How do you convert a string such as 2009-05-08 14:40:52,531 into a DateTime?
Since you are handling 24-hour based time and you have a comma separating the seconds fraction, I recommend that you specify a custom format:
DateTime myDate = DateTime.ParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff",
System.Globalization.CultureInfo.InvariantCulture);
You have basically two options for this. DateTime.Parse() and DateTime.ParseExact().
The first is very forgiving in terms of syntax and will parse dates in many different formats. It is good for user input which may come in different formats.
ParseExact will allow you to specify the exact format of your date string to use for parsing. It is good to use this if your string is always in the same format. This way, you can easily detect any deviations from the expected data.
You can parse user input like this:
DateTime enteredDate = DateTime.Parse(enteredString);
If you have a specific format for the string, you should use the other method:
DateTime loadedDate = DateTime.ParseExact(loadedString, "d", null);
"d" stands for the short date pattern (see MSDN for more info) and null specifies that the current culture should be used for parsing the string.
try this
DateTime myDate = DateTime.Parse(dateString);
a better way would be this:
DateTime myDate;
if (!DateTime.TryParse(dateString, out myDate))
{
// handle parse failure
}
Use DateTime.Parse(string):
DateTime dateTime = DateTime.Parse(dateTimeStr);
Nobody seems to implemented an extension method. With the help of #CMS's answer:
Working and improved full source example is here: Gist Link
namespace ExtensionMethods {
using System;
using System.Globalization;
public static class DateTimeExtensions {
public static DateTime ToDateTime(this string s,
string format = "ddMMyyyy", string cultureString = "tr-TR") {
try {
var r = DateTime.ParseExact(
s: s,
format: format,
provider: CultureInfo.GetCultureInfo(cultureString));
return r;
} catch (FormatException) {
throw;
} catch (CultureNotFoundException) {
throw; // Given Culture is not supported culture
}
}
public static DateTime ToDateTime(this string s,
string format, CultureInfo culture) {
try {
var r = DateTime.ParseExact(s: s, format: format,
provider: culture);
return r;
} catch (FormatException) {
throw;
} catch (CultureNotFoundException) {
throw; // Given Culture is not supported culture
}
}
}
}
namespace SO {
using ExtensionMethods;
using System;
using System.Globalization;
class Program {
static void Main(string[] args) {
var mydate = "29021996";
var date = mydate.ToDateTime(format: "ddMMyyyy"); // {29.02.1996 00:00:00}
mydate = "2016 3";
date = mydate.ToDateTime("yyyy M"); // {01.03.2016 00:00:00}
mydate = "2016 12";
date = mydate.ToDateTime("yyyy d"); // {12.01.2016 00:00:00}
mydate = "2016/31/05 13:33";
date = mydate.ToDateTime("yyyy/d/M HH:mm"); // {31.05.2016 13:33:00}
mydate = "2016/31 Ocak";
date = mydate.ToDateTime("yyyy/d MMMM"); // {31.01.2016 00:00:00}
mydate = "2016/31 January";
date = mydate.ToDateTime("yyyy/d MMMM", cultureString: "en-US");
// {31.01.2016 00:00:00}
mydate = "11/شعبان/1437";
date = mydate.ToDateTime(
culture: CultureInfo.GetCultureInfo("ar-SA"),
format: "dd/MMMM/yyyy");
// Weird :) I supposed dd/yyyy/MMMM but that did not work !?$^&*
System.Diagnostics.Debug.Assert(
date.Equals(new DateTime(year: 2016, month: 5, day: 18)));
}
}
}
I tried various ways. What worked for me was this:
Convert.ToDateTime(data, CultureInfo.InvariantCulture);
data for me was times like this 9/24/2017 9:31:34 AM
Try the below, where strDate is your date in 'MM/dd/yyyy' format
var date = DateTime.Parse(strDate,new CultureInfo("en-US", true))
Convert.ToDateTime or DateTime.Parse
DateTime.Parse
Syntax:
DateTime.Parse(String value)
DateTime.Parse(String value, IFormatProvider provider)
DateTime.Parse(String value, IFormatProvider provider, DateTypeStyles styles)
Example:
string value = "1 January 2019";
CultureInfo provider = new CultureInfo("en-GB");
DateTime.Parse(value, provider, DateTimeStyles.NoCurrentDateDefault););
Value: string representation of date and time.
