I write the xml using c#, and I want to make this script shorter, anyone know how to do it? I was think about using array,but don't know how to create the array...
XmlDocument doc = new XmlDocument();
XmlNode contentElements = doc.CreateElement("content");
doc.AppendChild(contentElements);
xmlNode itemElement1 = doc.CreateElement("item1");
xmlNode itemElement2 = doc.CreateElement("item2");
xmlNode itemElement3 = doc.CreateElement("item3");
xmlNode itemElement4 = doc.CreateElement("item4");
xmlNode itemElement5 = doc.CreateElement("item5");
contentElements.AppendChild(itemElement1);
contentElements.AppendChild(itemElement2);
contentElements.AppendChild(itemElement3);
contentElements.AppendChild(itemElement4);
contentElements.AppendChild(itemElement5);
Thanks a lot~~~
You can use an array as shown below
XmlDocument doc = new XmlDocument();
XmlNode contentElements = doc.CreateElement("content");
doc.AppendChild(contentElements);
string[] elements = new string[] { "item1", "item2", "item3", "item4", "item5" };
foreach (string element in elements)
{
XmlNode itemElement = doc.CreateElement(element);
contentElements.AppendChild(itemElement);
}
Related
How do we iterate an XmlDocument using an xpath?
I'm attempting to return a list of nodes by xpath:
public static List<string> Filter(string xpath, string input, string ns, string nsUrl)
{
var bytes = Encoding.UTF8.GetBytes(input); //i believe this unescapes the string
var stream = new MemoryStream(bytes);
var doc = new XmlDocument();
XmlNamespaceManager namespaceManager = new XmlNamespaceManager(doc.NameTable);
namespaceManager.AddNamespace(ns, nsUrl);
var links = new List<string>();
var nodes = doc.SelectNodes(xpath, namespaceManager);
using (var reader = new XmlTextReader(stream))
{
reader.Namespaces = false;
doc.Load(reader);
}
foreach (XmlNode node in nodes)
{
if (IsNullOrWhiteSpace(node.InnerText))
{
continue;
}
links.Add(node.InnerText);
}
return links;
}
however, the count is always 0 !
I'm using this xpath. notice how i am using only 1 namespace:
/ns0:Visit/ns0:DocumentInterface/ns0:Documents/ns0:Document/ns0:BinaryData
The header of the file looks like this:
<ns0:Visit xmlns:ns0="http://NameSpace.ExternalSchemas.Patient"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
I'm certain that I am using the right xpath because I tested it against my payload:
I'm calling the function this way:
var links = Filter(xpath, xml, "ns0", "http://NameSpace.ExternalSchemas.Patient");
How do we iterate an XmlDocument using an xpath? Perhaps the XmlDocument should be an XDocument instead?
static void Main(string[] args)
{
WebClient _httpReq = new WebClient(); // to talk to the web only for get method
string response = _httpReq.DownloadString("https://open-ic.epic.com/FHIR/api/FHIR/DSTU2/Patient?family=Argonaut&given=Jason");
Console.WriteLine(response);\\prints the xml string fetched from FHIR provider EPIC
XmlDocument xml = new XmlDocument();
xml.LoadXml(response); // suppose that myXmlString contains "<Names>...</Names>"
XmlNodeList xnList = xml.SelectNodes("/entry/resource/patient/name");
// here code is trying to extract the name attribute
foreach (XmlNode xn in xnList)
{
string firstName = xn["family value"].InnerText;
string lastName = xn["given value"].InnerText;
Console.WriteLine("Name: {0} {1}", firstName, lastName);
//print the first name and last name of the patient
}
Console.ReadLine();
}
i do it like this:
XmlDocument MyDocument = new XmlDocument();
MyDocument.Load("...");
XmlNode MyNode = MyDocument.SelectSingleNode("/Node_Name");
foreach (XmlAttribute MyAttribute in MyNode.Attributes)
{
if (MyAttribute.Name == "Attribute_Name")
{
object Value = MyAttribute.Value;
break;
}
}
Review XPath. Once you start understanding it, you will find it efficient and easier to code than iterating through lists. It also lets you directly get the nodes/attributes you want.
Then the code would be something similar to
string attrVal = doc.SelectSingleNode("/entry/resource/patient/#name").Value;
Or you can Load XML in XMlDocument and You can fetch element and out of that element you can read specific atairbute,
XmlDocument doc = new XmlDocument();
doc.LoadXml("<reply success=\"true\">More nodes go here</reply>");
XmlElement root = doc.DocumentElement;
string s = root.Attributes["success"].Value;
I am using following code to read an XML file from this address.
