I have a service which returns the below xml as string.I am using Xdocument parse method and XmlDocument load methods to convert the string to xml. but i want to parse and get the status and i_numer which i need to use for further processing.can some one point me in right direction or give some hints.below is the xml i am using.
i tried the innerxml property from the Xdocument and XmlDocument which is returning the whole "" element and this is not what i needed.
<Report>
<Incidentreport Company="company1" ID="sample">
<status i_number="12345678" status="sucessful" />
</Incidentreport>
</Report>
The following should work:
string str = [string of xml goes here];
string i_number = string.Empty;
XmlDocument doc = new XmlDocument();
doc.Load(str);
XmlNode node = doc.SelectSingleNode("//status");
i_number = node.Attributes["i_number"].Value;
You can use SelectSingleNode() which accept XPath parameter to get the target attribute value in one go * :
var raw = #"<Report>
<Incidentreport Company='company1' ID='sample'>
<status i_number='12345678' status='sucessful' />
</Incidentreport>
</Report>";
var doc = new XmlDocument();
doc.LoadXml(raw);
var result = doc.SelectSingleNode("/Report/Incidentreport/status/#i_number");
Console.WriteLine(result.Value);
dotnetfiddle demo
*) notice how XML attribute can be referenced by using #attribute_name syntax in XPath
Related
How to get the xml node value in a string.
i am getting This error
Data at the root level is invalid. Line 1, position 1.
error shown in this line
xmldoc.LoadXml(xmlFile);
my xml
<?xml version="1.0" encoding="utf-8" ?>
<UOM>
<!-- The selected currency used will be stored here for Code reference" -->
<ActiveCurrencyType>
<ActiveCurrency>U.S.Dollar</ActiveCurrency>
<ActiveCode>USD</ActiveCode>
<ActiveSymbol>$</ActiveSymbol>
</ActiveCurrencyType>
<!-- The selected Dimension used will be stored here for Code reference -->
<ActiveDimension>
<ActiveDimensionUOM>Inches</ActiveDimensionUOM>
<ActiveDimensionSymbol>.in</ActiveDimensionSymbol>
</ActiveDimension>
<!-- The selected weight used will be stored here for Code reference -->
<ActiveWeight>
<ActiveWeightUOM>Pounds</ActiveWeightUOM>
<ActiveWeightSymbol>lb</ActiveWeightSymbol>
</ActiveWeight>
</UOM>
C# code
string xmlFile = Server.MapPath("~/HCConfig/HCUOM.xml");
XmlDocument xmldoc = new XmlDocument();
xmldoc.LoadXml(xmlFile);
XmlNodeList nodeList = xmldoc.GetElementsByTagName("ActiveDimensionSymbol");
string ActiveDimensionSymbol = string.Empty;
foreach (XmlNode node in nodeList)
{
ActiveDimensionSymbol = node.InnerText;
}
How can I achieve this?
You're using the wrong overload, LoadXml doesn't do what you think it does.
Use xmldoc.Load(xmFile); because that method takes an file path as input. LoadXml expects an string with xml in it.
The exception is an indicator of that mistake. What is processed is not XML, and a filepath isn't that.
After this changes the string ActiveDimensionSymbol contains .in if I run this locally.
If you want to use LoadXml you should first read your whole file in a string, for example like so:
xmldoc.LoadXml(File.ReadAllText(xmlFile));
but is really only overhead to call File.ReadAllText if there is an method that accepts a file.
You can use the Descendants() method to get all XElements by certain name, found in the System.Xml.Linq namespace.
XDocument doc = XDocument.Load("XMLFile1.xml");
string[] allActiveWeightUOMs = doc.Descendants("ActiveWeightUOM").Select(o => o.Value).ToArray();
// allActiveWeightUOMs : "Pounds" ...
As can seen here link the method that you are using to load the XML excepts xml by string not xml file. You can use XmlDocument.Load instead of XmlDocument.LoadXml
Try this code its works just fine with this xml
string xmlFile = Server.MapPath("~/HCConfig/HCUOM.xml");
XDocument doc = XDocument.Load(xmlFile );
var nodeList = doc.Descendants("ActiveDimensionSymbol");
string ActiveDimensionSymbol = string.Empty;
foreach (var node in nodeList)
{
ActiveDimensionSymbol = node.Value;
}
Hi i am facing an issue extracting innertext from an xml script saved as varchar2 in my oracle database.
