How to read XML document from property in Episerver - c#

I want to read XML document from a property which is created in edit mode of Episerver.
I have made one property of type 'URL to Document'.
When I try to fetch it from code behind, it gives only file path. I am not able to read the content of XML file which is uploaded in property.
string XMLContent = Currentpage.Getproperty<string>("XMLFile");
Can anyone help out on this?

You need to load the file as well. Something like this:
var path = CurrentPage["XMLFile"] as string;
if (HostingEnvironment.VirtualPathProvider.FileExists(path))
{
var file = HostingEnvironment.VirtualPathProvider.GetFile(path) as UnifiedFile;
if (file != null)
{
using (var stream = file.Open())
{
// Here is your XML document
var xml = XDocument.Load(stream);
}
}
}
You can also load the file content by using the local path on disk, file.LocalPath.

try this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string XMLContent = "";
//using XML
XmlDocument doc1 = new XmlDocument();
doc1.LoadXml(XMLContent);
//using xml linq
XDocument doc2 = XDocument.Parse(XMLContent);
}
}
}
​

Related

Consuming API XML into csv file C#

I have the following XML in an API
I wish to read the data from the tags and build a CSV file with the values.
My code so far,
using System;
using System.Collections.Generic;
using System.Text;
using System.Web;
using System.IO;
using System.Net;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication3
{
class Program
{
static void Main(string[] args)
{
string url = "https://localhost:5001/api/Scheduler/GetScheduler";
WebRequest request = WebRequest.Create(url);
try
{
WebResponse response = request.GetResponse();
using (var sr = new System.IO.StreamReader(response.GetResponseStream()))
{
XDocument xmlDoc = new XDocument();
try
{
xmlDoc = XDocument.Parse(sr.ReadToEnd());
Console.WriteLine(xmlDoc.Root.Element("ORD_NAME").Value);
}
catch (Exception)
{
// handle if necessary
}
}
}
catch (WebException)
{
// handle if necessary
}
}
}
}
I can see the data being read in, but xmlDoc, but xmlDoc.Root.Element("ORD_NAME").Value is NULL.
How do I get the data from the stream?
Thanks.
I think you want e.g
using (var stream = response.GetResponseStream())
{
XDocument xmlDoc = XDocument.Load(stream);
Console.WriteLine(string.Join("\n", from row in xmlDoc.Root.Elements("Scheduler") select string.Join(";", row.Elements().Select(e => e.Value))));
}
.NET probably has some better APIs to construct CSVs than using LINQ to XML directly, the above will fail to quote value or escape separators.

XML file to other schema based XML file using c#

is it possible to rewrite XML file according to other schema XSD using c# ?
this is XML file
this is the current schema XSD file
and this is the new schema same everything but changed node names
so how to get a new XML from the old one based on the new XSD using c#?
Using xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication13
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
List<XElement> shipTo = doc.Descendants("shipto").ToList();
foreach (XElement ship in shipTo)
{
ship.Element("name").ReplaceWith(new XElement("FullName", (string)ship.Element("name")));
ship.Element("address").ReplaceWith(new XElement("FirstAddress", (string)ship.Element("address")));
ship.Element("city").ReplaceWith(new XElement("homeTown", (string)ship.Element("city")));
ship.Element("country").ReplaceWith(new XElement("HomeLand", (string)ship.Element("country")));
}
}
}
}

Add Node at begin and end of the existing xml file using c#

I generated a XML file through API call then I tried to read the file using XML source component in ssis but it is read only data sets except all data contains in file .
Here my file
<?XML version 1.0 >
<ABC>
<a>info<a/>
<ABC/>
But I want file like below then only I can easily read file using component
We can manipulate the file manually for single file but not for thousand files
<?XML Version 1.0>
<X>
<ABC>
<a>info <a/>
<ABC/>
</X>
How to add that 'X' node to the existing file .
I am not having much exposure on .Net technology .
Kindly help me at the earliest of time .
Thank You
KiranKumar
Using xml linq
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string xml =
"<?xml version=\"1.0\" encoding=\"utf-8\" ?>" +
"<ABC>" +
"<a>info</a>" +
"</ABC>";
XDocument doc = XDocument.Parse(xml);
XElement root = doc.Root;
root.ReplaceWith(new XElement("X", root));
}
}
}
Try streaming API.
using (var reader = XmlReader.Create("test.xml"))
using (var writer = XmlWriter.Create("test2.xml"))
{
writer.WriteStartElement("X");
reader.MoveToContent();
writer.WriteNode(reader.ReadSubtree(), true);
writer.WriteEndElement();
}
This approach handles xml without excessive memory consumption.
Also, this method allows to modify xml on the fly, getting it from the input API stream and writing to output stream.
using (var reader = XmlReader.Create(inputStream))
using (var writer = XmlWriter.Create(outputStream))

