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XML Serialization Missing Some Elements

following is the part of my xml serializing object.
private decimal tOAMOUNTField;
public decimal TOAMOUNT
{
get
{
return this.tOAMOUNTField;
}
set
{
this.tOAMOUNTField = value;
}
}
XmlSerializer xsSubmit = new XmlSerializer(typeof(MyClassObject));
var entity = new Myobject();
entity .TOAMOUNT = 2.22M;
using (StringWriter sww = new StringWriter())
{
using (XmlWriter writer = XmlWriter.Create(sww))
{
// sww.WriteLine(#"<?xml version=""1.0"" encoding=""UTF-8""?>");
xsSubmit.Serialize(writer , entity);
output = sww.ToString();
}
}
above mention "ToAmount" Property is not serializing in XML
Kindly point out the mistake because all other properties are serializing

You are initializing a XmlSerializer object with type MyClassObject.
XmlSerializer xsSubmit = new XmlSerializer(typeof(MyClassObject));
But are serializing a 'Myobject()' object.
Try changing it in:
XmlSerializer xsSubmit = new XmlSerializer(typeof(Myobject));

C#: How to shorten that XML appending?

I have that XML file which looks like this:
<?xml version="1.0" encoding="utf-8"?>
<backupatmail>
<backup id="0">
<foldername>TestFolder</foldername>
<backupdate>09/10/2015</backupdate>
<comment>Sample comment text is here</comment>
<numberofparts>7</numberofparts>
<lastsucceed>Test.007</lastsucceed>
</backup>
<backup id="1">
<foldername>TestFolder2</foldername>
<backupdate>09/10/2015</backupdate>
<comment>Sample comment text is here</comment>
<numberofparts>15</numberofparts>
<lastsucceed>Test.015</lastsucceed>
</backup>
</backupatmail>
Now, I want to append new node(?):
<backup id="999">
<foldername>testing1</foldername>
<backupdate>99/99/9999</backupdate>
</backup>
I wrote following code:
public static void AddBackupToXML()
{
XmlDocument doc = new XmlDocument();
doc.Load(GlobalSettings.appDefaultFolder + "backups.xml");
XmlElement backupNodeNew = doc.CreateElement("backup");
XmlAttribute backupId = doc.CreateAttribute("id");
backupId.Value = "999";
backupNodeNew.Attributes.Append(backupId);
XmlNode nodeTitle = doc.CreateElement("foldername");
nodeTitle.InnerText = "testing1";
XmlNode nodeUrl = doc.CreateElement("backupdate");
nodeUrl.InnerText = "99/99/9999";
backupNodeNew.AppendChild(nodeTitle);
backupNodeNew.AppendChild(nodeUrl);
doc.DocumentElement.AppendChild(backupNodeNew);
doc.Save(GlobalSettings.appDefaultFolder + "backups.xml");
}
Is there any shorten way to do that and also keep simplicity at beginners level?

I will recommend you to use LINQ to XML. It has more simple API for working with XML and your code will look like
var file_name = GlobalSettings.appDefaultFolder + "backups.xml";
XDocument xdoc = XDocument.Load(file_name);
var backup999 = new XElement("backup",
new XAttribute("id", 999),
new XElement("foldername", "testing1"),
new XElement("backupdate", "99/99/9999")
);
xdoc.Root.Add(backup999);
xdoc.Save(file_name);

How I did it plenty of times, using copy special feature of visual studio http://blog.codeinside.eu/2014/09/08/Visual-Studio-2013-Paste-Special-JSON-And-Xml/ I generated the classed describing the xml structure, handle it really clean and easy from code and transfomed when required with System.Xml.Serialization https://support.microsoft.com/en-us/kb/815813 in xml doc or whatever was the need.
The same way from xml to c# object https://msdn.microsoft.com/en-us/library/fa420a9y(v=vs.110).aspx.

