First.. I'm not interested in JSON.NET or any other parsers. Only DataContractJsonSerializer
I have to work with structures I get and send to REST API and they look like so:
{ "records": [
{
"attributes": {
"OBJECTID": 1,
"Address": "380 New York St.",
"City": "Redlands",
"Region": "CA",
"Postal": "92373"
}
},
{
"attributes": {
"OBJECTID": 2,
"Address": "1 World Way",
"City": "Los Angeles",
"Region": "CA",
"Postal": "90045"
}
}
]
What we can see is something like this:
class SomeData
{
public List<SomeRecord> Records { get; set; }
}
class SomeRecord
{
public List<KeyValuePair<string, string>> Attributes { get; set; }
}
How do I attribute my object so serializer can produce structure like this? Or should I create object with properties covering each attribute?
Problem is - this webservice seem to be attributes here and there and I'm not even sure of all possible names. So, List of KVP seems like a good choice, but it doesn't work for me.
Following should work,
[DataContract]
[KnownType(typeof(Record))]
public class RecordList
{
public RecordList()
{
Records = new List<Record>();
}
[DataMember]
public List<Record> Records { get; set; }
}
public class Record
{
public Record()
{
Attributes = new AttributeList();
}
[DataMember]
public AttributeList Attributes { get; set; }
}
[Serializable]
public class AttributeList : DynamicObject, ISerializable
{
private readonly Dictionary<string, object> attributes = new Dictionary<string, object>();
public override bool TrySetMember(SetMemberBinder binder, object value)
{
attributes[binder.Name] = value;
return true;
}
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
foreach (var kvp in attributes)
{
info.AddValue(kvp.Key, kvp.Value);
}
}
}
[Test]
public void TestSerialize()
{
var holder = new RecordList();
dynamic record = new Record();
record.Attributes.OBJECTID = 1;
record.Attributes.Address = "380 New York St.";
record.Attributes.City = "Redlands";
record.Attributes.Address = "Region";
record.Attributes.Region = "CA";
record.Attributes.Postal = "92373";
holder.Records.Add(record);
var stream1 = new MemoryStream();
var serializer = new DataContractJsonSerializer(typeof(RecordList));
serializer.WriteObject(stream1, holder);
stream1.Position = 0;
StreamReader sr = new StreamReader(stream1);
Console.Write("JSON form of holder object: ");
Console.WriteLine(sr.ReadToEnd());
}
Related
I need to serialize a response of an object with a dictionary dynamically
left the json examples
I am trying to serialize this response object (request_validator) in a c# class
but this is not working
someone who can help me please, any ideas?
{
"person": {
"testing": "CC",
"simple": "1234545",
"errorNames": {
"id": "655789",
"error": "simple"
},
"errorColor": {
"id": "2",
"error": "error color"
}
}
}
{
"request_validator": [
{
"person.errorNames": [
"error names"
],
"person.errorColor": [
"error color"
]
}
]
}
public class DeserializeResponse{
public Dictionary<string, List<string>> request_validator { get; set; }
}
var error = JsonConvert.DeserializeObject<List<DeserializeResponse>>(content);
You can use Newtonsoft.Json library to get all properties from string array into dictionary
in this case you just need to point to the searched level
using Newtonsoft.Json.Linq;
...
JObject validator = JObject.Parse(content);
IJEnumerable<JToken> validatorTokens = validator.SelectTokens("request_validator")?.Values();
Dictionary<string, List<string>> errors = new Dictionary<string, List<string>>();
if (validatorTokens != null)
{
foreach (JProperty prop in validatorTokens.Values())
{
if (!errors.ContainsKey(prop.Name))
{
errors.Add(prop.Name, new List<string>());
}
errors[prop.Name].Add(prop.Value?.ToString());
}
}
public class DeserializeResponse
{
[JsonPropertyName("request_validator")]
public RequestValidator[] RequestValidator { get; set; }
}
public class RequestValidator
{
[JsonPropertyName("person.errorNames")]
public string[] PersonErrorNames { get; set; }
[JsonPropertyName("person.errorColor")]
public string[] PersonErrorColor { get; set; }
}
...
