no code-behind.
MVVM is the pattern of separation of concerns. It helps to separate your application's architecture to the three parts(in order of appearance):
Model
View
ViewModel
Where Model is class containing your business logic.
View represents your view class which contains only view related logic(XAML and code-behind) It is Ok to have code-behind unless code contains only view's logic (for example in button click eventhandler you copy color of one textbox to another, which of course can be done in XAML, but from MVVM point of view it is not important)
ViewModel represents View's behavior without any reference to the View.
Notice that for example this property on my opinion will violate MVVM pattern, because Visibility is view related type
public Visibility MyVisibility { get; set; }
So dependencies between parts of MVVM goes like this:
Model doesn't know about anything
ViewModel know only about Model
View know about ViewModel
View ---> ViewModel ---> Model
I think for using MVVM is not important how tightly View bounded to the ViewModel. It is already bounded, because you use ViewModel's properties and commands.
Not bounding tightly (for example using interface as ViewModel) will give your possibility to test View without real ViewModel by creating own "design-time" viewmodels for example.
If your current solution works and satisfy your needs and you just starting with MVVM and WPF then continue with that until you meet need to fully isolate View from ViewModel's types
This will work, but it isn't really true to the MVVM pattern, as the View is now directly tied to the View Model.
Most existing MVVM frameworks use the concept of a View Manager. A class that creates a view from a view model instance, connects them together, and displays the view. You would end up with something like this:
DruckviewViewModel vm = new DruckviewViewModel()
ViewManager.Instance.DisplayViewFor(vm);
It would figure out, based on naming conventions, that DruckviewViewModel uses the Druckview. It would create the view, set the DataContextProperty, and make the view visible.
Without using one of these frameworks, this is a lot of work to build on your own, but this is considered a "Best Practice" pattern.
You may want to consider using an existing framework, a good list comparing their features can be found here.
BTW, if you are wondering how to get intellisense in the XAML designer without setting the DataContext in the constructor of the view. The proper way to do it is to add a design instance in XAML, with an attribute like this.
d:DataContext="{d:DesignInstance local:DruckviewViewModel}"

Battleship in WPF using MVVM strucutre

I am completely new to WPF and MVVM, that's why I decided to start working on that. I am developing a Battleship game. If I create Canvas in my View, and create another canvas in ViewModel and bind them - everything works fine. However there is a problem. To begin with, I add Rectangles and TextBlocks to my Canvas to represent the grid. My "Field" Class (Model) is used in ViewModel for the logic to be done. And I want to have the property inside that class IsLegendHidden (bool). If I set that to true, then the method is called. In that method the linq looks for the textblocks related to my legend and then sets their visibility to hidden. It works fine, however having logic in the Model class is wrong in MVVM structure. But moving the algorithm to the ViewModel side will eliminate the ability to use class property "IsLegendHidden". But I want to have that property inside the model class. How can I solve that?
Your Model Class is free to implement INotifyPropertyChanged and it can notify the ViewModel when a particular property changes. This allows you to have a simpler model and get the logic done in the ViewModel.
You can also have a separate modeling of properties that are more focused on view concerns that the ViewModel can consult.
When using MVVM I like to try to separate things as much as possible. The model objects should just represent the concept they're modeling. The ViewModel is tied to a specific view so it will interpret or translate the model's properties into what is important to the view. You can have something on the Model that isn't 'IsLegendHidden', but that powers the ViewModel's 'IsLegendHidden' property.

How can control in the view get specific data from view model?

