I have a windows form that reads strings from a file and shows them all in a textbox when I press a button.
private void buttonTxt_Click(object sender, EventArgs e)
{
string[] Test = File.ReadAllLines("C:\\testfile.txt");
for (int i = 0; i < testfile.Length; i++)
{
TextBox.Text += testfile[i];
}
}
I'd like to make two radio buttons. So that first button lets my program work the way I described (by default) AND second radio button makes it work vice versa -- so that I could write in a textbox myself and when I press a button it writes a new line to the same file. Is there a way to do it?
Simply add an if statement in this event handler and implement both sending and receiving the data. Done. Sample in principle:
private const string FilePath = #"C:\testfile.txt";
private void buttonTxt_Click(object sender, EventArgs e)
{
if (radioReadMode.Checked) // check which radio button is selected
{ // read mode
string[] Test = File.ReadAllLines(FilePath);
for (int i = 0; i < testfile.Length; i++)
TextBox.Text += testfile[i];
}
else
{ // write mode
File.WriteAllText(FilePath, TextBox.Text);
}
}
I believe this is what you might be looking for. If radio button 1 is checked then if the file exists it will read that file and put it into a textbox in the form. If you switch to radio button 2. You can type in the text box and then when you press the button it will append it to the file.
public partial class Form1 : Form
{
System.IO.StreamReader sr;
System.IO.StreamWriter sw;
public Form1()
{
InitializeComponent();
radioButton1.Checked = true;
}
private void button1_Click(object sender, EventArgs e)
{
if (radioButton1.Checked == true)
{
if (System.IO.File.Exists("C:\\testfile.txt"))
{
try
{
sr = new System.IO.StreamReader("C:\\testfile.txt");
while (!sr.EndOfStream)
{
textBox1.Text += sr.ReadLine() + "\r\n";
}
}
finally
{
sr.Close();
sr.Dispose();
}
}
}
if (radioButton2.Checked == true)
{
if (System.IO.File.Exists("C:\\testfile.txt"))
{
try
{
sw = new System.IO.StreamWriter("C:\\testfile.txt", true);
string result = textBox1.Text;
string[] lststr = result.Split(new Char[] { '\r', '\n' }, StringSplitOptions.RemoveEmptyEntries);
foreach (string s in lststr)
{
sw.WriteLine(s);
}
}
finally
{
sw.Flush();
sw.Close();
sw.Dispose();
}
}
}
}
private void radioButton1_CheckedChanged(object sender, EventArgs e)
{
textBox1.Clear();
textBox1.ReadOnly = true;
}
private void radioButton2_CheckedChanged(object sender, EventArgs e)
{
textBox1.Clear();
textBox1.ReadOnly = false;
}
}
Yes, there's a way. Just add another button to your form and inside read the text from the text box this way:
var textBoxContent = TextBox.Text;
and save it to your file this way
File.WriteAllText("C:\\testfile.txt", textBoxContent);
Note: I recommend getting the path to your file into a variable
Related
I've a gui and I get temperature data from a Uc. I can see the data in the rich text box and save to a text file. But I cannot understand how to sort the saved data in the column format. Right now it is a long row of data. Please advice.
Would it be advisable to replace the rich text box to a normal text box?
I've a button to save data to the text file (button3_Click);
using System;
using System.Windows.Forms;
using System.IO.Ports;
using System.IO;
namespace Serial_receive
{
public partial class Form1 : Form
{
// All members variables should be placed here
// make it more readable, hopefully!
