Is there a way to deserialize an integer into a string ? I need it for compatibility reason.
using System.Text.Json;
using System.Text.Json.Serialization;
namespace Abc.Test
{
[JsonSerializable(typeof(OrderInfo), GenerationMode = JsonSourceGenerationMode.Metadata)]
public partial class OrderInfoContext : JsonSerializerContext
{ }
public partial class OrderInfo
{
public string UserReference { get; set; }
}
public class Program
{
static void Main(string[] args)
{
var json = #"{""UserReference"": 123}"; // <---- how having 123 deserialize as a string?
var s = JsonSerializer.Deserialize(json, OrderInfoContext.Default.OrderInfo);
}
}
}
In some cases it can make sense to separate your serialization objects (aka DTOs) from your domain objects. This give you several benefits:
Allow your domain objects to have behavior defined, without affecting serialization.
A place to handle any complicated changes to the model without losing backwards compatibility.
Allow the serialization objects to fulfill requirements like public setters, without affecting the usage in the rest of the code.
Ex:
public class OrderInfoDTO
{
public int UserReference { get; set; }
public OrderInfo ToModel() => new OrderInfo(UserReference.ToString();
}
public class OrderInfo{
public string UserReference {get;}
public OrderInfo(string userReference) => UserReference = userReference;
}
You can use a custom converter on a property. I'll look something like:
public partial class OrderInfo
{
[JsonConverter(typeof(YourCustomConverter))]
public string UserReference { get; set; }
}
I have looked at several solutions over the web on reading nested json files but I haven't found one suitable to my need. Maybe because I am new to JSON. Here is my issue:
I have the following JSON in a file:
{
"ConfigError" : {
"DateSent": "2022-04-28T14:03:16.6628493-07:00",
"ToolType": "WSM",
"IsSent": true
},
"FileCopyError" : {
"DateSent": "2022-06-14T14:03:16.6628493-07:00",
"ToolType": "RMT",
"IsSent": false
}
}
For this I have written two classes. One for the Inner object:
public class SummaryEmailStatus
{
public DateTime DateSent { get; set; }
public string ToolType { get; set; }
public bool IsSent { get; set; }
}
One for the Outer Objects:
public class SummaryEmailClass
{
SummaryEmailStatus Status { get; set; } = new SummaryEmailStatus();
}
I would like to be able to read the JSON in C#. I'm primarily concerned with the inner objects. They are of same class but they need to be used differently. So ideally I'd want a function that I can pass in "ConfigError" or "FileCopyError" into and it will return SummaryEmailStatus class object populated by the values in the JSON:
public static void ReadJasonFile(string jsonFileName, string objctName)
{
List<SummaryEmailClass> emailClassList = new List<SummaryEmailClass>();
dynamic jsonFile = JsonConvert.DeserializeObject(File.ReadAllText(jsonFileName));
SummaryEmailStatus sumclass = jsonFile[objctName];
}
But this gives me a run time error saying:
Cannot implicitly convert type "Newtonsoft.Json.Linq.JObject to SummaryEmailStatus
How can I successfully parse out the inner summaryemailstatus objects?
Additionally, I'd like to be able to create the JSON data within C#. The reason being, when I read the JSON, I will do some task and then will need to update the values of the JSON with the current timestamps. I'd imagine, I'd need to rewrite the file. How can I write a nested JSON like this in C#?
If JSON is not the best way to do this, I am open to alternatives
you can try
string json = File.ReadAllText(jsonFileName);
Dictionary<string,SummaryEmailStatus> summaryEmailStatus =
JsonConvert.DeserializeObject<Dictionary<string,SummaryEmailStatus>>(json);
you can use it
SummaryEmailStatus configError = summaryEmailStatus["ConfigError"];
if you want update data
summaryEmailStatus["ConfigError"].DateSent= DateTime.Now;
and serialize back
json = JsonConvert.SerializeObject(summaryEmailStatus);
or if you have only 2 main properties, create a class
public class SummaryEmailClass
{
SummaryEmailStatus ConfigError { get; set; }
SummaryEmailStatus FileCopyError{ get; set; }
}
and use it
SummaryEmailClass summaryEmailStatus =
JsonConvert.DeserializeObject<SummaryEmailStatusClass>(json);
SummaryEmailStatus configError = summaryEmailStatus.ConfigError;
Summary
You need to convert your JObject into the type you are expecting, as shown here:
SummaryEmailStatus sumclass = jsonFile[objctName].ToObject<SummaryEmailStatus>();
Details
jsonFile[objtName] is of type JObject. The reason is because JsonConvert.DeserializeObject has no idea that you intend to convert that into a list of SummaryEmailStatus.
