Test if the player's desired movement exceeds a magnitude? - c#

Say I have a point in a Vector3, and my FPSController (I'm using the standard one that comes with Unity 5) moves a magnitude of 10 away from this Vector3. I want to not allow movement, in any direction, beyond magnitude 10. Ideally, I would anticipate which direction the player pressed to move in, test that vector, and if it's below magnitude of 10 then it'll allow the movement to proceed. That way, if you're at 10 and press "back", you wont be able to move but if you press "forward" then no problem.
I know I'm being a bit abstract here. From what I understand the FPSController.cs script is using the CharacterController component. I've studied the FPSController code for awhile tonight and notice it's doing all sorts of calculations on the local position, but the magnitude needs to be between two world coordinates.
I know how to calculate the magnitude already, all I need to know is how to test the anticipated direction. I have a feeling it's easier than I think?

You are overthinking this! Instead of thinking how you can constrain velocity, think about constraining position. Check out Vector3 Vector3.ClampMagnitude(Vector3, float), which returns the vector scaled to a maximum length. By "transforming" the player position to the target, clamping to the max length, then transforming back to world coordinates you can constrain the player's position.
// target: the Vector3 you can't get too far from.
// distance: the float max distance from the target.
transform.position = Vector3.ClampMagnitude(transform.position - target, distance) + target;

Related

#Unity Cube Movement (Jumping +1 Forward/Right/Backward/Left)

Hey stackoverflow Community,
First of all:
I'm still very new about programming with C# and Unity.
My question:
I'm working on an idea for a Movement of a Cube.
It is planned that the cube will move forward by pressing a key (W-Key). But it shouldn't just move forward. It should jump forward to the next point. So always plus 1 of its axis into which it should go. Accordingly, it is only intended to go forward, right, down, left. He won't be able to jump over behind. You should also see that the cube jumps in the respective direction, so it should not teleport itself. :D
Does anyone have an idea how I can realize this movement?
I am very much looking forward to your ideas.
(Sorry if my English is not so good, my English not the best. ^^)
best regards
xKarToSx
So, in order to understand movement, it's best to first understand Vectors in Unity. Since you want to be moving the cube in the forward direction, I'm going to assume this is a 3D game, in which case you want to use a Vector3.
A Vector3 has three components: X, Y, and Z. Each component is tied to an axis. In simple terms, X is tied to left and right, Y is tied to up and down, and Z is tied to forward and back. So, Vector3 position = new Vector3(0, 1, 2); will be a vector that is 1 unit above and 2 units in front of the starting position.
Assuming you've attached this script to the cube you want to move, you can track its position with transform.position. So, if you want to move the cube one unit forward, your code would look something like this:
if(Input.GetKeyDown(KeyCode.W)) // This code will activate once the user presses W.
{
transform.position += new Vector3(0, 0, 1);
}
That will move the cube one unit forward in the Z direction. However, you don't want it to teleport, you want to see it move, correct? In that case, you want to check out Unity's Vector3.Lerp function. Basically, you would use it to smoothly transition an object between two defined positions. You'll need to implement a timer and a for loop in order to make this work correctly.
So, to summarize, for moving one unit forward in the Z direction, your code would look something like this:
if(Input.GetKeyDown(KeyCode.Z))
{
float startTime = Time.time; //Time.time is the current in-game time when this line is called. You'll want to save this to a variable
float speed = 1.0f; //The speed if something you'll want to define. The higher the speed, the faster the cube will move.
Vector3 startPosition = transform.position; //Save the starting position to a different variable so you can reference it later
Vector3 endPosition = startPosition + Vector3.forward; //Vector3.Forward is equivalent to saying (0, 0, 1);
float length = Vector3.Distance(startPosition, endPosition); //You'll need to know the total distance that the cube will move.
while(transform.position != endPosition) //This loop while keep running until the cube reaches its endpoint
{
float distCovered = (Time.time - startTime) * speed; //subtracting the current time from your start time and multiplying by speed will tell us how far the cube's moved
float fraction = distCovered / length; //This will tell us how far along the cube is in relation to the start and end points.
transform.position = Vector3.Lerp(startPosition, endPosition, fraction); //This line will smoothly transition between the start and end points
}
}
I hope this helps you. This is my first time answering a question so sorry if I got some things wrong/it's not the most optimized. Good Luck!

