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RegEx for string starts with number and followed by + character

I want a regular expression for such inputs:
1+2
3
1+22+3
But If I write following inputs then it should not allow. Such as;
+1+2
1+
a+1+b+c
12+
The string must start with number and then followed by only + character. But After the + character, it has to be any number.
I tried this [^0-9][^+]? but İt deletes the + sign at the start with the regex I wrote, but there is a problem. While deleting the + character, it also removes the number next to it. This event keeps repeating.
How can I do this?

Please try :
\d+(\+\d)*
Demo: https://regex101.com/r/hfqmYr/2
Where:
\d -> Matches with any digit
+ -> Matches a symbol one or more times
* -> Matching a symbol 0 or many times

As mentioned in the comments, it looks like you can use:
^[0-9]+(?:\+[0-9]+)*$
This is to allow the mentioned sample data and discard those you don't want to allow. See an online demo. The pattern matches:
^ - Start line anchor.
[0-9]+ - 1+ Digits (ASCII).
(?:\+[0-9]+)* - 0+ Times a non-capture group to allow for a literal plus followed by 1+ digits (ASCII).
$ - End line anchor.
As per my knowledge .NET requires you to explicitly mention these ASCII digits to avoid matching numbers from other languages (unless specified otherwise using ECMAScript options).

How to validate Regex

Im having a hard time with grouping parts of a Regex. I want to validate a few things in a string that follows this format: I-XXXXXX.XX.XX.XX
Validate that the first set of 6 X's (I-xxxxxx.XX.XX.XX) does not contain characters and its length is no more than 6.
Validate that the third set of X's (I-XXXXXX.XX.xx.XX) does not contain characters and is only 1 or 2.
Now, I have already validation on the last set of XX's to make sure the numbers are 1-8 using
string pattern1 = #"^.+\.(0?[1-8])$";
Match match = Regex.Match(TxtWBS.Text, pattern1);
if (match.Success)
;
else
{ errMessage += "WBS invalid"; errMessage +=
Environment.NewLine; }
I just cant figure out how to target specific parts of the string. Any help would be greatly appreciated and thank you in advance!

You're having some trouble adding new validation to this string because it's very generic. Let's take a look at what you're doing:
^.+\.(0?[1-8])$
This finds the following:
^ the start of the string
.+ everything it can, other than a newline, basically jumping the engine's cursor to the end of your line
\. the last period in the string, because of the greedy quantifier in the .+ that comes before it
0? a zero, if it can
[1-8] a number between 1 and 8
()$ stores the two previous things in a group, and if the end of the string doesn't come after this, it may even backtrace and try the same thing from the second to last period instead, which we know isn't a great strategy.
This ends up matching a lot of weird stuff, like for example the string The number 0.1
Let's try patterning something more specific, if we can:
^I-(\d{6})\.(\d{2})\.(\d{1,2})\.([1-8]{2})$
This will match:
^I- an I and a hyphen at the start of the string
(\d{6}) six digits, which it stores in a capture group
\. a period. By now, if there was any other number of digits than six, the match fails instead of trying to backtrace all over the place.
(\d{2})\. Same thing, but two digits instead of six.
(\d{1,2})\. Same thing, the comma here meaning it can match between one and two digits.
([1-8]{2}) Two digits that are each between 1 and 8.
$ The end of the string.
I hope I understood what exactly you're trying to match here. Let me know if this isn't what you had in mind.

This regex:
^.-[0-9]{6}(\.[1-8]{1,2}){3}$
will validate the following:
The first character can be any character, but is of length 1
It is followed by a dash
The dash is followed by exactly 6 numbers 0 - 9. (If this could be less than 6 characters - for example, between 3 and 6 characters - just replace {6} with {3,6}).
This is followed by 3 groups of characters. Each of this groups are proceeded by a period, are of length 1 or 2, and can be any number 1 - 8.
An example of a valid string is:
I-587954.12.34.56
This is also valid:
I-587954.1.3.5
But this isn't:
I-587954.12.80.356
because the second-to-last group contains a 0, and because the last group is of length 3.
Pleas let me know if I have misunderstood any of the rules.

