I have a text data. I would like to place the data dynamically to a certain point [Absolute point, it may be (0,0) (10,10) or (100,100)].
Here the problem comes. My requirement is text block's center point should be the base point. How to make it and place it directly on the canvas? [Which means align the absolute point and center point of the textblock]. Because in winforms we can set the alignment property and place it directly. Please check this question .It describes how to move the textblock after placing it on the canvas since actual width can be found.
I have two specific questions
Is it possible to do it in WPF
Is there anyway to find the actual width before placement, in case I can do it as in the other question
Update (Further explanation)::::: This is my Data Template to place the text, I can use TranslateTransform to translate the text as soon as the text is placed on the canvas by using MoveToPoint function mention below.
The real problem come, how to pass the ActualWidth to MoveToPoint inside datatemplate,
XAML
<DataTemplate DataType="{x:Type local:Text}">
<TextBlock Text="{Binding Description}"
FontSize= "{Binding Thickness}"
RenderTransformOrigin="0.5,0.5"
Foreground="#FFF63AFF"
FontWeight="Bold" >
<TextBlock.RenderTransform>
<TransformGroup>
<TranslateTransform X= "{Binding StartPoint.X}" Y= "{Binding StartPoint.Y}" />
<RotateTransform Angle= "{Binding Angle}" />
</TransformGroup>
</TextBlock.RenderTransform>
</TextBlock>
</DataTemplate>
C#
void MoveToPoint(UIElement sender, Point point)
{
Canvas.SetLeft(sender, point.X - sender.RenderTransformOrigin.X * sender.ActualWidth);
Canvas.SetTop(sender, point.Y - sender.RenderTransformOrigin.Y * sender.ActualHeight);
}
Related
I have an WPF usercontrol which is used in a winforms applications. WPF usercontrol is contained within an ElementHost container.
This WPF usercontrol has some images, button with images, labels, etc.
I have a dictionary with some geometries, the following is one of them.
<Geometry x:Key="hlpGeometry">F0 M22,22z M0,0z M11,22C17.0751,22 22,17.0751 22,11 22,4.92487 17.0751,0 11,0 4.92487,0 0,4.92487 0,11 0,17.0751 4.92487,22 11,22z M12.1901,16.6889L10.2662,16.6889 10.2662,18.6998 12.1901,18.6998 12.1901,16.6889z M8.18758,5.59005C7.40125,6.43439,7.00808,7.55265,7.00808,8.94484L8.72898,8.94484C8.76121,8.10695 8.89334,7.46564 9.12537,7.02091 9.53787,6.2217 10.2823,5.82209 11.3587,5.82209 12.2288,5.82209 12.8508,6.05412 13.2246,6.51818 13.6049,6.98224 13.795,7.53009 13.795,8.16173 13.795,8.61291 13.6661,9.04797 13.4083,9.46691 13.2665,9.70539 13.0796,9.9342 12.8475,10.1533L12.0741,10.9171C11.3329,11.6454 10.8527,12.2932 10.6336,12.8604 10.4144,13.4211 10.3049,14.1623 10.3049,15.084L12.0258,15.084C12.0258,14.2719 12.116,13.6596 12.2965,13.2471 12.4834,12.8281 12.8862,12.319 13.505,11.7195 14.3557,10.8945 14.9197,10.2694 15.1969,9.84396 15.4804,9.41857 15.6222,8.86427 15.6222,8.18107 15.6222,7.05314 15.2387,6.12824 14.4718,5.40636 13.7112,4.67804 12.6961,4.31388 11.4263,4.31388 10.0535,4.31388 8.9739,4.73927 8.18758,5.59005z</Geometry>
<DrawingGroup x:Key="hlpDrawingGroup" ClipGeometry="M0,0 V22 H22 V0 H0 Z">
<GeometryDrawing Brush="#FF00AA2B" Geometry="{StaticResource hlpGeometry}" />
</DrawingGroup>
<DrawingImage x:Key="ico_helpDrawingImage" Drawing="{StaticResource hlpDrawingGroup}" />
I have an WPF Image and I bound above DrawingImage to it using the Source attribute. I bind the source attribute to a property in the view model.