var error = JsonSerializer.Deserialize<DeserializeResponse>(content);
The JSON looks like this
{
"123": {
"Type": "IN",
"OUTAgentMACID": "00-14-22-01-23-45",
"PlateNumber": {
"Image": "/poll/data/date0/img.png",
"Number": "ABC1234",
"TimeStamp": 5901291
}
},
"124": {
"Type": "OUT",
"OUTAgentMACID": "00-14-22-01-31-45",
"PlateNumber": {
"Image": "/poll/data/date0/img.png",
"Number": "ABC1234",
"TimeStamp": 5991291
}
},
"125": {
"Type": "IN",
"INAgentMACID": "00-14-22-01-63-45",
"PlateNumber": {
"Image": "/poll/data/date1/img.png",
"Number": "ABC1234",
"TimeStamp": 6001239
}
}
}
The probable class structure is
public class PlateNumber
{
public string Image { get; set; }
public string Number { get; set; }
public int TimeStamp { get; set; }
}
public class Activity
{
public string Type { get; set; }
public string AgentMACID { get; set; }
public PlateNumber PlateNumber { get; set; }
}
public class SessionActivity
{
public Dictionary<int, Activity> Activities { get; set; }
}
Helper looks like this
public class helpers : DefaultContractResolver
{
private Dictionary<string, string> PropertyMappings { get; set; }
public helpers()
{
PropertyMappings = new Dictionary<string, string>
{
{"INAgentMACID", "AgentMACID"},
{"OUTAgentMACID", "AgentMACID"},
};
}
protected override string ResolvePropertyName(string propertyName)
{
string resolvedName = null;
var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
}
}
Now when I try to deserializing it like this
var settings = new JsonSerializerSettings();
settings.ContractResolver = new helpers();
var activities = JsonConvert.DeserializeObject<SessionActivity>("Some.json"), settings);
the activities is null.
The Problem is AgentMACID Since the JSON have either OUTAgentMACID or INAgentMACID depending on the Type
Please help me design the class for this JSON.
I think it's not directly possible that you have one Property, which represents two Properties of the json- (as I've read here Make JsonPropertyAttribute allow multiple usages on same property)
What I undertsand from this post, you would be forced to have another property, which just "forwards" the value to the one you want.
example:
public class Activity
{
public string Type { get; set; }
public string AgentMACID { get; set; }
private string AgentMACID2 { set { AgentMACID = value; } } // used to map the other field of json
public PlateNumber PlateNumber { get; set; }
}
in the Contract Resolver you have to mape vias versa as you did. With the second field I added, it might looks as this:
PropertyMappings = new Dictionary<string, string>
{
{"AgentMACID","OUTAgentMACID"},
{"AgentMACID2","INAgentMACID"}
};
And deserialize by this:
var activities = JsonConvert.DeserializeObject<Dictionary<int, Activity>>("json content", settings);
1 - Deserialize a Dictionary from JSON
Based on your json object :
{
"123": {
"Type": "IN",
"OUTAgentMACID": "00-14-22-01-23-45",
"PlateNumber": {
"Image": "/poll/data/date0/img.png",
"Number": "ABC1234",
"TimeStamp": 5901291
}
},
"124": {
"Type": "OUT",
"OUTAgentMACID": "00-14-22-01-31-45",
"PlateNumber": {
"Image": "/poll/data/date0/img.png",
"Number": "ABC1234",
"TimeStamp": 5991291
}
},
"125": {
"Type": "IN",
"INAgentMACID": "00-14-22-01-63-45",
"PlateNumber": {
"Image": "/poll/data/date1/img.png",
"Number": "ABC1234",
"TimeStamp": 6001239
}
}
}
You can deserialize a dictionary using :
var activities = JsonConvert.DeserializeObject<Dictionary<int, Activity>>("Some.json"), settings);
2.1 - Manage multiple json property names in one C# property