My personal preference is to not use the xml api directly. Rather, use the model object then serialize and de-serialize it. It's much cleaner in my opinion and the code to do what you actually need is only 3 lines once your have the generic serializer in place.
What you can do is de-serialize your object into an actual "backupatmail" object and then call backupatmail.BackUpItems.Add(your new item here) and then deserialize it back into a string.
This approach is slower than using LinqToXml during runtime but most of the time a extra millisecond or more isn't a big deal.
Here's the serialization/ deserialization code.
using System.Xml;
using System.Xml.Serialization;
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
public class SerializationUtils
{
public static T Deserialize<T>(string data)
{
XmlSerializer objSerializer = new XmlSerializer(typeof(T));
using (var reader = new StringReader(data))
{
return (T)objSerializer.Deserialize(reader);
}
}
public static string Serialize<T>(T obj)
{
XmlSerializer objSerializer = new XmlSerializer(typeof(T));
XmlSerializerNamespaces emptyNamespaces = new XmlSerializerNamespaces(new [] { XmlQualifiedName.Empty });
var settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.ConformanceLevel = ConformanceLevel.Auto;
#if DEBUG
settings.Indent = true;
#else
settings.Indent = false;
#endif
using (var stream = new StringWriter())
using (var writer = XmlWriter.Create(stream, settings))
{
objSerializer.Serialize(writer, obj, emptyNamespaces);
return stream.ToString();
}
}
}
and for your use.
string mailItems = GetXmlStringFromSomewhere();
var objMail = SerializationUtils.Deserialize<BackUpMail>(mailItems);
var newItem = new BackUp() { FolderName = "testing1", BackupDate = DateTime.Now};
objMail.BackUpItems.Add(newItem);
var strMailWAddedItem = SerializationUtils.Serialize(objMail);
Here are your entity classes.
public class BackUpMail
{
public List<BackUp> BackUpItems {get;set;}
}
public class BackUp
{
[XmlAttribute("id")]
public string ID {get;set}
[XmlElement("foldername")]
public string FolderName {get;set;}
[XmlElement("backupdate")]
public DateTime BackupDate {get;set;}
[XmlElement("comment")]
public string Comment {get;set}
[XmlElement("numberofparts")]
public string NumberOfParts {get;set}
[XmlElement("lastsucceed")]
public string LastSucceed {get;set}
}

Since you have the code, just parameterize it.
public static void someOtherMethod(){
XmlDocument doc = new XmlDocument();
doc.Load(GlobalSettings.appDefaultFolder + "backups.xml");
// some loop..
doc.DocumentElement.AppendChild(createNode(id[i], foldername[i], backupdate[i]));
doc.Save(GlobalSettings.appDefaultFolder + "backups.xml");
}
public static void createNode(string id, string foldername, string backupdate)
{
XmlElement backupNodeNew = doc.CreateElement("backup");
XmlAttribute backupId = doc.CreateAttribute("id");
backupId.Value = id;
backupNodeNew.Attributes.Append(backupId);
XmlNode nodeTitle = doc.CreateElement("foldername");
nodeTitle.InnerText = foldername;
XmlNode nodeUrl = doc.CreateElement("backupdate");
nodeUrl.InnerText = backupdate;
backupNodeNew.AppendChild(nodeTitle);
backupNodeNew.AppendChild(nodeUrl);
return backupNodeNew;
}

Deserialize xml using Bond throws System.IO.InvalidDataException : Unexpected node type

I played a little with Bond using this code:
using System;
using System.IO;
using System.Text;
using System.Xml;
using Bond;
using Bond.Protocols;
using NUnit.Framework;
public class Sandbox
{
[Test]
public void RoundtripWithSchema()
{
var sb = new StringBuilder();
var source = new WithSchema { Value = 1 };
using (XmlWriter xmlWriter = XmlWriter.Create(sb))
{
var writer = new SimpleXmlWriter(xmlWriter);
Serialize.To(writer, source);
}
var xml = sb.ToString();
Console.Write(xml);
Console.WriteLine();
using (var xmlReader = XmlReader.Create(new StringReader(xml)))
{
var reader = new SimpleXmlReader(xmlReader);
var roundtripped = Deserialize<WithSchema>.From(reader); // System.IO.InvalidDataException : Unexpected node type
Assert.AreEqual(source.Value, roundtripped.Value);
}
}
[Test]
public void RoundtripUsingSerializerWithSchema()
{
var sb = new StringBuilder();
var source = new WithSchema { Value = 1 };
using (XmlWriter xmlWriter = XmlWriter.Create(sb))
{
var writer = new SimpleXmlWriter(xmlWriter);
var serializer = new Serializer<SimpleXmlWriter>(typeof(WithSchema));
serializer.Serialize(source, writer);
}
var xml = sb.ToString();
Console.Write(xml);
Console.WriteLine();
using (var xmlReader = XmlReader.Create(new StringReader(xml)))
{
var reader = new SimpleXmlReader(xmlReader);
var serializer = new Deserializer<SimpleXmlReader>(typeof(WithSchema));
var roundtripped = serializer.Deserialize<WithSchema>(reader); // System.IO.InvalidDataException : Unexpected node type
Assert.AreEqual(source.Value, roundtripped.Value);
}
}
}
[Schema]
public class WithSchema
{
[Id(0)]
public int Value { get; set; }
}
Both samples output the expected xml:
<?xml version="1.0" encoding="utf-16"?>
<WithSchema>
<Value>1</Value>
</WithSchema>
Both fail when deserializing throwing System.IO.InvalidDataException : Unexpected node type
Don't know where to look for the bug really, suggestions?

