I have collected a code in c# for browsing files and folders in windows. My sample code segment is as follows:
void ButtonbrowseOnClick(object obj, EventArgs ea)
{
int size = -1;
DialogResult result = openFileDialog1.ShowDialog(); // Show the dialog.
if (result == DialogResult.OK) // Test result.
{
string file = openFileDialog1.FileName;
try
{
string text = File.ReadAllText(file);
size = text.Length;
}
catch (IOException)
{
}
}
Console.WriteLine(size); // <-- Shows file size in debugging mode.
Console.WriteLine(result); // <-- For debugging use.
}
But, I am getting the following error:
The name 'openFileDialog1' does not exist in the current context
What's wrong in the code segment?
It does not exist cause it hasn't been defined.
OpenFileDialog openFileDialog1 = new OpenFileDialog();
Are you sure you have defined the openFileDialog1? Changing the second line of your method to the bellow, seems to solve the problem
void ButtonbrowseOnClick(object obj, EventArgs ea)
{
int size = -1;
OpenFileDialog openFileDialog1 = new OpenFileDialog(); //define the variable
DialogResult result = openFileDialog1.ShowDialog();
//your code
Related
Not sure how to implement this, i am not using SaveFileDialog which i have seen uses OverWritePrompt = true cant seem to get that to work for me.
I am using WPF.
The structure:-
I have a textBox called filePathBox - This contains a file path used from opening an: OpenFileDialog
private void fileBrowser_Click(object sender, RoutedEventArgs e)
{
//Firstly creating the OpenFileDialog
Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();
//Setting the filter for the file extension of the files as well as the default extension
dlg.DefaultExt = ".txt";
dlg.Filter = "All Files|*.*";
//Display the dialog box by calling the ShowDialog method
Nullable<bool> result = dlg.ShowDialog();
//Grab the file you selected and display it in filePathBox
if (result == true)
{
//Open The document
string filename = dlg.FileName;
filePathBox.Text = filename;
}
}
You can then click a button and the .txt file displays in a textBox called textResult
private void helpfulNotes_Click(object sender, RoutedEventArgs e)
{
if (File.Exists(filePathBox.Text) && System.IO.Path.GetExtension(filePathBox.Text).ToLower() == ".txt")
{
textResult.Text = File.ReadAllText(filePathBox.Text);
}
if (string.IsNullOrWhiteSpace(filePathBox.Text))
{
MessageBox.Show("Please choose a file by clicking on the folder Icon :(");
}
}
Once you have made changes to that text in 'textResult' i have a button to save the text back to the file path that was originally loaded using the OpenFileDialog
private void saveText_Click(object sender, RoutedEventArgs e)
{
if (string.IsNullOrEmpty(textResult.Text))
{
saveText.IsEnabled = false;
MessageBox.Show("No Text to save!");
}
else
{
saveText.IsEnabled = true;
string test = textResult.Text;
System.IO.File.WriteAllText(filePathBox.Text, test);
}
//fileSaveIcon.Visibility = Visibility.Visible;
//fileChangedIcon.Visibility = Visibility.Hidden;
}
At the moment it all saves fine, only it doesn't prompt the user saying are you sure you want to overwrite the file.
At the moment i could
load a file for the purpose of this named TestNote.txt into the
filePathBox
Type some text in textResult before even clicking to display the
file
Click save and it would just overwrite TestNote.txt with the text i
just entered without even warning me
Hopefully i have explained this adequately and provided all the code you need
Just add a messagebox to show your alert message before writing to the text file.
private void saveText_Click(object sender, RoutedEventArgs e)
{
if (string.IsNullOrEmpty(textResult.Text))
{
saveText.IsEnabled = false;
MessageBox.Show("No Text to save!");
}
else
{
if(MessageBox.Show("are you sure you want to overwrite the file.", "Alert", MessageBoxButtons.YesNo)==DialogResult.Yes)
{
saveText.IsEnabled = true;
string test = textResult.Text;
System.IO.File.WriteAllText(filePathBox.Text, test);
}
}
//fileSaveIcon.Visibility = Visibility.Visible;
//fileChangedIcon.Visibility = Visibility.Hidden;
}
Well, OverWritePrompt is a SaveFileDialog property, which you're not using: you're always using File.WriteAllText(), which always overwrites the target file.
You want to provide a Save function that saves an earlier opened file without prompt, a Save As function that prompts the user for a new filename and also call Save As when saving a new file.