string t;
SerialPort sp;
public Form1()
{
InitializeComponent();
Control.CheckForIllegalCrossThreadCalls = false;
// User can already search for ports when the constructor of the FORM1 is calling
// And let the user search ports again with a click
// Searching for ports function
SearchPorts();
}
//search button
private void button1_Click(object sender, EventArgs e)
{
comboBox1.Items.Clear();
SearchPorts();
}
void SearchPorts()
{
string[] ports = SerialPort.GetPortNames();
foreach (string port in ports)
{
comboBox1.Items.Add(port);
}
}
private void button2_Click(object sender, EventArgs e)
{
// Catch exception if it will be thrown so the user will see it in a message box
OpenCloseSerial();
}
void OpenCloseSerial()
{
try
{
if (sp == null || sp.IsOpen == false)
{
t = comboBox1.Text.ToString();
sErial(t);
button2.Text = "Close Serial port"; // button text
}
else
{
sp.Close();
button2.Text = "Connect and wait for inputs"; // button text
}
}
catch (Exception err) // catching error message
{
MessageBox.Show(err.Message); // displaying error message
}
}
void sErial(string Port_name)
{
try
{
sp = new SerialPort(Port_name, 115200, Parity.None, 8, StopBits.One); // serial port parameters
sp.DataReceived += new SerialDataReceivedEventHandler(DataReceivedHandler);
sp.Open();
}
catch (Exception err)
{
throw (new SystemException(err.Message));
}
}
//
private void DataReceivedHandler(object sender,SerialDataReceivedEventArgs e)
{
// This below line is not need , sp is global (belongs to the class!!)
//SerialPort sp = (SerialPort)sender;
if (e.EventType == SerialData.Chars)
{
if (sp.IsOpen)
{
string w = sp.ReadExisting();
if (w != String.Empty)
{
Invoke(new Action(() => richTextBox1.AppendText(w)));
}
}
}
}
private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
{
if (sp == null || sp.IsOpen == false)
{
OpenCloseSerial();
}
}
private void Form1_Load(object sender, EventArgs e)
{
this.Text = "Serial Channel to FRDM-KW40Z";
}
private void button3_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.InitialDirectory = #"C:\Users\varman\Documents\";
saveFileDialog1.Title = "Save text Files";
saveFileDialog1.CheckFileExists = true;
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.DefaultExt = "txt";
saveFileDialog1.Filter = "Text files (*.txt)|*.txt|All files (*.*)|*.*";
saveFileDialog1.FilterIndex = 2;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
string temperature = "Temperature";
string sorted = richTextBox1.Text.Replace(temperature, Environment.NewLine + temperature);
sorted = sorted.Substring(sorted.IndexOf(temperature));
File.WriteAllText(saveFileDialog1.FileName, sorted);
Text += "\r\n";
richTextBox1.Text = saveFileDialog1.FileName;
}
}
private void richTextBox1_TextChanged(object sender, EventArgs e)
{
richTextBox1.ScrollBars = ScrollBars.Both;
}
}
}
I assume you want to sort it only in the output file because you didn't share the code that change richTextBox1.Text.
So you can add a new line for each temperature before writing to the file:
private void button3_Click(object sender, EventArgs e)
{
...
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
string temperature = "Temperature";
string sorted = richTextBox1.Text.Replace(temperature, Environment.NewLine + temperature);
File.WriteAllText(saveFileDialog1.FileName, sorted);
Text += "\r\n";
richTextBox1.Text = saveFileDialog1.FileName;
}
}
Add this line of code before File.WriteAllText if you want to write the text that starts with "Temperature" (this way you remove the "?????" at the beginning):
sorted = sorted.Substring(sorted.IndexOf(temperature));
EDIT:
Following your last edit - you added the code that updates the RichTextBox. So you can do the sorting by column only in DataReceivedHandler. See below:
private void DataReceivedHandler(object sender,SerialDataReceivedEventArgs e)
{
if (e.EventType != SerialData.Chars || !sp.IsOpen)
{
return;
}
string w = sp.ReadExisting();
if (w != String.Empty)
{
string temperature = "Temperature";
string sorted = w.Replace(temperature, Environment.NewLine + temperature);
Invoke(new Action(() => richTextBox1.AppendText(sorted)));
}
}
Basically what you need to understand is that File.WriteAllText(fileName, input) is where you write input into the file, so you can manipulate input as you wish before that line. If you wish to alter the text before it's dispalyed in the RichTextBox then you need to see where you execute something like richTextBox1.AppendText(input) or richTextBox1.Text = input and do all the changes you want on input before that line.
Today when I type something any text in textBox1 and then click the start button it will search inside files for the text i typed in textBox1.
Now I want to add something somehow that if the user type in the textBox1 for example: hello,hi it will search for hello and also for hi in the files. Not as one string/text but two separated. If I type: hello,hi,world now it will search in same time same files also for hello hi and world.
