I have a c# project which I added a xml-file (Add -> New -> xml).
The property of the file for Copy to Output Directory is set to Copy if newer and in the project properties for Publish -> Application Files -> Publish Status is set to Include.
When I debug my project I read and write that xml-file and it is correct updating in the bin/Debug folder but not in the main folder of the solution. So the xml-file in the solution is not updated, only the xml-file in the Debug folder.
I know from other projects that I get a hint when I stop debugging after a xml-file was modified that the xml-file was updated and if I want to reload it. That hint I don't get so something must be wrong with the link to that file.
If you want to rewrite the XML file that is part of your project, you have to write to that XML file - not to the copy in your bin\debug folder. This is not generally what most people want. If the file is part of your project, most people would consider that a source file that you would want to keep in its original condition, not a file that you want to edit while debugging.
If that is what you want to accomplish, make sure you read and write to ..\..\MyFile.xml relative to your executable. That's assuming the XML file is in the root folder of your project, and that your project isn't configured to use any non-standard folder structure.
Related
I have a WPF project that is now finished, and I want to publish the app into an installer that other people can use.
When I publish the project, the project compiles into setup.exe, but on install the folders that I have do not get included.
I've been reading the guides, and made sure to include the files inside the folders as Content or a Resource. I've also made sure they are always copied. When some of my files are copied, they have a .deploy extension, and I need it to be an .xml in order for some function to read them. Images that I have in the app load fine however.
What do I need to do to have my custom files be EXACTlY as they are, xml as xml, txt as txt and so on. Also I have some empty folders, like this TempCF that I use at some point. Do i need to create it via code?
If you go to Project->Properties->Publish->Install Mode and Settings->Options->Deployment in Visual Studio, there is a "Use ".deploy" file extension" option that you can untick to get rid of the .deploy extension being added to your published files:
Empty project folders are not included in the output. Either put a dummy content file in them or create the folder dynamically as needed during runtime.
# Nikola L.
You could try to use the following methods to add the files in your program to the installation package so that you can have the files you need in your installation path. If I misunderstood your question, please let me know.
The steps are as follows:
1.Right-click on the Setup project and select View -> File System
2.In the File System page, right-click the Application Folder (File System on target Machine) and select Add->Folder(named User's Application Data ) -> File…-> find the file under your project and select the file you need.
Such as:
3.Right-click the Setup project.
Install your setup package.
You can find the files you added in your installation path.
The result is like the picture below:
I'm trying to publish a project which needs some data which is stored in a .txt file.
The file is currently located in bin\Debug.
The Path for the Streamreader is relative using Applicaton.StartupPath.
I added the .txt file to the solution explorer, but somehow i get a bad path error message every time i try to start the published setup.
How do I publish my Project with the needed .txt File?
You have various ways of achieving this.
The txt file included in the solution file will have a property called Build Action. Change it to Content and it should be published with your deployments.
You can add it to your resources, but then you will need to access it differently.
Add it to your installation package
I have some project what contains 3 dll libraries (one of them has 2 dependencies)
At the output folder of 'DLL parent' I need to have all source files of this 2 children. Moveover I want to save structure of this cs files by making 'cs' folder at output folder of DLL-parent, create subfolder with DLL-Child name there and copy all cs files of it to this folder.
For doing this I use post build events for DLL-Child.
And at bottom level when I build just this dll it works perfect.
After I set this command line at DLL-Child post build event it's output is created with folder with source files inside.
But when I build whole solution problem that this folder is not copied from output of DLL-Child to output of DLL-Parent.
Why ? At references section of DLL-Parent I set 'Copy local' to true for dependencies but it copies nothing.
Have your files be exported in separate folders per project. With this simple post build script (it's better to set it as post build event and select on successful build so as to not copy it each time but only when a build has been done properly)
copy "$(ProjectDir)FolderName\*" "PathYouWantYourFilesCopiedTo"
You can output all files from specific folder in your project.
You do not need checks for folders existing, VS does it on it's own. Create one build event for each folder of your files. If you have them in separate folders, nothing will overwrite nothing (as long as you maintain the folder structure in the output). And copy a whole folder is easier than copying file by file.
Basically what you need to do is to specify explicitly folder names for the output location. That will stop overwriting of files.
I'm planning to build my winform into a .exe file. I'm just wondering what to do with the XML files that my application needs?
I did some research and found out that I can add the XML files in the Resource folder before creating a .exe file.
Or I need to create a setup file? When the user runs the setup file, the XML files will be installed into their pc.Now I wonder which one is the best way to go for,
Note: XML files might get modified by the user.
If you want to ship the XML files as seperate to the .EXE then you can set the Copy to Output Directory to Copy if newer. (click on file and then go to properties).
OR if you want it as part of the .EXE I think you can change the Build Action to Embedded Resource.
I personally would create a Setup as per your edit and include the XML files. I usually just add everthing from the bin/release folder that is needed when I create a setup file.
You could either deploy the necessary files along with the executable in the same folder or embed them as resources (if they are read-only). If you need to modify them do not embed them as resources into the executable.
The correct way depends on how you intend to use the files. If the files always are deployed together with your application, the application never writes to them and they are never upgraded without upgrading the application, you can go with them embedded as resources.
If you need to update them separately from the application, you need to have them as physical files.
You don't necessarely need a installation package, unless you need to apply some logic during setup, such as updating the content of the setup based on user input or to check preconditions. The application can just be copied into place regardless of if you have embedded the files or not.
I have a solution in Visual Studio Express that looks like this:
The LogicSchema class in C# that will parse a specified XML file at run-time. The following is in the main method of Program.cs:
LogicSchema ls = new LogicSchema(
XDocument.Load(
"schemas\\C#Schema.xml",
LoadOptions.PreserveWhitespace));
I created a folder in my solution called "schemas" to save the XML file and set the Build Action to Content and the "Copy to Output Directory" value to be Copy if newer.
My expectation is that if open the file in notepad, make a change, and save it, the updated version of the XML file will be copied to the ouput directory (in this case, bin\debug) when I press F5. However, the updated file is not copied to the output directory unless I select Rebuild. Regular Build does not work.
What do I need to change so that when I press F5, the file is copied to the output directory when it's been updated?
It seems to work also in Visual Studio 2008 Team System -
must be Expression edition specific, so cannot repro...
OK, my original guess was not true - it is about XML file being in the referenced library. Can repro it now.
I think the most natural way would be to embed the XML as resource and then read it with GetManifestResourceStream(). This way, the XML file would follow your dll as you reference it without copying it separately even if you reference the dll directly and not through project reference.
...or then you could use Pre-build event? (Project properties - Build Events):
copy $(ProjectDir)test.xml $(SolutiontDir)projectFolder\bin\debug\test.xml
I would think it will always run even if VS thinks no source files have changed. At least in full VS2008 this is the case - just tested.