While fetching i am getting the xml in the following format:
"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<SpecificAction xmlns=\"http://www.xyz.com/schemas/core/caut\">action to take</SpecificAction>"
the following xml is fetched using the code below:
instance.cautDescription = records.GetStringOrDefault("SPEC_ACTION");
the field SPEC_ACTION is of VARCHAR2(4000 BYTE) type.
due to the presence of \ character in the xml from database i am not able to extract the inner text withing the Tag. I tried the following code for fetching the inner text:
string s = instance.cautDescription;
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(s);
XmlNode specificAction = xmlDoc.DocumentElement.SelectSingleNode("/SpecificAction");
string specific = specificAction.InnerText;
xmlString = specificAction.InnerText;
return xmlString;
My code is returning null can this be avoided if so how , any support would be really helpful.
This is classic problem when working with XML having default namespace. In XML, when you have default namespace (namespace without prefix, like xmlns="...."), all elements without prefix considered in default namespace. But in XPath, all elements without prefix considered has no namespace. To bridge this different paradigm, you need to declare a prefix that point to default namespace URI and use it in XPath :
var nsManager = new XmlNamespaceManager(xmlDoc.NameTable);
nsManager.AddNamespace("ns", xmlDoc.DocumentElement.NamespaceURI);
XmlNode specificAction = xmlDoc.DocumentElement.SelectSingleNode("/ns:SpecificAction", nsManager);
string specific = specificAction.InnerText;
Since the "SpecificAction" node has a namespace, you will need to supply a namespace manager.
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(s);
XmlNamespaceManager ns = new XmlNamespaceManager(xmlDoc.NameTable);
ns.AddNamespace("xyz", "http://www.xyz.com/schemas/core/caut");
XmlNode specificAction = xmlDoc.SelectSingleNode("/xyz:SpecificAction", ns);
return specificAction.InnerText;
I am trying to obtain the complete string of the query element (2nd element) within an xml string like the following:
"<iq type=\"result\" id=\"Roster\" to=\"JJJ#mail.kkk.com\"><query
xmlns=\"jabber:iq:roster\"><item jid=\"al#abc.def.com\" name=\"Albert\"
subscription=\"both\"><group>A</group></item></query></iq>"
I am using XmlDocument and code that looks like this:
XmlDocument XDoc = new XmlDocument();
XDoc.LoadXml(DataBuf);
XmlElement QueryElem = XDoc.DocumentElement["query"];
string QueryBuf = QueryElem.InnerXml;
I need the full xml string starting with the query element. The InnerXML method only returns the data starting with the "item" data.
How can I obtain the full string starting with query that ends with /query and that does not contain the iq element data?
Use XmlNode.OuterXml property:
string QueryBuf = QueryElem.OuterXml;
returns
<query xmlns="jabber:iq:roster"><item jid="al#abc.def.com" name="Albert" subscription="both"><group>A</group></item></query>
I am currently trying to learn how to parse data, and its a bit confusing. can someone check out my code and see what I'm doing wrong or if im even heading in the right direction.
XML File:
<xml xmlns:a='BLAH'
xmlns:b='BLAH'
xmlns:c='BLAH'
xmlns:d='BLAH'>
<a:info>
<b:cat Option1='blah' Option2='blah' Option3='blah' />
</a:info>
</xml>
C# Code:
XmlDocument doc = new XmlDocument();
doc.Load(richTextBox2.Text);
XmlNamespaceManager man = new XmlNamespaceManager(doc.NameTable);
man.AddNamespace("a", "BLAH");
man.AddNamespace("b", "BLAH");
man.AddNamespace("c", "BLAH");
man.AddNamespace("d", "BLAH");
XmlNode temps = doc.SelectSingleNode("/a:info/b:cat/Option1/", man);
richTextBox1.Text = temps.InnerText;
I am new to C#, I cant find a good example explaining how to successfully use loops to find more then one:
<b:chat />
You are using the wrong API if you're looking for LINQ to XML. Use the XDocument class instead.