This is implemented like this, pseudo:
private string _currentlyOpenedFile;
public void FileOpen_Click(...)
{
var openFileDialog = new ...OpenFileDialog();
if (openFileDialog.ShowDialog())
{
// Save the filename when opening a file.
_currentlyOpenedFile = openFileDialog.FileName;
}
}
public void FileNew_Click(...)
{
// Clear the filename when closing a file or making a new file.
_currentlyOpenedFile = null;
}
public void FileSave_Click(...)
{
if (_currentlyOpenedFile == null)
{
// New file, treat as SaveAs
FileSaveAs_Click();
return;
}
}
public void FileSaveAs_Click(...)
{
var saveFileDialog = new ...SaveFileDialog();
if (openFileDialog.ShowDialog())
{
// Write the file.
File.WriteAllText(text, openFileDialog.FileName);
// Save the filename after writing the file.
_currentlyOpenedFile = openFileDialog.FileName;
}
}
Here you'll be leveraging the SaveFileDialog's functionality which prompts the user whether they want to overwrite an already existing file.
I want to keep the last path which is selected. This is the code:
private void testFileButton_Click(object sender, EventArgs e)
{
fd = new OpenFileDialog();
fd.FileName = testParameters.testFileFile;
fd.InitialDirectory = testParameters.testFileDir;
if (fd.ShowDialog() == DialogResult.OK)
{
try
{
if (fd.SafeFileName != null)
{
testParameters.testFileDir = Path.GetDirectoryName(fd.FileName);
testParameters.testFileFile = Path.GetFileName(fd.FileName);
testFileLabel.Text = fd.FileName;
}
}
catch (IOException)
{
MessageBox.Show("Error: Could not read file");
}
}
}
to be able to keep the last selected path, I tried to add RestorDirectory and index but I did not get any result:
private void testFileButton_Click(object sender, EventArgs e)
{
fd = new OpenFileDialog();
fd.FileName = testParameters.testFileFile;
fd.InitialDirectory = testParameters.testFileDir;
fd.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
fd.FilterIndex = 2;
fd.RestoreDirectory = true;
if(...){
...
}
}
then I tried to use "else" instead:
private void testFileButton_Click(object sender, EventArgs e)
{
fd = new OpenFileDialog();
fd.FileName = testParameters.testFileFile;
fd.InitialDirectory = testParameters.testFileDir;
if (fd.ShowDialog() == DialogResult.OK)
{
try
{
if (fd.SafeFileName != null)
{
testParameters.testFileDir = Path.GetDirectoryName(fd.FileName);
testParameters.testFileFile = Path.GetFileName(fd.FileName);
testFileLabel.Text = fd.FileName;
}
}
}
catch (IOException)
{
MessageBox.Show("Error: Could not read file");
}
}
else
{
openFileDialog1.InitialDirectory = #"C:\";
}
}
but again without any result..
Does anyone have any idea?
Editing: Last attemp
private void testFileButton_Click(object sender, EventArgs e)
{
//http://stackoverflow.com/questions/7793158/obtaining-only-the-filename-when-using-openfiledialog-property-filename
OpenFileDialog fd = new OpenFileDialog();
fd.FileName = testParameters.testFileFile;
Environment.CurrentDirectory = #"C:\" ;
if (fd.ShowDialog() == DialogResult.OK )
{
try
{
if (fd.SafeFileName != null)
{
string ffileName = fd.FileName;
testParameters.testFileDir = Path.GetDirectoryName(ffileName);
testParameters.testFileFile = Path.GetFileName(ffileName);
testFileLabel.Text = ffileName;
}
}
catch (IOException)
{
MessageBox.Show("Error: Could not read file");
}
}
}
The documentation states:
true if the dialog box restores the current directory to its original value if
the user changed the directory while searching for files; otherwise, false.
Update: Changing my answer a little, since I think I may have misunderstood your intention:
If I'm not mistaken, your dialog will open to fd.InitialDirectory each time you open it, since that is per definition the default for a new instance of fd. I believe this might be your problem here: You are calling fd = new OpenFileDialog(); each time you are trying to open it.
If you change your code to use the same instance for fd each time (define it in an outer scope, and e.g. access a singleton instance via a Property?), it might remember it's previous directory itself - that is the default behavior (which you can override using the RestoreDirectory property).
