I was trying to insert an XML node in XML document at a specific position.
This is my xml:
<Envelope xmlns="http://schemas.xmlsoap.org/soap/envelope/">
<Body>
<readContract xmlns="http://implementation.company.schema.reference">
<ContactNumbers>10158</ContactNumbers>
<productGroups>0085</productGroups>
<indicationBalanceInfo>false</indicationBalanceInfo>
<indicationBlocked>true</indicationBlocked>
</readContract>
</Body>
</Envelope>
And am trying to insert another tag <productGroups>0093</productGroups> below to the tag <productGroups>0085</productGroups>
Expecting like the below:
<Envelope xmlns="http://schemas.xmlsoap.org/soap/envelope/">
<Body>
<readContract xmlns="http://implementation.company.schema.reference">
<ContactNumbers>10158</ContactNumbers>
<productGroups>0085</productGroups>
<productGroups>0093</productGroups>
<indicationBalanceInfo>false</indicationBalanceInfo>
<indicationBlocked>true</indicationBlocked>
</readContract>
</Body>
</Envelope>
Used the below C# code to achieve it.
XmlDocument doc = new XmlDocument();
string inputxml = this.StServiceCallActivity5.InputEnvelope.InnerXml.ToString();
//Here inputxml contains whole xml document.
string addxml = "<productGroups>0093</productGroups>";
doc.LoadXml(inputxml);
XmlDocumentFragment xmlDocFrag = doc.CreateDocumentFragment();
xmlDocFrag.InnerXml = addxml;
XmlElement parentEle = doc.DocumentElement;
parentEle.AppendChild(xmlDocFrag);
And it returns value like
<Envelope xmlns="http://schemas.xmlsoap.org/soap/envelope/">
<Body>
<readContract xmlns="http://implementation.company.schema.reference">
<ContactNumbers>10158</ContactNumbers>
<productGroups>0085</productGroups>
<productGroups>0093</productGroups>
<indicationBalanceInfo>false</indicationBalanceInfo>
<indicationBlocked>true</indicationBlocked>
</readContract>
</Body>
<productGroups xmlns="">0093</productGroups>
</Envelope>
Am a newbie to C# code, kindly help me to get the XML doc as expected.
your help is much appreciated.
When you do this:
XmlElement parentEle = doc.DocumentElement;
parentEle.AppendChild(xmlDocFrag);
You're appending the node to the root of the document. You probably wanted to select the actual readContract node that the item is supposed to be appended into. As an example:
XmlNode newNode = doc.CreateNode(XmlNodeType.Element, "productGroup", "");
newNode.InnerText = "something";
XmlNode readContractNode = doc["Envelope"]["Body"]["readContract"];
XmlElement groups = readContractNode["productGroups"];
readContractNode.InsertAfter(newNode, groups);
Of course you'd probably want to handle the case where there are already multiple child productGroup elements, but the idea is the same.
Looks like namespaces are causing the problem. This worked for me:
XmlDocument doc = new XmlDocument();
doc.LoadXml(File.ReadAllText("XMLFile1.xml"));
XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable);
ns.AddNamespace("ns1", "http://schemas.xmlsoap.org/soap/envelope/");
ns.AddNamespace("ns2", "http://implementation.company.schema.reference");
var rootNode = doc.SelectSingleNode("//ns1:Envelope", ns);
var readContractNode = rootNode.FirstChild.FirstChild;
var newNode = doc.CreateNode(XmlNodeType.Element, "productGroups", "http://implementation.company.schema.reference");
newNode.InnerText = "0093";
readContractNode.InsertAfter(newNode, readContractNode.SelectSingleNode("//ns2:productGroups", ns));
Or if you don't fancy namespaces like I me, you can try a bit more "brute-forcy" approach:
XmlDocument doc = new XmlDocument();
doc.LoadXml(File.ReadAllText("XMLFile1.xml"));
var newNode = doc.CreateNode(XmlNodeType.Element, "productGroups", "http://implementation.company.schema.reference");
newNode.InnerText = "0093";
doc.FirstChild.FirstChild.FirstChild.InsertAfter(newNode, doc.FirstChild.FirstChild.FirstChild.FirstChild.NextSibling);
It can be optimized but I think it helps to make the point that root cause is the different namespaces in the document.
