I am trying to remove the last node from an XML file, but cannot find any good answers for doing this. Here is my code:
XmlReader x = XmlReader.Create(this.PathToSpecialFolder + #"\" + Application.CompanyName + #"\" + Application.ProductName + #"\Recent.xml");
int c = 0;
while (x.Read())
{
if (x.NodeType == XmlNodeType.Element && x.Name == "Path")
{
c++;
if (c <= 10)
{
MenuItem m = new MenuItem() { Header = x.ReadInnerXml() };
m.Click += delegate
{
};
openRecentMenuItem.Items.Add(m);
}
}
}
x.Close();
My XML node structure is as follows...
<RecentFiles>
<File>
<Path>Text Path</Path>
</File>
</RecentFiles>
In my situation, there will be ten nodes maximum, and each time a new one is added, the last must be removed.
You can try this
XmlDocument doc = new XmlDocument();
doc.Load(fileName);
XmlNodeList nodes = doc.SelectNodes("/RecentFiles/File");
nodes[nodes.Count].ParentNode.RemoveChild(nodes[nodes.Count]);
doc.Save(fileName);
It sounds like you want something like:
var doc = XDocument.Load(path);
var lastFile = doc.Descendants("File").LastOrDefault();
if (lastFile != null)
{
lastFile.Remove();
}
// Now save doc or whatever you want to do with it...
Related
I have a string like this { {Name Mike} {age 19} {gender male}} in a txt file.
I would like this to be converted to xml as the below output. As i am new to this, it seems to be pretty doubts for me.
<name>Mike</name>
<age>19</age>
<gender>male</male>
any help would be appreciated.
Here is my solution, at first you have to create a xml file in my case I have created x.xml at my bin folder and must create a root elemnt on the xml file, in my case sample xml at the begening as below, root element name can be anything, I have used just root
<root>
</root>
then code for writting you string as below
string s = "{{Name Mike} {age 19} {gender male}}";
string[] s2 = s.Replace("{", "").Replace("}", "").Split(' ');
for (int i = 0; i < s2.Length; i++)
{
XDocument doc = XDocument.Load("x.xml");
XElement rt = doc.Element("root");
XElement elm = rt.Element(s2[i]);
if (elm != null)
{
elm.SetValue(s2[i + 1]);
}
else
{
XElement x = new XElement(s2[i], s2[i + 1]);
rt.Add(x);
}
doc.Save("x.xml");
i++;
}
hope this will solve your problem
Update
if you want to automate file creation without creating the xml file by hand then you can do this way
string s = "{{Name Mike} {age 19} {gender male}}";
string[] s2 = s.Replace("{", "").Replace("}", "").Split(' ');
if (!File.Exists("x.xml"))
{
TextWriter tw = new StreamWriter("x.xml", true);
tw.WriteLine("<root>\n</root>");
tw.Close();
}
for (int i = 0; i < s2.Length; i++)
{
XDocument doc = XDocument.Load("x.xml");
XElement rt = doc.Element("root");
XElement elm = rt.Element(s2[i]);
if (elm != null)
{
elm.SetValue(s2[i + 1]);
}
else
{
XElement x = new XElement(s2[i], s2[i + 1]);
rt.Add(x);
}
doc.Save("x.xml");
i++;
}
I'm almost getting there, but I need some help.
This is the code that I use to process our XML file. I'm able to find the section that I need to store; I just don't know how to save it.
XmlDocument doc = new XmlDocument();
doc.XmlResolver = null;
doc.Load(#"c:\xml\Sales.xml");
XmlElement root = doc.DocumentElement;
XmlNodeList nodes = root.SelectNodes("nd/ni/nv/noid");
foreach (XmlNode node in nodes)
{
if (node.OuterXml.IndexOf("Server=1,Function=1,Location=") > 0)
{
Console.WriteLine(node.OuterXml);
// This prints out "<noid>Server=1,Function=1,Location=24</noid>"
// How do I read the four <r> nodes within this <noid>?