The Bond SimpleXmlReader is having trouble with the <?xml version="1.0" encoding="utf-16"?> line. If you leave this out when serializing, you can deserialize without a problem.
Try something like this
using (XmlWriter xmlWriter = XmlWriter.Create(sb, new XmlWriterSettings { OmitXmlDeclaration = true }))
{
var writer = new SimpleXmlWriter(xmlWriter);
Serialize.To(writer, source);
}
My guess is that XmlNodeType.XmlDeclaration probably needs to be added to the IgnoredTokens set in Bond's SimpleXmlParser.
Bond versions later than v4.0.1 will have this issue (Bond issue #112 on GitHub) fixed.
Inspiration for this answer came from the Bond simple_xml sample.

remove type declaration from XML while serialize

I need to get clear xml without any namespace and type declarations. Here is the serialized xml:
<placeBetRequest p1:type="PlaceBetRequestTeamed" xmlns:p1="http://www.w3.org/2001/XMLSchema-instance">
...
</placeBetRequest>
Need to someway configure XmlSerializer to set it don't add any attributes but only mine (if I set them with [XmlAttribte]
the clean xml need to looks like this:
<placeBetRequest>
...
</placeBetRequest>
Here is my serialization method:
public static string XmlConvert<T>(T obj, params Type[] wellKnownTypes) where T : class
{
var emptyNamepsaces = new XmlSerializerNamespaces(new[] { XmlQualifiedName.Empty });
var settings = new XmlWriterSettings {Indent = true, OmitXmlDeclaration = true};
XmlSerializer serializer = wellKnownTypes == null
? new XmlSerializer(typeof(T))
: new XmlSerializer(typeof(T), wellKnownTypes);
using (var stream = new StringWriter())
using (var writer = XmlWriter.Create(stream, settings))
{
serializer.Serialize(writer, obj, emptyNamepsaces);
return stream.ToString();
}
}
Please help. Thanks.

I've been using regex
string input =
"<p1:placeBetRequest p1:type=\"PlaceBetRequestTeamed\" xmlns:p1=\"http://www.w3.org/2001/XMLSchema-instance\">" +
"</p1:placeBetRequest>";
string pattern = #"(?'prefix'\</?)(?'ns'[^:]*:)";
string output = Regex.Replace(input, pattern, "${prefix}");

Can I add a prefix to root element when I have no control over the serialized .NET type?

I have a library that contains a .NET type. The library has its own configuration (annotations etc) for serializing the type to XML, and I do not have the source code.
No matter what I do, I could not manage to add the prefix I want to add to the root element of the output XML. Using XmlSerializerNamespaces made no difference. Here is a snippet that shows my code at the moment:
var comp = row[0] as LibraryType;
var ser = new XmlSerializer(comp.GetType());
var strWriter = new StringWriter();
var xmlWriter = XmlWriter.Create(strWriter);
ser.Serialize(xmlWriter, comp);
string serXml = strWriter.ToString();
Is there a way in configure XMLSerializer to create an xlm output for root such as
<lt:LibraryType ....
instead of the current
<LibraryType .....
I'm getting ?

Lets say that your library type looks like
public class Foo
{
public int i { get; set; }
}
public class Bar
{
public Foo Foo { get; set; }
}
then serialization should look like
var comp = new Bar {Foo = new Foo()};
var overrides = new XmlAttributeOverrides();
overrides.Add(typeof (Bar), new XmlAttributes {XmlRoot = new XmlRootAttribute {Namespace = "http://tempuri.org"}});
// in case you want to remove prefix from members
var emptyNsAttribute = new XmlAttributes();
emptyNsAttribute.XmlElements.Add(new XmlElementAttribute { Namespace = "" });
overrides.Add(typeof(Bar), "Foo", emptyNsAttribute);
// if you actual library type contains more members, then you have to list all of them
var ser = new XmlSerializer(comp.GetType(), overrides);
var strWriter = new StringWriter();
var xmlWriter = XmlWriter.Create(strWriter);
var ns = new XmlSerializerNamespaces();
ns.Add("lt", "http://tempuri.org");
ser.Serialize(xmlWriter, comp, ns);
string serXml = strWriter.ToString();
and the output will be
<?xml version="1.0" encoding="utf-16"?><lt:Bar xmlns:lt="http://tempuri.org"><Foo><i>0</i></Foo></lt:Bar>