Something like below:
<Image x:Name="MyImage"
Height="24"
Width="24"
VerticalAlignment="Center"
Source="{Binding Path=MyIcon}"/>
It is working fine when windows is scaled to 100% but when scaled to a higher one, let's say, 125%, then the image gets fuzzy.
Also the image look like gets bigger than 24x24 and it is being cut-off when I set a scale greater than 100% (125%).
How can I make image to not get fuzzy and set image to always be the same size 24x24?
You can use the UseLayoutRounding and SnapsToDevicePixels properties.
Set the UseLayoutRounding property to true to prevent blurring caused by anti-aliasing and to tell the layout system to align elements with pixel boundaries.
RenderOptions.BitmapScalingMode is mainly for larger images to be displayed more smoothly, you can choose HighQuality.
Use high quality bitmap scaling, which is slower than LowQuality mode, but produces higher quality output.
You can check this link:
https://learn.microsoft.com/en-us/dotnet/api/system.windows.media.bitmapscalingmode?redirectedfrom=MSDN&view=windowsdesktop-7.0
Code：
<Image x:Name="img" MouseWheel="img_MouseWheel"
Height="24"
Width="24"
UseLayoutRounding="True"
SnapsToDevicePixels="True"
VerticalAlignment="Center"
RenderOptions.BitmapScalingMode="HighQuality"
Source="2.jpg"/>
With images I have always found the below to always clear up the fuzzy stuff.
<Image x:Name="MyImage"
Height="24"
Width="24"
RenderOptions.BitmapScalingMode="HighQuality"
VerticalAlignment="Center"
Source="{Binding Path=MyIcon}"/>
I'm trying to create a tile in WPF that looks like the tiles of the Windows 8 Start screen.
Actually, the problem is that I don't know how to make the tilt effect of the Windows 8 tiles ( the click effect ).
I tried different transformations such as matrix transofmration, but this is not what I want.
Explanation in image :
Default style:
Here is my code
<Grid >
<Grid.LayoutTransform>
<MatrixTransform>
<MatrixTransform.Matrix >
<Matrix OffsetX="5" OffsetY="5" M11="1" M12="0.1"></Matrix></MatrixTransform.Matrix>
</MatrixTransform>
</Grid.LayoutTransform>
<Grid.Background>
<ImageBrush ImageSource="/MaCollectivitéWPF;component/src/Img/Home/Porte Document-petite.jpg" Stretch="UniformToFill" >
</ImageBrush>
</Grid.Background>
It's almost what I want but I only want the bottom to be tilted.
I've take a look at the 3D controls but I think it's to complicated for what I'm looking for.
Is there a solution with Layout Transformation I would not have seen yet ?
I think you want to pinch Greg Schechter's Planerator for tilting.
Your use case is exactly the one in the article, so I doubt you'd need to change anything. I've not tried it myself, but it seems to reduce tilting the plane to fairly easy xaml. Worth a look at least.
<pl:Planerator RotationY="35">
<StackPanel Orientation="Horizontal" ... >
<StackPanel>
<Label FontSize="24" Content=" " Foreground="#FF000000"/>
<Border ... >
<MediaElement x:Name="myMediaElement" />
</Border>
</StackPanel>
<ListBox ... />
</StackPanel>
</pl:Planerator>
I resize the border according to timeline. Why when the Width becomes very big the Border disappear. For example for Width=100000 the Border is visible but for Width=200000 the Border disappears.
<StackPanel>
<Border BorderThickness="0,0,0,1" BorderBrush="Black" Height="100" Width="1000000">
</Border>
</StackPanel>
It turns out, that there are some limitations on the Border setting BorderThickness property.
Unfortunately, I can not say exactly how they look, I tried to find them using ILSpy (you can try to look for them am).