Example of getting a singleton instance: This will only instantiate the dialog once, and return the same instance each time you call the property:
Private OpenFileDialog _fd;
private OpenFileDialog SingleFd {
get { return _fd ?? (_fd = new OpenFileDialog()); }
}
// Now in your method, use:
var singleInstance = SingleFd;
You are not using same variable for file dialog everywhere. Like in if block you are showing file dialog fd, but in else part you are using variable openFileDialog. I couldn't understand why you are doing this, or probably it is a typo. Use same variable at both place if you want to set initial directory to "C:\" if user cancels the dialog.
Instead of creating instance in every call, create an instance once and use it for subsequent calls.
Regarding directory restore, if we don't set initial directory, by default it restores the previous directory, even for the different instances.
OpenFileDialog initially uses the current directory which is a process-wide setting. You have overridden this behavior by setting the InitialDirectory. Just don't do that and it will work.
If you want to persist the last directory used across process restarts, capture Environment.CurrentDirectory and save it. Set it before opening the dialog.
Note, that the current directory is a process-wide setting so that different parts of the app can interfere. Also, all relative paths are interpreted relative to this directory (which is why relative path are usually a bug waiting).
string path = #"C:\";
OpenFileDialog fd = new OpenFileDialog();
fd.FileName = "SelectFolder";
fd.InitialDirectory =path;
fd.ValidateNames = false;
fd.CheckFileExists = false;
if (fd.ShowDialog() == DialogResult.OK)
{
try
{
if (fd.SafeFileName != null)
{
string txt1 = System.IO.Path.GetFullPath(fd.FileName),
txt2 = txt1.Replace("SelectFolder", "").Trim();
testFileLabel.Text = txt2.Replace(path, "").Replace(#"\", ""); ;
}
}
catch (IOException)
{
MessageBox.Show("Error: Could not read file");
}
}
The Solution is to set the InitialDirectory path Blank
openFileDialog.InitialDirectory = ""
openFileDialog.RestoreDirectory = True
I am currently coding a "quickstart program" which lets you open an .exe file and start them whenever you click a button.
For this I used an openFileDialog to let the user open the desired .exe files.
Additionally I extract the icons from the .exe to show it, above the start button.
This enables the user to select a file (.exe) the DialogResult of the openFileDialog shows none. It never shows OK, even though I load a normal and working .exe.
Here is my code.
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.ShowDialog();
if (DialogResult == DialogResult.OK)
{
string path = openFileDialog1.FileName;
ExtractIcon(path);
}
}
private void ExtractIcon(string filePath)
{
Icon ico = Icon.ExtractAssociatedIcon(filePath);
pictureBox1.Image = ico.ToBitmap();
}
Is there any problem with my code or is it because of DialogResult?
Try changing the code something like this:
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
string path = openFileDialog1.FileName;
ExtractIcon(path);
}
You need to store the return value of ShowDialog() in a variable and then compare this to DialogResult.OK
var result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK){
string path = openFileDialog1.FileName;
ExtractIcon(path);
}
What is DialogResult variable? Shouldn't it be:
var result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK)
{
string path = openFileDialog1.FileName;
ExtractIcon(path);
}
I'm trying to use openFileDialog to open a Bitmap image and place it on my form. My form construtor...
public Form1()
{
InitializeComponent();
drawing = new Bitmap(drawingPanel.Width, drawingPanel.Height, drawingPanel.CreateGraphics());
Graphics.FromImage(drawing).Clear(Color.White);
// set default value for line thickness
tbThickness.Text = "5";
}
... opens a new form with a blank screen, and I can draw on it using the mouse and various color selector buttons. I then save the file with this method:
private void btnSave_Click(object sender, EventArgs e)
{
// save drawing
if (file == null) // file is a FileInfo object that I want to use
// to check to see if the file already exists
// I haven't worked that out yet
{
drawing.Save("test.bmp");
//SaveBitmap saveForm = new SaveBitmap();
//saveForm.Show();
}
else
{
drawing.Save(fi.FullName);
}
}
The image does save to the debug folder as a .bmp file. Then I use OpenFileDialog to open the file:
private void btnOpen_Click(object sender, EventArgs e)
{
FileStream myStream;
OpenFileDialog openFile = new OpenFileDialog();
openFile.Filter = "bmp files (*.bmp)|*.bmp";
if (openFile.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = (FileStream)openFile.OpenFile()) != null)
{
using (myStream)
{
PictureBox picBox = new PictureBox();
picBox.Location = drawingPanel.Location;
picBox.Size = drawingPanel.Size;
picBox.Image = new Bitmap(openFile.FileName);
this.Controls.Add(picBox);
}
}
}
catch (Exception ex)
{
}
}
}
What happes is that OpenFileDialog box comes up. When I select the file test.bmp, the screen goes away and then reappears, when I select it again, the OpenFileDialog window goes away and I'm back to my form with no image. Was hoping for some pointers. No compile or runtime errors.
