I have this base class:
public class BaseEvent
{
public int EventID { get; set; }
public int GetEventID()
{
return EventID;
}
}
And then I have another class inherited from that base one:
public class ValidationResult<T> where T : BaseEvent
{
private void AddEventStatusUpdater(ValidationResult<T> validationResult)
{
validationResult.GetEventID();
}
}
The issue I´m having is that I cannot access the GetEventID() method from the base class.
I think this may happen because I´m using a T generic. Is there any other way to access this method?
public class ValidationResult<T> where T : BaseEvent
Says that T must be a BaseEvent, not that ValidationResult<T> inherits from BaseEvent. That'd be:
public class ValidationResult<T> : BaseEvent
And there T would not have any constraint
Is that what you want?
You have begun to implement a generic interface rather than inheriting from the base class. I think you meant to do the following:
public class ValidationResult : BaseEvent
{
private void AddEventStatusUpdater()
{
var id = this.GetEventID();
}
}
Related
How do I force all derived classes of an interface to have a constructor with a signature? This doesn't work:
public interface Constructor<T> where T : Constructor<T>, new()
{
Constructor(T);
}
public interface IParameters
{
}
public interface IRule : Constructor<IParameters>
{
//IRule (IParameters); must exist
}
You can't, not via an interface. But you can sort of get at it with an abstract class. Similar to what the accepted answer here describes, try:
public abstract class MustInitialize<T>
{
public MustInitialize(T parameters)
{
}
}
public class Rule : MustInitialize<IParameters>, IRule
{
IParameters _parameters;
public Rule(IParameters parameters)
: base (parameters)
{
_parameters= parameters;
}
}
You can't force a specific constructor signature.
Even with an abstract class as demonstrated in Mark's answer, you can only force the constructor of the abstract class, but nothing is stopping the author of the derived class to do something like this:
public class Rule : MustInitialize<IParameters>, IRule
{
public Rule()
: base (new Parameters())
{
// Assuming Parameters is a class that implements the IParameters interface
}
}
However, you can force dependency injection by using method (setter) injection:
public interface IMethodInjection<T>
{
void Method(T injected);
}
I think you can design your base class like the following example:
public abstract class MyBase
{
private MyBase()
{
}
public MyBase(string a)
{
}
}
public class MyDerived : MyBase
{
public MyDerived(string a) : base(a)
{
}
}
You can even delete the private constructor if its not needed
I was using generic types in C# and I am new to using generic types. So, right now I am stuck with a problem. I have some classes like these:
public class MyModel1
{
}
public class MyModel2
{
}
public class BaseClass<T>
{
}
public class ChildClass1 : BaseClass<MyModel1>
{
}
public class ChildClass2 : BaseClass<MyModel2>
{
}
public class AnotherClass
{
//What will be the syntax of declaring this method
//The syntax of the following method is wrong and incomplete.
//It's there just to give an idea about whai i want to do.
public void MyMethod<T>()
where T : BaseClass<..what to write..>
{
}
}
My question is what will be the correct syntax of declaring MyMethod if I want to call MyMethod like this:
MyMethod<ChildClass1>();
If I understood correctly, you try to filter "MyMethod" so that T is a class of type "ChildClass ...".
You can add a generic parameter to your function like this:
public void MyMethod<T, U>()
where T : BaseClass<U>
{
}
But then you have to call MyMethod in that way.
MyMethod<ChildClass1, MyModel1>();
So it's quite complicated to use.
Another solution is to create a new "blank" class :
public abstract class Base // mark it as abstract if you don't need to use it in your code
{
}
public class MyModel1
{
}
public class MyModel2
{
}
public class BaseClass<T> : Base //The class inherits the new class
{
}
public class ChildClass1 : BaseClass<MyModel1>
{
}
public class ChildClass2 : BaseClass<MyModel2>
{
}
public class AnotherClass
{
public void MyMethod<T>()
where T : Base
{
}
}
You've forgotten to mention the return type and adding <T> after the class name. For example, if the return type is void, you could declare the method as:
public void MyMethod<T>()
where T : BaseClass<T>
{
}
This will work (by which I mean it compiles)
public void MyMethod<T>()
where T : BaseClass<MyModel1>
{ }
so does this:
public void MyMethod<T>()
where T : ChildClass1
{ }
Further edit after reading your comment...