^I-([0-9]{1,6})\.(.{1,2})\.(0[1-2])\.(.{1,2})$
groups delimited by . (\.) :
([0-9]{1,6}) - 1-6 digits
(.{1,2}) - 1-2 any single character
(0[1-2]) - 01 or 02
(.{1,2}) - 1-2 any single character
you can write and easy test regex on your input data, just google "regex online"

Repeating pattern matching with Regex

I am trying to validate an input with a regular expression. Up until now all my tests fail and as my experience with regex is limited I thought someone might be able to help me out.
Pattern: digit (possibly "," digit) (possibly ;)
A String may not begin with a ; and not end with a ;.
Digits are allowed to stand alone or with
My regEx (not working): ((\d)(,\d)?)(;?) the problem is it does not seem to check until the end of the string. Also the optional parts are giving me headaches.
Update: ^[0-9]+(,[0-9])?(;[0-9]+(,[0-9])?)+$this seems to work better but it does not match the single digit.
OK:
2,3;4,4;3,2
2,3
2
2,3;3;4,3
NOK:
2,3,,,,
2,3asfafafa
;2,3
2,3;;3,4
2,3;3,4;

Your ^[0-9]+(,[0-9])?(;[0-9]+(,[0-9])?)+$ regex matches 1 or more digits, then an optional sequence of , and 1 digit, followed with one or more similar sequences.
You need to match zero or more comma-separated numbers:
^\d+(?:,\d+)?(?:;\d+(?:,\d+)?)*$
^
See the regex demo
Now, tweaking part:
If only single-digit numbers should be matched, use ^\d(?:,\d)?(?:;\d(?:,\d)?)*$
If the comma-separated number pairs can have the second element empty, add ? after each ,\d (if single digit numbers are to be matched) or * (if the numbers can have more than one digit): ^\d(?:,\d?)?(?:;\d(?:,\d?)?)*$ or ^\d+(?:,\d*)?(?:;\d+(?:,\d*)?)*$.

Regex validation in ASP.Net MVC

In my demo MVC Application I have the following validation rules for validating my domain model classes.
RuleFor(m => m.Password)
.Matches(#"^(?=(\d){2,})(?=([a-z])+)(?=(\.\$\~\&)*)").WithMessage("Password should contain at least 2 digits");
But the password validation fails .
Basically I want to validate that a password input value should at least contain 2 digits, at least either one of the special characters (.$~&) and at least one alphabet in any order.
They can appear in any order.
Basically I should match the strings like
'a2ss1~A33',
'678.&aA88'
but not
'aaa2sfhdjkf^',
'aass'.
Also I just came across lookahead s in regex.
I still have a doubt why cant just we have the rule for validating the password field ?
.Matches(#"^((\d){2,})(.*[a-zA-Z])([\.\$\~\&]*)").WithMessage("Password should contain at least 2 digits");
When to use lookaheads in regex and when not to ?

You can use
^(?=(\D*\d){2})(?=[^A-Za-z]*[A-Za-z])(?=[^.$~&]*[.$~&]).*
See the regex demo.
The regex matches:
^ - start of string
(?=(\D*\d){2}) - 2 digits anywhere in the string are required
(?=[^A-Za-z]*[A-Za-z]) - an ASCII letter is required somewhere in a string
(?=[^.$~&]*[.$~&]) - the symbol from the [.$~&] set is required
.* - (optional, remove if full string match is not required) matches all characters other than a newline up to the end of the line
Lookaheads enable several checks from the same position in string (here, at the very beginning as they are all placed right after ^). The regex ^((\d){2,})(.*[a-zA-Z])([\.\$\~\&]*) requires 2 or more digits at the beginning, followed with any 0+ characters other than a newline followed with 1 letter followed with 0+ some special symbols. There can be anything else after that, since you are not checking the end of the string.

Explain the Regex mentioned

Can any one please explain the regex below, this has been used in my application for a very long time even before I joined, and I am very new to regex's.
/^.*(?=.{6,10})(?=.*[a-zA-Z].*[a-zA-Z].*[a-zA-Z].*[a-zA-Z])(?=.*\d.*\d).*$/
As far as I understand
this regex will validate
- for a minimum of 6 chars to a maximum of 10 characters
- will escape the characters like ^ and $
also, my basic need is that I want a regex for a minimum of 6 characters with 1 character being a digit and the other one being a special character.

