We Keep Coding

Opening the varbinary column in a popup window using contenttype

I am making a file uploader using html tags. I have id, Name and Data in my table. Data is storing the contents of the file in binary format in a column of datatype varbinary(max). I am able to successfully upload the file and I am also able to read the byte array back.
Code for upload at code behind:
protected void Upload(object sender, EventArgs e)
{
string filename = Path.GetFileName(FileUpload1.PostedFile.FileName);
string contentType = FileUpload1.PostedFile.ContentType;
using (Stream fs = FileUpload1.PostedFile.InputStream)
{
using (BinaryReader br = new BinaryReader(fs))
{
byte[] bytes = br.ReadBytes((Int32)fs.Length);
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
string query = "insert into FileUploader2 values (#Name, #ContentType, #Data)";
using (SqlCommand cmd = new SqlCommand(query))
{
cmd.Connection = con;
cmd.Parameters.AddWithValue("#Name", filename);
cmd.Parameters.AddWithValue("#ContentType", contentType);
cmd.Parameters.AddWithValue("#Data", bytes);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
Context.Response.Write("Uploaded Successfully!");
}
}
}
}
Response.Redirect(Request.Url.AbsoluteUri);
}
I am also creating a grid which shows me list of files along with an icon which when clicked will view me the file after reading the byte array. I have a JS function on that onclick which I am accessing through WebMethod at code-behind. Following is my code when user clicks on view icon:
[System.Web.Services.WebMethod]
public static void ShowDocument()
{
string filename = string.Empty;
string contentType = string.Empty;
byte[] bytes = null;
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
con.Open();
using (SqlCommand com = new SqlCommand("SELECT * FROM FileUploader2", con))
{
using (SqlDataReader reader = com.ExecuteReader())
{
if (reader.Read())
{
filename = (string)reader["Name"];
contentType = (string)reader["ContentType"];
bytes = (byte[])reader["Data"];
}
}
}
}
System.Web.HttpContext.Current.Response.ContentType = contentType;
System.Web.HttpContext.Current.Response.AddHeader("Content-Disposition", "attachment;
filename=" + filename);
System.Web.HttpContext.Current.Response.OutputStream.Write(bytes, 0, bytes.Length);
System.Web.HttpContext.Current.Response.Flush();
}
This code is working fine as well and correctly reads all the columns. Now after reading, I want to view the file as well in a pop window. How can I do so? I think I have to take contenttype to let it know what type of file I want to open and then use the bytes to do so. But I have no idea how to achieve that.

Store a File Size in a database table using file upload controle

I need to save a file size in database table while uploading a file in using upload control.
i am simple pitching my upload control code here.
Please take a look.
protected void UploadFileControl(object sender, EventArgs e)
{
string fileName = Path.GetFileName(FileUpload1.PostedFile.FileName);
string contentType = FileUpload1.PostedFile.ContentType;
using (Stream fs = FileUpload1.PostedFile.InputStream)
{
using (BinaryReader br = new BinaryReader(fs))
{
byte[] bytes = br.ReadBytes((Int32)fs.Length);
using (SqlConnection con = new SqlConnection(con))
{
string str = "INSERT INTO XYZ VALUES (#FileName, #ContentType, #Data)";
using (SqlCommand cmd = new SqlCommand(str))
{
cmd.Connection = con;
cmd.Parameters.AddWithValue("#FileName", fileName);
cmd.Parameters.AddWithValue("#ContentType", contentType);
cmd.Parameters.AddWithValue("#Data", bytes);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}
}
}
}
This is simple upload control code.