Once you have your array of JObjects, you can convert that into a SummaryEmailStatus as shown in the following snippet:
public static void ReadJasonFile(string jsonFileName, string objctName)
{
List<SummaryEmailClass> emailClassList = new List<SummaryEmailClass>();
dynamic jsonFile = JsonConvert.DeserializeObject(File.ReadAllText(jsonFileName));
SummaryEmailStatus sumclass = jsonFile[objctName].ToObject<SummaryEmailStatus>();
}
Easy way is kept both objects in JSON, I rewrite your code and add root. For example, if you want to write Config Error and don't write File Copy Error, you can save one of them like null.
public class ConfigError
{
public DateTime DateSent { get; set; }
public string ToolType { get; set; }
public bool IsSent { get; set; }
}
public class FileCopyError
{
public DateTime DateSent { get; set; }
public string ToolType { get; set; }
public bool IsSent { get; set; }
}
public class Root
{
public ConfigError ConfigError { get; set; }
public FileCopyError FileCopyError { get; set; }
}
//in your method to get all data
var json = File.ReadAllText(jsonFileName);
var myDeserializedClass = JsonConvert.DeserializeObject<Root>(json);
Example change config and write to file
var json = #"{
""ConfigError"" : {
""DateSent"": ""2022-04-28T14:03:16.6628493-07:00"",
""ToolType"": ""WSM"",
""IsSent"": true
},
""FileCopyError"" : {
""DateSent"": ""2022-06-14T14:03:16.6628493-07:00"",
""ToolType"": ""RMT"",
""IsSent"": false
}
}";
var conf = JsonConvert.DeserializeObject<Root>(json);
conf.ConfigError.DateSent = DateTime.Now;
conf.ConfigError.ToolType = "New way";
conf.ConfigError.IsSent = false;
conf.FileCopyError = null;
var newJson = JsonConvert.SerializeObject(conf);
File.WriteAllText("your path", newJson);
I'm trying to make a Config.cs class to use on my project.
Structure is supposed to consist of categories of settings. For example, Config.LogOnDetails should hold the values for MySQL login.
Here is my current structure.
public class Config
{
public string pPath;
public string configPath;
public string configFilePath;
public class LogOnDetails
{
public string MySQLDatabaseName { get; set; }
public string MySQLUser { get; set; }
public string MySQLPassword { get; set; }
public string MySQLAddress { get; set; }
}
public Config()
{
pPath = Directory.GetCurrentDirectory();
configPath = Path.Combine(pPath, #"/config");
configFilePath = Path.Combine(configPath, "/config.json");
//If it doesn't exist, create a directory for the configuration to be stored in
if (!Directory.Exists(configPath))
{
Directory.CreateDirectory("config");
}
if (!File.Exists(configFilePath))
{
string json = JsonConvert.SerializeObject(this);
File.WriteAllText(configFilePath, json);
Console.WriteLine("Created a new blank config file!");
}
}
}
Here is how I'm trying to load the config to the class.
//Initialize configuration
Config.LogOnDetails logOnDetails = new Config.LogOnDetails();
//Load config from json
config.LogOnDetails = JsonConvert.DeserializeObject<Config.LogOnDetails>(config.configFilePath);
But this doesn't seem to work and looks like I don't understand subclasses properly. How can I organize my class so it will work?
json example:
{
"pPath": null,
"configPath": null,
"configFilePath": null,
"MySQLDatabaseName": null,
"MySQLUser": null,
"MySQLPassword": null,
"MySQLAddress": null
}
First off, I'm going to start with a general point. The Config class should know nothing about how it is stored, or where it is stored. That is a completely separate "concern". See Separation of concerns
Start off with the definition of what you want to store. That seems to be your MySql info, and some other info. These should all be individual classes (To be clear, you can nest them, but there is no need to and complicates the answer a little):
public class LogOnDetails
{
public string MySQLDatabaseName { get; set; }
public string MySQLUser { get; set; }
public string MySQLPassword { get; set; }
public string MySQLAddress { get; set; }
}
You can have another one:
public class Settings
{
public string Locale { get; set; }
}
And you can compose these into a master config object
public class Config
{
public string SomeTopLevelProp {get; set; }
public LogOnDetails LogOnDetails { get; set; }
public Settings Settings { get; set; }
}
The way to serialize and deserialize this is fairly straightforward
var config = new Config()
{
SomeTopLevelProp = "ABCDEF",
LogOnDetails = new LogOnDetails()
{
MySqlDatabaseName = "Foo" ,
MySQLUser = "MyUser"
// snip the rest of the props
},
Settings = new Settings
{
Locale = "en-GB"
}
}
var json = JsonConvert.SerializeObject(config );
var mySettingDeserialized = JsonConvert.DeserializeObject<Config>(json);
I have purposely left out the writing to a file part - you seem to know how to do that - but keep it outside of the Config class. For example a separate classes, perhaps just with 2 static methods which knows how/where to store the config
public static class ConfigLoader
{
public static void StoreConfig(Config config, string location) {... }
public static Config LoadConfig(string location) {... }
}
A note on security - storing your database password as plain text in a json config file is generally a bad idea. You might consider encrypting it, and storing that and decrypting it when using the value.