Provider: object which provides culture specific info.
Styles: formatting options that customize string parsing for some date and time parsing methods. For instance, AllowWhiteSpaces is a value which helps to ignore all spaces present in string while it parse.
It's also worth remembering DateTime is an object that is stored as number internally in the framework, Format only applies to it when you convert it back to string.
Parsing converting a string to the internal number type.
Formatting converting the internal numeric value to a readable
string.
I recently had an issue where I was trying to convert a DateTime to pass to Linq what I hadn't realised at the time was format is irrelevant when passing DateTime to a Linq Query.
DateTime SearchDate = DateTime.Parse(searchDate);
applicationsUsages = applicationsUsages.Where(x => DbFunctions.TruncateTime(x.dateApplicationSelected) == SearchDate.Date);
Full DateTime Documentation
string input;
DateTime db;
Console.WriteLine("Enter Date in this Format(YYYY-MM-DD): ");
input = Console.ReadLine();
db = Convert.ToDateTime(input);
//////// this methods convert string value to datetime
///////// in order to print date
Console.WriteLine("{0}-{1}-{2}",db.Year,db.Month,db.Day);
You could also use DateTime.TryParseExact() as below if you are unsure of the input value.
DateTime outputDateTimeValue;
if (DateTime.TryParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff", System.Globalization.CultureInfo.InvariantCulture, System.Globalization.DateTimeStyles.None, out outputDateTimeValue))
{
return outputDateTimeValue;
}
else
{
// Handle the fact that parse did not succeed
}
I just found an elegant way:
Convert.ChangeType("2020-12-31", typeof(DateTime));
Convert.ChangeType("2020/12/31", typeof(DateTime));
Convert.ChangeType("2020-01-01 16:00:30", typeof(DateTime));
Convert.ChangeType("2020/12/31 16:00:30", typeof(DateTime), System.Globalization.CultureInfo.GetCultureInfo("en-GB"));
Convert.ChangeType("11/شعبان/1437", typeof(DateTime), System.Globalization.CultureInfo.GetCultureInfo("ar-SA"));
Convert.ChangeType("2020-02-11T16:54:51.466+03:00", typeof(DateTime)); // format: "yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffzzz"
Put this code in a static class> public static class ClassName{ }
public static DateTime ToDateTime(this string datetime, char dateSpliter = '-', char timeSpliter = ':', char millisecondSpliter = ',')
{
try
{
datetime = datetime.Trim();
datetime = datetime.Replace(" ", " ");
string[] body = datetime.Split(' ');
string[] date = body[0].Split(dateSpliter);
int year = date[0].ToInt();
int month = date[1].ToInt();
int day = date[2].ToInt();
int hour = 0, minute = 0, second = 0, millisecond = 0;
if (body.Length == 2)
{
string[] tpart = body[1].Split(millisecondSpliter);
string[] time = tpart[0].Split(timeSpliter);
hour = time[0].ToInt();
minute = time[1].ToInt();
if (time.Length == 3) second = time[2].ToInt();
if (tpart.Length == 2) millisecond = tpart[1].ToInt();
}
return new DateTime(year, month, day, hour, minute, second, millisecond);
}
catch
{
return new DateTime();
}
}
In this way, you can use
string datetime = "2009-05-08 14:40:52,531";
DateTime dt0 = datetime.TToDateTime();
DateTime dt1 = "2009-05-08 14:40:52,531".ToDateTime();
DateTime dt5 = "2009-05-08".ToDateTime();
DateTime dt2 = "2009/05/08 14:40:52".ToDateTime('/');
DateTime dt3 = "2009/05/08 14.40".ToDateTime('/', '.');
DateTime dt4 = "2009-05-08 14:40-531".ToDateTime('-', ':', '-');
String now = DateTime.Now.ToString("YYYY-MM-DD HH:MI:SS");//make it datetime
DateTime.Parse(now);
this one gives you
2019-08-17 11:14:49.000
Different cultures in the world write date strings in different ways. For example, in the US 01/20/2008 is January 20th, 2008. In France this will throw an InvalidFormatException. This is because France reads date-times as Day/Month/Year, and in the US it is Month/Day/Year.
