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iterating XmlDocument with xpath

How do we iterate an XmlDocument using an xpath?
I'm attempting to return a list of nodes by xpath:
public static List<string> Filter(string xpath, string input, string ns, string nsUrl)
{
var bytes = Encoding.UTF8.GetBytes(input); //i believe this unescapes the string
var stream = new MemoryStream(bytes);
var doc = new XmlDocument();
XmlNamespaceManager namespaceManager = new XmlNamespaceManager(doc.NameTable);
namespaceManager.AddNamespace(ns, nsUrl);
var links = new List<string>();
var nodes = doc.SelectNodes(xpath, namespaceManager);
using (var reader = new XmlTextReader(stream))
{
reader.Namespaces = false;
doc.Load(reader);
}
foreach (XmlNode node in nodes)
{
if (IsNullOrWhiteSpace(node.InnerText))
{
continue;
}
links.Add(node.InnerText);
}
return links;
}
however, the count is always 0 !
I'm using this xpath. notice how i am using only 1 namespace:
/ns0:Visit/ns0:DocumentInterface/ns0:Documents/ns0:Document/ns0:BinaryData
The header of the file looks like this:
<ns0:Visit xmlns:ns0="http://NameSpace.ExternalSchemas.Patient"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
I'm certain that I am using the right xpath because I tested it against my payload:
I'm calling the function this way:
var links = Filter(xpath, xml, "ns0", "http://NameSpace.ExternalSchemas.Patient");
How do we iterate an XmlDocument using an xpath? Perhaps the XmlDocument should be an XDocument instead?

Not getting string in xml formatted form?

I am trying to create a xml document of following format:
<![CDATA[<Caption xmlns="http:happy.x.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.happybus.tv/yy/happybus.xsd">
<TemplateID>xxxxx</TemplateID>
<CaptionOptions>
<CaptionField>
<Field>xxx</Field>
<Text>xxx</Text>
</CaptionField>
<CaptionField>
<Field>xxxx</Field>
<Text>""</Text>
</CaptionField>
</CaptionOptions>
</Caption>]]>
Here is the code that I wrote
XmlDocument xml2 = new XmlDocument();
XmlElement e = xml2.CreateElement("Caption");
e.InnerText ="Hello";
XmlElement template = xml2.CreateElement("TemplateID");
template.InnerText = "#TemplateID";
XmlElement captionOptions = xml2.CreateElement("CaptionOptions");
XmlElement captionField = xml2.CreateElement("CaptionField");
XmlElement fieldId = xml2.CreateElement("FieldID");
fieldId.InnerText = "#FieldID";
XmlElement textstring = xml2.CreateElement("TextString");
textstring.InnerText = "#TextString";
captionField.AppendChild(fieldId);
captionField.AppendChild(textstring);
captionOptions.AppendChild(captionField);
e.AppendChild(template);
e.AppendChild(captionOptions);
xml2.AppendChild(e);
StringWriter string_writer2 = new StringWriter();
XmlTextWriter xml_text_writer2 = new XmlTextWriter(string_writer2);
xml_text_writer2.Formatting = Formatting.Indented;
xml2.WriteTo(xml_text_writer2); // xml is your XmlDocument
string formattedXml2 = string_writer2.ToString();
Console.Write(formattedXml2);
I have tried a similar example with different XML doc but it clearly work, I even tried debugging but it is not getting formatted.

Have you tried using the XDocument and related classes? I find they make manual construction of xml easier and more intuitive since the code looks very similar to the xml. The ToString method seems to output the xml formatted the way you want:
void Main()
{
var xDoc = new XDocument
(
new XElement("Parent",
new XElement("TemplateID", "xxxxx"),
new XElement("CaptionOptions",
new XElement("CaptionField",
new XElement("Field", "xxx"),
new XElement("Text", "xxx")
),
new XElement("CaptionField",
new XElement("Field", "xxxx"),
new XElement("Text", "")
)
)
)
);
Console.WriteLine(xDoc.ToString());
//To enclose the xml in a CDATA, you could use:
var cData = new XCData(xDoc.ToString());
Console.WriteLine(cData.ToString());
}

