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How to edit a file in IsolatedStorage C#

I have been fiddling with this problem for the past hour so I thought you guys may be able to help on a Friday afternoon!
Problem
I am trying to edit an XML file in localstorage but can't figure out how to edit the existing file and re-save the file. The edit I have made it to remove a certain node from the XML.
Code
Here is the method that does all the work.
This first code snippet was already in the code and basically creates the XML file and saves it to localstorage.:
protected byte[] CreateFileData(PortableBusinessObjects.Location location, string geoObjectFilename)
{
byte[] fileData = null;
var xmlFile = System.IO.Path.GetFileNameWithoutExtension(geoObjectFilename) + ".xml";
var zipFile = System.IO.Path.GetFileNameWithoutExtension(geoObjectFilename) + ".zip";
using (IsolatedStorageFileStream fileStream = localStorage.CreateFile(xmlFile))
{
XmlWriter writer = XmlWriter.Create(fileStream);
if (location.GetType() == typeof(PortableBusinessObjects.Shape))
_xmlShapeSerializer.Serialize(writer, location);
else if (location.GetType() == typeof(PortableBusinessObjects.Point))
_xmlPointSerializer.Serialize(writer, location);
fileStream.Flush();
fileStream.Close();
}
}
This is my attempt at overwriting the saved file (Doesn't work):
using (IsolatedStorageFileStream doc = localStorage.OpenFile(xmlFile, FileMode.Open))
{
System.Xml.Linq.XDocument test = System.Xml.Linq.XDocument.Load(doc);
test.Descendants("Time").Remove();
XmlWriter writer = XmlWriter.Create(doc);
doc.Flush();
doc.Close();
}
Question
Where do I place my code that removes the "Time" nodes and saves the file?

Your saving code doesn't do any saving - you just create an XmlWriter and do nothing with it.
There are various methods built into XDocument than can help you here. While you could pass your XmlWriter to it, you can actually save directly to the stream:
test.Save(doc);
Note you will need to move to the beginning of the stream before writing to it - loading your XML will have read to the end:
doc.Position = 0;

You should use the IsolatedStorageFileStream together with the StreamWriter.
See How to: Read and Write to Files in Isolated Storage
With XDocument you then have to Save() the new contents to the stream.

How to Load Xml file whilelocking it using XDocument.Load() method?

I am using following two code to load an XML.Some other process is updating the same XML while i am trying to Load it.It's giving me below error in both case:-
The process cannot access the file
'D:\Projects\WriteOnXml\Xml\test.xml' because it is being used by
another process.
1)
using (FileStream xml = File.Open(filePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite))
{
XDocument xdoc = XDocument.Load(xml);
}
2)
using (StreamReader sr = new StreamReader(dest))
{
xdoc = XDocument.Load(sr);
}
I want to load it while it is updating by some other process.
Any better approach.

have a look on that question:
c# xml.Load() locking file on disk causing errors
it seems that if you could use xml document it will work...