Consequently, a string like 20/01/2008 will parse to January 20th, 2008 in France, and then throw an InvalidFormatException in the US.
To determine your current culture settings, you can use System.Globalization.CultureInfo.CurrentCulture.
string dateTime = "01/08/2008 14:50:50.42";
DateTime dt = Convert.ToDateTime(dateTime);
Console.WriteLine("Year: {0}, Month: {1}, Day: {2}, Hour: {3}, Minute: {4}, Second: {5}, Millisecond: {6}",
dt.Year, dt.Month, dt.Day, dt.Hour, dt.Minute, dt.Second, dt.Millisecond);
This worked for me:
CultureInfo provider = CultureInfo.InvariantCulture;
DateTime dt = DateTime.ParseExact("2009-05-08 14:40:52,531","yyyy-MM-dd HH:mm:ss,fff", provider);
Do you want it fast?
Let's say you have a date with format yyMMdd.
The fastest way to convert it that I found is:
var d = new DateTime(
(s[0] - '0') * 10 + s[1] - '0' + 2000,
(s[2] - '0') * 10 + s[3] - '0',
(s[4] - '0') * 10 + s[5] - '0')
Just, choose the indexes according to your date format of choice. If you need speed probably you don't mind the 'non-generic' way of the function.
This method takes about 10% of the time required by:
var d = DateTime.ParseExact(s, "yyMMdd", System.Globalization.CultureInfo.InvariantCulture);
I have date represented as integer like 20140820 and I want to parsing it as datetime, like 2014.08.20.
Do I need to parse each integer value (2014)(08)(02) using index or is there simpler way?
If your CurrentCulture supports yyyyMMdd format as a standard date and time format, you can just use DateTime.Parse method like;
int i = 20140820;
DateTime dt = DateTime.Parse(i.ToString());
If it doesn't support, you need to use DateTime.ParseExact or DateTime.TryParseExact methods to parse it as custom date and time format.
int i = 20140820;
DateTime dt;
if(DateTime.TryParseExact(i.ToString(), "yyyyMMdd",
CultureInfo.InvariantCulture,
DateTimeStyles.None, out dt))
{
Console.WriteLine(dt);
}
Then you can format your DateTime with .ToString() method like;
string formattedDateTime = dt.ToString("yyyy.MM.dd", CultureInfo.InvariantCulture);
The easiest and most performance way would be something like:
int date = 20140820;
int d = date % 100;
int m = (date / 100) % 100;
int y = date / 10000;
var result = new DateTime(y, m, d);
Try This :-
string time = "20140820";
DateTime theTime= DateTime.ParseExact(time,
"yyyyMMdd",
CultureInfo.InvariantCulture,
DateTimeStyles.None);
OR
string str = "20140820";
string[] format = {"yyyyMMdd"};
DateTime date;
DateTime.TryParseExact(str,
format,
System.Globalization.CultureInfo.InvariantCulture,
System.Globalization.DateTimeStyles.None,
out date))
now date variable will have required converted date of string '20140820'
int sampleDate = 20140820;
var dateFormat = DateTime.ParseExact(sampleDate.ToString(), "yyyyMMdd",
CultureInfo.InvariantCulture).ToString("yyyy.MM.dd");
result:
2014.08.20
So, we have two competing implementations,
using System;
using System.Globalization;
public class Program
{
public static void Main()
{
int i = 20140820;
Console.WriteLine($"StringParse:{StringParse.Parse(i)}");
Console.WriteLine($"MathParse:{MathParse.Parse(i)}");
}
}
public static class StringParse
{
public static DateTime Parse(int i)
{
return DateTime.ParseExact(
i.ToString().AsSpan(),
"yyyyMMdd".AsSpan(),
CultureInfo.InvariantCulture);
}
}
public static class MathParse
{
public static DateTime Parse(int i)
{
return new DateTime(
Math.DivRem(Math.DivRem(i, 100, out var day), 100, out var month),
month,
day);
}
}
The string approach is probably safer and probably handles edge cases better.
Both will be fast and unlikely to be a performance bottle neck but it is my untested assertion that the math approach probably has better performance.
How can I change only the time in my DateTime variable "s"?
