I have problem with upload image file from Android to remote webservice in asp net c#.
The problem is that the image file sent from Android to the remote server is zero kilobytes; the upload worked, the image file name uploaded is correct in correct folder in the remote server and I don't have error in debug Android and in debug asp net, but this image is empty.
I would greatly appreciate your help.
Thanks in advance
android code in java class:
File mFile = new File("/storage/emulated/0/image_file.jpg");
if(mFile.exists()){
ByteArrayOutputStream stream = new ByteArrayOutputStream();
Bitmap bmp = BitmapFactory.decodeFile(mFile.getAbsolutePath());
bmp.recycle();
bmp.compress(Bitmap.CompressFormat.PNG, 100, stream);
byte[] byteArray = stream.toByteArray();
Request.addProperty("byteArray", byteArray);
}
WebService in asp net c#
[WebMethod]
public string sendUpload(Byte[] byteArray, string fileName)
{
string Path;
Path = "D:\\Inetpub\\wwwroot\\myAppAndroid\\uploads\\" + fileName;
FileStream objfilestream = new FileStream(Path, FileMode.Create,
FileAccess.ReadWrite);
objfilestream.Close();
return byteArray + "; " + fileName.ToString();
}
First Edit question, I have error in this line
file.Write(byteArray, 0, byteArray.Length);
[WebMethod]
public string sendUpload(Byte[] byteArray, string fileName)
{
string strdocPath;
strdocPath = "D:\\Inetpub\\wwwroot\\myAppAndroid\\uploads\\" + fileName;
System.IO.FileStream file = System.IO.File.Create(HttpContext.Current.Server.MapPath(".\\myAppAndroid\\uploads\\" + fileName));
file.Write(byteArray, 0, byteArray.Length);
file.Close();
return byteArray + "; " + fileName.ToString();
}
you should write the content of the received file on filesystem:
[WebMethod]
public string sendUpload(Byte[] byteArray, string fileName)
{
string Path;
Path = "D:\\Inetpub\\wwwroot\\myAppAndroid\\uploads\\" + fileName;
FileStream objfilestream = new FileStream(Path, FileMode.Create,
FileAccess.ReadWrite);
// here some code is missing
objfilestream.Close();
return byteArray + "; " + fileName.ToString();
}
you have a Byte[] as input that you never write on the server disk.
Related
following is the code added:
The image object is in the library.imaging.
"using System.Drawing;"
"using System.Drawing.Imaging;"
{
byte[] b = Convert.FromBase64String("R0lGODlhAQABAIAAA");
Image image;
using (MemoryStream memstr = new MemoryStream(b))
{
image = Image.FromStream(memstr);
}
}
Here is the new code I'm working on:
{
string base64BinaryStr = " ";
byte[] PDFDecoded = Convert.FromBase64String(base64BinaryStr);
string FileName = (#"C:\Users\Downloads\PDF " + DateTime.Now.ToString("dd-MM-yyyy-hh-mm"));
BinaryWriter writer = new BinaryWriter(File.Create(FileName + ".pdf"));
writer.Write(PDFDecoded);
string s = Encoding.UTF8.GetString(PDFDecoded);
}
So this is your current code:
byte[] PDFDecoded = Convert.FromBase64String(base64BinaryStr);
string FileName = (#"C:\Users\Downloads\PDF " + DateTime.Now.ToString("dd-MM-yyyy-hh-mm"));
BinaryWriter writer = new BinaryWriter(File.Create(FileName + ".pdf"));
writer.Write(PDFDecoded);
You don't actually need BinaryWriter for this. File.Create already gives you a FileStream:
FileStream writer = File.Create(FileName + ".pdf");
writer.Write(PDFDecoded, 0, PDFDecoded.Length);
But this will still have the problem you're experiencing because you're not flushing the data to it. We also need to close the file. Thankfully, we can wrap it in using and it will do both for us:
using (FileStream writer = File.Create(FileName + ".pdf"))
{
writer.Write(PDFDecoded, 0, PDFDecoded.Length);
}
But a simpler way to do this is:
File.WriteAllBytes(FileName + ".pdf", PDFDecoded);
As for PDF -> Image, you'll probably have to see if there is a library available for this (search "PDF to Image NuGet") that can help you with this as I don't think there is anything built-in.
Just a thought, you don't need to create a physical PDF file, you can have it in memory and convert it to image from there.