ORA-01460: unimplemented or unreasonable conversion requested-uploading files

Following is the code to upload file in party_images table.
protected void upload_Click(object sender, EventArgs e)
{
try
{
using (OracleConnection connection = new OracleConnection(conString))
{
connection.Open();
string filename = Path.GetFileName(FileUpload1.FileName);
string[] tokenize = filename.Split('.');
FileUpload1.SaveAs(Server.MapPath("~/files/") + descBox.Text + "." + tokenize[1]);
string sourceLoc = Server.MapPath("~/files/" + descBox.Text + "." + tokenize[1]);
FileStream fs = new FileStream(sourceLoc, FileMode.Open, FileAccess.Read);
byte[] ImageData = new byte[fs.Length];
fs.Read(ImageData, 0, System.Convert.ToInt32(fs.Length));
fs.Close();
String block = " BEGIN " +
" INSERT INTO party_images(party_id, sr_no, descr, party_image) VALUES ('"+Session["userId"]+"',"+srNo.Text+",'"+descBox.Text+"."+tokenize[1]+"', :1); " +
" END; ";
OracleCommand cmd = new OracleCommand();
cmd.CommandText = block;
cmd.Connection = connection;
cmd.CommandType = CommandType.Text;
OracleParameter param = cmd.Parameters.Add("blobtodb", OracleDbType.LongRaw);
param.Direction = ParameterDirection.Input;
param.Value = ImageData;
cmd.ExecuteNonQuery();
descBox.Text = "";
srNo.Text = "";
}
}
catch (Exception ex) {
ClientScript.RegisterStartupScript(this.GetType(), "unSuccessMessage", "window.onload = function(){ alert('"+ex.Message+"')};", true);
}
finally
{
populateGrid(loadFromDb());
}
}
table description is,
PARTY_ID is VARCHAR2(10)
SR_NO is NUMBER
DESCR is VARCHAR2(50)
PARTY_IMAGE is LONG RAW()
This function is uploading all the files i.e., images,.docx,.pdf,.sql but when I upload any .docx containing screen shots or pictures then the upper error appears.
I have tried the following links,
ORA-01460: unimplemented or unreasonable conversion requested
The requested format conversion is not supported.
ORA-01460: unimplemented or unreasonable conversion requested
But I haven't got any solution. How can I upload any type of file without having this error?

Why are you using LONG RAW to store binary objects? That's a datatype which has been deprecated for over twenty years.
If you define PARTY_IMAGE as a BLOB (or maybe BFILE) you will find it a lot easier to work with. Find out more.

Why I am getting one more character?

Hello Im using this C# code for images upload.
protected void UploadFile(object sender, EventArgs e)
{
string filename = Path.GetFileName(FileUpload1.PostedFile.FileName);
string contentType = FileUpload1.PostedFile.ContentType;
using (Stream fs = FileUpload1.PostedFile.InputStream)
{
using (BinaryReader br = new BinaryReader(fs))
{
byte[] bytes = br.ReadBytes((Int32)fs.Length);
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (MySqlConnection con = new MySqlConnection(constr))
{
string query = "INSERT INTO foto(FileName, ContentType, Content) VALUES (#FileName, #ContentType, #Content)";
using (MySqlCommand cmd = new MySqlCommand(query))
{
cmd.Connection = con;
cmd.Parameters.AddWithValue("#FileName", filename);
cmd.Parameters.AddWithValue("#ContentType", contentType);
cmd.Parameters.AddWithValue("#Content", bytes);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}
}
}
Response.Redirect(Request.Url.AbsoluteUri);
}
I upload the image in a longblob field, then to show the image I am using C# WebService, AJAX, JavaScript, converting the image to Base64String but image is displayed like if do not exist.
Here is my Base64String:
Base64String
As you can see the problem is with this extra characters:
AAEAAAD/////AQAAAAAAAAAPAQAAAHgBAAAC
Why this happen? And how can I solve it?