Deserialization Xml Document Error

I have a problem when I deserialize the xml into List of Objects. I searched it on the net this morning, but my problem isn't resolved.
Deserialization method
public static List<FileAction> DeSerialization()
{
XmlRootAttribute xRoot=new XmlRootAttribute();
xRoot.ElementName="ArrayOfSerializeClass";
xRoot.IsNullable=true;
XmlSerializer serializer = new XmlSerializer(typeof(List<FileAction>),xRoot);//, new XmlRootAttribute("ArrayOfSerializeClass")
using (Stream streamReader = File.OpenRead(#"C:\serialization\SerializationWithFileWatcher\Output\XmlSerialize.xml"))//FileStream fs =new FileStream(xmlPath,FileMode.Open)
{
using (XmlReader reader = XmlReader.Create(streamReader))
{
int count =0;
List<FileAction> serialList2 = (List<FileAction>)serializer.Deserialize(reader);
return (List<FileAction>)serializer.Deserialize(reader);
}
}
Calling Method
String resultPath = #"C:\serialization\SerializationWithFileWatcher\Output\XmlSerialize.xml";
if (!File.Exists(resultPath))
{
XmlSerializer xs = new XmlSerializer(typeof(List<SerializeClass>));
using (FileStream fileStream = new FileStream(#"C:\serialization\SerializationWithFileWatcher\Output\XmlSerialize.xml", FileMode.Create))
{
xs.Serialize(fileStream, serializeList);//seri
fileStream.Close();
}
Console.WriteLine("Succesfully serialized to XML");
}
else
{
//string path= #"C:\serialization\SerializationWithFileWatcher\Output\XmlSerialize.xml";
DeSerialization();
XmlSerializer xs = new XmlSerializer(typeof(List<SerializeClass>));
FileStream fs = new FileStream(#"C:\serialization\SerializationWithFileWatcher\Output\XmlSerialize.xml", FileMode.Append, FileAccess.Write);
using (XmlWriter xwr = XmlWriter.Create(fs))//TextWriter xwr = new StreamWriter
{
xs.Serialize(xwr, serializeList);//seri
//fs.Close();
}
Console.WriteLine("Succesfully serialized to XML");
}
return serializeList;
The reason why I am calling it here is that I want to add this object again to the xml file.
THe error is that here is an error in XML document (15,27).
My Xml structure
<?xml version="1.0"?>
<ArrayOfSerializeClass xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<SerializeClass>
<creationTime>2013-11-25T09:53:25.3325289+05:30</creationTime>
<fileAction>Renamed</fileAction>
<Properties>
<FileAttributes fileName="validate json.txt">
<fileSize>307</fileSize>
<extension>.txt</extension>
<lastAccessTime>2013-11-25T09:53:25.3325289+05:30</lastAccessTime
<fullPath>C:\serialization\SerializationWithFileWatcher\SerializationWithFileWatcherProj\validate json.txt</fullPath>
</FileAttributes>
</Properties>
</SerializeClass>
</ArrayOfSerializeClass>

What I understand from the code above is that you are trying to extend the current XML, by first reading it as a FileStream and then using an XmlWriter to add some more content to it.
If my understanding is correct, then you are trying to write to the end of an existing XML file, which is not allowed since any XML document can have only one root node. In your case, that root node is ArrayOfSerializeClass.
So, in order to successfully achieve your task, you must append your XML within the root node.
Update:
Possible solution here: how to append a xml file in c#?

Manipulating Word 2007 Document XML in C#

I am trying to manipulate the XML of a Word 2007 document in C#. I have managed to find and manipulate the node that I want but now I can't seem to figure out how to save it back. Here is what I am trying:
// Open the document from memoryStream
Package pkgFile = Package.Open(memoryStream, FileMode.Open, FileAccess.ReadWrite);
PackageRelationshipCollection pkgrcOfficeDocument = pkgFile.GetRelationshipsByType(strRelRoot);
foreach (PackageRelationship pkgr in pkgrcOfficeDocument)
{
if (pkgr.SourceUri.OriginalString == "/")
{
Uri uriData = new Uri("/word/document.xml", UriKind.Relative);
PackagePart pkgprtData = pkgFile.GetPart(uriData);
XmlDocument doc = new XmlDocument();
doc.Load(pkgprtData.GetStream());
NameTable nt = new NameTable();
XmlNamespaceManager nsManager = new XmlNamespaceManager(nt);
nsManager.AddNamespace("w", nsUri);
XmlNodeList nodes = doc.SelectNodes("//w:body/w:p/w:r/w:t", nsManager);
foreach (XmlNode node in nodes)
{
if (node.InnerText == "{{TextToChange}}")
{
node.InnerText = "success";
}
}
if (pkgFile.PartExists(uriData))
{
// Delete template "/customXML/item1.xml" part
pkgFile.DeletePart(uriData);
}
PackagePart newPkgprtData = pkgFile.CreatePart(uriData, "application/xml");
StreamWriter partWrtr = new StreamWriter(newPkgprtData.GetStream(FileMode.Create, FileAccess.Write));
doc.Save(partWrtr);
partWrtr.Close();
}
}
pkgFile.Close();
I get the error 'Memory stream is not expandable'. Any ideas?

I would recommend that you use Open XML SDK instead of hacking the format by yourself.