DateTime s = some datetime;
You can't change a DateTime value - it's immutable. However, you can change the variable to have a new value. The easiest way of doing that to change just the time is to create a TimeSpan with the relevant time, and use the DateTime.Date property:
DateTime s = ...;
TimeSpan ts = new TimeSpan(10, 30, 0);
s = s.Date + ts;
s will now be the same date, but at 10.30am.
Note that DateTime disregards daylight saving time transitions, representing "naive" Gregorian time in both directions (see Remarks section in the DateTime docs). The only exceptions are .Now and .Today: they retrieve current system time which reflects these events as they occur.
This is the kind of thing which motivated me to start the Noda Time project, which is now production-ready. Its ZonedDateTime type is made "aware" by linking it to a tz database entry.
Alright I'm diving in with my suggestion, an extension method:
public static DateTime ChangeTime(this DateTime dateTime, int hours, int minutes, int seconds, int milliseconds)
{
return new DateTime(
dateTime.Year,
dateTime.Month,
dateTime.Day,
hours,
minutes,
seconds,
milliseconds,
dateTime.Kind);
}
Then call:
DateTime myDate = DateTime.Now.ChangeTime(10,10,10,0);
It's important to note that this extension returns a new date object, so you can't do this:
DateTime myDate = DateTime.Now;
myDate.ChangeTime(10,10,10,0);
But you can do this:
DateTime myDate = DateTime.Now;
myDate = myDate.ChangeTime(10,10,10,0);
s = s.Date.AddHours(x).AddMinutes(y).AddSeconds(z);
In this way you preserve your date, while inserting a new hours, minutes and seconds part to your liking.
one liner
var date = DateTime.Now.Date.Add(new TimeSpan(4, 30, 0));
would bring back todays date with a time of 4:30:00, replace DateTime.Now with any date object
DateTime is an immutable type, so you can't change it.
However, you can create a new DateTime instance based on your previous instance. In your case, it sounds like you need the Date property, and you can then add a TimeSpan that represents the time of day.
Something like this:
var newDt = s.Date + TimeSpan.FromHours(2);
If you already have the time stored in another DateTime object you can use the Add method.
DateTime dateToUse = DateTime.Now();
DateTime timeToUse = new DateTime(2012, 2, 4, 10, 15, 30); //10:15:30 AM
DateTime dateWithRightTime = dateToUse.Date.Add(timeToUse.TimeOfDay);
The TimeOfDay property is a TimeSpan object and can be passed to the Add method. And since we use the Date property of the dateToUse variable we get just the date and add the time span.
Simplest solution :
DateTime s = //some Datetime that you want to change time for 8:36:44 ;
s = new DateTime(s.Year, s.Month, s.Day, 8, 36, 44);
And if you need a specific Date and Time Format :
s = new DateTime(s.Year, s.Month, s.Day, 8, 36, 44).ToString("yyyy-MM-dd h:mm:ss");
You can assign an initial value to a new DateTime value in many different ways:
Extension Method
Extension method DateTime
public static DateTime ChangeTime(this DateTime dateTime, int hours, int minutes, int seconds = default, int milliseconds = default)
{
return new DateTime(dateTime.Year, dateTime.Month, dateTime.Day, hours, minutes, seconds, milliseconds, dateTime.Kind);
}
then using ChangeTime:
DateTime datetime = DateTime.Now; //Your DateTime
datetime = datetime.ChangeTime(12, 20, 10);
using the Add methods
DateTime datetime = DateTime.Now; //Your DateTime
datetime = datetime.Date.AddHours(12).AddMinutes(20).AddSeconds(10);
using the Timespan
DateTime datetime = DateTime.Now; //Your DateTime
datetime = datetime.Date.Add(new TimeSpan(12, 20, 10));
using initial value
DateTime datetime = DateTime.Now;
datetime = new DateTime(datetime.Year, datetime.Month, datetime.Day, 12, 20, 10);
DateTime ts = DateTime.Now;
ts = new DateTime ( ts.Year, ts.Month, ts.Day, 0, 0, 0 ) ;
Console.WriteLine ( "Today = " + ts.ToString("M/dd/yy HH:mm:ss") ) ;
Executed:
Today = 9/04/15 00:00:00
Happened upon this post as I was looking for the same functionality this could possibly do what the guy wanted. Take the original date and replace the time part
DateTime dayOpen = DateTime.Parse(processDay.ToShortDateString() + " 05:00 AM");
Adding .Date to your date sets it to midnight (00:00).
