C# User Control Leave Event - c#

I am very new with the C# UserControl. I have problems with the event Leave. This is my situation: I would like to go from usercontrolA to userControlB. Before going to userControlB, usercontrolA_Leave event is called.
private void usercontrolA_Leave(object sender, EventArgs e)
{
MessageBox.Show("you are leaving.....");
}
After MessageBox is shown, the program will not proceed to my userControlB. HOWEVER when there is no MessageBox in the code, the program can proceed to userControlB.
private void usercontrolA_Leave(object sender, EventArgs e){//anything but MessageBox}
In my case, I need MessageBox.
I need MessageBox(or other thing) for me to decide whether staying or leaving.. .
msdn Control.Leave Event
I heard about setting set focusor lost focus. Is that possible to use this?
I hope you guys could understand what I have written. Thank you in advance.. :)

You will not be able to preserve mouse movements once a MessageBox is created. This is a modal box that comes up on top of the existing window and takes the focus away from the current form and interrupts the mouse.
Consider an option that does not interrupt the mouse, such as writing out to a textbox. Create a TextBox will the multi-line and scrollbar options enabled. Then write to it.
private void usercontrolA_Leave(object sender, EventArgs e)
{
textBox1.Append("you are leaving A...\r\n");
}
private void usercontrolB_Enter(object sender, EventArgs e)
{
textBox1.Append("you are entering B...\r\n");
}

Related

C# VS2019 - Implement Multiple pages in one form that switch with a click of a button

I've tried many methods to try and get this to work, but have had very little success making it stable. What would be a good way of going about this?
When I click the first button I can view my first panel just fine, but it permanently hides the second panel despite me click button 2 which in theory should unhide the first panel and and show the second one. I'm guessing this method is outdated. I should note that both panels are directly on top of each other. If anyone has a solution to this please let me know.
private void button1_Click(object sender, EventArgs e)
{
firstPanel.Show();
secondPanel.Hide();
}
private void button2_Click(object sender, EventArgs e)
{
secondPanel.Show();
firstPanel.Hide();
}

SendKeys.send is sending more than one character

sorry for my bad english.
I am writing a keyboard application for the touchscreen. but,
for example, when I press the A key, sometimes it's writes 5 times A key . I am using basically button click event.
private void button42_Click(object sender, EventArgs e)
{
SendKeys.Send("A");
Thread.Sleep(100);
}
there is no problem with the mouse_click event. just touch
how can i do it?
1.Try handling it in a mouse_up or touch_up event instead of using a delay here. Actual implementation and events will depend on you framework.
mouse_up /touch_up will make sure that you even only fires when touch is released.
To add repetition on touch and hold, you may have to add additional logic however.
Try declaring a field to toggle the value of event fired.
private bool handling=false;
private void button42_Click(object sender, EventArgs e)
{
if(!handling)
{
handling=true;
SendKeys.Send("A");
Task.Delay(100).Wait();
handling=false;
}
}

C# WinForms - Detect User Click Into Text Box

I have been developing a windows form application and ran into a problem.
After trying various things (Listed below) I have come to seek your knowledge to help point me in the right direction.
I have replicated a much simpler version of my program:
As you can see, I have two textboxes. I want to be able to click on the textbox on the bottom (textbox1) and call some form of an event, in this case, for simplicity, pop up a message box.
I have been through the events listed here:
https://msdn.microsoft.com/en-us/library/system.windows.forms.textbox_events(v=vs.110).aspx
And implemented them into my code as I expected one of them to work. However, this is not the case.
private void textBox1_TextChanged(object sender, EventArgs e)
{
MessageBox.Show("TextBox Entered");
}
//Above - Will pop message box when text entered.
private void textBox1_GotFocus(object sender, EventArgs e)
{
MessageBox.Show("TextBox Entered");
}
private void textBox1_Enter(object sender, EventArgs e)
{
MessageBox.Show("TextBox Entered");
}
private void textBox1_Click(object sender, EventArgs e)
{
MessageBox.Show("TextBox Entered");
}
Does anybody know what I am missing? I presume what I am trying to achieve is actually possible?
Kind Regards,
B.
Ensure the event is subscribed to the methods you have written. You can do this in the design view using the Events tab of the property window (looks like a lightning bolt). As mentioned by others, a double click in the events window will generate the event's method for you, and subscribe to it automatically.
Another way is to subscribe directly using code; you could write this in the form constructor for example:
textBox1.TextChanged += textBox1_TextChanged;

How to properly handle events on labels ontop of a button?