<root xmlns:test="url" test:attr1="10" test:attr2="someValue>
<elementwrapper>
<secondElementwrapper>
<element>someValue</element>
<differentelement>anotherValue</differentelement>
</secondElementwrapper>
</elementwrapper>
</root>
The following classes are made:
public class XmlEntities
{
[XmlRoot("root")]
public class Root
{
[XmlElement("elementwrapper")]
public Elementwrapper Elementwrapper{ get; set; }
}
public class Elementwrapper
{
[XmlElement("secondElementwrapper")]
public SecondElementwrapper SecondElementwrapper{ get; set; }
}
public class Values
{
[XmlElement("element")]
public string Element{ get; set; }
[XmlElement("differentelement")]
public string Differentelement{ get; set; }
}
}
And here is where i serialize and deserialize the xml:
var reader = XmlReader.Create(url);
var xmlRecord = new XmlEntities.Root();
try
{
var serializer = new XmlSerializer(typeof(XmlEntities.Root));
xmlRecord = (XmlEntities.Root)serializer.Deserialize(reader);
reader.Close();
}
catch (Exception e) { }
I want to access xmlRecord.Element instead of xmlRecord.Elementwrapper.Values.Element
How do i get the test:attr1 value?*
If i remove the class Elementwrapper and Root, xmlRecord returns null.
[XmlAttribute] inside the Root class to get attr1 value doesnt work for me.
Thank you!
EDIT:
The element was a copy/paste wrong doing. Fixed that. I also added :test infront of the attr1, forgot that.
EDIT:
Adding the following as sgk mentioned, inside the root class, allowed me to access the attribute
[XmlAttribute("attr1", Namespace = "url")]
public string attr { get; set; }
EDIT: And is there a way to map the classes differently? So i can access xmlRecord.Element directly?
EDIT: #TonyStark seems like what i want needs to be approached a different way, but then again this already works i just need to access the element trough the nodes (xmlRecord.elementwrapper.secondelementwrapper.element) for those that are wondering.
To access the attribute of root i simply use : xmlRecord.attr after i added the xmlattribute that its written above.
I want to access xmlRecord.Element instead of xmlRecord.Elementwrapper.Values.Element - Based on the XML structure you have, to Deserialize and access the <element> value and <differentelement> value - you need to go through root-->elementwrapper-->secondElementwrapper.
How do i get the attr1 value? - add [XmlAttribute("attr1")] inside class Root
Then, [XmlElement("<elementwrapper>")] should be [XmlElement("elementwrapper")] otherwise when you Deserialize you will always get null as there is no matching element.
See below
public class XmlEntities
{
[XmlRoot("root")]
public class Root
{
[XmlElement("elementwrapper")]
public Elementwrapper Elementwrapper { get; set; }
[XmlAttribute("attr1", Namespace="url")]
public string attr1;
}
public class Elementwrapper
{
[XmlElement("secondElementwrapper")]
public SecondElementwrapper SecondElementwrapper { get; set; }
}
public class SecondElementwrapper
{
[XmlElement("element")]
public string Element { get; set; }
[XmlElement("differentelement")]
public string Differentelement { get; set; }
}
}
This is my first time using XML Serialization and this is driving me absolutely nuts after 2 days of trying to troubleshoot this.
I get this error when the deserialization kicks in:
The XML element 'name' from namespace '' is already present in the current scope. Use XML attributes to specify another XML name or namespace for the element.
The error happens on this line in my code:
Album album = (Album)serializer.Deserialize(reader);
I not sure why. There is no dup "name" node so I just don't get it. This is an XML doc received from an HttpWebResponse from a 3rd party REST API.
