I Have a C# program; when I hit a button I want it to open a CMD window, then automatically type in the cmd window and run that said command. So far I have this from 4 hours of research. But nothing is working.
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
//p.StartInfo.CreateNoWindow = true;
p.Start();
p.StandardInput.WriteLine("ipconfig");
Any idea on how to fill in a certain text then automatically run it when the button is hit?
With StandardInput and StandardOutput redirected, you cannot see the new window opened. If you want to create a new cmd window and run ipconfig in it, you could do this:
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/c ipconfig & pause";
p.Start();
I agree that if all you want to do is execute "ipconfig" you could just invoke it instead of cmd.exe. Assuming you want to do other things with cmd.exe, here is an example of how to invoke it, have it execute a command, and then terminate (using the /K switch instead of /C will keep cmd.exe running):
using System;
using System.Diagnostics;
namespace ConsoleApplication2
{
class Program
{
static void Main(string[] args)
{
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/C ipconfig";
p.Start();
var output = p.StandardOutput.ReadToEnd();
Console.Write(output);
Console.ReadKey();
}
}
}
Related
I have a console program written in c++, and I would like to continually check its output to use in my c# project.
This is the code I've tried to steal from another StackOverflow question, but with no luck.
Edit:( By no luck, I mean: the output is pretty much empty, although if I set p.StartInfo.CreateNoWindow to false, I can see my script.exe launch and output into its window. )
Process p = new Process();
p.StartInfo.FileName = #"external\script.exe";
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.CreateNoWindow = true;
p.Start();
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine("Output:");
Console.WriteLine(output);
I had a similar issue and it had to do with where the output was going. The solution was to run cmd and execute my script from the cmd process. See this answer to another question for more information. reading from stdout and stderr together Your new code would look like:
Process p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/c yourscriptpath.exe 2>&1";
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.CreateNoWindow = true;
p.Start();
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine("Output:");
Console.WriteLine(output);
I'm trying to copy output from a program running out of the CMD prompt to the Windows clipboard.
private void button1_Click(object sender, EventArgs e)
{
/*Relevant Code*/
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = String.Format("/k cd {0} && backdoor -rt -on -s{1} -p{2}", backdoorDir, pSN, sPPC);
p.Start();
p.WaitForExit();
string result = p.StandardOutput.ReadToEnd();
System.Windows.Forms.Clipboard.SetText(result);
}
If I were to enter this directly into CMD, it would look like this:
First Command (change directory):
cd C:\users\chris\appdata\roaming\backdoor
Second Command (Launches backdoor, a cmd tool. Arguments follow.):
backdoor -rt -on -sCCDXE -p14453
And when doing this through CMD, I get this result:
The backdoor password is: 34765
C:\users\chris\appdata\roaming\backdoor>
However, when running my C# code, this is the only thing that gets added to my clipboard:
C:\users\chris\appdata\roaming\backdoor>
Why isn't it capturing "The backdoor password is: 34765?" It's like the p.StandardOutput.ReadToEnd() isn't reading everything.
Call ReadToEnd before WaitForExit
Chris' code:
private void button1_Click(object sender, EventArgs e)
{
/*Relevant Code*/
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = String.Format("/k cd {0} && backdoor -rt -on -s{1} -p{2}", backdoorDir, pSN, sPPC);
p.Start();
string result = p.StandardOutput.ReadToEnd();
p.WaitForExit();
System.Windows.Forms.Clipboard.SetText(result);
}
Sample console app code:
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/C dir";
p.Start();
string result = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine(result);
Console.ReadLine();
argument /C executes the command and then terminates the cmd process. This is necessary for this code to work. Otherwise, it will wait for ever.
One reson may well be that the program is not actually writing to StdOut but to the screen directly.
Test this by piping the output into a file:
backdoor -rt -on -sCCDXE -p14453 > c:\text.txt
If the new file doesn't contain the output either then you are stuck and may need to look into screen scraping..
I currently have a portion of code that creates a new Process and executes it from the shell.
Process p = new Process();
...
p.Start();
p.WaitForExit();
This keeps the window open while the process is running, which is great. However, I also want to keep the window open after it finishes to view potential messages. Is there a way to do this?
It is easier to just capture the output from both the StandardOutput and the StandardError, store each output in a StringBuilder and use that result when the process is finished.
var sb = new StringBuilder();
Process p = new Process();
// redirect the output
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardError = true;
// hookup the eventhandlers to capture the data that is received
p.OutputDataReceived += (sender, args) => sb.AppendLine(args.Data);
p.ErrorDataReceived += (sender, args) => sb.AppendLine(args.Data);
// direct start
p.StartInfo.UseShellExecute=false;
p.Start();
// start our event pumps
p.BeginOutputReadLine();
p.BeginErrorReadLine();
// until we are done
p.WaitForExit();
// do whatever you need with the content of sb.ToString();
You can add extra formatting in the sb.AppendLine statement to distinguish between standard and error output, like so: sb.AppendLine("ERR: {0}", args.Data);
This will open the shell, start your executable and keep the shell window open when the process ends
Process p = new Process();
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "CMD.EXE";
psi.Arguments = "/K yourmainprocess.exe";
p.StartInfo = psi;
p.Start();
p.WaitForExit();
or simply
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "CMD.EXE";
psi.Arguments = "/K yourmainprocess.exe";
Process p = Process.Start(psi);
if(p != null && !p.HasExited)
p.WaitForExit();
Be carefull espacially on switch /k, because in many examples is usually used /c.