The textchanged event
private void textBox1_TextChanged(object sender, EventArgs e)
{
if (textBox1.Text != "" && textBox3.Text != "" && Directory.Exists(textBox3.Text))
{
startButton.Enabled = true;
Properties.Settings.Default["Setting2"] = textBox1.Text;
Properties.Settings.Default.Save();
}
else
{
startButton.Enabled = false;
}
}
The start button click event
private void startButton_Click(object sender, EventArgs e)
{
label21.Visible = true;
startButton.Enabled = false;
stopButton.Enabled = true;
pauseresumeButton.Enabled = true;
timer1.Start();
if (!backgroundWorker1.IsBusy)
{
SetWorkerMode(true);
backgroundWorker1.RunWorkerAsync();
}
}
Dowork event
private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
{
BackgroundWorker worker = sender as BackgroundWorker;
_stopwatch.Restart();
DirSearch(textBox3.Text, textBox2.Text, textBox1.Text, worker, e);
_stopwatch.Stop();
}
The DirSearch method where I search for the text in files.
void DirSearch(string rootDirectory, string filesExtension, string textToSearch, BackgroundWorker worker, DoWorkEventArgs e)
{
List<string> filePathList = new List<string>();
List<string> restrictedFiles = new List<string>();
int overallfiles = 0;
int numberoffiles = 0;
int numberofdirs = 0;
try
{
filePathList = SearchAccessibleFilesNoDistinct(rootDirectory, null).ToList();
}
catch (Exception err)
{
string ad = err.ToString();
}
foreach (string file in filePathList)
{
try
{
_busy.WaitOne();
if (worker.CancellationPending == true)
{
e.Cancel = true;
return;
}
List<MyProgress> prog = new List<MyProgress>();
int var = File.ReadAllText(file).Contains(textToSearch) ? 1 : 0;
overallfiles++;
if (var == 1)
{
numberoffiles++;
prog.Add(new MyProgress { Report1 = file, Report2 = numberoffiles.ToString() });
backgroundWorker1.ReportProgress(0, prog);
}
numberofdirs++;
label1.Invoke((MethodInvoker)delegate
{
label1.Text = numberofdirs.ToString();
label1.Visible = true;
});
}
catch (Exception)
{
restrictedFiles.Add(file);
continue;
}
}
}
In DirSearch the variable textToSearch contains the text I typed in textBox1.
If I typed in textBox1 only HI so like it is now it will search in each file for the existing of HI.
But if I type HI,HELLO,WORLD
Now I want it to search for existing in each file of HI HELLO WORLD not as one text string but each word on it's own existing.
If I type Hi HELLO WORLD then it will search it as one string/text but once the user put , between it should search each word/text.
You can split the input in the textbox based on space, comma's or any other separator and then pass these as individual inputs to your search method, hope this helps
I have code like this:
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.ShowDialog();
}
private void openFileDialog1_FileOk(object sender, CancelEventArgs e)
{
string ext = Path.GetExtension(openFileDialog1.FileName);
if(string.Compare(ext, ".FDB") == 0)
{
string fileName = openFileDialog1.SafeFileName;
string fileDirectory = Path.GetDirectoryName(openFileDialog1.FileName);
string databaseTxt = #"C:\Users\arist\AppData\Roaming\TDWork\";
string[] database = { fileDirectory + fileName };
if (Directory.Exists(databaseTxt))
{
System.IO.File.WriteAllLines(databaseTxt + "databases.txt", database);
}
else
{
DirectoryInfo di = Directory.CreateDirectory(databaseTxt);
System.IO.File.WriteAllLines(databaseTxt + "databases.txt", database);
}
}
else
{
MessageBox.Show("Fajl koji ste izabrali nije Firebird baza (.FDB)");
e.Cancel = true;
}
}
Now, i want to create more buttons that open same file dialog. Problem is that i want to pass openFileDialog directory to different textboxes. So logic is this:
If i open with button1, pass value to textbox1,
If i open with button2, pass value to textbox2,
if i open with button3, pass value to textbox3.
So i wanted to create int check (1, 2, 3) so when i press button1, it pass check = 1 to OpenDialog1_FileOk, so i just do switch there and do actions.
Problem is i do not know how to pass it to handler, and if that is possible. Also if there is any other solution, please write it.