Here's the complete code:
My Album Class (the type I'm Deserializing to):
public class Album
{
#region Constructors
public Album()
{
}
#endregion
#region ElementConstants
public static class ElementConstants
{
public const string aID = "aid";
public const string Owner = "owner";
public const string AlbumName = "name";
public const string CoverPhotoID = "cover_pid";
public const string CreateDate = "created";
public const string LastModifiedDate = "modified";
public const string Description = "description";
public const string Location = "location";
public const string AlbumURL = "link";
public const string Size = "size";
public const string Visible = "visible";
}
#endregion ElementConstants
#region Public Properties
[XmlArray(ElementName = "photos_GetAlbums_response")]
[XmlArrayItem( "album" )]
public Album[] Albums { get; set; }
[XmlElement (ElementName = ElementConstants.AlbumName, DataType = "string")]
public string AlbumID { get; set; }
[XmlElement(ElementName = ElementConstants.aID, DataType = "int")]
public Int32 CoverPhotoID { get; set; }
[XmlElement(ElementName = ElementConstants.Owner, DataType = "string")]
public string Owner { get; set; }
[XmlElement(ElementName = ElementConstants.AlbumName, DataType = "string")]
public string AlbumName { get; set; }
[XmlElement(ElementName = ElementConstants.aID, DataType = "DateTime")]
public DateTime CreateDate { get; set; }
[XmlElement(ElementName = ElementConstants.LastModifiedDate, DataType = "DateTime")]
public DateTime LastModifiedDate { get; set; }
[XmlElement(ElementName = ElementConstants.Description, DataType = "string")]
public string Description { get; set; }
[XmlElement(ElementName = ElementConstants.Location, DataType = "string")]
public string Location { get; set; }
[XmlElement(ElementName = ElementConstants.AlbumURL, DataType = "string")]
public string Link { get; set; }
[XmlElement(ElementName = ElementConstants.Size, DataType = "size")]
public string Size { get; set; }
[XmlElement(ElementName = ElementConstants.Visible, DataType = "string")]
public string Visible { get; set; }
#endregion
}
My Serializer Class:
public class Serializer
{
public static Album CreateAlbumFromXMLDoc(XmlDocument doc)
{
// Create an instance of a serializer
var serializer = new XmlSerializer(typeof(Album));
var reader = new StringReader(doc.ToString());
// Deserialize the Xml Object and cast to type Album
Album album = (Album)serializer.Deserialize(reader);
return album;
}
}
The XML that I am trying to Deserialized (copied from the Xml Doc object being passed into the CreateAlbumFromXMLDoc method when debugging in VS):
<?xml version="1.0" encoding="UTF-8"?>
<photos_GetAlbums_response xsi:schemaLocation="http://api.example.com/1.0/ http://api.example.com/1.0/xxx.xsd" list="true">
<album>
<aid>3231990241086938677</aid>
<cover_pid>7031990241087042549</cover_pid>
<owner>1337262814</owner>
<name>LA</name>
<created>1233469624</created>
<modified>1233469942</modified>
<description>trip to LA</description>
<location>CA</location>
<link>http://www.example.com/album.php?aid=7333&id=1337262814</link>
<size>48</size>
<visible>friends</visible>
</album>
<album>
<aid>7031990241086936240</aid>
<cover_pid>7031990241087005994</cover_pid>
<owner>1337262814</owner>
<name>Wall Photos</name>
<created>1230437805</created>
<modified>1233460690</modified>
<description/>
<location/>
<link>http://www.example.com/album.php?aid=3296&id=1337262814</link>
<size>34</size>
<visible>everyone</visible>
</album>
<album>
<aid>7031990241086937544</aid>
<cover_pid>7031990241087026027</cover_pid>
<owner>1337262814</owner>
<name>Mobile Uploads</name>
<created>1231984989</created>
<modified>1233460349</modified>
<description/>
<location/>
<link>http://www.example.com/album.php?aid=6300&id=1337262814</link>
<size>3</size>
<visible>friends</visible>
</album>
<album>
<aid>7031990241086936188</aid>
<cover_pid>7031990241087005114</cover_pid>
<owner>1337262814</owner>
<name>Christmas 2008</name>
<created>1230361978</created>
<modified>1230362306</modified>
<description>My Album</description>
<location/>
<link>http://www.example.com/album.php?aid=5234&id=1337262814</link>
<size>50</size>
<visible>friends</visible>
</album>
<album>
<aid>7031990241086935881</aid>
<cover_pid>7031990241087001093</cover_pid>
<owner>1637262814</owner>
<name>Hock</name>
<created>1229889219</created>
<modified>1229889235</modified>
<description>Misc Pics</description>
<location/>
<link>http://www.example.com/album.php?aid=4937&id=1637262814</link>
<size>1</size>
<visible>friends-of-friends</visible>
</album>
<album>
<aid>7031990241086935541</aid>
<cover_pid>7031990241086996817</cover_pid>
<owner>1637262814</owner>
<name>Test Album 2 (for work)</name>
<created>1229460455</created>
<modified>1229460475</modified>
<description>this is a test album</description>
<location/>
<link>http://www.example.com/album.php?aid=4547&id=1637262814</link>
<size>1</size>
<visible>everyone</visible>
</album>
<album>
<aid>7031990241086935537</aid>
<cover_pid>7031990241086996795</cover_pid>
<owner>1637262814</owner>
<name>Test Album (for work)</name>
<created>1229459168</created>
<modified>1229459185</modified>
<description>Testing for work</description>
<location/>
<link>http://www.example.com/album.php?aid=4493&id=1637262814</link>
<size>1</size>
<visible>friends</visible>
</album>
</photos_GetAlbums_response>
A side note: Just for the hell of it, I paste that XML into XML Notepad 2007, it tells me:
Your XML document contains no xml-stylesheet processing instruction. To provide an XSLT transform, add the following to the top of your file and edit the href attribute accordingly:
I don't think that really means it's malformed or anything but just something to note.