Assume the following input XML-document (please note namespace URLs):
<xml xmlns:a='http://localhost/scheme_a'
xmlns:b='http://localhost/scheme_b'
xmlns:c='http://localhost/scheme_c'
xmlns:d='http://localhost/scheme_d'>
<a:info>
<b:cat Option1='1' Option2='1' Option3='1' />
</a:info>
<a:info>
<b:cat Option1='2' Option2='2' Option3='2' />
</a:info>
</xml>
There are the ways to get all <b:chat /> elements.
XmlDocument class:
var xmlDocument = new XmlDocument();
xmlDocument.Load(...);
var xmlNamespaceManager = new XmlNamespaceManager(xmlDocument.NameTable);
xmlNamespaceManager.AddNamespace("a", "http://localhost/scheme_a");
xmlNamespaceManager.AddNamespace("b", "http://localhost/scheme_b");
xmlNamespaceManager.AddNamespace("c", "http://localhost/scheme_c");
xmlNamespaceManager.AddNamespace("d", "http://localhost/scheme_d");
var bCatNodes = xmlDocument.SelectNodes("/xml/a:info/b:cat", xmlNamespaceManager);
var option1Attributes = bCatNodes.Cast<XmlNode>().Select(node => node.Attributes["Option1"]);
// Also, all Option1 attributes can be retrieved directly using XPath:
// var option1Attributes = xmlDocument.SelectNodes("/xml/a:info/b:cat/#Option1", xmlNamespaceManager).Cast<XmlAttribute>();
LINQ to XML XDocument Class. XName can be passed with a namespace to Descendants() and Element() methods.
Use Descendants() to get all <b:chat /> elements.
var xDocument = XDocument.Load(...);
XNamespace xNamespace = "http://localhost/scheme_b";
var xElements = xDocument.Descendants(xNamespace + "cat");
// For example, get all the values of Option1 attribute for the b:chat elements:
var options1 = xElements.Select(element => element.Attribute("Option1")).ToList();
Can someone help me read attribute ows_AZPersonnummer with asp.net using c# from this xml structure
<listitems
xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
xmlns:rs="urn:schemas-microsoft-com:rowset"
xmlns:z="#RowsetSchema"
xmlns="http://schemas.microsoft.com/sharepoint/soap/">
<rs:data ItemCount="1">
<z:row
ows_AZNamnUppdragsansvarig="Peter"
ows_AZTypAvUtbetalning="Arvode till privatperson"
ows_AZPersonnummer="196202081276"
ows_AZPlusgiro="5456436534"
ows_MetaInfo="1;#"
ows__ModerationStatus="0"
ows__Level="1" ows_ID="1"
ows_owshiddenversion="6"
ows_UniqueId="1;#{11E4AD4C-7931-46D8-80BB-7E482C605990}"
ows_FSObjType="1;#0"
ows_Created="2009-04-15T08:29:32Z"
ows_FileRef="1;#uppdragsavtal/Lists/Uppdragsavtal/1_.000"
/>
</rs:data>
</listitems>
And get value 196202081276.
Open this up in an XmlDocument object, then use the SelectNode function with the following XPath:
//*[local-name() = 'row']/#ows_AZPersonnummer
Basically, this looks for every element named "row", regardless of depth and namespace, and returns the ows_AZPersonnummer attribute of it. Should help avoid any namespace issues you might be having.
The XmlNamespaceManager is your friend:
string xml = "..."; //your xml here
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
XmlNamespaceManager nsm = new XmlNamespaceManager(new NameTable());
nsm.AddNamespace("z", "#RowsetSchema");
XmlNode n = doc.DocumentElement
.SelectSingleNode("//#ows_AZPersonnummer", nsm);
Console.WriteLine(n.Value);
You can also use LINQ to XML:
XDocument xd = XDocument.Parse(xml);
XNamespace xns = "#RowsetSchema";
string result1 = xd.Descendants(xns + "row")
.First()
.Attribute("ows_AZPersonnummer")
.Value;
// Or...
string result2 =
(from el in xd.Descendants(xns + "row")
select el).First().Attribute("ows_AZPersonnummer").Value;
I'd say you need an XML parser, which I believe are common. This looks like a simple XML structure, so the handling code shouldn't be too hard.
Use <%# Eval("path to attribute") %> but you need to load the xml has a DataSource.
Otherwise you can load it using XmlTextReader. Here's an example.