We Keep Coding

Split string with plus sign as a delimiter

I have an issue with a string containing the plus sign (+).
I want to split that string (or if there is some other way to solve my problem)
string ColumnPlusLevel = "+-J10+-J10+-J10+-J10+-J10";
string strpluslevel = "";
strpluslevel = ColumnPlusLevel;
string[] strpluslevel_lines = Regex.Split(strpluslevel, "+");
foreach (string line in strpluslevel_lines)
{
MessageBox.Show(line);
strpluslevel_summa = strpluslevel_summa + line;
}
MessageBox.Show(strpluslevel_summa, "summa sumarum");
The MessageBox is for my testing purpose.
Now... The ColumnPlusLevel string can have very varied entry but it is always a repeated pattern starting with the plus sign.
i.e. "+MJ+MJ+MJ" or "+PPL14.1+PPL14.1+PPL14.1" as examples.
(It comes form Another software and I cant edit the output from that software)
How can I find out what that pattern is that is being repeated?
That in this exampels is the +-J10 or +MJ or +PPL14.1
In my case above I have tested it by using only a MessageBox to show the result but I want the repeated pattering stored in a string later on.
Maybe im doing it wrong by using Split, maybe there is another solution.
Maybe I use Split in the wrong way.
Hope you understand my problem and the result I want.
Thanks for any advice.
/Tomas

How can I find out what that pattern is that is being repeated?
Maybe i didn't understand the requirement fully, but isn't it easy as:
string[] tokens = ColumnPlusLevel.Split(new[]{'+'}, StringSplitOptions.RemoveEmptyEntries);
string first = tokens[0];
bool repeatingPattern = tokens.Skip(1).All(s => s == first);
If repeatingPattern is true you know that the pattern itself is first.
Can you maybe explain how the logic works
The line which contains tokens.Skip(1) is a LINQ query, so you need to add using System.Linq at the top of your code file. Since tokens is a string[] which implements IEnumerable<string> you can use any LINQ (extension-)method. Enumerable.Skip(1) will skip the first because i have already stored that in a variable and i want to know if all others are same. Therefore i use All which returns false as soon as one item doesn't match the condition(so one string is different to the first). If all are same you know that there is a repeating pattern which is already stored in the variable first.

You should use String.Split function :
string pattern = ColumnPlusLevel.Split("+")[0];

...but it is always a repeated pattern starting with the plus sign.
Why do you even need String.Split() here if the pattern always only repeats itself?
string input = #"+MJ+MJ+MJ";
int indexOfSecondPlus = input.IndexOf('+', 1);
string pattern = input.Remove(indexOfSecondPlus, input.Length - indexOfSecondPlus);
//pattern is now "+MJ"
No need of string split, no need to use LinQ

String has a method called Split which let's you split/divide the string based on a given character/character-set:
string givenString = "+-J10+-J10+-J10+-J10+-J10"'
string SplittedString = givenString.Split("+")[0] ///Here + is the character based on which the string would be splitted and 0 is the index number
string result = SplittedString.Replace("-","") //The mothod REPLACE replaces the given string with a targeted string,i added this so that you can get the numbers only from the string

C# How to check if a string contains a specifc combination of chars

I have a List, named values which contains values similar to the following string values:
GKgpuzjBUh
IS1bbf2ffd806f6d
IS102a8a395ced93
Dark Von Diakonov
IS148159f7c24f78
I need to check if the specific a string in the starts with IS1

You dont need regex. Use str.StartsWith("IS1").

Not clear from the question, so here are a few options.
You want to find out if ANY string in the list starts with IS1
var found = values.Any(item => item.StartsWith("IS1"));
You want to find all the strings in the list which start with IS1
var matches = values.Where(item => item.StartsWith("IS1"));

how to remove last part of string in c#

I was trying to remove last part of a string but failed.Here string named D:\software\VS2012\newtext.txt and i want to trim last section of string so here newtext.txt . I should get D:\software\VS2012 but how to do it in c#.When i tried it is removing all the string that has '\'. Here is what i did in c#
string str = #"D:\softwares\VS2012\newtext.txt";
str= str.Remove(str.IndexOf('\\'));
Console.WriteLine(str);

There is a premade function for this in the framework
string str = #"D:\softwares\VS2012\newtext.txt";
string path = System.IO.Path.GetDirectoryName(str);
(Reference)
Note that your original code does not work because you are removing from the first backslash, not the last. Substitute this line to make your code work
str = str.Remove(str.LastIndexOf('\\'));