So..
My ultimate goal is to get pass this damn error obviously and get an array of albums back using my code above once I can get past the error. I also want to make sure my code is correct in trying to retrieve that arrray back of albums using my Album[] property in my Album class or anything else I might be missing here. I think it's pretty close and should work but it's not.
Follow-up. I've been pulling my hair out since then.
Here's the latest. I did not use some things for now (from Marc) like the Enum, etc. I might change that later. I also pulled out the datetime stuff as it just looked wierd and I did not get errors on that anway without...at least yet. The main problem now is still my damn XML.
It's still appearing to have problems with the format I guess? Unless it's covering up another problem, no clue. This is driving me fing crazy.
I now get this error when the deserialization kicks in:
Data at the root level is invalid. Line 1, position 1.
The error happens on this line in my code: GetAlbumsResponse album = (GetAlbumsResponse)serializer.Deserialize(reader);
How I get the response into an XmL doc:
public static XmlDocument GetResponseXmlDocument(HttpWebResponse response)
{
Stream dataStream = null; // stream from WebResponse
XmlDocument doc = new XmlDocument();
if (doc == null)
{
throw new NullReferenceException("The web reponse was null");
}
// Get the response stream so we can read the body of the response
dataStream = response.GetResponseStream();
// Open the stream using a StreamReader for easy access
StreamReader reader = new StreamReader(dataStream);
// Load response into string variable so that we can then load into an XML doc
string responseString = reader.ReadToEnd();
// Create an XML document & load it with the response data
doc.LoadXml(responseString);
// Final XML document that represents the response
return doc;
}
My Album Class & Root Level Class (thanks to help from Marc..I get it now):
namespace xxx.Entities
{
[Serializable, XmlRoot("photos_GetAlbums_response")]
public class GetAlbumsResponse
{
[XmlElement("album")]
public List<Album> Albums { get; set; }
[XmlAttribute("list")]
public bool IsList { get; set; }
}
public class Album
{
#region Constructors
public Album()
{
}
#endregion
#region ElementConstants
/// <summary>
/// Constants Class to eliminate use of Magic Strings (hard coded strings)
/// </summary>
public static class ElementConstants
{
public const string aID = "aid";
public const string Owner = "owner";
public const string AlbumName = "name";
public const string CoverPhotoID = "cover_pid";
public const string CreateDate = "created";
public const string LastModifiedDate = "modified";
public const string Description = "description";
public const string Location = "location";
public const string AlbumURL = "link";
public const string Size = "size";
public const string Visible = "visible";
}
#endregion ElementConstants
#region Public Properties
[XmlElement (ElementName = ElementConstants.aID, DataType = "string")]
public string AlbumID { get; set; }
[XmlElement(ElementName = ElementConstants.CoverPhotoID, DataType = "int")]
public Int32 CoverPhotoID { get; set; }
[XmlElement(ElementName = ElementConstants.Owner, DataType = "string")]
public string Owner { get; set; }
[XmlElement(ElementName = ElementConstants.AlbumName, DataType = "string")]
public string AlbumName { get; set; }
public string Created { get; set; }
public DateTime Modified { get; set; }
[XmlElement(ElementName = ElementConstants.Description, DataType = "string")]
public string Description { get; set; }
[XmlElement(ElementName = ElementConstants.Location, DataType = "string")]
public string Location { get; set; }
[XmlElement(ElementName = ElementConstants.AlbumURL, DataType = "string")]
public string Link { get; set; }
public string Size { get; set; }
[XmlElement(ElementName = ElementConstants.Visible, DataType = "string")]
public string Visible { get; set; }
#endregion
}
}
My Serializer Class:
namespace xxx.Utilities
{
public class Serializer