For your second issue you can define your Activity class like this :
public class Activity
{
public string Type { get; set; }
public string AgentMACID { get; set; }
// Optional: you can rename your property with this property attribute
// [JsonProperty("INAgentMACID")]
public string INAgentMACID { set { AgentMACID = value; } }
// Optional: you can rename your property with this property attribute
// [JsonProperty("OUTAgentMACID")]
public string OUTAgentMACID { set { AgentMACID = value; } }
public PlateNumber PlateNumber { get; set; }
}
2.2 - You can also inherit DefaultContractResolver as you were doing :
public class RenamePropertySerializerContractResolver : DefaultContractResolver
{
private readonly Dictionary<Type, HashSet<string>> _ignores;
private readonly Dictionary<Type, Dictionary<string, string>> _renames;
public RenamePropertySerializerContractResolver()
{
_renames = new Dictionary<Type, Dictionary<string, string>>();
}
public void RenameProperty(Type type, string propertyName, string newJsonPropertyName)
{
if (!_renames.ContainsKey(type))
_renames[type] = new Dictionary<string, string>();
_renames[type][propertyName] = newJsonPropertyName;
}
protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization)
{
var property = base.CreateProperty(member, memberSerialization);
if (IsRenamed(property.DeclaringType, property.PropertyName, out var newJsonPropertyName))
property.PropertyName = newJsonPropertyName;
return property;
}
private bool IsRenamed(Type type, string jsonPropertyName, out string newJsonPropertyName)
{
Dictionary<string, string> renames;
if (!_renames.TryGetValue(type, out renames) || !renames.TryGetValue(jsonPropertyName, out newJsonPropertyName))
{
newJsonPropertyName = null;
return false;
}
return true;
}
}
And finally use you new ContractResolver :
var jsonResolver = new RenamePropertySerializerContractResolver();
jsonResolver.RenameProperty(typeof(Activity), "INAgentMACID", "AgentMACID");
jsonResolver.RenameProperty(typeof(Activity), "OUTAgentMACID", "AgentMACID");
var serializerSettings = new JsonSerializerSettings();
serializerSettings.ContractResolver = jsonResolver;
var activities = JsonConvert.DeserializeObject<IDictionary<int, Activity>>(json, serializerSettings);
sources : https://blog.rsuter.com/advanced-newtonsoft-json-dynamically-rename-or-ignore-properties-without-changing-the-serialized-class/
I'm using newtonsoft in my .net core project and came across a particular json format.
I've got a list and the 'normal' json that come out after serialization is something like this:
{
"id": "0124",
"entities": [
{
"name": "chris",
"surname": "green"
},
{
"name": "albert",
"surname": "red"
}
]
}
I need to transform it in something like:
{
"id": "0124",
"entities": [
{
"chris": "green",
"albert": "red"
}
]
}
I don't know how many entities there could be inside my list.
Thank you all
EDIT
Thanks for the help guys, so this is the code:
var jsonBody = JsonConvert.SerializeObject(
new BulkRegisterDto
{
Id = "0124",
Entities = entities
}
);
public class BulkRegisterDto
{
[JsonProperty(PropertyName = "id")]
public string Id{ get; set; }
[JsonProperty(PropertyName = "entities")]
public IList<Person> Entities { get; set; }
}
public class Person
{
public string Name { get; set; }
public string Surname { get; set; }
}
These are not the real properties. I'm trying to use a dynamic JObject. We will see if it works
#Aleks Andreev I set your answer as the right one because it solves the problem but i prefer a better approach and I created my custom json converter using #MindSwipe comment.