You may want to use XmlNode.InsertAfter Method.
public virtual XmlNode InsertAfter(
XmlNode newChild,
XmlNode refChild
)
Where
newChild = The XmlNode to insert
and
refChild = The XmlNode that is the reference node. The newNode is placed after the refNode
Please check this link for information.
And check this link with answer on SO.
P.S.
Always check other answers before posting new question.
Related
I wanted to add a xmlNode in a parent but at the top/beginning. Is there a variant of XMLNode.AppendChild() that i can use?
As far as I understand your question you are probably looking for the XmlNode.PrependChild() method.
Example:
XmlDocument doc = new XmlDocument();
XmlNode root = doc.DocumentElement;
//Create a new node.
XmlElement node = doc.CreateElement("price");
//Add the node to the document.
root.PrependChild(node);
MSDN documentation
I believe the question is asking how to add a node to the beginning of the XML file. I did that in the following manner:
// This is the main xml document
XmlDocument document = new XmlDocument();
// This part is creation of RootNode, however you want
XmlNode RootNode = document.CreateElement("Comments");
document.AppendChild(RootNode);
//Adding first child node as usual
XmlNode CommentNode1 = document.CreateElement("UserComment");
RootNode.AppendChild(commentNode1);
//Now create a child node and add it to the beginning of the XML file
XmlNode CommentNode2 = document.CreateElement("UserComment");
RootNode.InsertBefore(commentNode2, RootNode.FirstChild);
I have to analyze a XML doc with special namespace using C#, and I get some idea from this post. But my code fail to get the expected XML node, because the XML structure is very special...
There is a namespace in root node in XML
<MDOC xmlns="urn:schemas-microsoft-com/PSS/PSS_Survey01">
Here is my code to get this root node
XmlDocument doc = new XmlDocument();
doc.Load(path);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("urn", "schemas-microsoft-com/PSS/PSS_Survey01");
XmlNode root = doc.SelectSingleNode("MDOC", nsmgr);
Help me!
I am not sure what is special about your XML structure.
I would write the code little differently
string xmlNamespace = String.Empty;
XmlNamespaceManager nsmgr;
XmlNodeList nodeInfo = FABRequestXML.GetElementsByTagName("RootNodeName");
xmlNamespace = Convert.ToString(nodeInfo[0].Attributes["xmlns"].Value);
nsmgr = new XmlNamespaceManager(MyXml.NameTable);
nsmgr.AddNamespace("AB", xmlNamespace);
XmlNode myNode = MyXml.DocumentElement.SelectSingleNode("AB:NodeName", nsmgr);
Hope that helps
I wanted to convert a string (which obviously is an xml) to an XmlNode in C#.While searching the net I got this code.I would like to know whether this is a good way to convert a string to XmlNode? I have to preform this conversion within a loop, so does it cause any performace issues?
XmlTextReader textReader = new XmlTextReader(new StringReader(xmlContent));
XmlDocument myXmlDocument = new XmlDocument();
XmlNode newNode = myXmlDocument.ReadNode(textReader);
Please reply,
Thanks
Alex
should be straight-forward:
string xmlContent = "<foo></foo>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlContent);
XmlNode newNode = doc.DocumentElement;
or with LINQ if that's an option:
XElement newNode = XDocument.Parse(xmlContent).Root;
The accepted answer works only for single element. XmlNode can have multiple elements like string xmlContent = "<foo></foo><bar></bar>"; (Exception: "There are multiple root elements");
To load multiple elements use this:
string xmlContent = "<foo></foo><bar></bar>";
XmlDocument doc = new XmlDocument();
doc.LoadXml("<singleroot>"+xmlContent+"</singleroot>");
XmlNode newNode = doc.SelectSingleNode("/singleroot");
XmlDocument Doc = new XmlDocument();
Doc.LoadXml(xml);
I have the following xml:
<span>sometext</span>
and I want to wrap this XmlNode with another tag:
<p><span>sometext</span></p>
How can i achieve this. For parsing i use XmlDocument (C#).