{
public static List<Album> CreateAlbumFromXMLDoc(XmlDocument doc)
{
// Create an instance of a serializer
var serializer = new XmlSerializer(typeof(Album));
var reader = new StringReader(doc.ToString());
// Deserialize the Xml Object and cast to type Album
GetAlbumsResponse album = (GetAlbumsResponse)serializer.Deserialize(reader);
return album.Albums;
}
}
}
The true XML incoming, that I am trying to Deserialize (yes it does have xmlns):
<?xml version="1.0" encoding="UTF-8"?>
<photos_GetAlbums_response xmlns="http://api.example.com/1.0/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://api.example.com/1.0/ http://api.example.com/1.0/xxx.xsd" list="true">
<album>
<aid>7321990241086938677</aid>
<cover_pid>7031990241087042549</cover_pid>
<owner>1124262814</owner>
<name>Album Test 1</name>
<created>1233469624</created>
<modified>1233469942</modified>
<description>Our trip</description>
<location>CA</location>
<link>http://www.example.com/album.php?aid=7733&id=1124262814</link>
<size>48</size>
<visible>friends</visible>
</album>
<album>
<aid>231990241086936240</aid>
<cover_pid>7042330241087005994</cover_pid>
<owner>1124262814</owner>
<name>Album Test 2</name>
<created>1230437805</created>
<modified>1233460690</modified>
<description />
<location />
<link>http://www.example.com/album.php?aid=5296&id=1124262814</link>
<size>34</size>
<visible>everyone</visible>
</album>
<album>
<aid>70319423341086937544</aid>
<cover_pid>7032390241087026027</cover_pid>
<owner>1124262814</owner>
<name>Album Test 3</name>
<created>1231984989</created>
<modified>1233460349</modified>
<description />
<location />
<link>http://www.example.com/album.php?aid=6600&id=1124262814</link>
<size>3</size>
<visible>friends</visible>
</album>
</photos_GetAlbums_response>
Personally, I wouldn't use constants here - they make it hard to spot errors (and since you probably aren't re-using them, don't add much). For example:
[XmlElement (ElementName = ElementConstants.AlbumName, DataType = "string")]
public string AlbumID { get; set; }
...
[XmlElement(ElementName = ElementConstants.AlbumName, DataType = "string")]
public string AlbumName { get; set; }
Looks suspect to me...
An easier approach is to write the xml you want to a file (foo.xml, say) and use:
xsd foo.xml
xsd foo.xsd /classes
Then look at foo.cs.
Here we go... note the xml was invalid (& should be &; use of undeclared xsi namespace-alias). Note also that I added an enum for the visibility, added handling for converting the long to DateTime, and added the wrapper type:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
static class Program
{
const string xml = #"<?xml version=""1.0"" encoding=""UTF-8""?>
<photos_GetAlbums_response
xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
xsi:schemaLocation=""http://api.example.com/1.0/ http://api.example.com/1.0/xxx.xsd""
list=""true"">
<album>
<aid>3231990241086938677</aid>
<cover_pid>7031990241087042549</cover_pid>
<owner>1337262814</owner>
<name>LA</name>
<created>1233469624</created>
<modified>1233469942</modified>
<description>trip to LA</description>
<location>CA</location>
<link>http://www.example.com/album.php?aid=7333&id=1337262814</link>
<size>48</size>
<visible>friends</visible>
</album>
<album>
<aid>7031990241086936240</aid>
<cover_pid>7031990241087005994</cover_pid>
<owner>1337262814</owner>
<name>Wall Photos</name>
<created>1230437805</created>
<modified>1233460690</modified>
<description/>
<location/>
<link>http://www.example.com/album.php?aid=3296&id=1337262814</link>
<size>34</size>
<visible>everyone</visible>
</album>
<album>
<aid>7031990241086937544</aid>
<cover_pid>7031990241087026027</cover_pid>
<owner>1337262814</owner>
<name>Mobile Uploads</name>
<created>1231984989</created>
<modified>1233460349</modified>
<description/>
<location/>
<link>http://www.example.com/album.php?aid=6300&id=1337262814</link>
<size>3</size>
<visible>friends</visible>
</album>
<album>
<aid>7031990241086936188</aid>
<cover_pid>7031990241087005114</cover_pid>
