Is it possible to assign a base class object to a derived class reference with an explicit typecast in C#?.
I have tried it and it creates a run-time error.
No. A reference to a derived class must actually refer to an instance of the derived class (or null). Otherwise how would you expect it to behave?
For example:
object o = new object();
string s = (string) o;
int i = s.Length; // What can this sensibly do?
If you want to be able to convert an instance of the base type to the derived type, I suggest you write a method to create an appropriate derived type instance. Or look at your inheritance tree again and try to redesign so that you don't need to do this in the first place.
No, that's not possible since assigning it to a derived class reference would be like saying "Base class is a fully capable substitute for derived class, it can do everything the derived class can do", which is not true since derived classes in general offer more functionality than their base class (at least, that's the idea behind inheritance).
You could write a constructor in the derived class taking a base class object as parameter, copying the values.
Something like this:
public class Base {
public int Data;
public void DoStuff() {
// Do stuff with data
}
}
public class Derived : Base {
public int OtherData;
public Derived(Base b) {
this.Data = b.Data;
OtherData = 0; // default value
}
public void DoOtherStuff() {
// Do some other stuff
}
}
In that case you would copy the base object and get a fully functional derived class object with default values for derived members. This way you can also avoid the problem pointed out by Jon Skeet:
Base b = new Base();//base class
Derived d = new Derived();//derived class
b.DoStuff(); // OK
d.DoStuff(); // Also OK
b.DoOtherStuff(); // Won't work!
d.DoOtherStuff(); // OK
d = new Derived(b); // Copy construct a Derived with values of b
d.DoOtherStuff(); // Now works!
Solution with JsonConvert (instead of typecast)
Today i faced the same issue and i found a simple and quick solution to the problem using JsonConvert.
var base = new BaseClass();
var json = JsonConvert.SerializeObject(base);
DerivedClass derived = JsonConvert.DeserializeObject<DerivedClass>(json);
I had this problem and solved it by adding a method that takes a type parameter and converts the current object into that type.
public TA As<TA>() where TA : Base
{
var type = typeof (TA);
var instance = Activator.CreateInstance(type);
PropertyInfo[] properties = type.GetProperties();
foreach (var property in properties)
{
property.SetValue(instance, property.GetValue(this, null), null);
}
return (TA)instance;
}
That means that you can use it in you code like this:
var base = new Base();
base.Data = 1;
var derived = base.As<Derived>();
Console.Write(derived.Data); // Would output 1
As many others have answered, No.
I use the following code on those unfortunate occasions when I need to use a base type as a derived type. Yes it is a violation of the Liskov Substitution Principle (LSP) and yes most of the time we favor composition over inheritance. Props to Markus Knappen Johansson whose original answer this is based upon.
This code in the base class:
public T As<T>()
{
var type = typeof(T);
var instance = Activator.CreateInstance(type);
if (type.BaseType != null)
{
var properties = type.BaseType.GetProperties();
foreach (var property in properties)
if (property.CanWrite)
property.SetValue(instance, property.GetValue(this, null), null);
}
return (T) instance;
}
Allows:
derivedObject = baseObect.As<derivedType>()
Since it uses reflection, it is "expensive". Use accordingly.
No it is not possible, hence your runtime error.
But you can assign an instance of a derived class to a variable of base class type.
As everyone here said, that's not possible directly.
The method I prefer and is rather clean, is to use an Object Mapper like AutoMapper.
It will do the task of copying properties from one instance to another (Not necessarily the same type) automatically.
In c# 9.0 you can try to use records for this. They have default copy constructor that copy all fields - no need to use reflection / constructor with all fields.
public record BaseR
{
public string Prop1 { get; set; }
}
public record DerivedR : BaseR
{
public DerivedR(BaseR baseR) : base(baseR) { }
public string Prop2 { get; set; }
}
var baseR = new BaseR { Prop1 = "base prob" };
var derivedR = new DerivedR(baseR) { Prop2 = "new prop" };
Not in the Traditional Sense... Convert to Json, then to your object, and boom, done! Jesse above had the answer posted first, but didn't use these extension methods which make the process so much easier. Create a couple of extension methods:
public static string ConvertToJson<T>(this T obj)
{
return JsonConvert.SerializeObject(obj);
}
public static T ConvertToObject<T>(this string json)
{
if (string.IsNullOrEmpty(json))
{
return Activator.CreateInstance<T>();
}
return JsonConvert.DeserializeObject<T>(json);
}
Put them in your toolbox forever, then you can always do this:
var derivedClass = baseClass.ConvertToJson().ConvertToObject<derivedClass>();
Ah, the power of JSON.