Now the problem is that you cannot use Image from System.Drawing.Imaging for this, it doesn't support reading PDF file.
Instead you'll need to search for some library that can do that.
For example, try GemBox.Pdf, you can use it like this:
string base64String = "...";
byte[] pdfBytes = Convert.FromBase64String(base64String);
using (PdfDocument pdfDocument = PdfDocument.Load(new MemoryStream(pdfBytes)))
{
ImageSaveOptions imageOptions = new ImageSaveOptions(ImageSaveFormat.Png);
string imageName = DateTime.Now.ToString("dd-MM-yyyy-hh-mm") + ".png";
pdfDocument.Save(#"C:\Users\Downloads\" + imageName, imageOptions);
}
I've used the code provided on this Convert example.
I am trying to create a web service that returns a pdf file as a byte[] and then the app that consumes it grabs the byte[] and saves it as a pdf file and then opens it. The file fails to open at the end.
Here is the Web Service that returns a byte[]
[WebMethod]
public byte[] XXXX(int fileID)
{
try
{
using (EntitiesModel dbContext = new EntitiesModel())
{
string fileFullPath = .....
.......
if (fileFullNamePath != null)
{
FileStream fileStream = new FileStream(fileFullNamePath, FileMode.Open, System.IO.FileAccess.Read);
int len = fileStream.Length.ToInt();
Byte[] documentContents = new byte[len];
fileStream.Read(documentContents, 0, len);
fileStream.Close();
return documentContents;
Then it is called from an app with the following code
string soap = "<?xml version=\"1.0\" encoding=\"utf - 8\"?>" +
"<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">" +
"<soap:Body>" +
"<XXXX xmlns=\"http://tempuri.org/\">" +
"<fileID>XXXXX</fileID>" +
"</XXXX>" +
"</soap:Body>" +
"</soap:Envelope>";
string localhostContext = #"http://localhost:3381/";
string webserviceAddress = #"XXXX/XXXX/XXXXX.asmx";
string url = localhostContext + webserviceAddress ;
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
request.ContentType = "text/xml";
request.ContentLength = soap.Length;
request.Timeout = 20000;
request.Method = "POST";
using (Stream stream = request.GetRequestStream())
{
using (StreamWriter streamWriter = new StreamWriter(stream))
{
streamWriter.Write(soap); }
}
}
byte[] bytes;
try
{
WebResponse response = request.GetResponse();
bytes = ReadFully(response.GetResponseStream());
}
catch (Exception exception)
{
throw;
}
private byte[] ReadFully(Stream input)
{
byte[] buffer = new byte[16*1024];
using (MemoryStream memoryStream = new MemoryStream())
{
int read;
while ((read = input.Read(buffer, 0, buffer.Length)) > 0)
{
memoryStream.Position = 0;
memoryStream.Write(buffer, 0, read);
}
return memoryStream.ToArray();
}
}
FileStream objfilestream =
new FileStream(fileName, FileMode.Create,FileAccess.ReadWrite);
objfilestream.Write(bytes, 0, bytes.Length);
objfilestream.Close();
var process = Process.Start(fileName);
The code runs fine and creates a pdf and then tries to open that pdf. But the file can not be opened. Adobe Acrobat gives the error
Adobe Acrobat Reader could not open XXX.pdf because it is either not a
supported file type or because the file has been damaged (for example, it
was sent as an email attachment and wasn't correctly decoded).
Because I am not getting an error in the code I am at a loss to know where the error is that is not creating the proper file.
There was an issue with the Stream variable called input was not giving length so I used Jon Skeet's suggestion here Stackoverflow:Creating a byte array from a stream
new byte[16*1024];
rather than
new byte[input.length]
There were three things wrong.
memoryStream.Position = 0;
in the while loop was problematic so I removed it.
Secondly when reading the stream. What it returned was the SOAP XMl message with the encoded base64 string in the the XXXXResult XML tag. So I had to extract that.
Finally I had to use
byte[] fileResultBytes = Convert.FromBase64String(resultString);
to get the byte[] from the resultString extracted from the SOAP message. In the test SOAP message, that can be generated locally, it tells you the type of this result string. I missed that initially.
Thanks to VC.One and CodeCaster for their correct suggestions.