<owner>1337262814</owner>
<name>Christmas 2008</name>
<created>1230361978</created>
<modified>1230362306</modified>
<description>My Album</description>
<location/>
<link>http://www.example.com/album.php?aid=5234&id=1337262814</link>
<size>50</size>
<visible>friends</visible>
</album>
<album>
<aid>7031990241086935881</aid>
<cover_pid>7031990241087001093</cover_pid>
<owner>1637262814</owner>
<name>Hock</name>
<created>1229889219</created>
<modified>1229889235</modified>
<description>Misc Pics</description>
<location/>
<link>http://www.example.com/album.php?aid=4937&id=1637262814</link>
<size>1</size>
<visible>friends-of-friends</visible>
</album>
<album>
<aid>7031990241086935541</aid>
<cover_pid>7031990241086996817</cover_pid>
<owner>1637262814</owner>
<name>Test Album 2 (for work)</name>
<created>1229460455</created>
<modified>1229460475</modified>
<description>this is a test album</description>
<location/>
<link>http://www.example.com/album.php?aid=4547&id=1637262814</link>
<size>1</size>
<visible>everyone</visible>
</album>
<album>
<aid>7031990241086935537</aid>
<cover_pid>7031990241086996795</cover_pid>
<owner>1637262814</owner>
<name>Test Album (for work)</name>
<created>1229459168</created>
<modified>1229459185</modified>
<description>Testing for work</description>
<location/>
<link>http://www.example.com/album.php?aid=4493&id=1637262814</link>
<size>1</size>
<visible>friends</visible>
</album>
</photos_GetAlbums_response>";
static void Main()
{
XmlSerializer ser = new XmlSerializer(typeof(GetAlbumsResponse));
GetAlbumsResponse response;
using (StringReader reader = new StringReader(xml))
{
response = (GetAlbumsResponse)ser.Deserialize(reader);
}
}
}
[Serializable, XmlRoot("photos_GetAlbums_response")]
public class GetAlbumsResponse
{
[XmlElement("album")]
public List<Album> Albums {get;set;}
[XmlAttribute("list")]
public bool IsList { get; set; }
}
public enum AlbumVisibility
{
[XmlEnum("")]
None,
[XmlEnum("friends")]
Friends,
[XmlEnum("friends-of-friends")]
FriendsOfFriends,
[XmlEnum("everyone")]
Everyone
}
[Serializable]
public class Album
{
static readonly DateTime epoch = new DateTime(1970, 1, 1);
static long SerializeDateTime(DateTime value)
{
return (long)((value - epoch).TotalSeconds);
}
static DateTime DeserializeDateTime(long value)
{
return epoch.AddSeconds(value);
}
[XmlElement("aid")]
public long AlbumID { get; set; }
[XmlElement("cover_pid")]
public long CoverPhotoID { get; set; }
[XmlElement("owner")]
public long Owner { get; set; }
[XmlElement("name")]
public string AlbumName { get; set; }
[XmlIgnore]
public DateTime CreateDate { get; set; }
[XmlElement("created"), Browsable(false)]
[EditorBrowsable(EditorBrowsableState.Never)]
public long CreateDateInt64 {
get {return SerializeDateTime(CreateDate);}
set {CreateDate = DeserializeDateTime(value);}
}
[XmlIgnore]
public DateTime LastModifiedDate { get; set; }
[XmlElement("modified"), Browsable(false)]
[EditorBrowsable(EditorBrowsableState.Never)]
public long LastModifiedDateInt64
{
get { return SerializeDateTime(LastModifiedDate); }
set { LastModifiedDate = DeserializeDateTime(value); }
}
[XmlElement("description")]
public string Description { get; set; }
[XmlElement("location")]
public string Location { get; set; }
[XmlElement("link")]
public string Link { get; set; }
[XmlElement("size")]
public int Size { get; set; }
[XmlElement("visible")]
public AlbumVisibility Visibility { get; set; }
}
(08 Feb) First, treating xml as a string (for reading) isn't going to cause errors.
The problem is the namespace (the xmlns without the xsi); this wasn't in the earlier xml, so I couldn't include it... basically, you need to tell the serializer about it:
[Serializable, XmlRoot("photos_GetAlbums_response",
Namespace="http://api.example.com/1.0/")]
public class GetAlbumsResponse { /* code as before */ }
[Serializable, XmlType(Namespace="http://api.example.com/1.0/")]
public class Album { /* code as before */ }
On this occasion, a constant for the namespace would make sense (since you are re-using it).