First, you could use your openfiledialog just like this, without handling a whole new function for it:
if(openFileDialog1.ShowDialog() == DialogResult.OK){
//...code
}
Second, for your goal you'll have to be sure that the names of your controls are exactly ending on the digit you want (e.g. "button1" and "textbox1"). Then you can do it like this:
void Button1Click(object sender, EventArgs e)
{
//MessageBox.Show(bt.Name[bt.Name.Length - 1].ToString());
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
if(!Path.GetExtension(openFileDialog1.FileName).EndsWith(".FDB")) //checking if the extension is .FDB (as you've shown in your example)
{
MessageBox.Show("Fajl koji ste izabrali nije Firebird baza (.FDB)");
return; //return if it's not and no further code gets executed
}
string fileDirectory = Path.GetDirectoryName(openFileDialog1.FileName); //getting the directory
string nameOfMyButton = (sender as Button).Name; //you get the name of your button
int lastDigitOfMyName = Convert.ToInt16(Name[Name.Length - 1]); //returns the number of your button
TextBox neededTextboxToShowDirectory = this.Controls.Find("textbox" + lastDigitOfMyName, true).FirstOrDefault() as TextBox; //this will search for a control with the name "textbox1"
neededTextboxToShowDirectory.Text = fileDirectory; //you display the text
//... doing the rest of your stuff here
}
}
You could use a private field where you save temporarily the text of your TextBox and deploy it in the click event like this:
private int whichButton = 0;
private void button1_Click(object sender, EventArgs e)
{
whichButton = 1;
openFileDialog1.ShowDialog();
}
private void button2_Click(object sender, EventArgs e)
{
whichButton = 2;
openFileDialog1.ShowDialog();
}
private void button3_Click(object sender, EventArgs e)
{
whichButton = 3;
openFileDialog1.ShowDialog();
}
use then the whichButton to choose
private void openFileDialog1_FileOk(object sender, CancelEventArgs e)
{
switch (whichButton)
{
....
}
}
I have a WinForm of 15 textboxes in a row and each one has a save and show button next to it. The user can write text in these boxes and when they open the form they can click show and view the text they wrote and then save it and close the app and its still there to be shown.
For the code I thought I could use it individually on each textbox and button
namespace UniversityProject
{
public partial class managementsystem : Form
{
private const string fileName = #"C:\txtBoxdata.txt";
public managementsystem()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
textBox3.Text = File.ReadAllText(fileName);
}
private void button2_Click(object sender, EventArgs e)
{
File.WriteAllText(fileName, textBox3.Text);
}
I thought it would work by changing the textBox numbers but I think it might have something to do with the read all. As all the textboxes show the same data which is incorrect.
Let me try to clarify your question:
You have a bunch of textboxes where each represents a single line in a text file. Each time the user clicks on a button next to a textbox you want to replace the corresponding line.
Replacing a single line in a text file is quite easy. Just read all the lines into an array, replace the line and write everything back to the file:
private static void ReplaceLineInFile(string path, int lineNumber, string newLine)
{
if (File.Exists(path))
{
string[] lines = File.ReadAllLines(path);
lines[lineNumber] = newLine;
File.WriteAllLines(path, lines);
}
}
The only thing left is to know which line should be replaced. You can add a handler for each button (notice that the line numbers start with 0):
private void button1_Click(object sender, EventArgs e)
{
ReplaceLineInFile(fileName, 0, textBox1.Text);
}
private void button2_Click(object sender, EventArgs e)
{
ReplaceLineInFile(fileName, 1, textBox2.Text);
}
etc.
