I want to close two forms at the same time. I have one main form that starts with program. when user click button, the main form will hide and other form will pop up. on the second form if user click "back to main " button, it should hide second form and show main form. But the problem is if user tries to close the second form it should close the main form as well. How can i close the main form as well
I would just use the Application.Exit() for what is requested by this thread.
Application.Exit();
UPDATE: corrected
I had said this will not call the form closing events but in documentation it does actually call it here is a link to the documentation
http://msdn.microsoft.com/en-us/library/ms157894(v=vs.110).aspx
It was better if you specified what codes you wrote for going back to main form, so I could help you by changing your codes. But now because I don't know how you did it, I have to write codes for both of those tasks.
It can be possible using a Boolean variable to do what you want. Follow bellow codes:
public partial class MainForm : Form
{
//"Click" event of the button that should opens the second form:
private void goToSecondForm_Click(object sender, EventArgs e)
{
Form2 f2 = new Form2(); //Or you can write it out of this method.
this.Hide(); //Hides the main form.
f2.ShowDialog(); // Shows the second form.
this.Show(); // Shows the main form again, after closing the second form using your own button.
}
}
public partial class Form2 : Form
{
bool selfClose = false; //False shows that user closed the second form by default button and true shows that user closed it by your own button.
//"Click" event of the button that should closes just the second form and returns user to the main form:
private void ownCloseButton_Click(object sender, EventArgs e)
{
selfClose = true; //Means user clicked on your own button.
this.Close(); //So the program closes the second form and runs f2_FormClosed method, but because selfClose became true here, happened nothing there and program will go back to goToSecondForm_Click method in the main form and will run this.Show() .
}
//"FormClosed" event of the second form :
//Whether user clicked on your own button or on the default one, this method will run.
private void f2_FormClosed(object sender, FormClosedEventArgs e)
{
if (!selfClose) //It means user didn't click on your own button and both of forms must be closed .
Application.Exit(); //So the program closes all of forms (actually closes the program) and couldn't access to any other commands (including this.Show() in goToSecondForm_Click method).
}
}
As others have said, you need to somehow call .Close() on the main form when your child form is closed. However, as you've pointed out, you don't have a reference to the main form automatically in your child form! That leaves you with a few options.
1. Exit the application immediately.
This is done by calling Application.Exit(); in your child form's "back to main" button's click event handler. It will immediately close all forms, which might simply be what you want.
// .. ChildForm code ..
void OnBackToMainClicked(object sender, EventArgs e)
{
Application.Exit();
}
2. Pass a reference to the main form to the child form.
This is probably the most common way to solve this problem in general. When you create your child form in your main form, you'll need to pass a reference as follows:
// .. MainForm code ..
void OnGoToChildForm(object sender, EventArgs e)
{
var childForm = new ChildForm(this);
childForm.Show();
}
// .. ChildForm code ..
private MainForm mainForm; // This is where the child form will keep a reference to
// the main form that you can use later
public ChildForm(MainForm mainForm)
{
// This is the child form's constructor that we called above,
// and it's where we'll save the reference to the main form
this.mainForm = mainForm;
}
// This also needs to be the event handler for the close event
void OnBackToMainClicked(object sender, EventArgs e)
{
this.Close();
mainForm.Close();
}
3. Add an event handler on the child form's FormClosed event. This is a safe way to solve the problem if you are concerned about keeping your main application logic under the control of the main form. It's similar to the solution suggested by Lamloumi above, but it's all done in the main form's code.