Can't get attribute value with C# XPath

I've spent so much time with this already, still can't get the value of NTE attribute. Can someone please help?
C#
StreamReader sr = new StreamReader(resp.GetResponseStream());
XPathDocument xmlDoc = new XPathDocument(sr); // holds xml document
XPathNavigator xmlNav = xmlDoc.CreateNavigator(); //evaluates XPath expressions
XPathNodeIterator node = xmlNav.Select("/DATA2SC/CALL");
string dne = xmlNav.GetAttribute("NTE", "");
Console.WriteLine(dne);
sr.Close();
XML
<?xml version="1.0"?>
<DATA2SC PIN="00000">
<CALL
TR_NUM="00000001"
STATUS="WAITING_FOR_APPROVAL"
NTE="$15.00">
<PROBLEM>
Text
</PROBLEM>
</CALL>
</DATA2SC>

Can you try this code please ?
I already check and it's work
StreamReader sr = new StreamReader("c:\\x.xml");
XPathDocument xmlDoc = new XPathDocument(sr); // holds xml document
XPathNavigator xmlNav = xmlDoc.CreateNavigator(); //evaluates XPath expressions
var node = xmlNav.SelectSingleNode("/DATA2SC/CALL");
string dne = node.GetAttribute("NTE", "");
Console.WriteLine(dne);
OR
XDocument docXmlWorld = XDocument.Load("c:\\x.xml");
foreach (var node1 in docXmlWorld.Descendants("DATA2SC"))
{
foreach (var node2 in node1.Descendants("CALL"))
{
string dne = node2.Attribute("NTE").Value;
Console.Out.WriteLine(dne);
}
}
Or you can do like this too:
XDocument docXmlWorld = XDocument.Load("c:\\x.xml");
//Get the first child => [DATA2SC]
XElement elementNodeDATA2SC = docXmlWorld.Element("DATA2SC");
//Get the first child => [CALL]
XElement elementNodeCALL = elementNodeDATA2SC.Element("CALL");
//Get the attribute NTE from [CALL] node
string dne = elementNodeCALL.Attribute("NTE").Value;
Console.Out.WriteLine(dne);

The Select method, returns a collection of all nodes with the specified XPath.
You can use SelectSingleNode, to select the first node.
var node = xmlNav.SelectSingleNode("/DATA2SC/CALL");
string dne = node.GetAttribute("NTE", "");

Reading XML comments in C#

I have got some XML files that contain comments above the nodes. When I am reading the file in, as part of the process I would like to get the comment out as well. I know you can write a comment to the file using XmlComment, but not sure how to read them back out.
My XML looks similar to this:
<Objects>
<!--Comment about node-->
<GUID-bf2401c0-ef5e-4d20-9d20-a2451a199362>
<info job="SAVE" person="Joe" />
<info job="SAVE" person="Sally" />
</GUID-bf2401c0-ef5e-4d20-9d20-a2451a199362>
<!--Another Comment about node-->
<GUID-bf2401c0-ef5e-4d20-9d20-a5844113284112>
<info job="SAVE" person="John" />
<info job="SAVE" person="Julie" />
</GUID-bf2401c0-ef5e-4d20-9d20-a5844113284112>

Try this:
XmlReaderSettings readerSettings = new XmlReaderSettings();
readerSettings.IgnoreComments = false;
using (XmlReader reader = XmlReader.Create("input.xml", readerSettings))
{
XmlDocument myData = new XmlDocument();
myData.Load(reader);
// etc...
}
To read comments:
XmlReader xmlRdr = XmlReader.Create("Test.XML");
// Parse the file
while (xmlRdr.Read())
{
switch (xmlRdr.NodeType)
{
case XmlNodeType.Element:
// You may need to capture the last element to provide a context
// for any comments you come across... so copy xmlRdr.Name, etc.
break;
case XmlNodeType.Comment:
// Do something with xmlRdr.value

Using System.Xml.Linq:
var doc = XElement.Load(fileName);
var comments = doc.DescendantNodes().OfType<XComment>();
foreach (XComment comment in comments)
...