I have multiple of views (user controls), each with its own ViewModel. To navigate between them I am using buttons. Buttons display image and text from corresponding view model and also need column and row (because there are like 10 views: 10 columns with different number of rows each).
Right now buttons are created dynamically (I made a Navigator control for this) and for view models I have base class to hold text, image, column and row. Number of views available will be different (depends on user level and certain settings), that's why it's I need control here.
Question: how shall my control get data from view models?
Right now I have interface INavigator, defined in (lol) control itself. And view models implement it. I could go opposite, let my control to know about view models. Both looks wrong.
There is a single Navigator control what has, lets say, Items bound to a list of view models. It can cast each view model to INavigator or ViewModelBase (common for all pages) to obtain specific view model image, text, column and row. So either view model knows about control (to implement INavigator) or control knows about ViewModelBase.. And this is a problem, both solution bind tight control and view models, which is bad in mvvm.
Schematically
The way you've drawn your diagram answers your own question as to how you should structure the code for this.
What you need is one VM (let's call it MainVM) which contains an ObservableCollection<VMBase> of the other VMs (using your base type so that they can all happily live in the same collection).
Your View needs an ItemsControl (bound to your ObservableCollection<VMBase>) where you specify a DataTemplate for the Button using the properties exposed by the VMBase type only. Set the Command property in the Button to call SwitchCommand, CommandParameter is set to the item itself (i.e. {Binding .}).
Your View also needs a ContentControl bound to a SelectedVM property on MainVM which you can populate.
Implement SwitchCommand to set the SelectedVM property based on the value from the CommandParameter.
public void ExecuteSwitchCommand(object parameter)
{
var vmBase = parameter as VMBase;
if (vmBase != null)
SelectedVM = vmBase;
}
All properties mentioned here should be INotifyPropertyChanged enabled so that the View registers when they change and updates the UI.
To get the different UIs for the ContentControl, add type-specific DataTemplates for each of your specific VM types to the Resources file of your View (or if you're smart and are building a custom plug-in framework, merge the Resource Dictionaries).
A lot of people forget with MVVM that the whole point is that there is a purposeful separation of View from ViewModel, thus meaning you can potentially have many Views for a single ViewModel, which is what this demonstrates.
I find it's easiest to think of MVVM as a top-down approach... View knows about it's ViewModel, ViewModel knows about its Model, but Model does not know about its ViewModel and ViewModel does not know about its View.
I also find a View-first approach to development the easiest to work with, as UI development in XAML is static (has to be).
I think a lot of people get to wrapped up in 'making every component (M, V, VM) standalone and replaceable', myself included, but I've slowly come to the conclusion that is just counter-productive.
Technically, sure you could get very complicated and using IoC containers, create some ViewLocator object which binds a View-type to a ViewModel-type, but... what exactly does that gain you besides more confusion? It makes it honestly harder (because I've done this at one point) to develop because now you've lost design-time support first and foremost, among other things; and you're still either binding to a specific view model interface in your view or creating the binding at run-time. Why complicate it?
This article is a good read, and the first Note: explicitly talks about View vs. ViewModel. Hopefully, it will help you draw your own conclusions.
To directly answer your question, I think having your ViewModels implement an INavigator interface of some sort is probably ideal. Remember your VM is 'glue' between your view and model/business logic, its job is to transform business data into data that is consumable by your views, so it exists somewhere between both your UI and business layers.
This is why there are things like Messengers and View Services, which is where your navigator service on the ViewModels can fit in nicely.
I think the design has led to a no way out situation.
I believe that creating a custom button control where the dependency properties tie the image, the row and column actually provide a way for the page, which it resides on ,to get that information to them; whether they are dynamically created or not.
Continuing on with that thought. There is no MVVM logic applied to a custom control, the control contains what it needs to do its job and that is through the dependency properties as mentioned. Any functionality of the button should be done by commanding; all this makes the button data driven and robust enough to use in a MVVM methodology or not.
Question: how shall my control get data from view models?
There should only one viewmodel which is the page the control resides on. The control is simply bound to information which ultimately resides on that VM. How it gets there, that is up to the programmer. If the button is going to contain state data, that is bound from its dependency property in a two way fashion back to the item it is bound to.
By keeping VMs out of the buttons and only having one VM that is the best way to segregate and maintain the data. Unless I am really missing something here....
Same as others here I find it a bit hard to actually understand what you are asking, so this is quite general. The answer to the question header is simply: the Control gets the data from the ViewModel through bindings, always. You set the DataContext of your Control to the corresponding ViewModel, and from there you keep the ViewModel and the Control synchronized:
If you add an ItemsControl containing buttons to the View, you add an ObservableCollection<ButtonViewModel> to the ViewModel and bind the ItemsSource of the ItemsControl to this.
If you allow the user to dynamically add content to the View, the actual code that does it resides in the ViewModel, e.g. when the user clicks on a button "Add Button", you use the Command property to call a ViewModel method that adds a ButtonViewModel to the collection and the View will automatically reflect your changes.
There do exist complicated cases that are impossible to code exclusively in the ViewModel, I have found Behaviors to be the missing link there, but I'll get into that when you show me the specific case.
If you'd like to get a working example, please provide as much code as you can, with your exact expectations of what it should do.

MVVM: Convert code-behind to XAML

I've got an AllTopicsViewModel and its got a property ExerciseVM which is an AllExerciseViewModel, since I want to be able to refresh the AllExerciseViewModel of an ExerciseView so I am doing it like this (not even sure if it violates MVVM, pls. tell me). Well, I want to convert the 2 lines following the InitializeComponent to XAML but not sure how, can anyone help me out?
public MainWindow()
{
InitializeComponent();
AllTopicsViewModel vm = (AllTopicsViewModel)topicsView.DataContext;
vm.ExerciseVM = (AllExercisesViewModel)exercisesView.DataContext;
}
Yes, this is a misconception, according to the idea of MVVM.
Ideally, your View's codebehind (view.xaml.cs) contains nothing more than the auto generated code. Your view only accesses the ViewModel via WPF's data binding mechanisms. Because data binding via WPF is a loose coupling between the binding view and the bound-to ViewModel, you achieve the seperation that drives people to use MVVM.
You are retrieving the ViewModel in the Views codebehind from your control's DataContexts. With this, you create a strong reference between View and ViewModel. So, to help you with your question: You should think about what you are trying to to do with your ViewModel in the View's codebehind and how you can do it differently, either in the view's XAML or in the ViewModel's code itself.
If you like, post the complete MainWindow() class for some advice...
EDIT:
Ok, so its just about setting the child ViewModel on the parent ViewModel. The parent ViewModel AllTopicsViewModel should be responsible for setting its own ExerciseVM on initialization. This is not the View's job. the parent viewModel should assemble the data from one or more models and then create the child view models which the view consumes. Does that make sense for you?

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