You can do this:
public class AnotherClass<TBaseClass, TModel> where TBaseClass : BaseClass<TModel>
{
public void MyMethod(TBaseClass input)
{ }
}
I have a term for this, hopefully non-offensive. I call it The Generic Rabbit Hole of Madness. It's what happens when we try to combine generics and inheritance so that one set of classes can accomplish a broad set of goals that become increasingly confusing, and we solve it by adding more generic parameters and more generic classes.
You reach the bottom of the hole if you
- use <dynamic>
- check to see what the actual type is using GetType(), typeof, or is
- get it to compile but can't remember what it's supposed to do
Using C#, how do I create instances of classes that implement a generic interface, that inherits from another generic interface using Reflection.
I need to get the implementation of BarcodeTestHelper and BarcodeRepository and create instances of them.
My model:
public interface ITestData{}
public class BarcodelData : ITestData
{
public int Id { get; set; }
}
My API:
public interface IBaseTestHelper<T> where T : ITestData {}
public interface IBarcodeTestHelper : IBaseTestHelper<BarcodeTestData>
My implementation:
public class BarcodeTestHelper : TestBaseHelper, IBarcodeTestHelper
{
private readonly IBarcodeRepository<BarcodeTestData> _barcodeRepository;
public BarcodeTestHelper(IBarcodeRepository<BarcodeTestData> barcodeRepository)
{
_barcodeRepository = barcodeRepository;
}
}
public interface IBarcodeRepository<T> : IRepository<BarcodeTestData> where T : ITestData
{
BarcodeTestData SaveBarcode(string xmlBarcode);
}
public class BarcodeRepository : IBarcodeRepository<BarcodeTestData>
{
BarcodeTestData SaveBarcode(string xmlBarcode)
{
do save work
}
}
I have the following class:
public class DataInterop <T> where T : ITableAdapter
{
private ITableAdapter tableAdapter;
public DataInterop(T tableAdapter)
{
this.tableAdapter = tableAdapter;
}
}
In the ITableAdapter-Interface are Methods defined like Read(), Write(...), Update(...), Delete(...), ...
Now I want the Class DataInterop to have all Methods from the ITableAdapter interface.
Is it possible for a generic-class to inherit from an interface?
You just need to add : ITableAdaper after the DataInterop<T>
public class DataInterop<T>: ITableAdapter where T: ITableAdapter
{
private ITableAdapter tableAdapter;
public DataInterop(T tableAdapter)
{
this.tableAdapter = tableAdapter;
}
}
(It looks like you're implementing an Adapter Pattern or a Decorator Pattern.)
Yes it is possible, it's especially useful when you handle instances of the class without knowing the concrete type at runtime.
The syntax would be:
public class DataInterop <T> : ITableAdapter where T : ITableAdapter
Ofcourse you can. Sample layout -
public interface IBar
{
string Name { get; set; }
}
public class Foo<T> : IBar
{
public string Name { get; set; }
}
I have a generic class with a class constraint on it.
public class MyContainer<T> where T : MyBaseRow
MyBaseRow is an abstract class which I also want to contain a member of some flavour of MyContainer.
public abstract class MyBaseRow
{
public MyContainer<MyBaseRow> ParentContainer;
public MyBaseRow(MyContainer<MyBaseRow> parentContainer)
{
ParentContainer = parentContainer;
}
}
I am having problems with the constructors of classes inherited from MyBaseRow eg.
public class MyInheritedRowA : MyBaseRow
{
public MyInheritedRowA(MyContainer<MyInheritedRowA> parentContainer)
: base(parentContainer)
{ }
}
Won't allow MyInheritedRowA in the constructor, the compiler only expects and only allows MyBaseRow. I thought the generic class constraint allowed for inheritance? What am I doing wrong here and is there any way I can redesign these classes to get around this?
Many thanks in advance for any responses.
Basically, you can't use generics that way, because the covariance system doesn't work that way with classes. See here: http://geekswithblogs.net/abhijeetp/archive/2010/01/10/covariance-and-contravariance-in-c-4.0.aspx
You can however use an interface like this:
public interface MyContainer<out T> where T : MyBaseRow {
}
And that code will compile.
You can make a covariant generic interface (C#4.0):
public interface IContainer<out T> where T : MyBaseRow
{
}
public class MyContainer<T> : IContainer<T> where T : MyBaseRow
{
}
public abstract class MyBaseRow
{
public IContainer<MyBaseRow> ParentContainer;
public MyBaseRow(IContainer<MyBaseRow> parentContainer)
{
ParentContainer = parentContainer;
}
}
public class MyInheritedRowA : MyBaseRow
{
public MyInheritedRowA(IContainer<MyInheritedRowA> parentContainer)
: base(parentContainer)
{ }
}