This is my code below:
public class BulkEntityConverter : JsonConverter
{
public override object ReadJson(
JsonReader reader,
Type objectType,
object existingValue,
JsonSerializer serializer)
{
var obj = (JObject)JObject.ReadFrom(reader);
JProperty property = obj.Properties().FirstOrDefault();
// I didn't use this method
return new BulkRegisterDto
{
Id = property.Name,
Entities = new List<Person>()
};
}
public override void WriteJson(
JsonWriter writer,
object value,
JsonSerializer serializer)
{
BulkRegisterDto permission = (BulkRegisterDto)value;
var innerEntities = new JObject();
foreach (var entry in permission.Entities)
{
innerEntities.Add(entry.Name, entry.Surname);
}
var root = new JObject
{
{ "id", permission.Id},
{ "entities", new JArray { innerEntities } }
};
root.WriteTo(writer);
}
public override bool CanConvert(Type t)
{
return typeof(BulkRegisterDto).IsAssignableFrom(t);
}
public override bool CanRead
{
get { return true; }
}
}
Using this way i can get a clear class where to use my json converter like:
var jsonBody = JsonConvert.SerializeObject(manager, new BulkEntityConverter());
where manager is my BulkRegisterDto object
Thanks for all the support guys
You can deserialize your json to DTO:
[DataContract]
private class Person
{
[DataMember(Name = "name")]
public string Name { get; set; }
[DataMember(Name = "surname")]
public string Surname { get; set; }
}
[DataContract]
private class Entities
{
[DataMember(Name = "entities")]
public Person[] Persons { get; set; }
}
and then build expected json with raw JObject and JArray
var input = "{\r\n \"entities\": [\r\n {\r\n \"name\": \"chris\",\r\n \"surname\": \"green\"\r\n },\r\n {\r\n \"name\": \"albert\",\r\n \"surname\": \"red\"\r\n }\r\n ]\r\n}";
var json = JsonConvert.DeserializeObject<Entities>(input);
var root = new JObject();
var innerObject = new JObject();
root.Add("entities", new JArray {innerObject});
foreach (var entry in json.Persons)
innerObject.Add(entry.Name, entry.Surname);
If you call root.ToString() you will get
{
"entities": [
{
"chris": "green",
"albert": "red"
}
]
}
I need to serialize a JSON object that looks like this:
{
"Documents": [
{
"Title": "",
"DatePublished": "",
"DocumentURL": "",
"ThumbnailURL": "",
"Abstract": "",
"Sector": "",
"Country": [
"", "", ""
],
"Document Type": ""
}
]
}
What I'm doing is taking the data from SQL server and storing the results into an object like this:
public List<Dictionary<string, string>> GetResults()
{
int index = 0;
while (this.myReader.Read())
{
this.dataFrmDb = new Dictionary<string, string>();
for (int i = 0; i < myReader.FieldCount; i++)
{
if (myReader.GetName(i) == "Country")
{
string[] delimiter = { " _qfvcq_ " };
string text = myReader[myReader.GetName(i)].ToString();
string[] results = text.Split(delimiter, StringSplitOptions.None);
//This list stores the values for "Country".
List<string> countries = new List<string>();
for (int j = 0; j < results.Count(); j++)
{
countries.Add(results[j].ToString());
}
}
else
{
this.dataFrmDb.Add(myReader.GetName(i),
myReader[myReader.GetName(i)].ToString());
}
}
this.dictList.Add(this.dataFrmDb);
}
return this.dictList;
}
I then take this data and serialize like this:
Database connect = new Database(
System.Configuration.ConfigurationManager.AppSettings["DatabaseConnectionString"],
System.Configuration.ConfigurationManager.AppSettings["StoredProcedure"]);
List<Dictionary<string, string>> dataResults = connect.GetResults();
Dictionary<string, List<Dictionary<string, string>>> myList =
new Dictionary<string, List<Dictionary<string, string>>>();
myList.Add("Documents", dataResults);
string ans = JsonConvert.SerializeObject(myList, Formatting.Indented);
System.Console.WriteLine(ans);
I get the proper output but if you would look in the original JSON format, "Country" needs to have multiple values. I don't know how to implement that into this JSON object. How do I add a list with the "Country" values to the JSON object using JSON.net? Is there another way to go about this?