There are a couple of gotchas with this approach: We really are creating a new object, not casting, which may or may not matter. Private fields will not be transferred, constructors with parameters won't be called, etc. It is possible that some child json won't be assigned. Streams are not innately handled by JsonConvert. However, if our class doesn't rely on private fields and constructors, this is a very effective method of moving data from class to class without mapping and calling constructors, which is the main reason why we want to cast in the first place.
Expanding on #ybo's answer - it isn't possible because the instance you have of the base class isn't actually an instance of the derived class. It only knows about the members of the base class, and doesn't know anything about those of the derived class.
The reason that you can cast an instance of the derived class to an instance of the base class is because the derived class actually already is an instance of the base class, since it has those members already. The opposite cannot be said.
You can cast a variable that is typed as the base-class to the type of a derived class; however, by necessity this will do a runtime check, to see if the actual object involved is of the correct type.
Once created, the type of an object cannot be changed (not least, it might not be the same size). You can, however, convert an instance, creating a new instance of the second type - but you need to write the conversion code manually.
You have to use an object cloner/copier that will assign all the properties one by one.
Doing this by hand is inefficient and not future-proof. But serializing & deserializing to JSON and back is not the best solution, it is slow and very memory inefficient.
However, using AutoMapper is fast. PropMapper is even faster.
PS. Disclosure: I am a contributor at PropMapper open source project.
No, it is not possible.
Consider a scenario where an ACBus is a derived class of base class Bus. ACBus has features like TurnOnAC and TurnOffAC which operate on a field named ACState. TurnOnAC sets ACState to on and TurnOffAC sets ACState to off. If you try to use TurnOnAC and TurnOffAC features on Bus, it makes no sense.
class Program
{
static void Main(string[] args)
{
a a1 = new b();
a1.print();
}
}
class a
{
public a()
{
Console.WriteLine("base class object initiated");
}
public void print()
{
Console.WriteLine("base");
}
}
class b:a
{
public b()
{
Console.WriteLine("child class object");
}
public void print1()
{
Console.WriteLine("derived");
}
}
}
when we create a child class object,the base class object is auto initiated so base class reference variable can point to child class object.
but not vice versa because a child class reference variable can not point to base class object because no child class object is created.
and also notice that base class reference variable can only call base class member.
There actually IS a way to do this. Think about how you might use Newtonsoft JSON to deserialize an object from json. It will (or at least can) ignore missing elements and populate all the elements that it does know about.
So here's how I did it. A small code sample will follow my explanation.
Create an instance of your object from the base class and populate it accordingly.
Using the "jsonconvert" class of Newtonsoft json, serialize that object into a json string.
Now create your sub class object by deserializing with the json string created in step 2. This will create an instance of your sub class with all the properties of the base class.
This works like a charm! So.. when is this useful? Some people asked when this would make sense and suggested changing the OP's schema to accommodate the fact that you can't natively do this with class inheritance (in .Net).
In my case, I have a settings class that contains all the "base" settings for a service. Specific services have more options and those come from a different DB table, so those classes inherit the base class. They all have a different set of options. So when retrieving the data for a service, it's much easier to FIRST populate the values using an instance of the base object. One method to do this with a single DB query. Right after that, I create the sub class object using the method outlined above. I then make a second query and populate all the dynamic values on the sub class object.
The final output is a derived class with all the options set. Repeating this for additional new sub classes takes just a few lines of code. It's simple, and it uses a very tried and tested package (Newtonsoft) to make the magic work.
This example code is vb.Net, but you can easily convert to c#.
' First, create the base settings object.