One limitation I can say: if the value of one coordinate over 125,000 the line of Border disappears. Here is my list of examples:
Thickness Width
--------- ---------
0,0,0,1 125 001
0,0,0,2 251 000
0,0,0,3 375 001
0,0,0,4 501 000
In all these cases, the line is not drawn.
As an alternative, you can increase the value for Thickness each time (not varinat), or using a Line / Separator, for them, there should be no restrictions. You need to change the value of Margin, depending on conditions or setting the Visibility for him.
Example with Separator:
<Separator Name="HighSignal"
Width="1000000"
Background="Black"
Height="2"
Visibility="Collapsed"
Margin="0,100,0,0" />
<Separator Name="LowSignal"
Width="1000000"
Background="Black"
Height="2"
Visibility="Visible"
Margin="0,0,0,0" />
Note: For Separator you may create a Style, because for him base type a Control (for Line -Shape).
I have a <Grid> which contains some vertical and horizontal <Line>s. I want the grid to be scalable with the window size, and retain its aspect ratio, so it's contained in a <Viewbox Stretch="Uniform">.
However, I also want the lines to always render with a width of 1 pixel, so I use:
Line line = new Line();
line.SetValue(RenderOptions.EdgeModeProperty, EdgeMode.Aliased);
// other line settings here...
This makes the lines' initial appearance ideal, but as soon as you start resizing the window, the stretching/scaling kicks in, and the lines become a mixture of 1 and 2 pixels thick again.
Is there any way to have the lines always be 1 pixel thick and also allow for resizing of the window/grid?
Update - Using path geometry as per Clemens' suggestion
#Clemens - Thanks for highlighting the rendering differences between lines and paths. As I try to rework my code using your example, I'm getting that sinking feeling that I'm digging more holes for myself and not really grasping the entire concept (entirely my fault, not yours, I'm just new to WPF).
I'll add some screenshots to illustrate the following description:
I'm making a game board (for the game of Go, in case that helps understand the layout at all). I have a 9x9 grid, and I'm planning on placing the game pieces by simply adding an ellipse to a particular grid cell.
To draw the underlying lines on the board, however, I need to draw lines intersecting the middle of the cells across the board (in Go, pieces are placed on the intersections, not the middle of the cells).
It could well be that I'm taking entirely the wrong approach, please feel free to tell me to start again down a different route, rather than hacking around within the current structure.
This is how I've done it so far (I'm adding the paths programatically, due to the way the coordinates are calculated. Not sure if it can all be done in XAML):
XAML:
<Grid MinHeight="400" MinWidth="400" ShowGridLines="False" x:Name="boardGrid">
<Grid.Resources>
<ScaleTransform x:Key="transform"
ScaleX="{Binding ActualWidth, ElementName=boardGrid}"
ScaleY="{Binding ActualHeight, ElementName=boardGrid}" />
</Grid.Resources>
<Grid.RowDefinitions>
<RowDefinition></RowDefinition>
<!-- more rows, 9 in total -->
</Grid.RowDefinitions>
<Grid.ColumnDefinitions>
<ColumnDefinition></ColumnDefinition>
<!-- more columns, 9 in total -->
</Grid.ColumnDefinitions>
<!-- example game pieces -->
<Ellipse Stroke="Black" Fill="#333333" Grid.Row="3" Grid.Column="2" />
<Ellipse Stroke="#777777" Fill="#FFFFFF" Grid.Row="4" Grid.Column="4" />
</Grid>
C#:
int cols = 9;
int rows = 9;
// Draw horizontal lines
for (int row = 0; row < rows; row++)
{
var path = new System.Windows.Shapes.Path();
path.Stroke = Brushes.Black;
path.StrokeThickness = 1;
path.SetValue(RenderOptions.EdgeModeProperty, EdgeMode.Aliased);
Grid.SetRow(path, row);
Grid.SetColumnSpan(path, cols);
Grid.SetZIndex(path, -1);
double cellWidth = boardGrid.ColumnDefinitions[0].ActualWidth;
double cellHeight = boardGrid.RowDefinitions[0].ActualHeight;
double x1 = (cellWidth / 2) / boardGrid.ActualWidth;
double y1 = (cellHeight / 2) / boardGrid.ActualHeight;
double x2 = ((cellWidth * cols) - (cellWidth / 2)) / boardGrid.ActualWidth;
double y2 = (cellHeight / 2) / boardGrid.ActualHeight;
path.Data = new LineGeometry(new Point(x1, y1),
new Point(x2, y2),
(ScaleTransform)boardGrid.TryFindResource("transform"));
boardGrid.Children.Add(path);
}
// Similar loop code follows for vertical lines...