If you change dataFrmDb to be Dictionary<string, object> instead of a Dictionary<string, string>, then you can store the Countries list into it like the other values. Json.Net will then serialize it like you want.
Here is an example program which demonstrates:
class Program
{
static void Main(string[] args)
{
List<Dictionary<string, object>> dataResults = GetResults();
Dictionary<string, List<Dictionary<string, object>>> myList =
new Dictionary<string, List<Dictionary<string, object>>>();
myList.Add("Documents", dataResults);
string ans = JsonConvert.SerializeObject(myList, Formatting.Indented);
System.Console.WriteLine(ans);
}
public static List<Dictionary<string, object>> GetResults()
{
List<Dictionary<string, object>> dictList = new List<Dictionary<string, object>>();
Dictionary<string, object> dataFrmDb = new Dictionary<string, object>();
dataFrmDb.Add("Title", "An Example Document");
dataFrmDb.Add("DatePublished", DateTime.Now.ToString());
dataFrmDb.Add("DocumentURL", "http://www.example.org/documents/1234");
dataFrmDb.Add("ThumbnailURL", "http://www.example.org/thumbs/1234");
dataFrmDb.Add("Abstract", "This is an example document.");
dataFrmDb.Add("Sector", "001");
dataFrmDb.Add("Country", new List<string> { "USA", "Bulgaria", "France" });
dataFrmDb.Add("Document Type", "example");
dictList.Add(dataFrmDb);
return dictList;
}
}
Output:
{
"Documents": [
{
"Title": "An Example Document",
"DatePublished": "4/9/2013 7:25:05 PM",
"DocumentURL": "http://www.example.org/documents/1234",
"ThumbnailURL": "http://www.example.org/thumbs/1234",
"Abstract": "This is an example document.",
"Sector": "001",
"Country": [
"USA",
"Bulgaria",
"France"
],
"Document Type": "example"
}
]
}
A somewhat more straightforward way to do it is to create separate classes to hold the data, as was suggested by Joey Gennari. Json.NET can serialize those as well. The data classes would look something like this:
class Result
{
public List<Document> Documents { get; set; }
public Result()
{
Documents = new List<Document>();
}
}
class Document
{
public string Title { get; set; }
public string DatePublished { get; set; }
public string DocumentURL { get; set; }
public string ThumbnailURL { get; set; }
public string Abstract { get; set; }
public string Sector { get; set; }
public List<string> Country { get; set; }
[JsonProperty(PropertyName="Document Type")]
public string DocumentType { get; set; }
public Document()
{
Country = new List<string();
}
}
And here is the usage:
class Program
{
static void Main(string[] args)
{
Document doc = new Document();
doc.Title = "An Example Document";
doc.DatePublished = DateTime.Now.ToString();
doc.DocumentURL = "http://www.example.org/documents/1234";
doc.ThumbnailURL = "http://www.example.org/thumbs/1234";
doc.Abstract = "This is an example document.";
doc.Sector = "001";
doc.Country.Add("USA");
doc.Country.Add("Bulgaria");
doc.Country.Add("France");
doc.DocumentType = "example";
Result result = new Result();
result.Documents.Add(doc);
string json = JsonConvert.SerializeObject(result, Formatting.Indented);
System.Console.WriteLine(json);
}
}
The output for this example is exactly the same as the first.