Rotation matrix from normal vector, warping around the poles

I have a camera that needs to orbit locally around an object. This object has an arbitrary rotation, described by a normal vector. Imagine a spherical planet, with a camera looking down at a certain triangle on that planet.
My current implementation is to use the classic vector crossing method to generate a rotation matrix from the triangle's normal, then use that matrix as the basis for the standard orbit camera. This works fine near the equator of the planet, but once it gets near the poles, it starts blowing up, with the camera behaving increasingly erratically the closer that it gets to the very center of the pole.
I've determined that this is due to the first vector cross, as the two vectors are close to one another in that case - I'm not sure what the technical name for the phenomena is. If first vector is 0,1,0, the craziness happens when the normal is close to 0, 1, 0 or 0, -1, 0.
I've found quite a few descriptions of this problem, but no working solutions. The closest I've come was here: http://xboxforums.create.msdn.com/forums/p/13278/13278.aspx It mentions that to handle the 'singularity', use a different vector when it is detected. I can easily determine when the camera is on planet face that will cause this to happen (as my planet sphere is generated from 6 quadtrees projected to spherical coordinates), but there is a very noticeable snap when I switch to a new vector.
Here's the current code:
Vector3 triNormal; //the current normal of the target vertex
Vector3 origin = Vector3.Forward;
Matrix orientation.Forward = origin;
orientation.Up = triNormal;
orientation.Right = Vector3.Cross(orientation.Up, orientation.Forward);
orientation.Right.Normalize();
orientation.Forward = Vector3.Cross(orientation.Right, orientation.Up);
orientation.Forward.Normalize();
I've experimented with detecting when triNormal is on one of the pole faces, and setting 'origin' to something else such as Right. The camera then behaves properly once it is on the face, but is immediately snapped to a new rotation as it crosses over. This makes sense, as its reference vector has just changed, but needs to be eliminated for a smooth user experience. I tried figuring out how to offset the camera's yaw for the orbit camera to counteract the new coordinate system, but it doesn't seem to be a constant value, depending on where on the sphere the camera is currently aiming. I'm not sure how I could calculate what the difference is.
Also note that as it's in XNA and C#, I'm using a right-hand coordinate system.
I don't understand why you do this:
orientation.Forward = Vector3.Cross(orientation.Right, orientation.Up);
orientation.Forward.Normalize();
when you've already used previous orientation.Forward to get orientation.Right.
(If you are "crossing" normal vector I don't think you'll need to normalize them.)
Anyway, if triNormal is the current normal of the target vertex, and your camera is looking down to it, I think you should have:
orientation.Forward = -triNormal

C# bounce/throw physics for items dropping

I thought I'd be able to find this with some searching on the internet but everything I find is just balls bouncing off walls for something like pong or another arbitrary question. I'm making a 2D dungeon crawler game and when I kill enemies and they drop loot I want the item to come flying out as if it had just been thrown in the air and land a random point on the tile the unit was on.
I've been trying to figure this out myself but I can't figure it out, this is probably asked a lot, I'd be really grateful if someone could help me out.
EDIT AS REQUESTED:
Ok well when a monster would be destroyed I would choose a random location within the tile it's in, let's call this location endLoc and the monster's location startLoc. I would then find the center x point between these two locations and decrease the y by 20 ( because that's how many pixels i want the item to go up by), so let's called this variable launchLoc:
launchLoc = new Vector2(startLoc.X + ((endLoc.X - startLoc.X) / 2), startLoc.Y - 20)
I think that produces the right Vector.
So now I would need to launch the item from startLoc, to launchLoc, then have it come back down to endLoc. This is where it gets confusing and I'm not sure how to make a realistic arc for this. The end result would have the item move like it moved along a gaussian, as if it was thrown into the air.
I tried to make it so during each interval, the velocity is increased by 120th, of the X difference, between the startLoc and launchLoc, by an incrementing multiple, but I couldn't get it to work very well. I'm not sure if this was the best way to do. I use 120th because the y value is 20, and the item moves up 1 pixel every interval, so 1 to 20 added up gives 120, this would make the x movement constantly increase, like it was thrown up.
This is in 2D btw, I hope that helps.
You start with an initial velocity vector at time t0 (v(t0)) and position (p(t0)). Gravity can be assumed to produces a constant acceleration (a(t0) = <0, -9.8 m/s2>, though your value may differ) until the object lands. So the general form of the motion for going from one timeslice to the next is:
p(t) = 0.5*a(0)*(t-t0)2 + v(0)*(t-t0) + p(0)
v(t) = a(0)*(t-t0) + v(0)
To figure out when to stop that motion, you need to figure out at what time the object's path will intersect the surface against which it bounces. You'll have to do this for all of the surfaces for which this can reasonably be expected to happen. So for a plane with line equation Ux + Vy + T = 0 you break the position vector into its components, as in:
p(t) = <px(t), py(t)> Then use the quadratic formula to find tc where p(tc) satisfies the line equation:
0.5*(Uax(t0)+Vay(t0))*tc2 + (Uvx(t0)+Vvy(t0))*tc + (Upx(t0)+Vpy(t0)+T) = 0Chose the branch such that tc > t0. From there it's simple to figure out where the object will collide with the surface. You can then update the velocity vector and position vector based on the behavior of the bounce. If the plane is axially aligned (ie, it's a horizontal plane with normal vector parallel to the Z axis), then just flip the sign of the Z component of the velocity vector and multiply the whole velocity vector by some damping factor d, where 0≤d<1 to damp out the velocity. Then repeat until some predetermined time has passed or the velocity reaches some minimal amount (your call on that).
It becomes a bit more difficult with arbitrarily oriented planes. You will need to calculate the angle of incidence of the collision and reflect the velocity vector about the plane normal. I won't go into the details here, as I suspect you're probably not interested in it.