// .. MainForm code ..
void OnGoToChildForm(object sender, EventArgs e)
{
var childForm = new ChildForm(this);
childForm.FormClosed += new FormClosedEventHandler(SecondForm_FormClosed);
childForm.Show();
}
void SecondForm_FormClosed(object sender, EventArgs e)
{
// Perform any final cleanup logic here.
this.Close();
}
Form1 _FirstForm = New Form1();
Form2 _SecondForm = New Form2();
MainForm _MainForm = new MainForm();
_FirstForm.Close();
_SecondForm.Close();
_MainForm.Show();
Normally , in the Home form you have some ting like this :
SecondForm second= new SecondForm ();
second.Show();
this.Hide();
In the SecondForm you must ovveride the event of closure like this :
public class SecondForm :Form{
public SecondForm()
{
InitializeComponent();
this.FormClosed += new FormClosedEventHandler(SecondForm_FormClosed);
}
void SecondForm_FormClosed(object sender, FormClosedEventArgs e)
{
Application.Exit();
}
}
To be sure that your application is closed after you close the form. because the Home from is still active and hidden if you don't.
use this in Form2
private void button1_Click(object sender, EventArgs e)
{
Form1.FromHandle(this.Handle);
}
There Handle are the same now ;
hope this work.
Related
well I have a funny problem with closing dialog forms.
here is the problem:
I run application and open second form (through menu strip) as showdialog(); and then from second form open third form. When I open third form by button 1 and then close it everything is alright, but when I open the third form by button 2 and then close it, third form will be closed and then it closes the second form also. !!! In second form when I show a messageBox and close it also the second form will be closed.
here is my codes:
open second form from first form codes:
private void settingsToolMenu_Click(object sender, EventArgs e)
{
settingsForm s1 = new settingsForm(this);
s1.ShowDialog();
}
open third form from second by button 1 form codes:
private void addReportButton_Click(object sender, EventArgs e)
{
addReport a1 = new addReport(this);
a1.ShowDialog();
}
open third form from second by button 2 form codes:
private void editReportButton_Click(object sender, EventArgs e)
{
addReport a2 = new addReport(this);
a2.ShowDialog();
}
as you see there is no differences between button 1 and button 2
here is a video from application running.
Not sure what's happening out there, but there should be .Show() method, which runs a window in a different way including closing strategy. Try it out.
Try This
Instead of
addReport a2 = new addReport(this);
a2.ShowDialog();
Use
addReport a2 = new addReport();
a2.ShowDialog(this);
Then on click of Exit / Close button of dialog window
private void BtnExit_Click(object sender, EventArgs e)
{
this.Dispose();
}
Hope this will solve your issue.
I used this code and it worked. I have 3 forms, the first form is opened when running the app, the second form is opened with a button (can be menustrip, doesn't matter), then the third is opened like that too, after closing the third form the second form remains open.
FormN fm = new FormN();
fm.ShowDialog();
Use that piece of code in every method that is called from clicking on a button and it should work fine. Just change the "FormN" for whatever your forms are named. Also, if you need to pass any form's attributes into the next form you can do this:
Code at first form:
public string mytext; //Variable I want to use later, in Form2.
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
mytext = tb1.Text;
Form2 fm = new Form2(this);
fm.ShowDialog();
}
Notice how I save "tb1"'s (TextBox1) value in a variable before calling "fm.ShowDialog();", so I can use the TextBox1 value later inside the Form2.
Code at second form, having main form's variables (such as "mytext" value).
Form1 mfm;
public Form2(Form1 mainfm)
{
InitializeComponent();
mfm = mainfm;
}
public void button2_Click(object sender, EventArgs e)
{
//In this method I use the variable "mytext" wich is a Form1 attribute.
//You can see how I declare it in the first form's code (see above).
textBox1.Text = mfm.mytext;
}
With this you have created an object of your main form ("Form1 mfm;") with all the variables it contained before calling the second form, which can be used for the third form too.
in second form formClosing() event i wrote these codes:
private void settingsForm_FormClosing(object sender, FormClosingEventArgs e)
{
if(e.CloseReason != CloseReason.UserClosing)
{
e.Cancel = true;
}
}
and nothing can close the second form except user!
So basically I have two User Control
1.Maptab.cs
2.TransactionTab.cs
And a Main menu.
So I have a button in main menu and when click it calls the maptab.cs, and in maptab.cs I have a button named btnbuy. So what I want to do is to call the transactiontab.cs or bring to front in the main menu when the button btnbuy in the maptab.cs is clicked.