Here is a different way to solve it with DataContractJsonSerializer. First create a class to represent the object:
[DataContract]
public class DocumentHolder
{
[DataMember(Name = "Documents")]
public Documents Document { get; set; }
}
[DataContract]
public class Documents
{
[DataMember(Name = "Title", Order = 1)]
public string Title { get; set; }
[DataMember(Name = "DatePublished", Order = 2)]
public DateTime? DatePublished { get; set; }
[DataMember(Name = "DocumentURL", Order = 3)]
public string DocumentURL { get; set; }
[DataMember(Name = "ThumbnailURL", Order = 4)]
public string ThumbnailURL { get; set; }
[DataMember(Name = "Abstract", Order = 5)]
public string Abstract { get; set; }
[DataMember(Name = "Sector", Order = 6)]
public string Sector { get; set; }
[DataMember(Name = "Country", Order = 7)]
public List<string> Country { get; set; }
[DataMember(Name = "Document Type", Order = 8)]
public string DocumentType { get; set; }
public Documents()
{
this.Country = new List<string>();
}
}
Here's how you would fill the object and serialize it:
static void Main(string[] args)
{
var documentholder = new DocumentHolder { Document = new Documents { Title = "Title 1", DatePublished = DateTime.Now, Sector = "A17", Country = new List<string> { "EN-US", "EN-GB" } } };
DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(DocumentHolder));
var ms = new MemoryStream();
serializer.WriteObject(ms, documentholder);
var text = Encoding.UTF8.GetString(ms.ToArray());
}
In my web app I'm using Newtonsoft.Json and I have following object
[Newtonsoft.Json.JsonObject(Title = "MyCar")]
public class Car
{
[Newtonsoft.Json.JsonProperty(PropertyName = "name")]
public string Name{get;set;}
[Newtonsoft.Json.JsonProperty(PropertyName = "owner")]
public string Owner{get;set;}
}
and I want serialize them with root name (class name). This is desired format using
{'MyCar':
{
'name': 'Ford',
'owner': 'John Smith'
}
}
I know that I can do that with anonymous object, but is any property or another way in Newtonsoft.Json library?
Use anonymous class
Shape your model the way you want using anonymous classes:
var root = new
{
car = new
{
name = "Ford",
owner = "Henry"
}
};
string json = JsonConvert.SerializeObject(root);
I found an easy way to render this out... simply declare a dynamic object and assign the first item within the dynamic object to be your collection class...This example assumes you're using Newtonsoft.Json
private class YourModelClass
{
public string firstName { get; set; }
public string lastName { get; set; }
}
var collection = new List<YourModelClass>();
var collectionWrapper = new {
myRoot = collection
};
var output = JsonConvert.SerializeObject(collectionWrapper);
What you should end up with is something like this:
{"myRoot":[{"firstName":"John", "lastName": "Citizen"}, {...}]}
You can easily create your own serializer
var car = new Car() { Name = "Ford", Owner = "John Smith" };
string json = Serialize(car);
string Serialize<T>(T o)
{
var attr = o.GetType().GetCustomAttribute(typeof(JsonObjectAttribute)) as JsonObjectAttribute;
var jv = JValue.FromObject(o);
return new JObject(new JProperty(attr.Title, jv)).ToString();
}
Sorry, my english is not that good. But i like to improve the upvoted answers.
I think that using Dictionary is more simple and clean.
class Program
{
static void Main(string[] args)
{
agencia ag1 = new agencia()
{
name = "Iquique",
data = new object[] { new object[] {"Lucas", 20 }, new object[] {"Fernando", 15 } }
};
agencia ag2 = new agencia()
{
name = "Valparaiso",
data = new object[] { new object[] { "Rems", 20 }, new object[] { "Perex", 15 } }
};
agencia agn = new agencia()
{
name = "Santiago",
data = new object[] { new object[] { "Jhon", 20 }, new object[] { "Karma", 15 } }
};
Dictionary<string, agencia> dic = new Dictionary<string, agencia>
{
{ "Iquique", ag1 },
{ "Valparaiso", ag2 },
{ "Santiago", agn }
};
string da = Newtonsoft.Json.JsonConvert.SerializeObject(dic);
Console.WriteLine(da);
Console.ReadLine();
}
}
public class agencia
{
public string name { get; set; }
public object[] data { get; set; }
}
This code generate the following json (This is desired format)
{
"Iquique":{
"name":"Iquique",
"data":[
[
"Lucas",
20
],
[
"Fernando",
15
]
]
},
"Valparaiso":{
"name":"Valparaiso",
"data":[
[
"Rems",
20
],
[
"Perex",
15
]
]
},
"Santiago":{
"name":"Santiago",
"data":[
[
"Jhon",
20
],
[
"Karma",
15
]
]
}
}
string Json = JsonConvert.SerializeObject(new Car { Name = "Ford", Owner = "John Smith" }, Formatting.None);
for the root element use GlobalConfiguration.