In my c# application, when i upload a file , it needs to be converted to temp file and store in a temporary folder then read the temp file as image find its height width every thing and later stores in databse.I am getting error when I read the temp file as image, as Out of Memory, below is my entire code.
string img = System.Windows.Forms.Application.StartupPath +#"\"+ path;
//in path .png file is accessed.
string filename = Path.GetFileName(img);
string internetCache = Environment.GetFolderPath(Environment.SpecialFolder.InternetCache);
string IEPath=internetCache+#"\tmp";
if (!Directory.Exists(IEPath))
Directory.CreateDirectory(IEPath);
FileInfo fi = new FileInfo(img);
FileStream fs = fi.OpenRead();
//lResult = URLDownloadToFile(0, img.src, TempFolder & strFileName, 0, 0)
Stream stream = fs;
byte[] buffer = new byte[fs.Length];
stream.Seek(273, SeekOrigin.Begin);
stream.Read(buffer, 0, (int)buffer.Length);
string tempfile = Path.Combine(IEPath, Math.Abs(filename.GetHashCode()) + ".tmp");
File.WriteAllBytes(tempfile, buffer);
fs.Close();
stream.Close();
string _contentType = "application/octet-stream";
FileType Type = FileType.png;
string MimeType = "image/png";
FileStream fst = new FileStream(tempfile, FileMode.Open);
Image _image = System.Drawing.Image.FromStream(fst, true, true);
The last line where I am getting the exception as out of memory.
Please help me to find a solution.
I'd venture that the stream you are reading is corrupted (perhaps because you remove the leading 273 bytes).
I just followed the instructions of the question:
read some file
Copy the file to a temp file
Read as image
Get width & height
var bytes = File.ReadAllBytes(#"C:\temp\duck.jpg");
var temp = Path.GetTempFileName();
File.WriteAllBytes(temp, bytes);
var img = Image.FromFile(temp);
Console.WriteLine ("width: {0}, height: {0}", img.Width, img.Height);
1) I am having a problem in reading a text file from my given path .
2) When i download the zip file from ftp i extracted it my extracting is working fine ,
3) The problem is when i download the file from ftp the file which i download is zip file i extract it to a text file and delete the zip file after extracting it and when i
try to read text file from the given path, the path reads the zip file not a text file
4) the code i am using for FTP and extracting the zipfile is,
private void DownloadMonth(string filePath, string fileName)
{
FtpWebRequest reqFTP;
try
{
if (!Directory.Exists(filePath))
{
Directory.CreateDirectory(filePath);
}
FileStream outputStream = new FileStream(filePath + "\\" + fileName, FileMode.OpenOrCreate, FileAccess.ReadWrite, FileShare.ReadWrite);
reqFTP = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://" + ftpServerIP + "/" + ftpMonth + "/" + fileName));
reqFTP.Method = WebRequestMethods.Ftp.DownloadFile;
reqFTP.UseBinary = true;
reqFTP.KeepAlive = true;
reqFTP.UsePassive = true;
reqFTP.Credentials = new NetworkCredential(ftpUserID, ftpPassword);
FtpWebResponse response = (FtpWebResponse)reqFTP.GetResponse();
Stream ftpStream = response.GetResponseStream();
long c1 = response.ContentLength;
int bufferSize = 2048000;
int readCount;
byte[] buffer = new byte[bufferSize];
readCount = ftpStream.Read(buffer, 0, bufferSize);
while (readCount > 0)
{
outputStream.Write(buffer, 0, readCount);
readCount = ftpStream.Read(buffer, 0, bufferSize);
}
ftpStream.Close();
outputStream.Close();
response.Close();
string Path1 = (string)(Application.StartupPath + "\\TEMP\\TEMP_BACKFILL_" + "\\" + fileName);
DirectoryInfo di = new DirectoryInfo(Path1);
FileInfo fi = new FileInfo(Path1);
Decompress(fi);
File.Delete(Path1);
}
catch (Exception ex)
{
}
}
Decompress Code
public static void Decompress(FileInfo fi)
{
// Get the stream of the source file.
using (FileStream inFile = fi.OpenRead())
{
// Get original file extension, for example "doc" from report.doc.gz.
string curFile = fi.FullName;
string origName = curFile.Remove(curFile.Length - fi.Extension.Length);
//Create the decompressed file.