Why are you calling ShowDialog() twice?
Just call ShowDialog once, so it doesn't open twice, like you indicated.
From MSDN:
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.Filter = "bmp files (*.bmp)|*.bmp";
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = openFileDialog1.OpenFile()) != null)
{
using (myStream)
{
// Insert code to read the stream here.
PictureBox picBox = new PictureBox();
picBox.Location = drawingPanel.Location;
picBox.Size = drawingPanel.Size;
picBox.Image = new Bitmap (myStream);
this.Controls.Add(picBox);
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
You open a dialog panel, then when it closes you check to see if the result was OK; then you open another new dialog in the using block; then you assign the image result of that to the PictureBox, and then throw everything away when the using block disposes.
You're calling ShowDialogue twice which is likely the source of your problem. Just use the following code, remove everything else from the method. Your use of using is also incorrect. it does clean up which is disposing of the results. You need to refactor or remove the using statement.
private void btnOpen_Click(object sender, EventArgs e)
{
OpenFileDialog dlg = new OpenFileDialog()
{
dlg.Title = "Open Image";
dlg.Filter = "bmp files (*.bmp)|*.bmp";
if (dlg.ShowDialog() == DialogResult.OK)
{
PictureBox picBox = new PictureBox();
picBox.Location = drawingPanel.Location;
picBox.Size = drawingPanel.Size;
picBox.Image = new Bitmap (dlg.FileName);
this.Controls.Add(picBox);
}
}
}
The code above works but is without clean up or error handling. I'll leave that to you.
This is similar to older posts on this site but I keep getting an error message. I want to create a button in C # WPF that opens a dialogbox and saves a text file to be read at a later date. This code works for windows 32, but crashes on windows 64. How can I change this code to get it to work on both systems? I am a beginner at programming.
Microsoft.Win32.SaveFileDialog saveFile = new Microsoft.Win32.SaveFileDialog(); //throws error message here
private void savebutton_Click(object sender, RoutedEventArgs e)
{
saveFile.FileName = Class1.stringjobnum;
saveFile.Filter = "CCurtain (*.cur)|*.cur";
saveFile.FilterIndex = 2;
saveFile.InitialDirectory = "T:\\Tank Baffle Curtain Calculator\\SavedTanks";
saveFile.OverwritePrompt = true;
bool? result = saveFile.ShowDialog();
if (result.HasValue && result.Value)
{
clsSaveFile.s_FilePath = saveFile.FileName;
int iDotLoc = clsSaveFile.s_FilePath.LastIndexOf('.');
string strExtTest = clsSaveFile.s_FilePath.Substring(iDotLoc);
if (strExtTest != ".cur")
clsSaveFile.s_FilePath += ".cur";
FileInfo sourceFile = new FileInfo(clsSaveFile.s_FilePath);
clsSaveFile.saveFile();
}
}
You're setting an invalid FilterIndex, that might have something to do with it.
There is no 2nd filter in the filter string as written:
"CCurtain (*.cur)|*.cur"
Try setting the FilterIndex to 1 or adding another filter to the string.
You should try adding a catch around the statement to get a better idea as to what is going on.
try
{
code here
}
catch (Exception ex)
{
ex.message contains the info
}
Also, check for null:
bool? result = saveFile.ShowDialog();
if (result != null && (result.HasValue && result.Value))
{
// code
}
I would create the dialogbox IN the event. And you don't have two different filters.
private void savebutton_Click(object sender, RoutedEventArgs e)
{
Microsoft.Win32.SaveFileDialog saveFile = new Microsoft.Win32.SaveFileDialog();
saveFile.FileName = Class1.stringjobnum;
saveFile.Filter = "CCurtain|*.cur";;
saveFile.FilterIndex = 1;
saveFile.InitialDirectory = "T:\\Tank Baffle Curtain Calculator\\SavedTanks";
saveFile.OverwritePrompt = true;
// Show open file dialog box
Nullable<bool> result = saveFile.ShowDialog();
// Process open file dialog box results
if (result == true)
{
string filename = saveFile.FileName;
// are you sure you need to check the extension.
// if so extension is a a fileinfo property
}