So I just learned how to convert ints to binary with Convert.ToString(int , 2);
Now I can use this so ask a user for a number and then save it with
int name = int.Parse(Console.ReadLine());
and then convert it with
Convert.ToString(name , 2);
to get the number in binary.
But I'm wondering if the user could input it in binary and then I could save it as is, to later convert the user input into decimal with
Convert.ToInt32(binary,2).ToString();
I know this isn't correct but just to give you an idea of what I'm looking for here is an example, instead of int you could use binary. Like
binary name = binary.Parse(Console.ReadLine());
You will read a string input from Console.ReadLine - but you can just use Convert.ToInt32(val, 2) to convert a base 2 string to a number.
If you really want to create a binary number type, you will need to define a struct with implicit or explicit conversion to an int, but this seems unneccessary for your task. But, they key point here is that an int is kind of base agnostic - it's the value represented by a string in base whatever.
I think you're slightly confused - when you "convert int's to binary" all you're actually doing is converting the int into a string in it's binary representation. It's not actually binary - it's just a string that contains 1's and 0's that represent a binary number.
To accomplish your goal, all you need to do is:
string binary = Console.ReadLine();
And the user would need to enter "binary" such as 0100. Again, I put binary in quotes because it's still just a string, not a number. If you want the user to enter a number, like 4 and store it as a string of 0100, just do:
string binary = Convert.ToString(int.Parse(Console.ReadLine()), 2);
which will read the user input (4), convert it to an integer, and then convert it to it's string binary representation (0100).
To read it back to an int, do Convert.ToInt32(binary, 2);
Related
Now I know that converting a int to hex is simple but I have an issue here.
I have an int that I want to convert it to hex and then add another hex to it.
The simple solution is int.Tostring("X") but after my int is turned to hex, it is also turned to string so I can't add anything to it until it is turned back to int again.
So my question is; is there a way to turn a int to hex and avoid having turned it to string as well. I mean a quick way such as int.Tostring("X") but without the int being turned to string.
I mean a quick way such as int.Tostring("X") but without the int being
turned to string.
No.
Look at this way. What is the difference between those?
var i = 10;
var i = 0xA;
As a value, they are exactly same. As a representation, first one is decimal notation and the second one is hexadecimal notation. The X you use hexadecimal format specifier which generates hexadecimal notation of that numeric value.
Be aware, you can parse this hexadecimal notation string to integer anytime you want.
C# convert integer to hex and back again
There is no need to convert. Number ten is ten, write it in binary or hex, yes their representation will differ depending in which base you write them but value is same. So just add another integer to your integer - and convert the final result to hex string when you need it.
Take example. Assume you have
int x = 10 + 10; // answer is 20 or 0x14 in Hex.
Now, if you added
int x = 0x0A + 0x0A; // x == 0x14
Result would still be 0x14. See?
Numeric 10 and 0x0A have same value just they are written in different base.
Hexadecimal string although is a different beast.
In above case that could be "0x14".
For computer this would be stored as: '0', 'x', '1', '4' - four separate characters (or bytes representing these characters in some encoding). While in case with integers, it is stored as single integer (encoded in binary form).
I guess you missing the point what is HEX and what is INT. They both represent an numbers. 1, 2, 3, 4, etc.. numbers. There's a way to look at numbers: as natural numbers: INT and hexadecimal - but at the end those are same numbers. For example if you have number: 5 + 5 = 10 (int) and A (as hex) but it the same number. Just view on them are different
Hex is just a way to represent number. The same statment is true for decimal number system and binary although with exception of some custom made numbers (BigNums etd) everything will be stored as binary as long as its integer (by integer i mean not floating point number). What would you really like to do is probably performing calculations on integers and then printing them as a Hex which have been already described in this topic C# convert integer to hex and back again
The short answer: no, and there is no need.
The integer One Hundred and seventy nine (179) is B3 in hex, 179 in base-10, 10110011 in base-2 and 20122 in base-3. The base of the number doesn't change the value of it. B3, 17, 10110011, and 20122 are all the same number, they are just represented different. So it doesn't matter what base they are in as long as you do you mathematical operations on numbers in the same base it doesn't matter what the base is.
So in your case with Hex numbers, they can contain characters such as 'A','B', 'C', and so on. So when you get a value in hex if it is a number that will contain a letter in its hex representation it will have to be a string as letters are not ints. To do what you want, it would be best to convert both numbers to regular ints and then do math and convert to Hex after. The reason for this is that if you want to be able to add (or whatever operation) with them looking like hex you are going to to need to change the behavior of the desired operator on string which is a hassle.