XmlDocument xdoc = new XmlDocument();
xdoc.Load("https://www.ecb.europa.eu/stats/eurofxref/eurofxref-daily.xml");
XmlNodeList nodeList = xdoc.DocumentElement.SelectNodes("//gesmes/Cube/Cube");
if (nodeList == null) lblOutput.Text = "node is null";
foreach (XmlNode node in nodeList)
{
XmlNode innerNode = node.SelectSingleNode(".//Cube");
lblOutput.Text = innerNode.Attributes["currency"].Value;
}
The problem is I don't get any thing. nodeList.Count always gives me 0.
You need to handle the namespaces correctly.
There are probably more then one way to handle them and this is one
XmlDocument xdoc = new XmlDocument();
xdoc.Load("https://www.ecb.europa.eu/stats/eurofxref/eurofxref-daily.xml");
XmlNamespaceManager xnm = new XmlNamespaceManager(xdoc.NameTable);
xnm.AddNamespace("gesmes", "http://www.gesmes.org/xml/2002-08-01");
xnm.AddNamespace("eurofxref", "http://www.ecb.int/vocabulary/2002-08-01/eurofxref");
XmlNodeList nodeList = xdoc.DocumentElement.SelectNodes("//gesmes:Envelope/eurofxref:Cube/eurofxref:Cube", xnm);
if (nodeList == null)
{
var text = "node is null";
}
foreach (XmlNode node in nodeList)
{
XmlNode innerNode = node.SelectSingleNode(".//eurofxref:Cube", xnm);
var text = innerNode.Attributes["currency"].Value;
}
I don't know why it has to be this complicated but....
XmlDocument xdoc = new XmlDocument();
xdoc.Load("https://www.ecb.europa.eu/stats/eurofxref/eurofxref-daily.xml");
XmlNamespaceManager xMan = new XmlNamespaceManager(xdoc.NameTable);
xMan.AddNamespace("def", "http://www.ecb.int/vocabulary/2002-08-01/eurofxref");
XmlNodeList nodeList = xdoc.DocumentElement.SelectNodes("//def:Cube", xMan);
I want to create XML with two root nodes, like this
<?xml version="1.0" encoding="IBM437"?>
<header1>
<header2>
<fracc>6004</fracc>
<txncode>HTH</txncode>
<reason>testing</reason>
<timeout>20</timeout>
<rdate>2/3/2015 12:00:00 AM</rdate>
<rtime>6/18/2015 1:20:00 PM</rtime>
<seqno>5</seqno>
<prefix>8</prefix>
<msgtype>trr</msgtype>
<sendto>trr</sendto>
<replyto>trr</replyto>
</header2>
</header1>
My code is like this, I'm unable to add two root elements with my code, it's a must to use XmlDocument class.
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode = xmlDoc.CreateElement("header" );
xmlDoc.AppendChild(rootNode);
XmlNode accountNode = xmlDoc.CreateElement("fracc");
accountNode.InnerText = Infracc;
rootNode.AppendChild(accountNode);
XmlNode txnNode = xmlDoc.CreateElement("txncode");
txnNode.InnerText = Intxncode;
rootNode.AppendChild(txnNode);
XmlNode reasonNode = xmlDoc.CreateElement("reason");
reasonNode.InnerText = Inreason;
rootNode.AppendChild(reasonNode);
XmlNode timeoutNode = xmlDoc.CreateElement("timeout");
timeoutNode.InnerText = Intimeout.ToString();
rootNode.AppendChild(timeoutNode);
XmlNode rdateNode = xmlDoc.CreateElement("rdate");
rdateNode.InnerText = Indate.ToString();
rootNode.AppendChild(rdateNode);
XmlNode rtimeNode = xmlDoc.CreateElement("rtime");
rtimeNode.InnerText = Intime.ToString();
rootNode.AppendChild(rtimeNode);
XmlNode seqnoNode = xmlDoc.CreateElement("seqno");
seqnoNode.InnerText = Inseqno.ToString();
rootNode.AppendChild(seqnoNode);
XmlNode prefixNode = xmlDoc.CreateElement("prefix");
prefixNode.InnerText = Inprefix.ToString();
rootNode.AppendChild(prefixNode);
XmlNode msgtypeNode = xmlDoc.CreateElement("msgtype");
msgtypeNode.InnerText = Inmsgtype;
rootNode.AppendChild(msgtypeNode);
XmlNode sendtoNode = xmlDoc.CreateElement("sendto");
sendtoNode.InnerText = Insendto;
rootNode.AppendChild(sendtoNode);
XmlNode replytoNode = xmlDoc.CreateElement("replyto");
replytoNode.InnerText = Inreplyto;
rootNode.AppendChild(replytoNode);
xmlDoc.Save("boc.xml");
xmlDoc.Load("boc.xml");
xmlDoc.Save(Console.Out);
return xmlDoc;
and my output is this
<?xml version="1.0" encoding="IBM437"?>
<header>
<fracc>6004</fracc>
<txncode>ttt</txncode>
<reason>testing</reason>
<timeout>20</timeout>
<rdate>2/3/2015 12:00:00 AM</rdate>
<rtime>6/18/2015 1:20:00 PM</rtime>
<seqno>5</seqno>
<prefix>8</prefix>
<msgtype>tt</msgtype>
<sendto>t</sendto>
<replyto>t</replyto>
</header>
Please help me to add two root nodes.