They are a part of the child nodes of the containing node as all other nodes: http://msdn.microsoft.com/en-us/library/system.xml.xmlcomment.aspx

I know the question is very old, but yesterday I had the same problem. So here is my solution:
XmlReaderSettings settings = new XmlReaderSettings();
settings.IgnoreWhitespace = false;
settings.IgnoreComments = false;
XmlReaderSettings settings2 = new XmlReaderSettings();
settings2.IgnoreWhitespace = false;
settings2.IgnoreComments = false;
XmlReader xmlreaderOriginalCfg = XmlReader.Create(#"C:\...xml", settings);
XmlReader xmlreaderVerificationCfg = XmlReader.Create(#"C:\....xml", settings);
XmlDocument myData = new XmlDocument();
myData.Load(xmlreaderOriginalCfg);
XmlDocument myData2 = new XmlDocument();
myData2.Load(xmlreaderVerificationCfg);
XmlNode parentNode = myData.SelectSingleNode("/configuration/appSettings");
foreach (XmlComment comment in myData2.SelectNodes("//comment()"))
{
XmlComment importedCom = myData.CreateComment(comment.Value);
parentNode.AppendChild(importedCom);
foreach (XmlNode node in myData2.DocumentElement.SelectNodes("/configuration/appSettings/add"))
{
XmlNode imported = myData.ImportNode(node, true);
parentNode.AppendChild(imported);
}
}
myData.Save(this.pathNew);
Maybe it helps somebody

I stored your XML into a file, here is the code sample.
XmlDocument document = new XmlDocument();
document.Load("test.xml");
foreach (XmlComment comment in document.SelectNodes("//comment()"))
{
Console.WriteLine("Comment: \"{0}\".", comment.Value);
}

Some sample code on how to access comments hope this helps
using System;
using System.IO;
using System.Xml;
public class Sample {
public static void Main() {
XmlDocument doc = new XmlDocument();
doc.LoadXml(#"<Objects><!--Comment about node--><othernode/><!--Some more comment--></Objects>");
XmlNode root = doc.FirstChild;
if (root.HasChildNodes)
{
for (int i=0; i<root.ChildNodes.Count; i++)
{
if( root.ChildNodes[i] is XmlComment)
Console.WriteLine(root.ChildNodes[i].InnerText);
}
}
}
}

How to set attribute to an XML element using linq to xml in C#

i've an xml file like
<Root>
<Steps>
<Step Test="SampleTestOne" Status="Fail" />
<Step Test="SampleTestTwo" Status="Fail" />
</Steps>
</Root>
i need to change or overwrite the attribute value of "Status" in the Step element.
Now i'm using XmlDocument for this
like
XmlDocument XDoc = new XmlDocument();
XDoc.Load(Application.StartupPath + "\\Sample.xml");
XmlNodeList NodeList = XDoc.SelectNodes("//Steps/Step");
foreach (XmlNode Node in NodeList)
{
XmlElement Elem = (XmlElement)Node;
String sTemp = Elem.GetAttribute("Test");
if (sTemp == "SampleTestOne")
Elem.SetAttribute("Status", "Pass");
}
I need search the element and to update the status
is there any way to do this using XDocumentin c#
Thanks in advance

string filename = #"C:\Temp\demo.xml";
XDocument document = XDocument.Load(filename);
var stepOnes = document.Descendants("Step").Where(e => e.Attribute("Test").Value == "SampleTestOne");
foreach (XElement element in stepOnes)
{
if (element.Attribute("Status") != null)
element.Attribute("Status").Value = "Pass";
else
element.Add(new XAttribute("Status", "Pass"));
}
document.Save(filename);

You can use this code:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(xmlFile);
XmlNode node = xmlDoc.SelectSingleNode("Root/Steps/Step");
node.Attributes["Status"].Value = "True";
xmlDoc.Save(xmlFile);