I tried it like this in maptab.cs:
private void btnBuy_Click(object sender, EventArgs e)
{
Mainmenu main = new Mainmenu();
main.transactionTab1.BringToFront();
}
and it was not working. And also I'm gonna pass some values from maptab to transactiontab.
After creating an instance of form, just use Show() or ShowDialog() to display your desired form.
For example,
private void button1_Click(object sender, EventArgs e)
{
Form2 secondform = new Form2();
secondform.value = 33; //"value" variable must be declared as public in Form2
secondform.Show(); //Use secondform.ShowDialog(); to prevent user from entering main form without closing Form2.
}
I've looked at all the suggested answers and nothing seems to fit what I'm looking for. I want to call a second form from my main form, hide my main form while the second form is active, and then unhide the main form when the second form closes. Basically I want to "toggle" between the two forms.
So far I have:
In my main form:
private void countClick(object sender, EventArgs e)
{
this.Hide();
subForm myNewForm = new subForm();
myNewForm.ShowDialog();
}
and in my second form I have:
private void totalClick(object sender, EventArgs e)
{
this.Close();
}
How do I get the main form to show?
ShowDialog opens your secondary Form as Modal Dialog, meaning that the MainForm's code execution will stop at that point and your secondary Form will have the focus. so all that you need to do is put a this.Show after your ShowDialog call.
From above link:
You can use this method to display a modal dialog box in your application. When this method is called, the code following it is not executed until after the dialog box is closed.
private void countClick(object sender, EventArgs e)
{
this.Hide();
subForm myNewForm = new subForm();
myNewForm.ShowDialog();
this.Show();
}
Let's say in Form1 you click a Button to show Form2
Form2 frm2 = new Form2();
frm2.Activated += new EventHandler(frm2_Activated); // Handler when the form is activated
frm2.FormClosed += new FormClosedEventHandler(frm2_FormClosed); // Hander when the form is closed
frm2.Show();
Now, this one is when the Form2 is shown or is Activated you hide the calling form, in this case the Form1
private void frm2_Activated(object sender, EventArgs e)
{
this.Hide(); // Hides Form1 but it is till in Memory
}
Then when Form2 is Closed it will Unhide Form1.
private void frm2_FormClosed(object sender, FormClosedEventArgs e)
{
this.Show(); // Unhide Form1
}
This is difficult to do correctly. The issue is that you must avoid having no window at all that can get the focus. The Windows window manager will be forced to find another window to give the focus to. That will be a window of another application. Your window will disappear behind it.
That's already the case in your existing code snippet, you are hiding your main window before showing the dialog. That usually turns out okay, except when the dialog is slow to create. It will definitely happen when the dialog is closed.
So what you need to do is hide your window after you display the dialog and show it again before the dialog closes. That requires tricks. They look like this:
private void countClick(object sender, EventArgs e)
{
this.BeginInvoke(new Action(() => this.Hide()));
using (var dlg = new subForm()) {
dlg.FormClosing += (s, fcea) => { if (!fcea.Cancel) this.Show(); };
if (dlg.ShowDialog() == DialogResult.OK) {
// etc...
}
}
}
The BeginInvoke() call is a trick to get code to run after the ShowDialog() method runs. Thus ensuring your window is hidden after the dialog window is shown. The FormClosing event of the dialog is used to get the window to be visible again just before the dialog closes.
You need to find some way to pass a reference to the main form to the second form click event handler.
You can do this either by setting the form as a member variable of the second form class or pass it via the event arguments.
If you are working in the same namespace, you have the context, using mainform or the name you gave the "main form", try:
mainform.show();
I have a C# application in which I need specific or a function to execute on a form after closing the active form.
The form in which I need the code to excute becomes the active form after the previous active form is closed. So in a nutshell after closing this form the form in which I need the event handler or function to run will then become the active form. Is there a way that this is possible?
I have tried the Form_Enter event handler on the form that becomes active after the other form is closed, but that did not work.