2D Game Physics Vectors issue

I've been working on a simple program in C# in which a Ball [X,Y] cordinates are periodical incremented.
I've managed to implement a collision detection method, but I'm trying to determine how to reflect the ball at an angle oposed bouncing it back along the same linear path.
dx = -dx //This bounces the ball back along the same linear path
dy = -dy
Solution
Trigonometry
theta = range between 0<theta<=360 depending on where it bounced
x = cos(theta)*time
y= sin(theta)*time
The whole point of Newtonian physics is that it is not random, it is deterministic. If you throw the same ball against the same wall at the same angle and with the same velocity and the same spin, it goes to the same place every time.
This sort of program is a really great learning opportunity for both programming and physics. What I encourage you to do is to first write a program that simulates very simple bouncing. As you note, when an object is moving straight down and hits a horizontal surface, then you can model the bounce as simply reversing the vertical velocity component. Just get that right; no gravity, no nothing. That's a great start.
Then try adding bouncing off of horizontal walls, the same way.
Then try adding bouncing off of walls that are not aligned with horizontal or vertical directions. That's where you're going to have to learn how vectors and trigonometry work, because you'll have to work out what component of the ball's velocity is changed by striking the wall obliquely.
Then add gravity. Then add friction from the air. Then add the fact that the ball can be spinning. Add elasticity, so that you can model deformation of the ball.
Once you get to that point, if you want to introduce randomness you'll be able to figure out how to do it. For example, you might introduce randomness by saying "well, when the ball strikes the wall and deforms, I'll introduce a random element that changes its deformation by 0-10%". That will then change how the simulation bounces the ball. You can experiment with different kinds of randomness: add random air currents, for instance.
You will have to add in randomness yourself. To rephrase your question: "Deterministically, it bounces off at angle theta. How can I make it bounce back at angle theta + epsilon, where epsilon is some random value?"
To rotate a vector, see this. You will just specify theta.
pseudocode:
RotateVector(vec):
bounce_vec = [-vec.x vec.y]; //deterministic answer is negative x, normal y
bounce_angle = acos(dot(vec,bounce_vec) / (norm(vec)*norm(bounce_vec)));
modified_angle = bounce_angle + random_number();
ca = cos(modified_angle);
sa = sin(modified_angle);
rotation_matrix = [ca -sa; sa ca];
return rotation_matrix * vec;
Line 3 uses the law of cosines to figure out the angle. In line 4, that angle is modified randomly. The rest of the function rotates the original vector by your new angle.
As long as it's a perfect ball with a perfect surface it will not bounce back randomly. Neither vectors nor trigonometry will give you any randomness.
"randomly, though applying to the basic laws of physics" seems like an oxymoron. However...
If you want it to bounce in a random direction, while maintaining its current speed, you might do something like this (pseudocode):
first, bounce back the canonical way (dx = -dx or dy = -dy depending on the collision)
then convert the dx and dy to polar coordinates (theta and r)
jitter theta by a small amount (+ or - a few degrees, according to your taste)
make sure theta isn't heading into a wall that you just bounced off
convert theta and r back to dx and dy
That would be conserving scalar momentum.