// The values would be [124, 2, 43, 90]
}
}
The xml looks something like this:
<nd>
<ni>
<nv>
<noid>Managed=1,Network=1,smtp=1</noid>
<r>27</r>
<r>4</r>
</nv>
<nv>
<noid>Managed=1,Network=1,Ibc=1</noid>
<r>8</r>
<r>2</r>
</nv>
<nv>
<noid>Server=1,Function=1,Location=24</noid>
<r>124</r>
<r>2</r>
<r>43</r>
<r>90</r>
</nv>
<nv>
<noid>Unmanaged=9,Label=7,Place=5</noid>
<r>10</r>
<r>20</r>
</nv>
</ni>
</nd>
Console.WriteLine prints the correct <noid> text, so I know that I've already found the section with the relevant data.
My question is, how can I read the four <r> inside this <noid>? Ideally, within the IF statement, how can I read all the <r> elements that are between the <nv></nv>?
Thanks.
Using Linq-to-xml
var xmlText = File.ReadAllText(#"C:\YourDirectory\YourFile.xml");
var xDoc = XDocument.Parse(xmlText);
var rValues = new List<string>(); //THIS IS YOUR RESULT
var nvNodes = xDoc.Descendants("nv");
foreach(var el in nvNodes)
{
if (el.Element("noid").Value.Contains("Server=1,Function=1,Location="))
rValues = el.Elements("r").Select(e => e.Value).ToList();
}
Or, replacing the foreach with Linq (fails if First() is not satisfied)
var rValues = nvNodes.
First(nv => nv.Value.Contains("Server=1,Function=1,Location="))
.Elements("r")
.Select(r => r.Value);
A non-optimized, non-linq solution
XmlDocument doc = new XmlDocument();
doc.XmlResolver = null;
doc.Load(#"C:\YourDirectory\YourFile.xml");
var rValues = new List<string>(); //THIS IS YOUR RESULT
XmlElement root = doc.DocumentElement;
XmlNodeList nodes = root.SelectNodes("//nd/ni/nv");
foreach (XmlNode node in nodes)
{
if (node.FirstChild.InnerText.Contains("Server=1,Function=1,Location="))
{
foreach(XmlNode childnode in node.ChildNodes)
{
if (childnode.Name == "r")
rValues.Add(childnode.InnerText);
}
}
}
Try this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string input =
"<nd>" +
"<ni>" +
"<nv>" +
"<noid>Managed=1,Network=1,smtp=1</noid>" +
"<r>27</r>" +
"<r>4</r>" +
"</nv>" +
"<nv>" +
"<noid>Managed=1,Network=1,Ibc=1</noid>" +
"<r>8</r>" +
"<r>2</r>" +
"</nv>" +
"<nv>" +
"<noid>Server=1,Function=1,Location=24</noid>" +
"<r>124</r>" +
"<r>2</r>" +
"<r>43</r>" +
"<r>90</r>" +
"</nv>" +
"<nv>" +
"<noid>Unmanaged=9,Label=7,Place=5</noid>" +
"<r>10</r>" +
"<r>20</r>" +
"</nv>" +
"</ni>" +
"</nd>";
XElement nd = XElement.Parse(input);
var results = nd.Descendants("nv").Select(x => new
{
noid = (string)x.Element("noid"),
r = x.Elements("r").Select(y => (int)y).ToList()
}).ToList();
}
}
}
A short, but difficult to understand XPath expression:
XmlNodeList rNodes = root.SelectNodes(
"nd/ni/nv[noid/text()[contains(.,'Server=1,Function=1,Location=')]]/r");
foreach (XmlNode rNode in rNodes)
Console.WriteLine(rNode.InnerText);
Hi you is it possible to create a dynamica xml with xdocument I've been trying but it appears that it returns an exception about having a wrong structure
My code is the following
public string ReadTest(Stream csvFile)
{
XDocument responseXml = new XDocument( new XDeclaration("1.0", "utf-8", "yes"));
try
{
if ( csvFile != null || csvFile.Length!=0)
{
responseXml.Add(new XElement("root"));
//using(CsvFileReader reader=new CsvFileReader(File.OpenRead(#"C:\Users\toshibapc\Documents\Visual Studio 2013\Projects\WCFLecturaCSV\WCFLecturaCSV\App_Data\archivo.csv"))){
using (CsvFileReader reader = new CsvFileReader(csvFile))