I have a string that contains the next value: 0x6007.(stringToShort)
I want to convert this string to short var, however, when I attempt to convert it the next way:
short s = ((short)Convert.ToUInt16(stringToShort, 16));
then s equals to 24583 and not to 0x6007 as I need.
Can anyone help?
Values like "0x6007" and "24583" are for human consumption. They are textual representations of a number, and are meaningful only for humans.
As far as the computer is concerned, when dealing with actual numbers, it only understands binary (and even there, only in an abstract sense…it doesn't literally store the binary digits 0s and 1s).
Any time you ask the computer what number it's thinking of, it will convert from that binary-based representation to a human-readable representation (even if binary…we puny humans can't see the state of the bits in the computer and have to ask the computer to translate them to a visual representation).
When you store the value 0x6007 in (for example) a short variable, that variable contains the value 0x6007. It also contains the value 24583. Oh, and it also contains the value 110000000000111 (binary), and the value 60007 (octal), and even the value 12287 (base twelve). Because what the computer is storing is not any of those specific representations of numbers, but rather its own internal representation of the magnitude any of those human-readable numbers represent.
But they are all the same. And when you parse a human-readable string like "0x6007", you do get exactly that value in the variable into which you stored the result, i.e. the computer's internal representation of a number having the same magnitude.
By default, if you ask the computer to tell you what that value is, it will give you the decimal representation of "24583". But if you want the hexadecimal representation, you need only ask nicely and the computer will give that to you instead (e.g. switch the numeric display format in your debugger, or use the "X" numeric format specifier in string.Format(), Console.WriteLine(), etc.).
In C#, is there a way to convert an int value to a hex value without using the .ToString("X") method?
Your question is plain wrong (no offense intended). A number has one single value. Hex, Decimal, Binary, Octal, etc. are just different representations of one same integral number. Int32 is agnostic when it comes to what representation you choose to write it with.
So when you ask:
is there a way to convert an int value to a hex value
you are asking something thast doesn't make sense. A valid question would be: is there anyway to write a integer in hexadecimal representation that doesn't involve using .ToString("X")?
The answer is not really. Someway or the other (directly or not by you), .ToString("X") or some other flavor of ToString() will be called to correctly format the string representing the value.
And when you think of hexadecimal as a respresentation (a formatted string) of a given number, then .ToString() does make sense.
Use Convert.ToString( intValue, 16 );
It can be used to convert between any common numeric base, i.e., binary, octal, decimal and hexadecimal.
Did Binary and ASCII data type had been defined in C# 2.0?
I plan to detect several variables are Binary or ASCII or Integer(sbyte, byte, short, ushort, long, ulong) types.
I can use typeof(sbyte) ect.
But I failed to implement as this typeof(binary) or typeof(ascii).
What I need is something like this typeof function to detect the variables are Binary or ASCII type?
[update]
format code Octal
Binary 001000 10
ASCII 010000 20
Normally you would store text data in a string, and binary data in a byte[]. Do not try to store binary data in a string by applying an arbitrary encoding. For example, if you try to use Encoding.UTF8.GetString(binaryData) then it's highly likely that you won't be able to get the original data back again.
If you need to store binary data in a string, you should use something like Convert.ToBase64String (and then Convert.FromBase64String) which stores 3 bytes of binary data in each 4 characters in the string.
If you need to store data in a string and the type of the original data, you should either store the type separately, or keep a compound form such as "type:data". Sample strings might then be:
int:10
string:10 // The digits 1 and 0, but originally as text, not a number
binary:hFed234= // Base-64-encoded data
Have a look at System.Text.Encoding and System.Text.Decoder.
You need to attempt-parse it into a fitting datatype. Set them up with priority.
Something like:
1) Try to parse integer, if fail continue
2) Try to parse text, if fail continue
3) Save binary
To autodetect encoding see Determine a string's encoding in C#
Why does (string)int32 always throw: Cannot convert type 'int' to 'string'
public class Foo
{
private int FooID;
public Foo()
{
FooID = 4;
string s = (string)FooID; //throws compile error
string sss = FooID.ToString(); //no compile error
}
}
Because there is no type conversion defined from Int32 to string. That's what the ToString method is for.
If you did this:
string s = (string)70;
What would you expect to be in s?