The above "best answer" works if you don't care that the new "p" node ends up at the end of the parent. To replace it where it is, use:
string xml = "<span>sometext</span>";
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(xml);
// If you have XmlNode already, you can start from this point
XmlNode node = xDoc.DocumentElement;
XmlElement clone = node.Clone();
XmlNode parent = node.ParentNode;
XmlElement xElement = xDoc.CreateElement("p");
xElement.AppendChild(clone);
parent.ReplaceChild(xElement, node);
you can try something like this.
string xml = "<span>sometext</span>";
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(xml);
// If you have XmlNode already, you can start from this point
XmlNode node = xDoc.DocumentElement;
XmlNode parent = node.ParentNode;
XmlElement xElement = xDoc.CreateElement("p");
parent.RemoveChild(node);
xElement.AppendChild(node);
parent.AppendChild(xElement);
You must use the CreateNode(XmlNodeType.Element, "p", "") of XmlDocument.
Then append the old node to the new one with the AppendChild method
Can someone help me read attribute ows_AZPersonnummer with asp.net using c# from this xml structure
<listitems
xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
xmlns:rs="urn:schemas-microsoft-com:rowset"
xmlns:z="#RowsetSchema"
xmlns="http://schemas.microsoft.com/sharepoint/soap/">
<rs:data ItemCount="1">
<z:row
ows_AZNamnUppdragsansvarig="Peter"
ows_AZTypAvUtbetalning="Arvode till privatperson"
ows_AZPersonnummer="196202081276"
ows_AZPlusgiro="5456436534"
ows_MetaInfo="1;#"
ows__ModerationStatus="0"
ows__Level="1" ows_ID="1"
ows_owshiddenversion="6"
ows_UniqueId="1;#{11E4AD4C-7931-46D8-80BB-7E482C605990}"
ows_FSObjType="1;#0"
ows_Created="2009-04-15T08:29:32Z"
ows_FileRef="1;#uppdragsavtal/Lists/Uppdragsavtal/1_.000"
/>
</rs:data>
</listitems>
And get value 196202081276.
Open this up in an XmlDocument object, then use the SelectNode function with the following XPath:
//*[local-name() = 'row']/#ows_AZPersonnummer
Basically, this looks for every element named "row", regardless of depth and namespace, and returns the ows_AZPersonnummer attribute of it. Should help avoid any namespace issues you might be having.
The XmlNamespaceManager is your friend:
string xml = "..."; //your xml here
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
XmlNamespaceManager nsm = new XmlNamespaceManager(new NameTable());
nsm.AddNamespace("z", "#RowsetSchema");
XmlNode n = doc.DocumentElement
.SelectSingleNode("//#ows_AZPersonnummer", nsm);
Console.WriteLine(n.Value);
You can also use LINQ to XML:
XDocument xd = XDocument.Parse(xml);
XNamespace xns = "#RowsetSchema";
string result1 = xd.Descendants(xns + "row")
.First()
.Attribute("ows_AZPersonnummer")
.Value;
// Or...
string result2 =
(from el in xd.Descendants(xns + "row")
select el).First().Attribute("ows_AZPersonnummer").Value;
I'd say you need an XML parser, which I believe are common. This looks like a simple XML structure, so the handling code shouldn't be too hard.
Use <%# Eval("path to attribute") %> but you need to load the xml has a DataSource.
Otherwise you can load it using XmlTextReader. Here's an example.