PayPal Pay Operation - error 81002 - c#

I'm not sure why this PayPal Pay operation is giving me this error even though I seem to have covered all the required fields:
Error Code: 81002 Severity: Error Message: Unspecified Method (Method Specified is not Supported)"
string postData = JsonConvert.SerializeObject(request);
value of postData:
"actionType=PAY
&currencyCode=USD
&cancelUrl=https%3a%2f%2fexample.com%2fcancel
&returnUrl=https%3a%2f%2fexample.com%2freturn
&requestenvelope.errorLanguage=en_US
&receiverList.receiver(0).email=recipientemail%40gmail.com
&receiverList.receiver(0).amount=0.05
&VERSION=94.0
&USER=bizemail-facilitator_api1.gmail.com
&PWD=xxxxx
&SIGNATURE=xxxxxxxxx"
Here's how I do the post:
SendRequest("https://api-3t.sandbox.paypal.com/nvp", postData);
public string SendRequest(string url, string postData)
{
var uri = new Uri(url);
var request = WebRequest.Create(uri);
var encoding = new UTF8Encoding();
var requestData = encoding.GetBytes(postData);
request.ContentType = "application/x-www-form-urlencoded";
request.Method = "POST";
request.Timeout = (300*1000); //TODO: Move timeout to config
request.ContentLength = requestData.Length;
using (var stream = request.GetRequestStream()) {
stream.Write(requestData, 0, requestData.Length);
}
var response = request.GetResponse();
string result;
using (var reader = new StreamReader(response.GetResponseStream(), Encoding.ASCII)) {
result = reader.ReadToEnd();
}
return result;
}

The method PAY doesn't exist on the NVP api. Full list of methods supported by that API is found here.
The PAY method, however, is defined in the Adaptive Payments API. Depending on your needs, you have two options:
Change the endpoint to https://svcs.paypal.com/AdaptivePayments/PAY and modify your values
Use another method, like DoDirectPayment, but I'm not sure it does what you want to.

I assume the value of postData is before you serialize it to a JSON string, instead of after as you say, since it is clearly not a JSON string.
If so, then it is already x-www-form-urlencoded, and you do not need to serialize it to a JSON string at all.
Or if you do after all, then change just this: request.ContentType = "application/json";

Related

Unable to post to merchant API due to error saying I must provide a request body

I spent all day trying to figure out what I was doing wrong yesterday.
Coming here to try and find some help.
The follow error is triggered when I run the actual GetResponse.
I am new to APIs so I am sure I am missing something real simple.
You must provide a request body if you set ContentLength>0 or SendChunked==true. Do this by calling [Begin]GetRequestStream before [Begin]GetResponse.
Here is my code I am using to try and send JSON to the API. Payment object just has the form values entered in and the credentials to use the correct account on the merchants end.
var json = JsonConvert.SerializeObject(payment);
var apiUrl = new Uri($"Removed endpoint URL");
var postBytes = Encoding.UTF8.GetBytes(json);
ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;
var httpWebRequest = (HttpWebRequest)WebRequest.Create(apiUrl);
httpWebRequest.ContentType = "application/json";
httpWebRequest.Accept = "application/json";
httpWebRequest.Method = "POST";
httpWebRequest.ContentLength = postBytes.Length;
httpWebRequest.AllowWriteStreamBuffering = false;
//This is where the error triggers and drops to the catch.
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
I appreciate any help in advance, I may be doing this completely wrong, its a series of things I threw together trying to fix issues with the call.
Unless I missed it, you're not actually writing your payload data to the HttpWebRequest body before you're sending it.
using (Stream _reqStrm = httpWebRequest.GetRequestStream())
{
_reqStrm.Write(postBytes, 0, postBytes.Length);
}
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
....
Unrelated but if you can, consider HttpClient
Hth..