Dim basePMSettngs As gtmaPayMethodSettings = gtmaPayments.getBasePayMethodSetting(payTypeId, account_id)
Dim basePMSettingsJson As String = JsonConvert.SerializeObject(basePMSettngs, Formatting.Indented)
' Create a pmSettings object of this specific type of payment and inherit from the base class object
Dim pmSettings As gtmaPayMethodAimACHSettings = JsonConvert.DeserializeObject(Of gtmaPayMethodAimACHSettings)(basePMSettingsJson)
You can use an Extention:
public static void CopyOnlyEqualProperties<T>(this T objDest, object objSource) where T : class
{
foreach (PropertyInfo propInfo in typeof(T).GetProperties())
if (objSource.GetType().GetProperties().Any(z => z.Name == propInfo.Name && z.GetType() == propInfo.GetType()))
propInfo.SetValue(objDest, objSource.GetType().GetProperties().First(z => z.Name == propInfo.Name && z.GetType() == propInfo.GetType()).GetValue(objSource));
}
In Code:
public class BaseClass
{
public string test{ get; set;}
}
public Derived : BaseClass
{
//Some properies
}
public void CopyProps()
{
BaseClass baseCl =new BaseClass();
baseCl.test="Hello";
Derived drv=new Derived();
drv.CopyOnlyEqualProperties(baseCl);
//Should return Hello to the console now in derived class.
Console.WriteLine(drv.test);
}
Might not be relevent, but I was able to run code on a derived object given its base. It's definitely more hacky than I'd like, but it works:
public static T Cast<T>(object obj)
{
return (T)obj;
}
...
//Invoke parent object's json function
MethodInfo castMethod = this.GetType().GetMethod("Cast").MakeGenericMethod(baseObj.GetType());
object castedObject = castMethod.Invoke(null, new object[] { baseObj });
MethodInfo jsonMethod = baseObj.GetType ().GetMethod ("ToJSON");
return (string)jsonMethod.Invoke (castedObject,null);
You can do this using generic.
public class BaseClass
{
public int A { get; set; }
public int B { get; set; }
private T ConvertTo<T>() where T : BaseClass, new()
{
return new T
{
A = A,
B = B
}
}
public DerivedClass1 ConvertToDerivedClass1()
{
return ConvertTo<DerivedClass1>();
}
public DerivedClass2 ConvertToDerivedClass2()
{
return ConvertTo<DerivedClass2>();
}
}
public class DerivedClass1 : BaseClass
{
public int C { get; set; }
}
public class DerivedClass2 : BaseClass
{
public int D { get; set; }
}
You get three benefits using this approach.
You are not duplicating the code
You are not using reflection (which is slow)
All of your conversions are in one place
I know this is old but I've used this successfully for quite a while.
private void PopulateDerivedFromBase<TB,TD>(TB baseclass,TD derivedclass)
{
//get our baseclass properties
var bprops = baseclass.GetType().GetProperties();
foreach (var bprop in bprops)
{
//get the corresponding property in the derived class
var dprop = derivedclass.GetType().GetProperty(bprop.Name);
//if the derived property exists and it's writable, set the value
if (dprop != null && dprop.CanWrite)
dprop.SetValue(derivedclass,bprop.GetValue(baseclass, null),null);
}
}
I combined some portions of the previous answers (thanks to those authors) and put together a simple static class with two methods that we're using.
Yes, it's simple, no it doesn't cover all scenarios, yes it could be expanded and made better, no it's not perfect, yes it could possibly be made more efficient, no it's not the greatest thing since sliced bread, yes there are full-on robust nuget package object mappers out there that are way better for heavy use, etc etc, yada yada - but it works for our basic needs though :)
And of course it will try to map values from any object to any object, derived or not (only the public properties that are named the same of course - ignores the rest).
USAGE:
SesameStreetCharacter puppet = new SesameStreetCharacter() { Name = "Elmo", Age = 5 };
// creates new object of type "RealPerson" and assigns any matching property
// values from the puppet object
// (this method requires that "RealPerson" have a parameterless constructor )
RealPerson person = ObjectMapper.MapToNewObject<RealPerson>(puppet);
// OR
// create the person object on our own
// (so RealPerson can have any constructor type that it wants)
SesameStreetCharacter puppet = new SesameStreetCharacter() { Name = "Elmo", Age = 5 };
RealPerson person = new RealPerson("tall") {Name = "Steve"};
// maps and overwrites any matching property values from
// the puppet object to the person object so now our person's age will get set to 5 and
// the name "Steve" will get overwritten with "Elmo" in this example
ObjectMapper.MapToExistingObject(puppet, person);
STATIC UTILITY CLASS:
public static class ObjectMapper
{
// the target object is created on the fly and the target type
// must have a parameterless constructor (either compiler-generated or explicit)
public static Ttarget MapToNewObject<Ttarget>(object sourceobject) where Ttarget : new()
{
// create an instance of the target class
Ttarget targetobject = (Ttarget)Activator.CreateInstance(typeof(Ttarget));
// map the source properties to the target object
MapToExistingObject(sourceobject, targetobject);
return targetobject;
}
// the target object is created beforehand and passed in
public static void MapToExistingObject(object sourceobject, object targetobject)
{
// get the list of properties available in source class
var sourceproperties = sourceobject.GetType().GetProperties().ToList();
// loop through source object properties
sourceproperties.ForEach(sourceproperty => {
var targetProp = targetobject.GetType().GetProperty(sourceproperty.Name);
// check whether that property is present in target class and is writeable
if (targetProp != null && targetProp.CanWrite)
{
// if present get the value and map it
var value = sourceobject.GetType().GetProperty(sourceproperty.Name).GetValue(sourceobject, null);
targetobject.GetType().GetProperty(sourceproperty.Name).SetValue(targetobject, value, null);
}
});
}
}
You can use a copy constructor that immediately invokes the instance constructor, or if your instance constructor does more than assignments have the copy constructor assign the incoming values to the instance.