A. "70" the number written the way humans would read it.
B. "+70" the number written with a positive indicator in front.
C. "F" the character represented by ASCII code 70.
D. "\x00\x00\x00F" the four bytes of an int each separately converted to their ASCII representation.
E. "\x0000F" the int split into two sets of two bytes each representing a Unicode character.
F. "1000110" the binary representation for 70.
G. "$70" the integer converted to a currency
H. Something else.
The compiler can't tell so it makes you do it the long way.
There are two "long ways". The first is to use one of the the Convert.ToString() overloads something like this:
string s = Convert.ToString(-70, 10);
This means that it will convert the number to a string using base 10 notation. If the number is negative it displays a "-" at the start, otherwise it just shows the number. However if you convert to Binary, Octal or Hexadecimal, negative numbers are displayed in twos complement so Convert.ToString(-7, 16) becomes "ffffffba".
The other "long way" is to use ToString with a string formatter like this:
string s2 = 70.ToString("D");
The D is a formatter code and tells the ToString method how to convert to a string. Some of the interesting codes are listed below:
"D" Decimal format which is digits 0-9 with a "-" at the start if required. E.g. -70 becomes "-70".
"D8" I've shown 8 but could be any number. The same as decimal, but it pads with zeros to the required length. E.g. -70 becomes "-00000070".
"N" Thousand separators are inserted and ".00" is added at the end. E.g. -1000 becomes "-1,000.00".
"C" A currency symbol is added at the start after the "-" then it is the same as "N". E.g. Using en-Gb culture -1000 becomes "-£1,000.00".
"X" Hexadecimal format. E.g. -70 becomes "46".
Note: These formats are dependent upon the current culture settings so if you are using en-Us you will get a "$" instead of a "£" when using format code "C".
For more information on format codes see MSDN - Standard Numeric Format Strings.
When performing a cast operation like (string)30, you're basically telling the computer that "this object is similar enough to the object I'm casting to that I won't lose much (or any) data/functionality".
When casting a number to a string, there is a "loss" in data. A string can not perform mathematical operations, and it can't do number related things.
That is why you can do this:
int test1 = 34;
double test2 = (double)test1;
But not this:
int test1 = 34;
string test2 = (string)test1;
This example isn't perfect since (IIRC) the conversion here is implicit, however the idea is that when converting to a double, you don't lose any information. That data type can still basically act the same whether it's a double or an int. The same can't be said of an int to a string.
Casting is (usually) only allowed when you won't lose much functionality after the conversion is done.
The .ToString() method is different from casting because it's just a method that returns a string data type.
Just another note: In general, if you want to do an explicit conversion like this (and I agree with many other answers here as to why it needs to be an explicit conversion) don't overlook the Convert type. It is designed for these sorts of primitive/simple type conversions.
I know that when starting in C# (and coming from C++) I found myself running into type casts that seemed like they should have worked. C++ is just a bit more liberal when it comes to this sort of thing, so in C# the designers wanted you to know when your type conversion were ambiguous or ill-advised. The Convert type then fills in the gaps by allowing you to explicitly convert and understand the side-effects.
Int doesn't have an explicit operator to string. However, they have Int32.ToString();. Maybe you can create one with Extension methods, if you really want to.
Because C# does not know how to convert int to string, the library (.ToString) does.
Int32 can't be casted to string because C# compiler doesn't know how to converter from one type to another.
Why is that, you will ask the reason is simple int32 is type integer/numerical and string is, oh well type string/characters. You may be able to convert from numerical type to another numerical type (ex. float to int, but be warned possible loss of accuracy).
If all possible casts where coded in the compiler the compiler would become too slow and certainly would miss much of the possible casts created for user defined types which is a major NO NO.
So the workaround is that any object in C# has a function inherited .ToString() that knows how to handle every type because .ToString() is specifically coded for the specific type, and as you guessed by now returns a string.
After all Int32 type is some bits in memory (32 bits to be exact) and string type is another pile of bits (how many bits depends on how much has been allocated) the compiler/runtime doesn't know anything just by itself looking at that data until now. .ToString() function accesses the specific metadata needed to convert from one to the other.
I just found the answer. ToString works fine on an int variable. You just have to make sure you add the brackets.
ie...
int intMyInt=32;
string strMyString = intMyInt.ToString();
VB .net is perfectly capable of casting from an int to string... in fact so is Java. Why should C# have a problem with it? Sometimes it is necessary to use a number value in calculations and then display the result in a string format. How else would you manage to display the result of a calculation in a TextBox?
The responses given here make no sense. There must be a way to cast an int as a string.