Debugging an HttpWebResponse

This is being done on a Windows Forms App. I've spent a ton of time stepping through this code with the debugger. What I've found are the following things and they all seem to be at this line:
using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
1. If I include
request.SendChunked = true;
I get this error at the response line previously stated:
'System.Net.WebException: The remote server returned an error: (415) Unsupported Media Type.
2. If I comment out the code in #1, I receive this error at that main response line that I mentioned in the beginning:
'System.Net.WebException: The underlying connection was closed: The connection was closed unexpectedly.
3. If I go with route #1, the "Connection" of the request remains as "KeepAlive" all the way through. But if I go with route #2, the "Connection" of the request changes to "null" at the response line that I mentioned in the beginning.
private void HttpPost()
{
HttpWebRequest request = null;
Uri uri = new Uri("https://post.craigslist.org/bulk-rss/post");
request = (HttpWebRequest)WebRequest.Create(uri);
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
XmlDocument doc = new XmlDocument();
doc.Load("XMLFile1.xml");
//request.ContentLength = doc.InnerXml.Length;
request.SendChunked = true;
using (Stream writeStream = request.GetRequestStream())
{
UTF8Encoding encoding = new UTF8Encoding();
byte[] bytes = encoding.GetBytes(doc.InnerXml);
//request.ContentLength = bytes.Length;
writeStream.Write(bytes, 0, bytes.Length);
}
string result = string.Empty;
request.ProtocolVersion = System.Net.HttpVersion.Version11;
request.KeepAlive = false;
try
{
using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
using (System.IO.StreamReader readStream = new System.IO.StreamReader(responseStream, Encoding.UTF8))
{
result = readStream.ReadToEnd();
}
}
}
}
catch (Exception e)
{
string innerException = String.Format("Inner exception: '{0}'", e.Data);
string exceptionCause = String.Format("An error occurred: '{0}'", e);
System.IO.File.WriteAllText(#"C:\Users\Nathan\Documents\DebugOutputFile\exception.txt", exceptionCause);
System.IO.File.WriteAllText(#"C:\Users\Nathan\Documents\DebugOutputFile\innerException.txt", innerException);
}
}
I feel like these things are adding up towards a solution, but I could really use some guidance.
Option 1: Change your content type to match the body encoding
request.ContentType = "application/xml";
Option 2: Change your body encoding to match the specified content-type
If your server expects only "application/x-www-form-urlencoded", then you need to change your body encoding to suit it, for example, like this:
using (Stream writeStream = request.GetRequestStream())
{
UTF8Encoding encoding = new UTF8Encoding();
string response = String.Concat("arg=", HttpUtility.UrlEncode(doc.InnerXml))
byte[] bytes = encoding.GetBytes(doc.InnerXml);
//request.ContentLength = bytes.Length;
writeStream.Write(bytes, 0, bytes.Length);
}
You need to know the parameter name (above was set to "arg") and add a reference to System.Web, if you haven't.
See following XML...
<?xml version="1.0" encoding="UTF-8"?><test></test>
and encoded string for reference (your request body should look similar to this):
arg=%3C%3Fxml%20version%3D%221.0%22%20encoding%3D%22UTF-8%22%3F%3E%3Ctest%3E%3C%2Ftest%3E
Explanation
If you look at the response you are getting with the first approach: 415 - Unsupported Media Type, you can notice that the content type you are specifying ("application/x-www-form-urlencoded") doesn't match what you are sending in the body (an XML document). Chunk encoding should be enabled when sending files.
Note
When you are having trouble with a request done in source code, try to test the request alone with a web debugging tool, like Fiddler. There you would compose and issue the request until you get the response you want. Then you can compare that with what you are sending from source code (again you should use the same tool for inspecting your request).

Simple REST request c# - error

I am trying write simple request to REST service.Follow to documentation from REST Service provider:
I should use in header Content-Type: application/json.
Response return in json format
For authorization proccess I have to send two headers one with APIKey and second with APISign
Controller PING in REST service to test code.
I use .net 2.0
string sha1String = APIKey + "/rest/ping" + APISecret;
string XRestApiSign = SHA1HashStringForUTF8String(sha1String);
string data = "";
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(restServer);
request.Method = "POST";
request.ContentType = "application/json";
request.Headers.Add("X-Rest-ApiSign", XRestApiSign);
request.Headers.Add("X-Rest-ApiKey", APIKey);
request.ContentLength = data.Length;
StreamWriter requestWriter;
Stream webStream = request.GetRequestStream();
using (requestWriter = new StreamWriter(webStream, System.Text.Encoding.ASCII)) ;
{
requestWriter.Write(data);
}
request.BeginGetResponse((x) =>
{
using (HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(x))
{
List<string> list = Newtonsoft.Json.JsonConvert.DeserializeObject<List<string>>(response.GetResponseStream().ToString());
}
}, null);
I should get response string PONG but I get below message
Unexpected character encountered while parsing value: S. Path '', line 0, position 0
Is code OK ? Why I get this message?
This is mostly the case because the script that generates the JSON on the server side adds the byte order mark to the response.
In your case, however, you're trying to convert the stream to JSON, not the content of the stream. You need to read all text from the stream and deserialize the object from that. You need to call one of the methods on the stream that reads the content.
I modified my code with yours suggestion and it works. Now I have problem with send data :)
Subscription user1 = new Subscription
{
Email = "kubaIt#test.com.pl",
List = "xfct2bjcdv",
};
List<Subscription> user = new List<Subscription>();
user.Add(user1);
string json = JsonConvert.SerializeObject(user);
string data = json;
I added above. Other code is the same. I got error :The request was aborted: The request was canceled."
json = [{\"email\":\"kubaIt#test.com.pl\",\"list\":\"xfct2bjcdv\"}] //value from debuger