class Person
{
// Copy constructor
public Person(Person previousPerson)
{
Name = previousPerson.Name;
Age = previousPerson.Age;
}
// Copy constructor calls the instance constructor.
public Person(Person previousPerson)
: this(previousPerson.Name, previousPerson.Age)
{
}
// Instance constructor.
public Person(string name, int age)
{
Name = name;
Age = age;
}
public int Age { get; set; }
public string Name { get; set; }
}
Referenced the Microsoft C# Documentation under Constructor for this example having had this issue in the past.
With regarding #MarkusKnappenJohansson answer and below comments we can change his code extending extension function :) so it may update an existing deriving class instance via this code :
public static TDerived As<TDerived>(this Base baseInstance, TDerived updateDerivedInstance = null) where TDerived : Base, new()
{
Type baseType = typeof(Base);
Type derivedType = typeof(TDerived);
PropertyInfo[] properties = baseType.GetProperties();
object instanceDerived = null;
if (updateDerivedInstance == null)
{
instanceDerived = Activator.CreateInstance(derivedType);
}
else
{
instanceDerived = (object)(updateDerivedInstance);
}
foreach (PropertyInfo property in properties)
{
if (property.CanWrite)
{
property.SetValue(instanceDerived, property.GetValue(baseInstance, null), null);
}
}
return (TDerived)instanceDerived;
}
Usage for getting new derived Instance is var base = new Base(); base.Data = 1; var derived = base.As<Derived>(); Console.Write(derived.Data); // Would output 1
Usage for updating existing derived Instance is var derived = new Derived(); var base = new Base(); base.Data = 1; var derivedUpdated = base.As<Derived>(derived); Console.Write(derivedUpdated.Data); // Would output 1
Another solution is to add extension method like so:
public static void CopyProperties(this object destinationObject, object sourceObject, bool overwriteAll = true)
{
try
{
if (sourceObject != null)
{
PropertyInfo[] sourceProps = sourceObject.GetType().GetProperties();
List<string> sourcePropNames = sourceProps.Select(p => p.Name).ToList();
foreach (PropertyInfo pi in destinationObject.GetType().GetProperties())
{
if (sourcePropNames.Contains(pi.Name))
{
PropertyInfo sourceProp = sourceProps.First(srcProp => srcProp.Name == pi.Name);
if (sourceProp.PropertyType == pi.PropertyType)
if (overwriteAll || pi.GetValue(destinationObject, null) == null)
{
pi.SetValue(destinationObject, sourceProp.GetValue(sourceObject, null), null);
}
}
}
}
}
catch (ApplicationException ex)
{
throw;
}
}
then have a constructor in each derived class that accepts base class:
public class DerivedClass: BaseClass
{
public DerivedClass(BaseClass baseModel)
{
this.CopyProperties(baseModel);
}
}
It will also optionally overwrite destination properties if already set (not null) or not.
Is it possible to assign a base class object to a derived class reference with an explicit typecast in C#?.
Not only explicit, but also implicit conversions are possible.
C# language doesn't permit such conversion operators, but you can still write them using pure C# and they work. Note that the class which defines the implicit conversion operator (Derived) and the class which uses the operator (Program) must be defined in separate assemblies (e.g. the Derived class is in a library.dll which is referenced by program.exe containing the Program class).