If the xml you are showing is accurate, then the links are still corrupt, though... but maybe this is just copy/paste (i.e. don't apply this change until you know it errors...): you need & (not &). Suggest some "Replace"... at the crudest level:
string fixedXml = xml.Replace("&", "&");
(although something more precise might be better - perhaps a regex)
Note that with the different data I also had to make some of the data strings (rather than long):
[XmlElement("aid")]
public string AlbumID { get; set; }
[XmlElement("cover_pid")]
public string CoverPhotoID { get; set; }
[XmlElement("owner")]
public string Owner { get; set; }
With these changes (and mostly my original code) it works.
Of course, by this point you should be thinking "I wish I'd used xsd".
Yes - album is definitely not the root node in your XML.
What I would recommend you do is create a GetAlbumsResponse class which contains a list of albums, and move your deserialize code to the wrapper class.
Basically, remove the root element from your Album class definition, and :
[XmlRoot (ElementName="GetAlbums_response")]
public class GetAlbumsResponse
{
#region Constructors
public GetAlbumsResponse()
{
}
#endregion
[XmlArray(ElementName="album")]
public List<Album> Albums{get;set;}
... deserialization code...
}
Well,
there is a link from Microsoft targeting your problem
The Xml that would work for your current code is something like this:
<Album><photos_GetAlbums_response>
<Album>
<photos_GetAlbums_response>
<Album>
<photos_GetAlbums_response> ....
A response, which has an array of Albums, where each Album has a response which is an Array of Albums...etc.
Anyway, I already helped you in your other question, and even went to the trouble of creating a full working code sample. Why did you create another question for the same problem ?
Use System.Xml.XmlDocument to parse the input. It shouldn't take more than an hour to write the code to extract the data yourself.
Ok - I coded up an example. I took a look at the Facebook API, now here is a FULL working example.
Try this:
[XmlRoot("photos_getAlbums_response", Namespace="http://api.facebook.com/1.0/")]
public class GetAlbumsResponse
{
public GetAlbumsResponse()
{
}
[XmlElement("album")]
public List<Album> Albums { get; set; }
}
public class Album
{
[XmlElement("aid")]
public long Aid{get;set;}
[XmlElement("cover_pid")]
public long CoverPid{get;set;}
[XmlElement("owner")]
public long Owner{get;set;}
[XmlElement("name")]
public string Name{get;set;}
[XmlElement("created")]
public long Created{get;set;}
[XmlElement("modified")]
public long Modified{get;set;}
[XmlElement("description")]
public string Description{get;set;}
[XmlElement("location")]
public string Location{get;set;}
[XmlElement("link")]
public string Link{get;set;}
[XmlElement("size")]
public int Size{get;set;}
[XmlElement("visible")]
public string Visible{get;set;}
public Album()
{}
}
class XmlUtils
{
public static T DeserializeFromXml<T>(string xml)
{
T result;
XmlSerializer ser = new XmlSerializer(typeof(T));
using (TextReader tr = new StringReader(xml))
{
result = (T)ser.Deserialize(tr);
}
return result;
}
}
Now.. with an xml photos_getAlbums_response from the Facebook API,
You can deserialize like this:
GetAlbumsResponse response = XmlUtils.DeserializeFromXml<GetAlbumsResponse>(xmlResponseString);
This is a really old thread but I just faced the same issue my self while tried to serialize two different list types in the same class under the same XmlArray name, something like
<Root>
<ArrayNode>
<SubnodeType1>...</SubnodeType1>
<SubnodeType1>...</SubnodeType1>
</ArrayNode>
</Root>
Or
<Root>
<ArrayNode>
<SubnodeType2>...</SubnodeType2>
<SubnodeType2>...</SubnodeType2>
</ArrayNode>
</Root>
What has worked for me was to use a class decoration like:
[XmlRoot(Namespace = "", ElementName = "Root")]
public class Root
{
[XmlArray(ElementName = "ArrayNode", Namespace = "", IsNullable = false, Order = 1)]
[XmlArrayItem("SubnodeType1")]
public List<SubnodeType1> SubnodeType1 { get; set; }
[XmlArray(ElementName = "ArrayNode", Namespace = "", IsNullable = false, Order = 2)]
[XmlArrayItem("SubnodeType2")]
public List<SubnodeType2> SubnodeType2 { get; set; }
}
Hope it help someone else :)