//using (FileStream outFile = File.Create(fi.FullName + ""))
//using (FileStream outFile = File.Create(System.Text.RegularExpressions.Regex.Replace(fi.FullName, ".txt$", "") + ""))
using (FileStream outFile = File.Create(origName + ".txt"))
{
using (GZipStream Decompress = new GZipStream(inFile,
CompressionMode.Decompress))
{
//Copy the decompression stream into the output file.
byte[] buffer = new byte[4096];
int numRead;
while ((numRead = Decompress.Read(buffer, 0, buffer.Length)) != 0)
{
outFile.Write(buffer, 0, numRead);
}
Console.WriteLine("Decompressed: {0}", fi.Name);
}
}
}
}
The code i use to download the text file from FTP and read the text file is
private void button1_Click(object sender, EventArgs e)
{
this.DownloadMonth(a, name_Month);
string Path1 = (string)(Application.StartupPath + "\\TEMP\\TEMP_BACKFILL_" + "\\" + name_Month);
StreamReader reader1 = File.OpenText(Path1);
string str = reader1.ReadToEnd();
reader1.Close();
reader1.Dispose();
}
There would be a great appreciation if someone can solve my problem.
Thanks In Advance
It looks like you're trying to read the binary file from your button1_Click method, instead of the text file. That's just a matter of giving it the wrong filename. You could try just using:
string Path1 = Application.StartupPath + "\\TEMP\\TEMP_BACKFILL_\\"
+ name_Month + ".txt";
(in button1_Click)
... but really you should be able to diagnose what's going wrong yourself:
Is the file being downloaded correctly?
Is the decompression working?
Does the text file look okay afterwards (on the file system)?
If everything's working up to that point, then the download and decompression code is irrelevant, and it's obviously just the reading part in the click handler which is failing. If the text file isn't being created properly, then obviously something is wrong earlier in the process.
It's important to be able to diagnose this sort of thing yourself - you've got a clear 3-step process, and the results of that process should be easy to find just by looking on the file system, so the first thing to do is work out which bit is failing, and only look closely at that.
As an aside, in various places you're manually calling Close on things like streams and readers. Don't do that - use a using statement instead. You should also look at File.ReadAllText as a simpler alternative for reading the whole of a text file.
try string Path1 = origName + ".txt" in button click
hey guys, m using an api of "Bits on the Run" following is the code of upload API
public string Upload(string uploadUrl, NameValueCollection args, string filePath)
{
_queryString = args; //no required args
WebClient client = createWebClient();
_queryString["api_format"] = APIFormat ?? "xml"; //xml if not specified - normally set in required args routine
queryStringToArgs();
string callUrl = _apiURL + uploadUrl + "?" + _args;
callUrl = uploadUrl + "?" + _args;
try {
byte[] response = client.UploadFile(callUrl, filePath);
return Encoding.UTF8.GetString(response);
} catch {
return "";
}
}
and below is my code to upload a file, m using FileUpload control to get the full path of a file(but m not succeeded in that)...
botr = new BotR.API.BotRAPI("key", "secret_code");
var response = doc.Descendants("link").FirstOrDefault();
string url = string.Format("{0}://{1}{2}", response.Element("protocol").Value, response.Element("address").Value, response.Element("path").Value);
//here i want fullpath of the file, how can i achieve that here
string filePath = fileUpload.PostedFile.FileName;//"C://Documents and Settings//rkrishna//My Documents//Visual Studio 2008//Projects//BitsOnTheRun//BitsOnTheRun//rough_test.mp4";
col = new NameValueCollection();
FileStream fs = new FileStream(filePath, FileMode.Open);
col["file_size"] = fs.Length.ToString();
col["file_md5"] = BitConverter.ToString(HashAlgorithm.Create("MD5").ComputeHash(fs)).Replace("-", "").ToLower();
col["key"] = response.Element("query").Element("key").Value;
col["token"] = response.Element("query").Element("token").Value;
fs.Dispose();
string uploadResponse = botr.Upload(url, col, filePath);
i read in some forums saying that for some security purpose you can't get fullpath of a file from client side. If it is true then how can i achieve file upload in my scenario ?
Yes, this is true, for security reason you cannot get the fullpath of the client machine, what you can do is, try the following,
Stream stream = fileUpload.PostedFile.InputStream;
stream.Read(bytes, 0, fileUpload.PostedFile.ContentLength);
instead of creating your own FileStream use the stream provided by the FileUploadControl. Hoep it shall help.