CMD /K Run Command and then return to the CMD prompt.
CMD /C Run Command and then terminate
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/k yourmainprocess.exe";
p.Start();
p.WaitForExit();
Regarding: "Member Process.Start(ProcessStartInfo) cannot be accessed with an instance reference; qualify it with a type name instead"
This fixed the problem for me....
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "CMD.EXE";
psi.Arguments = "/K yourmainprocess.exe";
Process p = Process.Start(psi);
p.WaitForExit();
I am trying to create process on a remote machine using using System.Diagnostics.Process class.
I am able to create a process. But the problem is, creating a service is take a long time and console window is displayed.
Another annoying thing is the console window is displayed on top of my windows form and i cant do any other operations on that form.
I have set all properties like CreateNoWindow = true,
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden
but still it shows the console window. even i have redirected output and errors to seperate stream but no luck.
Is there any other way to hide the Console window? Please help me out .
Here is the part of my code i used to execute sc command.
Process proc = new Process();
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.StartInfo.FileName = "sc";
proc.StartInfo.Arguments = string.Format(#"\\SYS25 create MySvc binPath= C:\mysvc.exe");
proc.StartInfo.RedirectStandardError = false;
proc.StartInfo.RedirectStandardOutput = false;
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.Start();
proc.WaitForExit();
I had a similar issue when attempting to start a process without showing the console window. I tested with several different combinations of property values until I found one that exhibited the behavior I wanted.
Here is a page detailing why the UseShellExecute property must be set to false.
http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.createnowindow.aspx
Under Remarks section on page:
If the UseShellExecute property is true or the UserName and
Password properties are not null, the CreateNoWindow property
value is ignored and a new window is created.
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = fullPath;
startInfo.Arguments = args;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardError = true;
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
Process processTemp = new Process();
processTemp.StartInfo = startInfo;
processTemp.EnableRaisingEvents = true;
try
{
processTemp.Start();
}
catch (Exception e)
{
throw;
}
I've had bad luck with this answer, with the process (Wix light.exe) essentially going out to lunch and not coming home in time for dinner. However, the following worked well for me:
Process p = new Process();
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
// etc, then start process
This should work, try;
Add a System Reference.
using System.Diagnostics;
Then use this code to run your command in a hiden CMD Window.
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmd.StartInfo.Arguments = "Enter your command here";
cmd.Start();
This doesn't show the window:
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
cmd.StartInfo.CreateNoWindow = true;
...
cmd.Start();
How to hide cmd window while running a batch file?
I use the following code to run batch file
process = new Process();
process.StartInfo.FileName = batchFilePath;
process.Start();
If proc.StartInfo.UseShellExecute is false, then you are launching the process and can use:
proc.StartInfo.CreateNoWindow = true;
If proc.StartInfo.UseShellExecute is true, then the OS is launching the process and you have to provide a "hint" to the process via:
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
However the called application may ignore this latter request.
If using UseShellExecute = false, you might want to consider redirecting standard output/error, to capture any logging produced:
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.RedirectStandardOutput = true;
proc.OutputDataReceived += new DataReceivedEventHandler(ProcessOutputHandler);
proc.StartInfo.RedirectStandardError = true;
proc.ErrorDataReceived += new DataReceivedEventHandler(ProcessOutputHandler);
And have a function like
private void ProcessOutputHandler(object sendingProcess, DataReceivedEventArgs outLine)
{
if (!String.IsNullOrEmpty(outLine.Data)) // use the output outLine.Data somehow;
}
There's a good page covering CreateNoWindow this on an MSDN blog.
There is also a bug in Windows which may throw a dialog and defeat CreateNoWindow if you are passing a username/password. For details
http://connect.microsoft.com/VisualStudio/feedback/ViewFeedback.aspx?FeedbackID=98476
http://support.microsoft.com/?kbid=818858
According to the Process properties, you do have a:
Property: CreateNoWindow
Notes: Allows you to run a command line program silently.
It does not flash a console window.
and:
Property: WindowStyle
Notes: Use this to set windows as hidden.
The author has used ProcessWindowStyle.Hidden often.
As an example!
static void LaunchCommandLineApp()
{
// For the example
const string ex1 = "C:\\";
const string ex2 = "C:\\Dir";
// Use ProcessStartInfo class
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = "dcm2jpg.exe";
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.Arguments = "-f j -o \"" + ex1 + "\" -z 1.0 -s y " + ex2;
try
{
// Start the process with the info we specified.
// Call WaitForExit and then the using statement will close.
using (Process exeProcess = Process.Start(startInfo))
{
exeProcess.WaitForExit();
}
}
catch
{
// Log error.
}
}
Use:
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
This is what worked for me,
When you redirect all of the input and output, and set the window hidden it should work
Process p = new Process();
p.StartInfo.RedirectStandardError = true;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
try with this and this where the c# code is embedded into the batch files:
#echo off
echo self minimizing
call getCmdPid.bat
call windowMode.bat -pid %errorlevel% -mode minimized
echo --other commands--
pause
Though it might be not so easy to unhide the window.