You are not adding 2 root elements.
Change your lines of code
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode = xmlDoc.CreateElement("header" );
xmlDoc.AppendChild(rootNode);
like below -
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode1 = xmlDoc.CreateElement("header1");
xmlDoc.AppendChild(rootNode1);
XmlNode rootNode = xmlDoc.CreateElement("header2");
rootNode1.AppendChild(rootNode);
Based on your sample output, it's clear that <header1> is the root element and <header2> is inside <header1>, so all you need to do is append <header2> inside <header1> and append the rest of the elements inside <header2>. This code should work
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode = xmlDoc.CreateElement("header1");
xmlDoc.AppendChild(rootNode);
XmlNode rootNode2 = xmlDoc.CreateElement("header2");
rootNode.AppendChild(rootNode2);
XmlNode accountNode = xmlDoc.CreateElement("fracc");
accountNode.InnerText = Infracc;
rootNode2.AppendChild(accountNode);
XmlNode txnNode = xmlDoc.CreateElement("txncode");
txnNode.InnerText = Intxncode;
rootNode2.AppendChild(txnNode);
XmlNode reasonNode = xmlDoc.CreateElement("reason");
reasonNode.InnerText = Inreason;
rootNode2.AppendChild(reasonNode);
XmlNode timeoutNode = xmlDoc.CreateElement("timeout");
timeoutNode.InnerText = Intimeout.ToString();
rootNode2.AppendChild(timeoutNode);
XmlNode rdateNode = xmlDoc.CreateElement("rdate");
rdateNode.InnerText = Indate.ToString();
rootNode2.AppendChild(rdateNode);
XmlNode rtimeNode = xmlDoc.CreateElement("rtime");
rtimeNode.InnerText = Intime.ToString();
rootNode2.AppendChild(rtimeNode);
XmlNode seqnoNode = xmlDoc.CreateElement("seqno");
seqnoNode.InnerText = Inseqno.ToString();
rootNode2.AppendChild(seqnoNode);
XmlNode prefixNode = xmlDoc.CreateElement("prefix");
prefixNode.InnerText = Inprefix.ToString();
rootNode2.AppendChild(prefixNode);
XmlNode msgtypeNode = xmlDoc.CreateElement("msgtype");
msgtypeNode.InnerText = Inmsgtype;
rootNode2.AppendChild(msgtypeNode);
XmlNode sendtoNode = xmlDoc.CreateElement("sendto");
sendtoNode.InnerText = Insendto;
rootNode2.AppendChild(sendtoNode);
XmlNode replytoNode = xmlDoc.CreateElement("replyto");
replytoNode.InnerText = Inreplyto;
rootNode2.AppendChild(replytoNode);
xmlDoc.Save("boc.xml");
xmlDoc.Load("boc.xml");
xmlDoc.Save(Console.Out);
return xmlDoc;
Working fiddle: https://dotnetfiddle.net/EevsJq
i've an xml file like
<Root>
<Steps>
<Step Test="SampleTestOne" Status="Fail" />
<Step Test="SampleTestTwo" Status="Fail" />
</Steps>
</Root>
i need to change or overwrite the attribute value of "Status" in the Step element.
Now i'm using XmlDocument for this
like
XmlDocument XDoc = new XmlDocument();
XDoc.Load(Application.StartupPath + "\\Sample.xml");
XmlNodeList NodeList = XDoc.SelectNodes("//Steps/Step");
foreach (XmlNode Node in NodeList)
{
XmlElement Elem = (XmlElement)Node;
String sTemp = Elem.GetAttribute("Test");
if (sTemp == "SampleTestOne")
Elem.SetAttribute("Status", "Pass");
}
I need search the element and to update the status
is there any way to do this using XDocumentin c#
Thanks in advance
string filename = #"C:\Temp\demo.xml";
XDocument document = XDocument.Load(filename);
var stepOnes = document.Descendants("Step").Where(e => e.Attribute("Test").Value == "SampleTestOne");
foreach (XElement element in stepOnes)
{
if (element.Attribute("Status") != null)
element.Attribute("Status").Value = "Pass";
else
element.Add(new XAttribute("Status", "Pass"));
}
document.Save(filename);
You can use this code:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(xmlFile);
XmlNode node = xmlDoc.SelectSingleNode("Root/Steps/Step");
node.Attributes["Status"].Value = "True";
xmlDoc.Save(xmlFile);