{
CsvRow row = new CsvRow();
List<String> headers = new List<string>();
while (reader.ReadRow(row))
{
int cont = 0;
XElement dato = new XElement("AccountInfos", new XElement("Info"));
XElement datos=null;
foreach (String s in row)
{
if(s.Equals("AccountIDToMove", StringComparison.OrdinalIgnoreCase)|| s.Contains("AccountNameToMove") || s.Contains("NewParentAccountID") || s.Contains("NewParentAccountName")){
headers.Add(s);
}
else{
if (s != String.Empty)
{
datos = new XElement(headers[cont], s); //.Append("<" + headers[cont] + ">" + s + "<" + headers[cont] + "/>");
dato.Add(datos);
}
}
cont++;
}
if (headers.Count == 4 && datos != null)
responseXml.Add(dato);
} // fin de while
}
} // Check if no file i sent or not info on file
}
catch (Exception ex) {
//oError = ex.Message;
}
return responseXml.ToString();
}
What i would like to acomplish by using this code is to get an xml like this
<xml version="1.0">
<root>
<AccountInfos>
<Info>
<AccountIDToMove>312456</AccountIDToMove>
<AccountNameToMove>Burger Count</AccountNameToMove>
<NewParentAccountID>453124</NewParentAccountID>
<NewParentAccountName> Testcom sales 1</NewParentAccountName>
</Info>
<Info>
<AccountIDToMove>874145</AccountIDToMove>
<AccountNameToMove>Mac Count</AccountNameToMove>
<NewParentAccountID>984145</NewParentAccountID>
<NewParentAccountName> Testcom sales 1</NewParentAccountName>
</Info>
</AccountInfos>
</root>
For any answer or help thank you so much
You are adding multiple roots to your document. You initially add one here:
responseXml.Add(new XElement("root"));
And later add more root elements in a loop here:
responseXml.Add(dato);
However, each XML document must have exactly one single root element. Thus you probably want to do:
responseXml.Root.Add(dato);
I have created a small XML tool which gives me count of specific XML tags from multiple XML files.
The code for this is as follow:
public void SearchMultipleTags()
{
if (txtSearchTag.Text != "")
{
try
{
//string str = null;
//XmlNodeList nodelist;
string folderPath = textBox2.Text;
DirectoryInfo di = new DirectoryInfo(folderPath);
FileInfo[] rgFiles = di.GetFiles("*.xml");
foreach (FileInfo fi in rgFiles)
{
int i = 0;
XmlDocument xmldoc = new XmlDocument();
xmldoc.Load(fi.FullName);
//rtbox2.Text = fi.FullName.ToString();
foreach (XmlNode node in xmldoc.GetElementsByTagName(txtSearchTag.Text))
{
i = i + 1;
//
}
if (i > 0)
{
rtbox2.Text += DateTime.Now + "\n" + fi.FullName + " \nInstance: " + i.ToString() + "\n\n";
}
else
{
//MessageBox.Show("No Markup Found.");
}
//rtbox2.Text += fi.FullName + "instances: " + str.ToString();
}
}
catch (Exception)
{
MessageBox.Show("Invalid Path or Empty File name field.");
}
}
else
{
MessageBox.Show("Dont leave field blanks.");
}
}
This code returns me the tag counts in Multiple XML files which user wants.
Now the same I want to Search for particular text and its count present in XML files.
Can you suggest the code using XML classes.
Thanks and Regards,
Mayur Alaspure
Use LINQ2XML instead..It's simple and a complete replacement to othe XML API's
XElement doc = XElement.Load(fi.FullName);
//count of specific XML tags
int XmlTagCount=doc.Descendants().Elements(txtSearchTag.Text).Count();
//count particular text
int particularTextCount=doc.Descendants().Elements().Where(x=>x.Value=="text2search").Count();
System.Xml.XPath.