can you replace the bellowed lines with your above code
protected void UploadFile(object sender, EventArgs e)
{
string filename = Path.GetFileName(FileUpload1.PostedFile.FileName);
string contentType = FileUpload1.PostedFile.ContentType;
using (Stream fs = FileUpload1.PostedFile.InputStream)
{
using (BinaryReader br = new BinaryReader(fs))
{
System.Drawing.Image imagetuUpload = System.Drawing.Image.FromStream(fs);
Bitmap bitmap = new Bitmap(imagetuUpload);
System.IO.MemoryStream stream = new MemoryStream();
bitmap.Save(stream, System.Drawing.Imaging.ImageFormat.Jpeg);
stream.Position = 0;
byte[] upproimag = new byte[stream.Length + 1];
stream.Read(upproimag, 0, upproimag.Length);
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (MySqlConnection con = new MySqlConnection(constr))
{
string query = "INSERT INTO foto(FileName, ContentType, Content) VALUES (#FileName, #ContentType, #Content)";
using (MySqlCommand cmd = new MySqlCommand(query))
{
cmd.Connection = con;
cmd.Parameters.AddWithValue("#FileName", filename);
cmd.Parameters.AddWithValue("#ContentType", contentType);
cmd.Parameters.AddWithValue("#Content", upproimag);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}
}
}
Response.Redirect(Request.Url.AbsoluteUri);
}
i hop it may help you :)

long time back i was in same issue i do not remember other than doing this at that time:
I check if I am wrong or not going here:
http://jsfiddle.net/hpP45/
I try to decode first(google bse64 decoder )
https://www.base64decode.org/
and save decoded binary data as an jpeg file and open it.
if it does not open then i guess,there might be issue on your base64 encoding

Image Save and Retrieve in SQL Server in asp.net using c#

I am trying to save images in a SQL Server database.
I convert the image to bytes and store in SQL Server, but now I want to convert the saved bytes to an image and show it on a label in asp.net using c#.
I tried a lot but didn't find a solution.
Here is the code (convert bytes to Image)
if (fImage.HasFile)
{
if (fImage.PostedFile.ContentType == "image/jpg" || fImage.PostedFile.ContentType == "image/jpeg" || fImage.PostedFile.ContentType == "image/png")
{
int filelenght = fImage.PostedFile.ContentLength;
byte[] imagebytes = new byte[filelenght];
fImage.PostedFile.InputStream.Read(imagebytes, 0, filelenght);
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "Insert into tbImage(Img) values(#img)";
cmd.Connection = con;
cmd.Parameters.AddWithValue("#img", imagebytes);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
Response.Write("Image saved to database");
}
}

Something like this will convert Byte[] to Image:
MemoryStream ms = new MemoryStream(byte);
Image i = Image.FromStream(ms);

SqlCommand cmd = new SqlCommand("Select img from tbImage where id = " + id, con);
con.Open();
SqlDataReader reader = cmd.ExecuteReader();
if (reader.HasRows)
{
while (reader.Read())
{
byte[] img = (byte[])reader["img"];
MemoryStream ms = new MemoryStream(img);
PictureBox1.Image = Image.FromStream(ms);
}
}
con.Close();

All you need to do is to store the byte content in a variable and then write it to the File system:
var imgBlob = ... // Load the image binary array from the database
File.WriteAllBytes("path/to/file.jpg", imgBlob);

you can create a controller action to handle retrieving the image
public FileResult DownloadImage(int Photo_Id)
{
byte[] fileBytes = "get bytes from db here";
string fileName = "file name here"
return File(fileBytes, "contentType of the image" , fileName);
}

Thanks for your valuable reply.
i solve this problem with this one.
give a look.
int id = Convert.ToInt32(drpImage.SelectedValue);
SqlCommand cmd = new SqlCommand("Select img from tbImage where id = " + id+"", con);
con.Open();
SqlDataReader dr = null;
dr = cmd.ExecuteReader();
if (dr.HasRows)
{
while (dr.Read())
{
byte[] img = (byte[])dr["img"];
string base64string = Convert.ToBase64String(img, 0, img.Length);
lblImage.Text += "<img src='data:image/png;base64," + base64string + "' alt='No Image' width='200px' vspace='5px' hspace='5px' />";
}
}
con.Close();