//In library.dll:
public class Base { }
public class Derived {
[System.Runtime.CompilerServices.SpecialName]
public static Derived op_Implicit(Base a) {
return new Derived(a); //Write some Base -> Derived conversion code here
}
[System.Runtime.CompilerServices.SpecialName]
public static Derived op_Explicit(Base a) {
return new Derived(a); //Write some Base -> Derived conversion code here
}
}
//In program.exe:
class Program {
static void Main(string[] args) {
Derived z = new Base(); //Visual Studio can show squiggles here, but it compiles just fine.
}
}
When you reference the library using the Project Reference in Visual Studio, VS shows squiggles when you use the implicit conversion, but it compiles just fine. If you just reference the library.dll, there are no squiggles.
How about:
public static T As<T>(this object obj)
{
return JsonConvert.DeserializeObject<T>(JsonConvert.SerializeObject(obj));
}
Best way to add all base properties to derived item is use reflection in costructor. Try this code, without creating methods or instances.
public Derived(Base item) :base()
{
Type type = item.GetType();
System.Reflection.PropertyInfo[] properties = type.GetProperties();
foreach (var property in properties)
{
try
{
property.SetValue(this, property.GetValue(item, null), null);
}
catch (Exception) { }
}
}
I disagree that it is not possible. You can do it like this:
public class Auto
{
public string Make {get; set;}
public string Model {get; set;}
}
public class Sedan : Auto
{
public int NumberOfDoors {get; set;}
}
public static T ConvertAuto<T>(Sedan sedan) where T : class
{
object auto = sedan;
return (T)loc;
}
Usage:
var sedan = new Sedan();
sedan.NumberOfDoors = 4;
var auto = ConvertAuto<Auto>(sedan);
This is how I solved this for fields. You can do the same iteration through properties if you want. You may want to do some checks for null etc. but this is the idea.
public static DerivedClass ConvertFromBaseToDerived<BaseClass, DerivedClass>(BaseClass baseClass)
where BaseClass : class, new()
where DerivedClass : class, BaseClass, new()
{
DerivedClass derived = (DerivedClass)Activator.CreateInstance(typeof(DerivedClass));
derived.GetType().GetFields().ToList().ForEach(field =>
{
var base_ = baseClass.GetType().GetField(field.Name).GetValue(baseClass);
field.SetValue(derived, base_);
});
return derived;
}
You can just serialize the base object to JSON and then deserialize it to the derived object.
No, see this question which I asked - Upcasting in .NET using generics
The best way is to make a default constructor on the class, construct and then call an Initialise method
My goal is create an Action<> for set the configuration object in the constructor.
The Action<> that I have defined, set two configuration objects by reference, but the problem is that the assigned object is always null. I thought that internally, the objects, were assigned by reference but it seems that no.
In the example code, I have created a CarConfiguration in the main program and I try to set by reference this configuration to my new Car using an Action<> which defines the assignment between the main program CarConfiguration and the Car attribute configuration.
Why my car configuration attribute is always null even though is being assigned by reference in my Action<> method?
Main Class:
CarConfiguration carConfiguration = new CarConfiguration()
{
CarName = "Ferrari",
CarModel = "LaFerrari",
Spolier = true,
BuildDate = new DateTime(2018, 01, 01)
};
//Thats not work because the "conf" parameter is never assign in the Car constructor
Car myOwnCar = new Car(conf =>
{
conf = carConfiguration;
});
Console.WriteLine(myOwnCar.CarConfigurationText());
//That works, but is not my purpose do it like this!
Car myOtherCar = new Car(carConfiguration);
Console.WriteLine(myOtherCar.CarConfigurationText());
Configuration Class:
public class CarConfiguration
{
public bool Spolier { get; set; } = false;
public string CarName { get; set; } = String.Empty;
public string CarModel { get; set; } = String.Empty;
public DateTime BuildDate { get; set; } = default(DateTime);
}
Car Class:
public class Car
{
private CarConfiguration carConfiguration = null;
//That does not work because carConfiguration is not assigned in the Action as a reference
public Car(Action<CarConfiguration> configureCar)
{
configureCar(carConfiguration);
}
//That works!