Moving from standard .NET rest to RestSharp

For the most part, I have managed quite quickly to move my code from standard .NET code to using RestSharp. This has been simple enough for GET processes, but I'm stumped for POST processes
Consider the following
var request = System.Net.WebRequest.Create("https://mytestserver.com/api/usr") as System.Net.HttpWebRequest;
request.Method = "POST";
request.ContentType = "application/json;version=1";
request.Headers.Add("Content-Type", "application/json;version=1");
request.Headers.Add("Accepts", "application/json;version=1");
request.Headers.Add("Authorize", "key {key}");
using (var writer = new System.IO.StreamWriter(request.GetRequestStream())) {
byte[] byteArray = System.Text.Encoding.UTF8.GetBytes("{\n \"firstName\": \"Dan\",\n \"lastName\": \"Eccles\",\n \"preferredNumber\": 1,\n \"email\" : \"testuser#example.com\",\n \"password\": \"you cant get the wood\"\n}");
request.ContentLength = byteArray.Length;
writer.Write(byteArray);
writer.Close();
}
string responseContent;
using (var response = request.GetResponse() as System.Net.HttpWebResponse) {
using (var reader = new System.IO.StreamReader(response.GetResponseStream())) {
responseContent = reader.ReadToEnd();
}
This is fairly straight forward to move across, except for the serialisation code. Is there a particular way this has to be done for RestSharp? I've tried creating an object and using
var json = JsonConvert.SerializeObject(user);
restRequest.RequestFormat = DataFormat.Json;
restRequest.AddBody(json);
but the server still comes back with an error.
I'm also currently using JSON.NET for deserialization to an error object when the user passes in bad data. Is there a way I can deserialize to error object based on a single string using RestSharp?
You're close, but you don't need to worry about serialization with RestSharp.
var request = new RestRequest(...);
request.RequestFormat = DataFormat.Json;
request.AddBody(user); // user is of type User (NOT string)
By telling it that the format is JSON, then passing your already-serialized-as-JSON string, RestSharp is actually encoding it again as a string.
So you pass the string: {"firstName":"foo"} and it actually gets sent to the server as a JSON string object: "{\"firstName\":\"foo\"}" (note how your JSON is escaped as a string literal), which is why it's failing.
Note you can also use an anonymous object for the request:
var request = new RestRequest(...);
request.RequestFormat = DataFormat.Json;
request.AddBody(new{
firstName = "Dan",
lastName = "Eccles",
preferredNumber = 1,
// etc..
});
You use the same typed objects with the response (eg, RestSharp deserializes for you):
var response = client.Execute<UserResponse>(request);
// if successful, response.Data is of type UserResponse

WebRequest to connect to the Wikipedia API

This may be a pathetically simple problem, but I cannot seem to format the post webrequest/response to get data from the Wikipedia API. I have posted my code below if anyone can help me see my problem.
string pgTitle = txtPageTitle.Text;
Uri address = new Uri("http://en.wikipedia.org/w/api.php");
HttpWebRequest request = WebRequest.Create(address) as HttpWebRequest;
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
string action = "query";
string query = pgTitle;
StringBuilder data = new StringBuilder();
data.Append("action=" + HttpUtility.UrlEncode(action));
data.Append("&query=" + HttpUtility.UrlEncode(query));
byte[] byteData = UTF8Encoding.UTF8.GetBytes(data.ToString());
request.ContentLength = byteData.Length;
using (Stream postStream = request.GetRequestStream())
{
postStream.Write(byteData, 0, byteData.Length);
}
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
// Get the response stream.
StreamReader reader = new StreamReader(response.GetResponseStream());
divWikiData.InnerText = reader.ReadToEnd();
}
You might want to try a GET request first because it's a little simpler (you will only need to POST for wikipedia login). For example, try to simulate this request:
http://en.wikipedia.org/w/api.php?action=query&prop=images&titles=Main%20Page
Here's the code:
HttpWebRequest myRequest =
(HttpWebRequest)WebRequest.Create("http://en.wikipedia.org/w/api.php?action=query&prop=images&titles=Main%20Page");
using (HttpWebResponse response = (HttpWebResponse)myRequest.GetResponse())
{
string ResponseText;
using (StreamReader reader = new StreamReader(response.GetResponseStream()))
{
ResponseText = reader.ReadToEnd();
}
}
Edit: The other problem he was experiencing on the POST request was, The exception is : The remote server returned an error: (417) Expectation failed. It can be solved by setting:
System.Net.ServicePointManager.Expect100Continue = false;
(This is from: HTTP POST Returns Error: 417 "Expectation Failed.")
I'm currently in the final stages of implementing an C# MediaWiki API which allows the easy scripting of most MediaWiki viewing and editing actions.
The main API is here: http://o2platform.googlecode.com/svn/trunk/O2%20-%20All%20Active%20Projects/O2_XRules_Database/_Rules/APIs/OwaspAPI.cs and here is an example of the API in use:
var wiki = new O2MediaWikiAPI("http://www.o2platform.com/api.php");
wiki.login(userName, password);
var page = "Test"; // "Main_Page";
wiki.editPage(page,"Test content2");
var rawWikiText = wiki.raw(page);
var htmlText = wiki.html(page);
return rawWikiText.line().line() + htmlText;
You seem to be pushing the input data on HTTP POST, but it seems you should use HTTP GET.
From the MediaWiki API docs:
The API takes its input through
parameters in the query string. Every
module (and every action=query
submodule) has its own set of
parameters, which is listed in the
documentation and in action=help, and
can be retrieved through
action=paraminfo.
http://www.mediawiki.org/wiki/API:Data_formats

Categories