XML like data to CSV Conversion

So I have a device which has an inbuilt logger program which generates status messages about the device and keeps pushing them to a .txt file. These messages include information about the device status, network status amongst many other things. The data in the file looks something like the following:
<XML><DSTATUS>1,4,7,,5</DSTATUS><EVENT> hello,there,my,name,is,jack,</EVENT>
last,name,missing,above <ANOTHERTAG>3,6,7,,8,4</ANOTHERTAG> </XML>
<XML><DSTATUS>1,5,7,,3</DSTATUS><EVENT>hello,there,my,name,is,mary,jane</EVENT>
last,name,not,missing,above<ANOTHERTAG>3,6,7,,8,4</ANOTHERTAG></XML>
... goes on
Note that it is not well formed XML. Also, one element can have multiple parameters and can also have blanks... for example: <NETWORKSTAT>1,456,3,6,,7</NETWORKSTAT>
What my objective is is to write something in C# WPF, that would take this text file, process the data in it and create a .csv file with each event per line.
For example, for the above given brief example, the first line in the csv file would be:
1,4,7,,5,hello,there,my,name,is,jack,,last,name,missing,above,3,6,7,,8,4
Also, I do not need help using basic C#. I know how to read a file, etc.. but I have no clue as to how I would approach this problem in regards to the parsing and processing and converting. I'm fairly new to C# so I'm not sure which direction to go. Any help will be appreciated!
Since each top-level XML node in your file is well-formed, you can use an XmlReader with XmlReaderSettings.ConformanceLevel = ConformanceLevel.Fragment to iterate through each top-level node in the file and read it with Linq-to-XML:
public static IEnumerable<string> XmlFragmentsToCSV(string path)
{
using (var textReader = new StreamReader(path, Encoding.UTF8))
foreach (var line in XmlFragmentsToCSV(textReader))
yield return line;
}
public static IEnumerable<string> XmlFragmentsToCSV(TextReader textReader)
{
XmlReaderSettings settings = new XmlReaderSettings();
settings.ConformanceLevel = ConformanceLevel.Fragment;
using (XmlReader reader = XmlReader.Create(textReader, settings))
{
while (reader.Read())
{ // Skip whitespace
if (reader.NodeType == XmlNodeType.Element)
{
using (var subReader = reader.ReadSubtree())
{
var element = XElement.Load(subReader);
yield return string.Join(",", element.DescendantNodes().OfType<XText>().Select(n => n.Value.Trim()).Where(t => !string.IsNullOrEmpty(t)).ToArray());
}
}
}
}
}
To precisely match the output you wanted I had to trim whitespaces at the beginning and end of each text node value.
Also, the Where(t => !string.IsNullOrEmpty(t)) clause is to skip the whitespace node corresponding to the space here: </ANOTHERTAG> </XML>. If that space doesn't exist in the real file, you can omit that clause.
Due to non standard format had to switch from an XML Linq solution to a standard XML solution. Linq doesn't support TEXT strings that are not in tags.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.csv";
static void Main(string[] args)
{
string input =
"<XML><DSTATUS>1,4,7,,5</DSTATUS><EVENT> hello,there,my,name,is,jack,</EVENT>" +
"last,name,missing,above <ANOTHERTAG>3,6,7,,8,4</ANOTHERTAG> </XML>" +
"<XML><DSTATUS>1,5,7,,3</DSTATUS><EVENT>hello,there,my,name,is,mary,jane</EVENT>" +
"last,name,not,missing,above<ANOTHERTAG>3,6,7,,8,4</ANOTHERTAG></XML>";
input = "<Root>" + input + "</Root>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(input);
StreamWriter writer = new StreamWriter(FILENAME);
XmlNodeList rows = doc.GetElementsByTagName("XML");
foreach (XmlNode row in rows)
{
List<string> children = new List<string>();
foreach (XmlNode child in row.ChildNodes)
{
children.Add(child.InnerText.Trim());
}
writer.WriteLine(string.Join(",", children.ToArray()));
}
writer.Flush();
writer.Close();
}
}
}
​
Here is my solution that uses XML Linq. I create a XDocument by wrapping the fragments with a Root tag.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.csv";
static void Main(string[] args)
{
string input =
"<XML><DSTATUS>1,4,7,,5</DSTATUS><EVENT> hello,there,my,name,is,jack,</EVENT>" +
"last,name,missing,above <ANOTHERTAG>3,6,7,,8,4</ANOTHERTAG> </XML>" +
"<XML><DSTATUS>1,5,7,,3</DSTATUS><EVENT>hello,there,my,name,is,mary,jane</EVENT>" +
"last,name,not,missing,above<ANOTHERTAG>3,6,7,,8,4</ANOTHERTAG></XML>";
input = "<Root>" + input + "</Root>";
XDocument doc = XDocument.Parse(input);
StreamWriter writer = new StreamWriter(FILENAME);
List<XElement> rows = doc.Descendants("XML").ToList();
foreach (XElement row in rows)
{
string[] elements = row.Elements().Select(x => x.Value).ToArray();
writer.WriteLine(string.Join(",", elements));
}
writer.Flush();
writer.Close();
}
}
}
​

Use markup file inside assembly

How i can open an xml or xsl file inside the same assembly from source code in C#?
Any ideas?
Google found this
using System;
using System.IO;
using System.Reflection;
using System.Xml;
class Application
{
static void Main(string[] args)
{
Stream s =
Assembly.GetExecutingAssembly().GetManifestResourceStream("File1.xml");
XmlDocument xdoc = new XmlDocument();
using (StreamReader reader = new StreamReader(s))
xdoc.LoadXml(reader.ReadToEnd());
}
}

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