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asp.net bind a list to a gridview

List<MasterBook> listOfBooks = new List<MasterBook>();
after i put the masterbook objects which by the way have 3 fields( name,id and active ) into the list
GridView1.DataSource = listOfBooks;
GridView1.DataBind();
in the web form
<Columns>
<asp:TemplateField HeaderText="Book Name">
<ItemTemplate>
<asp:Label ID="BookNameText" runat="server"
Text="<%#Container.DataItem%>">
</asp:Label>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
the problem is that i want to display the bookmaster's name in the gridview column
this code print bookmaster in the column how can i make it type the name

Change:
<%#Container.DataItem%>
To:
<%#Eval("name")%>

Cast it to MasterBook:
Text="<%# ((MasterBook) Container.DataItem).Name %>">

The quick, dirty hack workaround is to overload the ToString() method of your MasterBookclass in order to return that name. Commit seppuku afterwards if you do it.
The elegant and graceful way is to make an object datasource. That way you can bind the grid view's columns to the objects' properties. In the case of a DataList or other templated data controls, you can bind your objects' properties to the data control's child controls in their templates.
The middle path is in hutchonoid's answer: evaluate a property of the object, not the object itself.

Use this sintax:
<asp:Label ID="BookNameText" runat="server"
Text="<%# ((MasterBook)Container.DataItem).Name %>">

Binding a Button to a GridView

This a pretty simple question, I'm just not sure how to do it exactly. I would like to bind a Button or perhaps ImageButton to a GridView in ASP.NET/C#. Currently, the GridView has two columns and is bound to a DataTable with two columns. I want to add a third column to the GridView, which will include the Button.
I know GridView has ButtonField, but I'm not too sure how to go about using it to do what I want. I want to dynamically generate these Buttons and add them to the GridView.
Here is how my GridView looks right now:
<asp:GridView
ID="GridView1"
Runat="server">
<Columns>
<asp:HyperLinkField
HeaderText="Display Name"
DataNavigateUrlFields="DISPNAME"
DataNavigateUrlFormatString="ViewItem.aspx"
DataTextField="DISPNAME">
<ItemStyle Width="70%" />
</asp:HyperLinkField>
<asp:BoundField
DataField="TypeDisp"
HeaderText="Type">
<ItemStyle Width="20%" />
</asp:BoundField>
</Columns>
</asp:GridView>

You can use a template field like the following,
<TemplateField>
<ItemTemplate>
<asp:ImageButton ImageUrl="image url" CommandName="SomeCommand" CommandArgument='<%# Eval("Id") %>'/>
</ItemTemplate>
</TemplateField>
Then you can handle the RowCommand event of the GridView and check the e.CommandName to see what command to be executed and you can get the e.CommandArgument as well which could be the row Id like I used in the code above.

If we are talking a button that's always present, you can use ButtonField, or even use a TemplateField and provide the template with the button, and bind the data to the button (sounds like you may want to bind data to the attributes of the button?)
If you are looking to dynamically generate buttons in the UI, tap into the RowCreated event and add the button the GridView. You'd have to do this on every page load; the GridView won't remember a button created programmatically.
HTH.

GridView - display '0' for all headers when empty data set

I'm using a GridView to display some ifnromation in ASP.NET. I need it to simply display 0 in the gridview fields (there's only ever one row returned) if the dataset is empty, plus of course display the headers. How do I do this?

Yes bind a dummy dataset with one row, with all zeros as fields, to the grid with zeros as the field labels. That would be the best way.

Bind your grid and add the EmptyDataTemplate like so:
<asp:GridView ID="gridview1" runat="server" ShowFooter="true">
<Columns>
<asp:BoundField DataField="id" HeaderText="ID field" />
</Columns>
<EmptyDataTemplate>put whatever you want in here</EmptyDataTemplate>
</asp:GridView>

Gridview with radio column, radio id problem

I have a gridview, and I put a radio column for it. But radio ids are not unique.
I've read
http://www.asp.net/Learn/data-access/tutorial-51-cs.aspx
http://shawpnendu.blogspot.com/2009/02/problem-to-group-radio-button-across.html
https://web.archive.org/web/20210510012500/http://aspnet.4guysfromrolla.com/articles/122602-1.aspx
but they are complicated.
Do you have other solution, with c# code behind? I've also tried to give unique id with a function from code behind, but ID='<%# function(...) %>' is not allowed.
Thank you in advance
there is gridview code:
<asp:GridView ID="gridView_stLists"
runat="server"
AutoGenerateColumns="False"
CellPadding="3"
BorderStyle="NotSet"
CssClass="table_layout"
Width="500">
<RowStyle CssClass="table_body" />
<Columns>
<asp:TemplateField HeaderStyle-Width="20">
<ItemTemplate>
<asp:RadioButton ID="rdBtn_stdl" runat="server"
OnCheckedChanged="rdBtn_stdl_CheckedChanged"
AutoPostBack="True"
GroupName="stdl" value='<%# Eval("uri") %>' />
</ItemTemplate>
I think radios must have different IDs in ID="rdBtn_stdl" section

Not totally sure what your question is, but here goes.
If you need to find a RadioButton in a GridViewRow, first get the row, then use FindControl()
GridViewRow myRow = GridView1.Rows[index];
RadioButton myRadioButton = (RadioButton)myRow.FindControl("nameOfRadioButton")
You can do that in reverse (if you need to handle the event RadioButton1_CheckedChanged, for example) by first casting the object sender to RadioButton, then casting RadioButton.Parent.Parent to GridViewRow, from which you can get the index.
Question:
Is the column you added a Template Column, in which you places a RadioButton? My two solutions will only work in this case.

The radio buttons need to have the same name attribute. Not unique. This is how the browser knows how to group them.

Found a good method at:
http://www.asp.net/Learn/data-access/tutorial-51-cs.aspx

Gridview Column Removing

I have a web application that I am working on(ASP.NET 2.0 C#). In it I have a GridView whose data source is an Oracle database. I get the data into the gridview in my codebehind, and don't set the datasource directly.
I wanted to create a hyperlink field (NAME) that takes me to a details page about a specific record. What ends up happening is that it creates the Hyperlink field as well as the regular field that it gets from the datasource, which I don't want. If I remove the field from my SELECT statement, it gives an error saying something like: "NAME" not found in datasource.
How can I eliminate the regular field, and get a hyperlink field instead? I have tried Gridview.Columns.Remove(columnlocation), but that won't work coz the columns don't exist there originally.
Please Help
Thank you.

Instead of removing columns, disable AutoGenerateColumns property of the gridview and set your hyperlink column manually like that :
<asp:gridview id="GridView1"
autogeneratecolumns="false"
runat="server">
<asp:HyperLinkField DataNavigateUrlFields="UserID"
DataNavigateUrlFormatString="UserDetails.aspx?id={0}"
DataTextField="UserName" />
</asp:gridview>

Sounds like you have AutoGenerateColumns property set to TRUE on your grid. This means that a column is generated for EVERY column you return from your query.
If you want to have some custom columns, you should set AutoGenerateColumns="false" and add all the columns to the GirdView as asp:BoundField and your Hyperlink column as asp:TemplateField
Let me know if I'm off the mark with this
here's some code:
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False">
<Columns>
<asp:BoundField DataField="Name" />
<asp:BoundField DataField="Whatever" />
<asp:TemplateField>
<ItemTemplate>
<a href='<%# Eval("UserId", "URL_TO_USER?userId={0}") %>'>Details</a>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>