public Car(CarConfiguration configureCar)
{
carConfiguration = configureCar;
}
public string CarConfigurationText()
{
StringBuilder strBuilder = new StringBuilder();
if (carConfiguration != null)
{
strBuilder.AppendLine(carConfiguration.CarModel);
strBuilder.AppendLine(carConfiguration.CarName);
strBuilder.AppendLine(carConfiguration.Spolier.ToString());
strBuilder.AppendLine(carConfiguration.BuildDate.ToString("mm-DD-yyyy"));
}
else
{
strBuilder.AppendLine("Car is not configure!");
}
return strBuilder.ToString();
}
}
Your action is assigning the configuration to the lambda parameter which has no effect as the parameter is an input value, it does not get returned out of the lambda. Objects are passed by reference, but references are copied to parameters in function calls, i.e. conf will receive a copy of the reference to carConfiguration when you call the action like so configureCar(carConfiguration);
Assigning and overwriting this local copy of the reference serves no purpose. You have to use the ref keyword to essentially pass a reference to the reference(variable) to the object. When assigning to a variable marked with ref it will overwrite the reference held in the original member variable and not the local variable inside the lambda. This is already demonstrated in the other answer.
The proper method to implement what you are trying to accomplish is not by passing references around but by configuring the object inside the action. If you want to use an existing configuration just pass the object as you've already done so. There is no need to write an action that accepts a reference to an object in an explicit manner.
public Car(Action<CarConfiguration> configureCar)
{
carConfiguration = new CarConfiguration();
configureCar(carConfiguration);
}
// This is the common configuration pattern seen in .NET
Car myOwnCar = new Car(conf =>
{
conf.CarName = "Ferrari";
conf.CarModel = "LaFerrari"
/** etc **/
});
If you want to copy values from an existing configuration, you can write a method to do so
public static class CarConfigurationExtensions
{
public static void CopyTo(CarConfiguration this source, CarConfiguration dest){
dest.CarName = source.CarName;
dest.CarModel = source.CarModel;
// etc
}
}
Car myOwnCar = new Car(conf => carConfiguration.CopyTo(conf));
But under no circumstance is writing an action that accepts a ref to a local variable a thing. Another alternative is to use a Func<CarConfiguration> like so, maybe if you want to do a lazy intialization.
public Car(Func<CarConfiguration> configurator)
{
_configurator = configurator;
}
private Func<CarConfiguration> _configurator;
private CarConfiguration _carConfiguration;
public CarConfiguration CarConfiguration =>
_carConfiguration ?? (_carConfiguration = _configurator());
Car myOwnCar = new Car(() => carConfiguration);
Note how the configuration is instantiated and stored- the first time it is accessed, perhaps the only time accepting a function in the constructor is useful.
Your code would work if instead of Action<CarConfiguration> you had used Action<ref CarConfiguration> (assuming this was legal), to allow passing the argument by reference. But there is no build-in Action<ref Τ>, so if you want one you should make it yourself:
public delegate void RefAction<T>(ref T arg1);
...and then use RefAction<CarConfiguration> instead of Action<CarConfiguration>.
I have a simple class that is intended for options of an winforms application. There should be a method that reset options to their default values. I know I can add a separate method to take care of this, but the code will be huge (If I add more options to the class) :
public SensorOptions()
{
ShowLabelMax = ShowLabelMin = ShowLabelAvr = ShowReceivedTextBox = true;
ChartMaxValue = 140;
ChartMinValue = -40;
ShowChartMinValue = ShowChartMaxValue = ShowChartAvrValue = ShowChartAvrLine = true;
LogFolder = Environment.SpecialFolder.MyDocuments.ToString();
LoggingEnabled = true;
}
public void ResetOptions()
{
this = new SensorOptions(); //can not do. 'this' is read-only
}
I mean I can copy/paste the code from constructor into ResetOptions() method. But is there any smarter ways to achieve this?
You cannot assign this because you may have references to this instance of your class in your program. If you could re-construct the object by re-assigning this, it would mean that all references to the old instance of the class become invalid.
No matter how many options you have in your class, you initialize each of them one or the other way (because you mention default value in your question - so you need to assign that default value somewhere at least once, probably in the constructor). Therefore, the solution to your problem is simple - move all initializers to the separate method and call it in the constructor, and then also call it every time you need to reset your options to their default values.
If any of your options are not assigned a default value explicitly, and use system default and you don't want to write option=default(optionType) for each option, you can use reflection to enumerate all fields/properties in that class and assign default values to them, like this:
public static object GetDefault(Type type)
{
if(type.IsValueType) return Activator.CreateInstance(type);
return null;
}
foreach(var field in this.GetType().GetFields())
field.SetValue(this, GetDefault(field.FieldType));
foreach(var prop in this.GetType().GetProperties())
prop.SetValue(this, GetDefault(prop.PropertyType));
Move all of the code from the constructor into the ResetOptions method, then in your constructor call the ResetOptions method. Your initialisiation code is only in one place then.