This is not very elegant because it duplicates the same code. It would be better to use a single event handler for all buttons and then figure out which textbox it adresses and which line should be replaced. I would recommend to have arrays for the textboxes and buttons and build them in the constructor:
private TextBox[] textBoxes;
private Button[] buttons;
public managementsystem()
{
InitializeComponent();
textBoxes = new TextBox[] { textBox1, textBox2, textBox3, textBox4, textBox5 };
buttons = new Button[] { button1, button2, button3, button4, button5 };
}
Your single event handler would be:
private void button_Click(object sender, EventArgs e)
{
Button button = sender as Button;
if (button != null)
{
int lineNumber = Array.IndexOf(buttons, button);
if (lineNumber >= 0)
{
ReplaceLineInFile(fileName, lineNumber, textBoxes[lineNumber].Text);
}
}
}
At some point you might want to save all values and/or create the file. Also you might want to load existing values into your textboxes when the form is loaded:
private void Form1_Load(object sender, EventArgs e)
{
LoadFile();
}
private void LoadFile()
{
if (!File.Exists(fileName))
{
WriteAllLines();
return;
}
string[] lines = File.ReadAllLines(fileName);
if (lines.Length != textBoxes.Length)
{
// the number of lines in the file doesn't fit so create a new file
WriteAllLines();
return;
}
for (int i = 0; i < lines.Length; i++)
{
textBoxes[i].Text = lines[i];
}
}
private void WriteAllLines()
{
// this will create the file or overwrite an existing one
File.WriteAllLines(fileName, textBoxes.Select(tb => tb.Text));
}
Notice that this will still work when you add new textboxes. The only thing you have to change is the creation of the arrays in the constructor. However, if you change the number of textboxes this will delete the existing file. To avoid this you can add or remove new lines manually.
The basic problem is you are trying to save different textbox values into one txt file. Change the txt file-names along with the textBox names, and you will be good to go .. :)
Get a hold of StreamWriter and StreamReader.
Open a new stream with either stream-writer or reader in your OnClick-events. Then use something like
using(StreamWriter sw = new StreamWriter("C:\\Path\\to\\file.txt")){
sw.WriteLine("TEXTBOX1: " + textbox1.text);
sw.Close();
}
Do this for all your textboxes. And eventually use the StreamReader to read from your file
using(StreamReader sr = new StreamReader("C:\\Path\\to\\file.txt")){
string s = sr.ReadToEnd();
//find value for your textbox;
textbox1.Text = s;
sw.Close();
}
Give it a shot!
I have made a method so that when you click on Browse From File the openDialogBox appear. But it does not . What is wrong ?
This is the method that I made to Open the OpenFileDialog:
public void Lista()
{
string[] col2 = new string[dataGridView1.Rows.Count];
for (int i = 0; i < dataGridView1.Rows.Count; i++)
if (col2[i] == "Browse From File...")
{
DialogResult result2 = openFileDialog2.ShowDialog();
if (result2 == DialogResult.OK)
{
// filename = openFileDialog1.FileName;
}
}
}
This is the method where I call the method Lista.
private void button1_Click(object sender, EventArgs e)
{
// opens window **BROWSE**
openFileDialog1.Title = "Choose File CSV ";
string filename = "";
DialogResult result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK)
{
filename = openFileDialog1.FileName;
textBox1.Text = filename;
string line;
// Read the file and display it line by line.
System.IO.StreamReader file = new System.IO.StreamReader(textBox1.Text);
stringforData = file.ReadLine();
while ((line = file.ReadLine()) != null)
{
//read inside the table
fileList.Add(line.Split(';'));
}
file.Close();
this.ToDataGrid();
this.Lista();
}
}
DataGridView by only having one editing control for all the rows. Here's how I handled a similar situation, First try a delegate to the EditControlShowing event
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
OpenFileDialog ofd = new OpenFileDialog();
private void Form1_Load(object sender, EventArgs e)
{
dataGridView1.Columns.Add("ID", "Product ID");
DataGridViewComboBoxColumn comboxboxCol = new DataGridViewComboBoxColumn();
comboxboxCol.HeaderText = "Type";
comboxboxCol.Items.Add("Obj1");
comboxboxCol.Items.Add("Obj2");
comboxboxCol.Items.Add("Obj3");
dataGridView1.Columns.Add(comboxboxCol);
dataGridView1.EditingControlShowing += new DataGridViewEditingControlShowingEventHandler(Grid_EditingControlShowing);
}
void Grid_EditingControlShowing(object sender, DataGridViewEditingControlShowingEventArgs e)
{
ComboBox combo = e.Control as ComboBox;
if (combo != null)
{
// the event to handle combo changes
EventHandler comboDelegate = new EventHandler(
(cbSender, args) =>
{
ofd.ShowDialog();
});
// register the event with the editing control
combo.SelectedValueChanged += comboDelegate;
}
}
}
}
Hope this will solve your Issue