Xpath supports counting: count(//nodeName)
If you want to count nodes with specific text, try count(//*[text()='Hello'])
See How to get count number of SelectedNode with XPath in C#?
By the way, your function should probably look something more like this:
private int SearchMultipleTags(string searchTerm, string folderPath) { ...
//...
return i;
}
Try using XPath:
//var document = new XmlDocument();
int count = 0;
var nodes = document.SelectNodes(String.Format(#"//*[text()='{0}']", searchTxt));
if (nodes != null)
count = nodes.Count;
I have a bunch of XPathExpressions that I used to read an XML file. I now need go the other way. (Generate an XML file based on the values I have.)
Here is an example to illustrate. Say I have a bunch of code like this:
XPathExpression hl7Expr1 = navigator.Compile("/ORM_O01/MSH/MSH.6/HD.1");
var hl7Expr2 = navigator.Compile("/ORM_O01/ORM_O01.PATIENT/PID/PID.18/CX.1");
var hl7Expr3 = navigator.Compile("/ORM_O01/ORM_O01.PATIENT/ORM_O01.PATIENT_VISIT/PV1/PV1.19/CX.1");
var hl7Expr4 = navigator.Compile("/ORM_O01/ORM_O01.PATIENT/PID/PID.3[1]/CX.1");
var hl7Expr5 = navigator.Compile("/ORM_O01/ORM_O01.PATIENT/PID/PID.5[1]/XPN.1/FN.1");
var hl7Expr6 = navigator.Compile("/ORM_O01/ORM_O01.PATIENT/PID/PID.5[1]/XPN.2");
string hl7Value1 = "SomeValue1";
string hl7Value2 = "SomeValue2";
string hl7Value3 = "SomeValue3";
string hl7Value4 = "SomeValue4";
string hl7Value5 = "SomeValue5";
string hl7Value6 = "SomeValue6";
Is there a way to take the hl7Expr XPathExpressions and generate an XML file with the corresponding hl7Value string in it?
Or maybe just use the actual path string to do the generation (instead of using the XPathExpression object)?
Note: I saw this question: Create XML Nodes based on XPath? but the answer does not allow for [1] references like I have on hl7Expr4.
I found this answer: https://stackoverflow.com/a/3465832/16241
And I was able to modify the main method to convert the [1] to attributes (like this):
public static XmlNode CreateXPath(XmlDocument doc, string xpath)
{
XmlNode node = doc;
foreach (string part in xpath.Substring(1).Split('/'))
{
XmlNodeList nodes = node.SelectNodes(part);
if (nodes.Count > 1) throw new ApplicationException("Xpath '" + xpath + "' was not found multiple times!");
else if (nodes.Count == 1) { node = nodes[0]; continue; }
if (part.StartsWith("#"))
{
var anode = doc.CreateAttribute(part.Substring(1));
node.Attributes.Append(anode);
node = anode;
}
else
{
string elName, attrib = null;
if (part.Contains("["))
{
part.SplitOnce("[", out elName, out attrib);
if (!attrib.EndsWith("]")) throw new ApplicationException("Unsupported XPath (missing ]): " + part);
attrib = attrib.Substring(0, attrib.Length - 1);
}
else elName = part;
XmlNode next = doc.CreateElement(elName);
node.AppendChild(next);
node = next;
if (attrib != null)
{
if (!attrib.StartsWith("#"))
{
attrib = " Id='" + attrib + "'";
}
string name, value;
attrib.Substring(1).SplitOnce("='", out name, out value);
if (string.IsNullOrEmpty(value) || !value.EndsWith("'")) throw new ApplicationException("Unsupported XPath attrib: " + part);
value = value.Substring(0, value.Length - 1);
var anode = doc.CreateAttribute(name);
anode.Value = value;
node.Attributes.Append(anode);
}
}
}
return node;
}