^.*(?=.{6,10})(?=.*[a-zA-Z].*[a-zA-Z].*[a-zA-Z].*[a-zA-Z])(?=.*\d.*\d).*$
^ is called an "anchor". It basically means that any following text must be immediately after the "start of the input". So ^B would match "B" but not "AB" because in the second "B" is not the first character.
.* matches 0 or more characters - any character except a newline (by default). This is what's known as a greedy quantifier - the regex engine will match ("consume") all of the characters to the end of the input (or the end of the line) and then work backwards for the rest of the expression (it "gives up" characters only when it must). In a regex, once a character is "matched" no other part of the expression can "match" it again (except for zero-width lookarounds, which is coming next).
(?=.{6,10}) is a lookahead anchor and it matches a position in the input. It finds a place in the input where there are 6 to 10 characters following, but it does not "consume" those characters, meaning that the following expressions are free to match them.
(?=.*[a-zA-Z].*[a-zA-Z].*[a-zA-Z].*[a-zA-Z]) is another lookahead anchor. It matches a position in the input where the following text contains four letters ([a-zA-Z] matches one lowercase or uppercase letter), but any number of other characters (including zero characters) may be between them. For example: "++a5b---C#D" would match. Again, being an anchor, it does not actually "consume" the matched characters - it only finds a position in the text where the following characters match the expression.
(?=.*\d.*\d) Another lookahead. This matches a position where two numbers follow (with any number of other characters in between).
.* Already covered this one.
$ This is another kind of anchor that matches the end of the input (or the end of a line - the position just before a newline character). It says that the preceding expression must match characters at the end of the string. When ^ and $ are used together, it means that the entire input must be matched (not just part of it). So /bcd/ would match "abcde", but /^bcd$/ would not match "abcde" because "a" and "e" could not be included in the match.
NOTE
This looks like a password validation regex. If it is, please note that it's broken. The .* at the beginning and end will allow the password to be arbitrarily longer than 10 characters. It could also be rewritten to be a bit shorter. I believe the following will be an acceptable (and slightly more readable) substitute:
^(?=(.*[a-zA-Z]){4})(?=(.*\d){2}).{6,10}$
Thanks to #nhahtdh for pointing out the correct way to implement the character length limit.

Check Cyborgx37's answer for the syntax explanation. I'll do some explanation on the meaning of the regex.
^.*(?=.{6,10})(?=.*[a-zA-Z].*[a-zA-Z].*[a-zA-Z].*[a-zA-Z])(?=.*\d.*\d).*$
The first .* is redundant, since the rest are zero-width assertions that begins with any character ., and .* at the end.
The regex will match minimum 6 characters, due to the assertion (?=.{6,10}). However, there is no upper limit on the number of characters of the string that the regex can match. This is because of the .* at the end (the .* in the front also contributes).
This (?=.*[a-zA-Z].*[a-zA-Z].*[a-zA-Z].*[a-zA-Z]) part asserts that there are at least 4 English alphabet character (uppercase or lowercase). And (?=.*\d.*\d) asserts that there are at least 2 digits (0-9). Since [a-zA-Z] and \d are disjoint sets, these 2 conditions combined makes the (?=.{6,10}) redundant.
The syntax of .*[a-zA-Z].*[a-zA-Z].*[a-zA-Z].*[a-zA-Z] is also needlessly verbose. It can be shorten with the use of repetition: (?:.*[a-zA-Z]){4}.
The following regex is equivalent your original regex. However, I really doubt your current one and this equivalent rewrite of your regex does what you want:
^(?=(?:.*[a-zA-Z]){4})(?=(?:.*\d){2}).*$
More explicit on the length, since clarity is always better. Meaning stay the same:
^(?=(?:.*[a-zA-Z]){4})(?=(?:.*\d){2}).{6,}$
Recap:
Minimum length = 6
No limit on maximum length
At least 4 English alphabet, lowercase or uppercase
At least 2 digits 0-9

REGEXPLANATION
/.../: slashes are often used to represent the area where the regex is defined
^: matches beginning of input string
.: this can match any character
*: matches the previous symbol 0 or more times
.{6,10}: matches .(any character) somewhere between 6 and 10 times
[a-zA-Z]: matches all characters between a and z and between A and Z
\d: matches a digit.
$: matches the end of input.
I think that just about does it for all the symbols in the regex you've posted

For your regex request, here is what you would use:
^(?=.{6,}$)(?=.*?\d)(?=.*?[!##$%&*()+_=?\^-]).*
And here it is unrolled for you:
^ // Anchor the beginning of the string (password).
(?=.{6,}$) // Look ahead: Six or more characters, then the end of the string.
(?=.*?\d) // Look ahead: Anything, then a single digit.
(?=.*?[!##$%&*()+_=?\^-]) // Look ahead: Anything, and a special character.
.* // Passes our look aheads, let's consume the entire string.
As you can see, the special characters have to be explicitly defined as there is not a reserved shorthand notation (like \w, \s, \d) for them. Here are the accepted ones (you can modify as you wish):
!, #, #, $, %, ^, &, *, (, ), -, +, _, =, ?
The key to understanding regex look aheads is to remember that they do not move the position of the parser. Meaning that (?=...) will start looking at the first character after the last pattern match, as will subsequent (?=...) look aheads.