MyDate.Date
Note The equivavalent SQL is CONVERT(DATETIME, CONVERT(DATE, #MyDate))
What makes this method so good is that it's both quick to type and easy to read. A bonus is that there is no conversion from strings.
I.e. To set today's date to 23:30, use:
DateTime.Now.Date.AddHours(23).AddMinutes(30)
You can of course replace DateTime.Now or MyDate with any date of your choice.
Since DateTime is immutable, a new instance has to be created when a date component needs to be changed. Unfortunately, there is no built-in functionality to set individual components of a DateTime instance.
Using the following extension methods
public static DateTime SetPart(this DateTime dateTime, int? year, int? month, int? day, int? hour, int? minute, int? second)
{
return new DateTime(
year ?? dateTime.Year,
month ?? dateTime.Month,
day ?? dateTime.Day,
hour ?? dateTime.Hour,
minute ?? dateTime.Minute,
second ?? dateTime.Second
);
}
public static DateTime SetYear(this DateTime dateTime, int year)
{
return dateTime.SetPart(year, null, null, null, null, null);
}
public static DateTime SetMonth(this DateTime dateTime, int month)
{
return dateTime.SetPart(null, month, null, null, null, null);
}
public static DateTime SetDay(this DateTime dateTime, int day)
{
return dateTime.SetPart(null, null, day, null, null, null);
}
public static DateTime SetHour(this DateTime dateTime, int hour)
{
return dateTime.SetPart(null, null, null, hour, null, null);
}
public static DateTime SetMinute(this DateTime dateTime, int minute)
{
return dateTime.SetPart(null, null, null, null, minute, null);
}
public static DateTime SetSecond(this DateTime dateTime, int second)
{
return dateTime.SetPart(null, null, null, null, null, second);
}
you can set individual DateTime components like
var now = DateTime.Now;
now.SetSecond(0);
When you construct your DateTime object, use a constructor that allows you to specify time:
var myDateTime = new DateTime(2000, 01, 01, 13, 37, 42); // 2000-01-01 13:37:42
If you already have a DateTime object and wish to change the time, uou can add minutes, hours or seconds to your DateTime using simple methods:
var myDateTime = new DateTime(2000, 01, 01); // 2000-01-01 00:00:00
myDateTime = myDateTime.AddHours(13); // 2000-01-01 13:00:00
myDateTime = myDateTime.AddMinutes(37); // 2000-01-01 13:37:00
myDateTime = myDateTime.AddSecounds(42); // 2000-01-01 13:37:42
Notice how we have to "save" the result from each method call to the myDateTime variable. This is because the DateTime is immutable, and its methods simply create new instances with the extra hours/minutes/seconds added.
If you need to add both hours and minutes (and/or seconds) and the same time, you can simplify the code by adding a TimeSpan to the original DateTime instead:
var myDateTime = new DateTime(2000, 01, 01); // 2000-01-01 00:00:00
myDateTime += new TimeSpan(13, 37, 42); // 2000-01-01 13:37:42
If you want to set absolute hours/minues/seconds, rather than adding to the existing values, you can use the aforementioned DateTime constructor, and reuse values for year/month/day from earlier:
myDateTime = new DateTime(myDateTime.Year, myDateTime.Month, myDateTime.Day,
20, 33, 19) // 2000-01-01 20:33:19
In fact, you can't change the time once it's created.