You have very simple architecture for your situation. In my opinion it would be better to apply a trick for this:
you have class for holding all your options (pseudo code):
class AllOptionsBackstage
{
public bool ShowLabelMax { get; set; }
public bool ShowLabelMin { get; set; }
public bool ShowLabelAvr { get; set; }
public AllOptionsBackstage()
{
// apply default values here
}
}
.....
class MyOptions
{
private AllOptionsBackstage _options;
public MyOptions()
{
Reset();
}
public bool ShowLabelMax
{
get{ return _options.ShowLabelMax; }
set{ _options.ShowLabelMax = value; }
}
public bool ShowLabelMin
{
get{return _options.ShowLabelMin;}
set{_options.ShowLabelMin=value; }
}
public bool ShowLabelAvr
{
get{ return _options.ShowLabelAvr;}
set{ _options.ShowLabelAvr = value; }
}
public void Reset()
{
_options = new AllOptionsBackstage(); // will reset all your options to default
}
}
Given the following code;
public class CustomControl {
private object _dataItem;
public object DataItem {
get { return _dataItem; }
set { _dataItem = value; }
}
public void Update(ref string t) {
t = "test";
}
}
public class Consume {
public void Example() {
CustomControl ctrl = new CustomControl();
ctrl.DataItem = anyObject.anyProperty;
string prop = anyObject.anyProperty;
ctrl.Update(ref prop);
anyObject.anyProperty = prop;
}
}
How can I change it so that the DataItem property is itself a reference, allowing you to pre-emptively set it to point to a variable thus allowing you to call Update() without any parameters.
So the Consume class would then look similar to;
public class Consume {
public void Example() {
CustomControl ctrl = new CustomControl();
ctrl.DataItem = anyObject.anyProperty;
ctrl.Update();
// anyObject.anyProperty has been updated to "test"
}
}
So the assigment of anyObject.anyProperty is then handled internally within CustomControl
You need to store the act of setting something to a string, so store an Action<string>:
public class CustomControl {
public Action<string> SetData { get; set; }
public void Update() {
// TODO nullity check
SetData("test");
}
}
Then Consume would look like:
public class Consume {
public void Example() {
CustomControl ctrl = new CustomControl();
// store {the act of setting this property of this object to a string}
ctrl.SetData = s => anyObject.anyProperty = s;
ctrl.Update();
}
}
The Update call will set anyObject.anyProperty to test. Note that you are storing specifically the act of setting this property of the particular anyObject you refer to in the assignment to SetData.
To expand on the lambda: we want to create a value of type Action<string>, that is, a thing which takes a string and returns no result. Such a thing is going to be executable code. Prior to C# 3, to create a 'value' that was executable code, we would have had to do something like:
ctrl.SetData = delegate(string s) { someObject.SomeProperty = s; };
With this syntax it's more obvious that we're creating a method - it has a { } delimited body, it has statements in it, and it's clear there is a string parameter that is used by the body.
One thing achieved by lambda expressions in C# 3 is the ability to condense this down; loosely, the whole of
// not compilable code
delegate(parameters) { body; }
can be replaced with
// not compilable code
(parameters) => body;
and in the case where there's only one parameter
// not compilable code
parameter => body;
which is what we have here: the expression assigned to ctrl.SetData is a piece of behaviour that accepts a string (s) and sets anyObject.anyProperty to that string. The real power is in the way the C# compiler can work out the types to it know we're creating an Action<string>.
At first I didn't understand what you're trying to do. What you're looking for is the Adapter or Facade pattern. That is, you have an object with a particular interface, but you need to adapt it to a different interface or provide a simpler interface.
One way to implement these patterns is to use composition and delegate the new interface to methods on the existing interface.
public interface IUpdatable<U>
{
void Update( U newValue );
}
public abstract class CustomControl<T,U> : IUpdatable<U>
where T : Control
{
private T Control { get; set; }
protected CustomControl( T control )
{
this.Control = control;
}
public abstract void Update( U newValue );
}
public class TextBoxFacade : CustomControl<TextBox,string>, IUpdatable<string>
{
public TextBoxFacade( TextBox textbox ) : base(textbox) { }
public override void Update( string newValue )
{
this.Control.Value = newValue;
}
}