Try using System.IO.Path.GetDirectoryName(string):
string dirname= System.IO.Path.GetDirectoryName(#"D:\softwares\VS2012\newtext.txt");

For removing a known portion of a string you can simply use the Replace.
In your case:
str = str.Replace("\\newtext.txt", ""); //this will give you the same result of the System.IO.Path.GetDirectoryName already suggested by gmiley, but it's more in a string context as per your question
Though if you want to remove the last part of a string by the last encounterd known character then the suggested "LastIndexOff('\')" method already suggested along with the Remove.
If you want to use a delimiter method, so depending on the delimiter character but not on the string format (in your case path format) the LastIndexOff(char) is the best option.
Although you could also split the string into an array and then rejoin the array after removing the last element:
var delmimter = '\\';
var strAy = str.Split(char);
str = String.Join('\\', strAy.SkipLast(1).ToArray());
With this method you don't need to rely on the existence of the delimiter char in the string and the result is always without the delimiter char at the end.
Besides, you can easily create an extension with the delimiter as a parameter.

We should check the existance of the char also
string str = #"D:\softwares\VS2012\newtext.txt";
int rstr = str.LastIndexOf('\\');
if (rstr>0) str= str.Remove(rstr);
Console.WriteLine(str);

c# How to insert a variable into a string?

I would like to know the different ways of inserting a variable into a string, in C#.
I am currently trying to insert values into a json string that I am building:
Random rnd = new Random();
int ID = rnd.Next(1, 999);
string body = #"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""help here""}";
How could I add the "ID" to the string body?

In a typical string inserting scenario, I'd do one of these:
string body = string.Format("My ID is {0}", ID);
string body = "My ID is " + ID;
However, your string is apparently JSON serialized data. I'd expect that I'd want to parse that into a class in order to work with it.
var myObj = JsonConvert.DeserializeObject<MyClass>(someString);
myObj.TID = ID;
// maybe do other things with it, then if I need JSON again...
string body = JsonConvert.SerializeObject(myObj);
One reason to take this approach is to make sure that any data I put in still makes the JSON valid. For example, if my ID were, instead of an int, a string with characters that needed escaping, directly inserting "\"\n\"" would not be the right thing to do.

String interpolation is the easiest way these days:
int myIntValue = 123;
string myStringValue = "one two three";
string interpolatedString = $"my int is: {myIntValue}. My string is: {myStringValue}.";
Output would be "my int is: 123. My string is: one two three.".
You can experiment with this sample yourself, over here.
The $ special character identifies a string literal as an interpolated
string. An interpolated string is a string literal that might contain
interpolation expressions. When an interpolated string is resolved to
a result string, items with interpolation expressions are replaced by
the string representations of the expression results. This feature is available starting with C# 6.

You could try this:
string body = #"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""" + ID + #"""}";
You can also use string.Concat:
string body = string.Concat(#"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""", ID, #"""}");

There are a number of ways to inject values into strings, however it's easy to lose sight of encodings, and cause major breakage.
If you just want to inject a value into another string, you can use:
string concatenation
string building
string formatting
Concatenation:
The simplest and most common way to build strings is by simply concatenating them together with the + operator:
var foo = 5;
var bar = "example-" + foo;
Concatenation can be difficult to read which makes it easy to introduce bugs, but for most simple tasks is the right tool for the job.
In this case, it's a poor choice:
string body = #"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""" + ID.ToString() + #"""}";
String Building
The StringBuilder class is useful for building large strings particularly when built iteratively.
var sb = new StringBuilder();
for (var i = 0; i < 1000; i++) {
sb.Append(i.ToString());
sb.Append(" ");
}
var output = sb.ToString();
It can still be difficult to read and hard to debug, but for cases where you're joining lots of strings together, it's super efficient
In this case, it's a poor choice:
StringBuilder sb = new StringBuilder();
sb.Append(#"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""");
sb.Append(ID.ToString());
sb.Append(#"""}");
string body = sb.ToString();
String formatting
The string.Format method makes templating data into a string super easy and efficient. If you plan on reusing the same string over and over, using a format string makes it much easier to read and debug code, particularly when there are lots of replacements:
var foo = 5;
var bar = string.Format("example-{0}", foo);
Format strings can also automatically apply culturally accurate formatting to particular data types, so that a DateTime is appropriately displayed, or so that a number has the appropriate number of trailing zeros.
In this case, it's a poor choice:
string string.Format(#"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""{0}""}", ID);
The right choice
You're not dumping data into any old string. That's JSON encoded data. If you just concatenate/build/format in any old value, you can break your string. For example, if the ID variable contained a " character, you'd break the entire JSON dataset.
Additionally, the length of the string and necessary quotes make it super difficult to read, which makes it difficult to maintain. Good luck when you get around to needing to add another formatted value, it's going to be a pain to change any existing value or add in new dynamic ones.
Instead of writing a JSON literal, write an object and encode it to JSON:
var bodyData =
new
{
currency = "country",
gold = 1,
detail = "detailid-979095986",
tId = ID //here's where you set the ID
};
var jss = new JavaScriptSerializer();
var body = jss.Serialize(bodyData);
This code is much easier to modify when the data changes, and will actually encode your data correctly. You don't need to worry about all those annoying double quote characters any more either.