But you can create it easily with many constructors:
https://learn.microsoft.com/en-us/dotnet/api/system.datetime.-ctor?view=netframework-4.7.2
For example, if you want to create a DateTime changing Seconds, you can just do this:
DateTime now = DateTime.Now;
DateTime secondschanged = new DateTime(now.Year, now.Month, now.Day, now.Hour, now.Minute, yourseconds);
If you have a DateTime like 2014/02/05 18:19:51 and want just 2014/02/05, you can do that:
_yourDateTime = new DateTime(_yourDateTime.Year, _yourDateTime.Month, _yourDateTime.Day)
Use Date.Add and add a New TimeSpan with the new time you want to add
DateTime dt = DateTime.Now
dt.Date.Add(new TimeSpan(12,15,00))
int year = 2012;
int month = 12;
int day = 24;
int hour = 0;
int min = 0;
int second = 23;
DateTime dt = new DateTime(year, month, day, hour, min, second);
To set end of a day:
date = new DateTime(date.Year, date.Month, date.Day, 23, 59, 59);
Here is a method you could use to do it for you, use it like this
DateTime newDataTime = ChangeDateTimePart(oldDateTime, DateTimePart.Seconds, 0);
Here is the method, there is probably a better way, but I just whipped this up:
public enum DateTimePart { Years, Months, Days, Hours, Minutes, Seconds };
public DateTime ChangeDateTimePart(DateTime dt, DateTimePart part, int newValue)
{
return new DateTime(
part == DateTimePart.Years ? newValue : dt.Year,
part == DateTimePart.Months ? newValue : dt.Month,
part == DateTimePart.Days ? newValue : dt.Day,
part == DateTimePart.Hours ? newValue : dt.Hour,
part == DateTimePart.Minutes ? newValue : dt.Minute,
part == DateTimePart.Seconds ? newValue : dt.Second
);
}
I have just come across this post because I had a similar issue whereby I wanted to set the time for an Entity Framework object in MVC that gets the date from a view (datepicker) so the time component is 00:00:00 but I need it to be the current time. Based on the answers in this post I came up with:
myEntity.FromDate += DateTime.Now.TimeOfDay;
//The fastest way to copy time
DateTime justDate = new DateTime(2011, 1, 1); // 1/1/2011 12:00:00AM the date you will be adding time to, time ticks = 0
DateTime timeSource = new DateTime(1999, 2, 4, 10, 15, 30); // 2/4/1999 10:15:30AM - time tick = x
justDate = new DateTime(justDate.Date.Ticks + timeSource.TimeOfDay.Ticks);
Console.WriteLine(justDate); // 1/1/2011 10:15:30AM
Console.Read();
DateTime s;
//s = datevalue
s = s.AddMilliseconds(10);
s = s.AddMinutes(10);
s = s.AddSeconds(10);
s = s.AddHours(10);
you could add +ve/-ve values in parameter.
s.Add(new TimeSpan(1, 1, 1));
Doesn't that fix your problems??
Dateime dt = DateTime.Now;
dt = dt.AddSeconds(10);
I prefer this:
DateTime s = //get some datetime;
s = new DateTime(s.Year, s.Month,s.Day,s.Hour,s.Minute,0);
Using an extencion to DateTime:
public enum eTimeFragment
{
hours,
minutes,
seconds,
milliseconds
}
public static DateTime ClearTimeFrom(this DateTime dateToClear, eTimeFragment etf)
{
DateTime dtRet = dateToClear;
switch (etf)
{
case eTimeFragment.hours:
dtRet = dateToClear.Date;
break;
case eTimeFragment.minutes:
dtRet = dateToClear.AddMinutes(dateToClear.Minute * -1);
dtRet = dtRet.ClearTimeFrom(eTimeFragment.seconds);
break;
case eTimeFragment.seconds:
dtRet = dateToClear.AddSeconds(dateToClear.Second * -1);
dtRet = dtRet.ClearTimeFrom(eTimeFragment.milliseconds);
break;
case eTimeFragment.milliseconds:
dtRet = dateToClear.AddMilliseconds(dateToClear.Millisecond * -1);
break;
}
return dtRet;
}
Use like this:
Console.WriteLine (DateTime.Now.ClearTimeFrom(eTimeFragment.hours))
this has to return:
2016-06-06 00:00:00.000
What's wrong with DateTime.AddSeconds method where you can add or substract seconds?
Try this one
var NewDate = Convert.ToDateTime(DateTime.Now.ToString("dd/MMM/yyyy")+" "+"10:15 PM")/*Add your time here*/;
The best solution is:
currdate.AddMilliseconds(currdate.Millisecond * -1).AddSeconds(currdate.Second * -1).AddMinutes(currdate.Minute * -1).AddHours(currdate.Hour * -1);
here is a ghetto way, but it works :)
DateTime dt = DateTime.Now; //get a DateTime variable for the example
string newSecondsValue = "00";
dt = Convert.ToDateTime(dt.ToString("MM/dd/yyyy hh:mm:" + newSecondsValue));