This is what I get when using the code above
This is pretty much how I want it to look. It's raised 2 more questions for me:
1) Am I taking the right approach where I'm calculating the x1, x2, y1 and y2 values by diving them by the total board width to create a number between 0 and 1, so that the ScaleTransform can then be applied to them?
2) Now that I'm not using a Viewbox any more, how do I accomplish fixed-ratio scaling? If I enlarge my window, the board stretches out of proportion (see image below). (It doesn't anti-alias the lines any more though, which is great.)
I know this is getting to be a bit of a monolithic post. I'm very grateful for your patience and responses.
A Viewbox can only "visually" scale its child element, including the thickness of any rendered stroke. What you need is a scaling that only applies to the geometry of the lines (or other shapes), but leaves the stroke unaffected.
Instead of using Line objects, you could draw your lines by Path objects that use transformed LineGeometries for their Data property. You could create a ScaleTransform that scales from logical coordinates to viewport coordinates by using the Grid's width and height as scaling factors in x and y direction. Each LineGeometry (or any other Geometry) would use logical coordinates in the range 0..1:
<Grid x:Name="grid">
<Grid.Resources>
<ScaleTransform x:Key="transform"
ScaleX="{Binding ActualWidth, ElementName=grid}"
ScaleY="{Binding ActualHeight, ElementName=grid}"/>
</Grid.Resources>
<Path Stroke="Black" StrokeThickness="1">
<Path.Data>
<LineGeometry StartPoint="0.1,0.1" EndPoint="0.9,0.9"
Transform="{StaticResource transform}"/>
</Path.Data>
</Path>
</Grid>
In order to get a uniform scaling you may simply bind both the ScaleTransform's ScaleX and ScaleY properties to either the ActualWidth or ActualHeight of the Grid:
<Grid x:Name="grid">
<Grid.Resources>
<ScaleTransform x:Key="transform"
ScaleX="{Binding ActualWidth, ElementName=grid}"
ScaleY="{Binding ActualWidth, ElementName=grid}"/>
</Grid.Resources>
...
</Grid>
You may also calculate the uniform scaling factor from the minimum value of the width and height, with a bit of code behind:
<Grid x:Name="grid" SizeChanged="grid_SizeChanged">
<Grid.Resources>
<ScaleTransform x:Key="transform"/>
</Grid.Resources>
...
</Grid>
with a SizeChanged handler like this:
private void grid_SizeChanged(object sender, SizeChangedEventArgs e)
{
var transform = grid.Resources["transform"] as ScaleTransform;
var minScale = Math.Min(grid.ActualWidth, grid.ActualHeight);
transform.ScaleX = minScale;
transform.ScaleY = minScale;
}
I'm trying to rotate this canvas
<Canvas Canvas.Left="203" Canvas.Top="274" Name="canvas1" Height="0" Width="0" >
<Rectangle.LayoutTransform>
<RotateTransform Angle="-45"/>
</Rectangle.LayoutTransform>
I want to rotate this canvas but in the same position.. check this image
The left image I dont want to do that.. I need to create the second one.. but always I need to set X, Y values? Or is there another way?
In WPF, has two properties to support display transformations, LayoutTransform and RenderTransform.Any Transform assigned to LayoutTransform is applied when layout is performed. RenderTransform is applied after layout when rendering is performed.
You need to change the Transformation to RenderTransform
<Rectangle.RenderTransform>
<RotateTransform Angle="-45"/>
</Rectangle.RenderTransform>
You can see the difference between LayoutTransform and RenderTransform.