I have a class which I inherit from Button. In this class, I create labels which I can use as custom button captions. The problem I have on these custom buttons is when I click the label nothing happens, and if I click outside the label but still on the button it works as usual. To solve this I wrote:
lblTitle.Click += new EventHandler(LabelClick);
And in LabelClick I wrote:
private void LabelClick(object sender, EventArgs e)
{
base.OnClick(e);
}
This worked good, but then I noticed that I didnt get the clickanimation of the click, when I clicked on the label. So I made the same thing with onMouseDown and Up.
lblTitle.MouseDown += new MouseEventHandler(LabelMouseDown);
lblTitle.MouseUp += new MouseEventHandler(LabelMouseUp);
private void LabelMouseDown(object sender, MouseEventArgs e)
{
base.OnMouseDown(e);
}
private void LabelMouseUp(object sender, MouseEventArgs e)
{
base.OnMouseUp(e);
}
But then I sometimes get the effect of clicking two times on the button. So now I'm wondering, how do I give the user the same click animation when clicked on the button and the label ontop of the button - without making the button click twice?
Thanks in advance and if you gonna downgrade this question, please leave a comment on why!
I think that the problem is that LabelClick & LabelMouseDown & LabelMouseUp all these three events are fired when you click the label which fires them in the base button. so your click event is duplicated when you make a MouseDown event. (this should be a comment, but i dont have enough reputation to leave a comment, hope it will help :) )

C# Keyboard button used to trigger a method

I'm writing a Hangman program in C# and when I press a keyboard button I want the button on the form to be clicked. Where should I write this? In form1.load()?
No, you should select the Form on which you want the event to be triggered, then go to the properties pane, select the event tab and go down to KeyPress event, double click it and add some code.
Normaly something like this would do what you want, just google the KeyChar value to determine the keyPress you want to control, you can add more if statements:
private void Form1_KeyPress(object sender, KeyPressEventArgs e)
{
if (e.KeyChar == (char)13)
{
Button1.PerformClick();
}
//Other if statements if you want to keep an eye out for other keyPresses
}
[edit] I just remembered you might be also considering the shortcuts, in wich case the Button1.Text property should be marked &Button1, this way the "B" would be underlined and accept the alt+B shortcut to execute the button click event.
The & symbol is set before the letter you want for the shortcut, make sure you dont use the same letter for various buttons.
You wouldn't write the code in Form.Load() if you want it to happen in response to a keyboard event. That event occurs (and the code inside of it is executed) when your form first loads (appears on screen).
How about handling the KeyPress event and writing the code in that method, instead? Your form has one of those events, too.
Sample code:
private void Form1_KeyPress(object sender, KeyPressEventArgs e)
{
Button1.PerformClick();
}
The PerformClick method will generate a Click event for a Button control. You can handle that Click event in a similar way:
private void Button1_Click(object sender, EventArgs e)
{
// do something in response to the button being clicked
// ...
MessageBox.Show("Button clicked!");
}
If this event-handling stuff is confusing to you, make sure that you pick up a good book on programming in C# and/or the .NET Framework so that you learn it well. It's very important and not something to skip!
You have to enable KeyPreview property on the form, then you have to implements the KeyPress event directly on the form :
Form1.KeyPress +=new KeyPressEventHandler(Form1_KeyPress);
private void Form1_KeyPress(object sender, KeyPressEventArgs e) {
if(e.KeyCode == someKey) {
button1.performclick();
}
}
private void Form_KeyDown(object sender, KeyEventArgs e)
{
if(e.KeyCode == Keys.Left)
{
// Do your hang job
Button_Click(sender, EventArgs.Empty);
}
}
You need to subscribe to the events of interest and process them after. But before you need to read and study how to do that. It's a not a difficult issue in C#.
http://msdn.microsoft.com/en-us/library/ms171534.aspx
One time subscribed to the events create a function that you can call from button click and from keydown.

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