Using OpenXML SDK 2.0, I do this:
public void SearchAndReplace(Dictionary<string, string> tokens)
{
using (WordprocessingDocument doc = WordprocessingDocument.Open(_filename, true))
ProcessDocument(doc, tokens);
}
private string GetPartAsString(OpenXmlPart part)
{
string text = String.Empty;
using (StreamReader sr = new StreamReader(part.GetStream()))
{
text = sr.ReadToEnd();
}
return text;
}
private void SavePart(OpenXmlPart part, string text)
{
using (StreamWriter sw = new StreamWriter(part.GetStream(FileMode.Create)))
{
sw.Write(text);
}
}
private void ProcessDocument(WordprocessingDocument doc, Dictionary<string, string> tokenDict)
{
ProcessPart(doc.MainDocumentPart, tokenDict);
foreach (var part in doc.MainDocumentPart.HeaderParts)
{
ProcessPart(part, tokenDict);
}
foreach (var part in doc.MainDocumentPart.FooterParts)
{
ProcessPart(part, tokenDict);
}
}
private void ProcessPart(OpenXmlPart part, Dictionary<string, string> tokenDict)
{
string docText = GetPartAsString(part);
foreach (var keyval in tokenDict)
{
Regex expr = new Regex(_starttag + keyval.Key + _endtag);
docText = expr.Replace(docText, keyval.Value);
}
SavePart(part, docText);
}
From this you could write a GetPartAsXmlDocument, do what you want with it, and then stream it back with SavePart(part, xmlString).
Hope this helps!

You should use the OpenXML SDK to work on docx files and not write your own wrapper.
Getting Started with the Open XML SDK 2.0 for Microsoft Office
Introducing the Office (2007) Open XML File Formats
How to: Manipulate Office Open XML Formats Documents
Manipulate Docx with C# without Microsoft Word installed with OpenXML SDK

The problem appears to be doc.Save(partWrtr), which is built using newPkgprtData, which is built using pkgFile, which loads from a memory stream... Because you loaded from a memory stream it's trying to save the document back to that same memory stream. This leads to the error you are seeing.
Instead of saving it to the memory stream try saving it to a new file or to a new memory stream.

The short and simple answer to the issue with getting 'Memory stream is not expandable' is:
Do not open the document from memoryStream.
So in that respect the earlier answer is correct, simply open a file instead.
Opening from MemoryStream editing the document (in my experience) easy lead to 'Memory stream is not expandable'.
I suppose the message appears when one do edits that requires the memory stream to expand.
I have found that I can do some edits but not anything that add to the size.
So, f.ex deleting a custom xml part is ok but adding one and some data is not.
So if you actually need to open a memory stream you must figure out how to open an expandable MemoryStream if you want to add to it.
I have a need for this and hope to find a solution.
Stein-Tore Erdal
PS: just noticed the answer from "Jan 26 '11 at 15:18".
Don't think that is the answer in all situations.
I get the error when trying this:
var ms = new MemoryStream(bytes);
using (WordprocessingDocument wd = WordprocessingDocument.Open(ms, true))
{
...
using (MemoryStream msData = new MemoryStream())
{
xdoc.Save(msData);
msData.Position = 0;
ourCxp.FeedData(msData); // Memory stream is not expandable.

XmlDocument::Save() appends the xml in file

I want to keep a single XmlDocument object in a class and let methods make changes to it and save it.
using (FileStream fs = new FileStream(#"D:\Diary.xml",
FileMode.Open, FileAccess.ReadWrite, FileShare.Read))
{
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(fs);
// ... make some changes here
xmlDoc.Save(fs);
}
The above code makes two copies of the xml structure inside the file.

Try
fs.SetLength(0);
before Save call

Add:
fs.Position = 0;
before the Save call.

It seems a bit strange that fs.Position from Foole's solution didn't work.
An equivalent would be
fs.Seek(0, SeekOrigin.Begin);
Alternatively
instead of using the same filestream:
//OrigPath is the path you're using for the FileReader
System.Xml.XmlWriter writer = System.Xml.XmlWriter.Create(OrigPath);
xmlDoc.Save(writer);
writer.Close();

Alternatively even this would work...
XmlDocument xmlDoc = new XmlDocument( );
xmlDoc.Load( #"D:\Diary.xml" );
//.... make some changes here
XmlText node = xmlDoc.CreateTextNode( "test" );
xmlDoc.DocumentElement.AppendChild( node );
xmlDoc.Save( #"D:\Diary.xml" );