Simple 2D rocket dynamics

I am currently experimenting with some physics toys in XNA using the Farseer Physics library, however my question isn't specific to XNA or Farseer - but to any 2D physics library.
I would like to add "rocket"-like movement (I say rocket-like in the sense that it doesn't have to be a rocket - it could be a plane or a boat on the water or any number of similar situations) for certain objects in my 2D scene. I know how to implement this using a kinematic simulation, but I want to implement it using a dynamic simulation (i.e. applying forces over time). I'm sort of lost on how to implement this.
To simplify things, I don't need the dynamics to rotate the geometry, just to affect the velocity of the body. I'm using a circle geometry that is set to not rotate in Farseer, so I am only concerned with the velocity of the object.
I'm not even sure what the best abstraction should be. Conceptually, I have the direction the body is currently moving (unit vector), a direction I want it to go, and a value representing how fast I want it to change direction, while keeping speed relatively constant (small variations are acceptable).
I could use this abstraction directly, or use something like a "rudder" value which controls how fast the object changes directions (either clockwise or counter clockwise).
What kind of forces should I apply to the body to simulate the movement I'm looking for? Keep in mind that I would also like to be able to adjust the "thrust" of the rocket on the fly.
Edit:
The way I see it, and correct me if I'm wrong, you have two forces (ignoring the main thrust force for now):
1) You have a static "fin" that is always pointed in the same direction as the body. If the body rotates such that the fin is not aligned with the direction of movement, air resistance will apply forces to along the length of the fin, proportional to the angle between the direction of movement and the fin.
2) You have a "rudder", which can rotate freely within a specified range, which is attached some distance from the body's center of mass (in this case we have a circle). Again, when this plane is not parallel to the direction of movement, air resistance causes proportional forces along the length of the rudder.
My question is, differently stated, how do I calculate these proportional forces from air resistance against the fin and rudder?
Edit:
For reference, here is some code I wrote to test the accepted answer:
/// <summary>
/// The main entry point for the application.
/// </summary>
static void Main(string[] args)
{
float dc = 0.001f;
float lc = 0.025f;
float angle = MathHelper.ToRadians(45);
Vector2 vel = new Vector2(1, 0);
Vector2 pos = new Vector2(0, 0);
for (int i = 0; i < 200; i++)
{
Vector2 drag = vel * angle * dc;
Vector2 sideForce = angle * lc * vel;
//sideForce = new Vector2(sideForce.Y, -sideForce.X); // rotate 90 degrees CW
sideForce = new Vector2(-sideForce.Y, sideForce.X); // rotate 90 degrees CCW
vel = vel + (-drag) + sideForce;
pos = pos + vel;
if(i % 10 == 0)
System.Console.WriteLine("{0}\t{1}\t{2}", pos.X, pos.Y, vel.Length());
}
}
When you graph the output of this program, you'll see a nice smooth circular curve, which is exactly what I was looking for!
If you already have code to integrate force and mass to acceleration and velocity, then you just need to calculate the individual part of each of the two elements you're talking about.
Keeping it simple, I'd forget about the fin for a moment and just say that anytime the body of your rocket is at an angle to it's velocity, it will generate a linearly increasing side-force and drag. Just play around with the coefficients until it looks and feels how you want.
Drag = angle*drag_coefficient*velocity + base_drag
SideForce = angle*lift_coefficent*velocity
For the rudder, the effect generated is a moment, but unless your game absolutely needs to go into angular dynamics, the simpler thing to do is let the rudder control put in a fixed amount of change to your rocket body angle per time tick in your game.
I suddenly "get" it.
You want to simulate a rocket powered missile flying in air, OK. That's a different problem than the one I have detailed below, and imposes different limits. You need an aerospace geek. Or you could just punt.
To do it "right" (for space):
The simulated body should be provided with a moment of inertia around its center of mass, and must also have a pointing direction and an angular velocity. Then you compute the angular acceleration from the applied impulse and distance from the CoM, and add that to the angular velocity. This allows you to compute the current "pointing" of the craft (if you don't use gyros or paired attitude jets, you also get a (typically very small) linear acceleration).
To generate a turn, you point the craft off the current direction of movement and apply the main drive.
And if you are serious about this you also need to subtract the mass of burned fuel from the total mass and make the appropriate corrections to the moment of inertia at each time increment.
BTW--This may be more trouble than it is worth: maneuvering a rocket in free-fall is tricky (You may recall that the Russians bungled a docking maneuver at the ISS a few years ago; well, that's not because they are stupid.). Unless you tell us your use case we can't really advise you on that.
A little pseudocode to hint at what you're getting into here:
rocket {
float structuralMass;
float fuelMass;
point position;
point velocity;
float heading;
float omega; // Angular velocity
float structuralI; // moment of inertia from craft
float fuelI; // moemnt of inertia from the fuel load
float Mass(){return struturalMass + fuelMass};
float I(){return struturalI + fuelI};
float Thrust(float t);
float AdjustAttitude(float a);
}
The upshot is: maybe you want a "game physics" version.
For reason I won't both to go into here, the most efficient way to run a "real" rocket is generally not to make gradual turns and slow acceleration, but to push hard when ever you want to change direction. In this case you get the angle to thrust by subtracting the desired vector (full vector, not the unit) from the current one. Then you pointing in that direction, and trusting all out until the desired course is reached.
Imagine your in floating in empty space... And you have a big rock in your hand... If you throw the rock, a small impulse will be applied to you in the exact opposite direction you throw the rock. You can model your rocket as something that rapidly converts quantum's of fuel into some amount of force (a vector quantity) that you can add to your direction vector.

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