I believe you can achieve what you are trying to do more simply. The code you use to show Form2 from Form1 (Main), you can add your code there like so:
Class Form1 {
private void button_click(object sender, EventArgs e) {
Form2 newForm = Form2();
newForm.ShowDialog(); // To prevent the main form carry on
// Your code needed to be excuted
}
}
In the form closing event set the DialogResult as follows:
private void Form1_FormClosing(object sender, FormClosingEventArgs e)
{
this.DialogResult = System.Windows.Forms.DialogResult.Yes;
}
When you open the form look for the response as follows:
if (Form1.ShowDialog() == DialogResult.Yes)
{
////do stuff.
}
I hope this helps.
i got 2 forms 1mdiparent, 1child
lets say mdiparent = Form1 then child = Form2 .
i got New button in Form1 calling childform (Form2) like:
private void newDocument_ItemClick(object sender, ClickEventArgs e)
{
Form2 formChild = new Form2();
Form2.Show()
}
now my question was whats the if else condition for : if Form2 == Close?
something like:
if (Form2.Close == true){ //condition }
or if (Form2 == Close){ //condition }
but i know its not the right code .so hope you could help me :) thanks .
If I understand your question correctly, you want to be notified by the system when the Form2 is closed so you could apply some internal logic to avoid the reopening of the child form and apply some kind of changes to your main interface.
If this is your problem then you could add your event handler for the FormClosing event of the Form2 directly in the code of Form1 when you open the Form2
// Flag to keep the state open/close of the child form
private bool childClosed = true;
private void newDocument_ItemClick(object sender, ClickEventArgs e)
{
if(childClosed == true)
{
Form2 formChild = new Form2();
// Setup the event handler form the Form2 closing directly here in the MDI
formChild.FormClosing += new FormClosingEventHandler(myFormClosing);
formChild.Show();
// set the flag to avoid the reopening
childClosed = false;
}
}
// Now, when the formChild closes, you will receive the event directly here in the MDI
private void myFormClosing(object sender, FormClosingEventArgs e)
{
// The child form is closing......
// Do your update here, but first check the close reason
if(e.CloseReason == CloseReason.UserClosing)
{
......
// reset the flag so you could reopen the child if needed
childClosed = true;
}
}
You will probably want to use either the Form.FormClosed event or the Form.FormClosing event. Probably the former since you don't really want to interact with the closing of the form.
You would create a method and have it called when the event is fired and this would do whatever you wanted (such as hide buttons and such like).
See http://msdn.microsoft.com/en-us/library/system.windows.forms.form.formclosed.aspx for details of the formclosed event.
When a form is closed, it's disposed too. Thus just check if it's disposed by following code:
Form2 formChild = new Form2();
// ...
if (formChild.IsDisposed) {
// Do someting
}
As #V4Vendetta pointed out: there is a FormClosing event (called before the form has closed. Used to tell the user "You haven't saved yet") and a FormClosed event (called after the form closed).
public class Form2 : Form
{
public bool hasClosed;
private void Form2_FormClosed(object sender, FormClosedEventArgs e)
{
hasClosed = true;
}
}
with this, you can do
if (formChild.hasClosed)
// do something
It is wrong to take this approach, the Form 2 is initialized in the button click event, therefore, you assume that the form object was not available.
if you want to change this order, then the form should be initialized somewhere else like the constructor of the Form 1.
private Form2 form2;
public Form1()
{
form2 = new Form2();
}
private void newDocument_ItemClick(object sender, ClickEventArgs e)
{
if(!form2.Visible)
{
form2.Show();
}else
{
form2.Hide();
}
}
Hiding a form is not same as closing a form, if you really open and close the form2 and carry out some action based on that, then you should set a property on the parent form when the form2 closing event is triggered, to do this you must pass the parent form as an argument in the form2 constructor.
You can check that with the help of the following code
foreach (Form f in Application.OpenForms)
{
if (f.Text == formName)
{
IsOpen = true;
break;
}
}
if(!IsOpen)
{....do your code....}