A very simple approach for me is just to create 2 classes.
public class ClassB
{
public string id{ get; set; }
public string name{ get; set; }
public int status { get; set; }
public DateTime? updated_at { get; set; }
}
public class ClassAList
{
public IList<ClassB> root_name{ get; set; }
}
And when you going to do serialization:
var classAList = new ClassAList();
//...
//assign some value
//...
var jsonString = JsonConvert.SerializeObject(classAList)
Lastly, you will see your desired result as the following:
{
"root_name": [
{
"id": "1001",
"name": "1000001",
"status": 1010,
"updated_at": "2016-09-28 16:10:48"
},
{
"id": "1002",
"name": "1000002",
"status": 1050,
"updated_at": "2016-09-28 16:55:55"
}
]
}
Hope this helps!
Well, you can at least tell Json.NET to include the type name: http://www.newtonsoft.com/json/help/html/T_Newtonsoft_Json_TypeNameHandling.htm . Newtonsoft.Json.JsonSerializer jser = new Newtonsoft.Json.JsonSerializer();
jser.TypeNameHandling = TypeNameHandling.Objects;
The type will be included at the beginning in the "$type" property of the object.
This is not exactly what you are looking for, but it was good enough for me when facing a similiar problem.
Writing a custom JsonConverter is another approach mentioned in similar questions. However, due to nature of how JsonConverter is designed, using that approach for this question is tricky, as you need to be careful with the WriteJson implementation to avoid getting into infinite recursion: JSON.Net throws StackOverflowException when using [JsonConvert()].
One possible implementation:
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
//JToken t = JToken.FromObject(value); // do not use this! leads to stack overflow
JsonObjectContract contract = (JsonObjectContract)serializer.ContractResolver.ResolveContract(value.GetType());
writer.WriteStartObject();
writer.WritePropertyName(value.GetType().Name);
writer.WriteStartObject();
foreach (var property in contract.Properties)
{
// this removes any property with null value
var propertyValue = property.ValueProvider.GetValue(value);
if (propertyValue == null) continue;
writer.WritePropertyName(property.PropertyName);
serializer.Serialize(writer, propertyValue);
//writer.WriteValue(JsonConvert.SerializeObject(property.ValueProvider.GetValue(value))); // this adds escaped quotes
}
writer.WriteEndObject();
writer.WriteEndObject();
}
I hope this help.
//Sample of Data Contract:
[DataContract(Name="customer")]
internal class Customer {
[DataMember(Name="email")] internal string Email { get; set; }
[DataMember(Name="name")] internal string Name { get; set; }
}
//This is an extension method useful for your case:
public static string JsonSerialize<T>(this T o)
{
MemoryStream jsonStream = new MemoryStream();
var serializer = new System.Runtime.Serialization.Json.DataContractJsonSerializer(typeof(T));
serializer.WriteObject(jsonStream, o);
var jsonString = System.Text.Encoding.ASCII.GetString(jsonStream.ToArray());
var props = o.GetType().GetCustomAttributes(false);
var rootName = string.Empty;
foreach (var prop in props)
{
if (!(prop is DataContractAttribute)) continue;
rootName = ((DataContractAttribute)prop).Name;
break;
}
jsonStream.Close();
jsonStream.Dispose();
if (!string.IsNullOrEmpty(rootName)) jsonString = string.Format("{{ \"{0}\": {1} }}", rootName, jsonString);
return jsonString;
}
//Sample of usage
var customer = new customer {
Name="John",
Email="john#domain.com"
};
var serializedObject = customer.JsonSerialize();
[Newtonsoft.Json.JsonObject(Title = "root")]
public class TestMain
this is the only attrib you need to add to get your code working.