You can use the
String.Format(#"{""currency"":""country"",""gold"":1,""detail"":""detailid-979095986"",""tId"":""{0}""}", ID)
Since this is params object[], you can use as many {n} as you want.

Instead of using on string, you could concatenate strings together using +, which would allow you to insert text between the generated strings.
string body = #"***" + ID + #"***";

Remove last characters from a string in C#. An elegant way?

I have a numeric string like this 2223,00. I would like to transform it to 2223. This is: without the information after the ",". Assume that there will be only two decimals after the ",".
I did:
str = str.Remove(str.Length - 3, 3);
Is there a more elegant solution? Maybe using another function? -I don´t like putting explicit numbers-

You can actually just use the Remove overload that takes one parameter:
str = str.Remove(str.Length - 3);
However, if you're trying to avoid hard coding the length, you can use:
str = str.Remove(str.IndexOf(','));

Perhaps this:
str = str.Split(",").First();

This will return to you a string excluding everything after the comma
str = str.Substring(0, str.IndexOf(','));
Of course, this assumes your string actually has a comma with decimals. The above code will fail if it doesn't. You'd want to do more checks:
commaPos = str.IndexOf(',');
if(commaPos != -1)
str = str.Substring(0, commaPos)
I'm assuming you're working with a string to begin with. Ideally, if you're working with a number to begin with, like a float or double, you could just cast it to an int, then do myInt.ToString() like:
myInt = (int)double.Parse(myString)
This parses the double using the current culture (here in the US, we use . for decimal points). However, this again assumes that your input string is can be parsed.

String.Format("{0:0}", 123.4567); // "123"
If your initial value is a decimal into a string, you will need to convert
String.Format("{0:0}", double.Parse("3.5", CultureInfo.InvariantCulture)) //3.5
In this example, I choose Invariant culture but you could use the one you want.
I prefer using the Formatting function because you never know if the decimal may contain 2 or 3 leading number in the future.
Edit: You can also use Truncate to remove all after the , or .
Console.WriteLine(Decimal.Truncate(Convert.ToDecimal("3,5")));

Use:
public static class StringExtensions
{
/// <summary>
/// Cut End. "12".SubstringFromEnd(1) -> "1"
/// </summary>
public static string SubstringFromEnd(this string value, int startindex)
{
if (string.IsNullOrEmpty(value)) return value;
return value.Substring(0, value.Length - startindex);
}
}
I prefer an extension method here for two reasons:
I can chain it with Substring.
Example: f1.Substring(directorypathLength).SubstringFromEnd(1)
Speed.

You could use LastIndexOf and Substring combined to get all characters to the left of the last index of the comma within the sting.
string var = var.Substring(0, var.LastIndexOf(','));

You can use TrimEnd. It's efficient as well and looks clean.
"Name,".TrimEnd(',');

Try the following. It worked for me:
str = str.Split(',').Last();

Since C# 8.0 it has been possible to do this with a range operator.
string textValue = "2223,00";
textValue = textValue[0..^3];
Console.WriteLine(textValue);
This would output the string 2223.
The 0 says that it should start from the zeroth position in the string
The .. says that it should take the range between the operands on either side
The ^ says that it should take the operand relative to the end of the sequence
The 3 says that it should end from the third position in the string

Use lastIndexOf. Like:
string var = var.lastIndexOf(',');