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The process tried to write to a nonexistent pipe when running cmd.exe using c#

I tried to call a .exe program I have calling cmd from a c# script that generates a command. When I run the code I get the output the process tried to write to a nonexistent pipe. But when I run said command using a cmd open from Windows it runs perfectly. What I am doing wrong? I am using Visual Studio 2022.
SilentMkdir(baseDir + "/00_CameraInit");
string binName =pre + binDir + "\\aliceVision_cameraInit.exe";
string dstDir =pre + baseDir + "/00_CameraInit\\";
string cmdLine = binName;
cmdLine = cmdLine + " --defaultFieldOfView 45.0 --verboseLevel info --sensorDatabase \"\" --allowSingleView 1";
cmdLine = cmdLine + " --imageFolder \"" + pre + srcImageDir + "\"";
cmdLine = cmdLine + " --output \"" + dstDir + "cameraInit.sfm\"";
Console.WriteLine(cmdLine);
var processInfo = new ProcessStartInfo("cmd.exe", cmdLine);
processInfo.UseShellExecute = false;
processInfo.RedirectStandardOutput = true;
processInfo.CreateNoWindow = false;
//processInfo.RedirectStandardOutput = !string.IsNullOrEmpty("output.txt");
int exitCode = -1;
string output = null;
try
{
var process = Process.Start(processInfo);
process.Start();
output = process.StandardOutput.ReadToEnd();
Console.WriteLine(output);
process.WaitForExit();
}
catch (Exception e)
{
Console.WriteLine("Run error" + e.ToString()); // or throw new Exception
}

How can I take ownership of a file in c# using takeown or icacls?

I know there are other posts on the matter but none have presented me with a working solution.
I'm trying to take ownership of files under C:\Windows\Media so I can replace them with my own. Currently I've been trying to do that by running either takeown or icacls in CMD, but neither seem to work. The takeown method actually returns success from CMD but I still get access denied when trying to delete the file. With the icacls method I get "the handle is invalid" and still get access denied.
The program is running as administator fyi.
And also in the icacls method changing Environment.Username to "Administrators" doesn't change anything.
Any help is appreciated!
Here is the code for the takeown method:
string[] soundFiles;
soundFiles = Directory.GetFiles(#"C:/Windows/Media", "*.wav");
//string cmdargs = #"/c takeown /F C:\Windows\Media";
string shortcmdargs = #"/c takeown /F ";
//Process.Start("CMD.exe", cmdargs);
string output = "null";
foreach(string file in soundFiles)
{
try
{
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = shortcmdargs + #"C:\Windows\Media\" + Path.GetFileName(file);
p.Start();
output = p.StandardOutput.ReadToEnd();
System.IO.File.Delete(file);
System.IO.File.Copy("neco.wav", file);
}
catch(Exception exce)
{
MessageBox.Show("Output: " + output + "\neException: " + exce);
}
}
And here is what I get when running it:
Here is the code for the icacls method:
string[] soundFiles;
soundFiles = Directory.GetFiles(#"C:/Windows/Media", "*.wav");
string cmdargs = #"/c takeown /F C:\Windows\Media";
string shortcmdargs = #"/c takeown /F ";
Process.Start("CMD.exe", cmdargs);
string output = "null";
foreach(string file in soundFiles)
{
try
{
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = #"/c icacls " + #"C:\Windows\Media\" + Path.GetFileName(file) + " /grant " + Environment.UserName + ":(OI)(CI)F /T";
p.Start();
output = p.StandardOutput.ReadToEnd();
System.IO.File.Delete(file);
System.IO.File.Copy("neco.wav", file);
}
catch(Exception exce)
{
MessageBox.Show("Output: " + output + "\neException: " + exce);
}
}
And here is what I get with it:

MSDEPLOY using CMD with C# script in Visual Studio

I am tryin got execute a msdeploy.exe command using cmd from visual studio with c# as scripting language
string filename = #"C:\Deploy\Test\Test.zip";
string servername = #"PADEVSPTAPP";
string compname = #"IIS Web Application Name";
string appvalue = #"Test";
string strCmdText;
strCmdText = "msdeploy.exe -verb:sync -source:package=" + filename + " -dest=auto,computerName=" + servername + " -setParam=name=" + compname + ",value=" + appvalue + " -allowUntrusted";
//System.Diagnostics.Process.Start("CMD.exe", strCmdText);
try
{
System.Diagnostics.ProcessStartInfo procStartInfo =
new System.Diagnostics.ProcessStartInfo("cmd", "/c " + strCmdText);
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
procStartInfo.CreateNoWindow = true;
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
string result = proc.StandardOutput.ReadToEnd();
proc.WaitForExit();
Console.WriteLine(result);
}
catch (Exception objException)
{
Console.WriteLine(objException.ToString());
}
the string outcome is
msdeploy.exe -verb:sync -source:package="C:\\Deploy\\Test\\Test.zip"
-dest=auto,computerName="PADEVSPTAPP" -setParam=name="IIS Web Application Name",value="Test" -allowUntrusted
but this does not work due to \\ in the command.
How should i execute this command.
I even tried with powershell script ,which also did not work
string PS_script = #"$msdeploy = ""C:\\Program Files\\IIS\\Microsoft Web Deploy V3\\msdeploy.exe""
$package = """;
PS_script = PS_script + Row.deployfile;
PS_script = PS_script + #"""
$compname = ""PADEVSPTAPP""
$appname = ""IIS Web Application Name""
$appvalue = """;
PS_script = PS_script + changetype[0];
PS_script = PS_script + #"""
$md = $(""`""{0}`"" -verb:sync -source:package=`""{1}`"" -dest=auto,ComputerName=`""{2}`"" -setParam=name=`""{3}`"",value=`""{4}`"" -allowUntrusted"" -f $msdeploy, $package, $compname, $appname, $appvalue)
cmd.exe /C ""`""$md`""""";
I have no clue where I am going wrong.

You are using an equals sign where it should be colon.
It's supposed to be -dest: and not -dest=
Same with setParam, it's supposed to be -setParam: not -setParam=
I suspect you don't actually have double backslashes \\ in your string it will just look like that if you inspect via the debugger - I suspect thats whats throwing you off.
Since you have spaces in your compname variable you need double quotes in your arguments string (probably around all your variables would be a good idea).
Also try running msdeploy.exe directly instead of via cmd.exe /c.
I assumed your msdeploy.exe is located in C:\Program Files (x86)\IIS\Microsoft Web Deploy V3
The string outcome is:
-verb:sync -source:package="C:\Deploy\Test\Test.zip" -dest:auto,computerName="PADEVSPTAPP" -setParam:name="IIS Web Application Name",value="Test" -allowUntrusted
Put it all together:
string filename = #"C:\Deploy\Test\Test.zip";
string servername = #"PADEVSPTAPP";
string compname = #"IIS Web Application Name";
string appvalue = #"Test";
string strCmdText;
strCmdText = "-verb:sync -source:package=\"" + filename + "\" -dest:auto,computerName=\"" + servername + "\" -setParam:name=\"" + compname + "\",value=\"" + appvalue + "\" -allowUntrusted";
//System.Diagnostics.Process.Start("CMD.exe", strCmdText);
try
{
System.Diagnostics.ProcessStartInfo procStartInfo =
new System.Diagnostics.ProcessStartInfo(#"C:\Program Files (x86)\IIS\Microsoft Web Deploy V3\msdeploy.exe");
procStartInfo.Arguments = strCmdText;
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
procStartInfo.CreateNoWindow = true;
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
string result = proc.StandardOutput.ReadToEnd();
proc.WaitForExit();
Console.WriteLine(result);
}
catch (Exception objException)
{
Console.WriteLine(objException.ToString());
}
BONUS INFO
If you need a more bulletproof way of determining where msdeploy.exe is located maybe have a look at these links:
https://gist.github.com/SergeyAxenov/15cf008531e6d0741533
How to find out what version of webdeploy/msdeploy is currently installed?

using poweriso cmd commands from c sharp code

I am making a C# program that will make input file an .iso file.
For example if we write C:\Users\User\Desktpo\a.txt in the textbox that I created and give a destination path for example C:\ it has to create an iso file name a in C:\.
So I downloaded PowerISO and learn about piso.exe then I made some other research about using Process.Start(); in C# so I write these lines of code:
string str = " create -o " + TextBox1.Text + ".iso -add " + TextBox2.Text + "//" ;
Process process = new Process();
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.FileName = "\"C:\PowerISO\piso.exe\"";
process.StartInfo.Arguments = str;
process.Start();
But this doesn't work.
Why?
EDIT: I am making an winform using Visual Studio 2017.

Please Note that
C:\PowerISO\piso.exe\
is not a valid C# path, the "\" before the P and the p is an escape indicater.
Either Add verbatim operator "#" before or escape it properly
edit:
In addition, you are adding extra double quotes to the FileName property.
You can check if the path is correct by asserting the file path with File.Exists method
Console.WriteLine(File.Exists(#"C:\PowerISO\piso.exe") ? "File exists." : "File does not exist.");
e.g
string str = " create -o " + TextBox1.Text + ".iso -add " + TextBox2.Text + "//" ;
Process process = new Process();
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.FileName = #"C:\PowerISO\piso.exe";
process.StartInfo.Arguments = str;
process.Start();
edit:
Verbatim operator will work, but escaping is better in my opinion.
string str = " create -o " + TextBox1.Text + ".iso -add " + TextBox2.Text + "//" ;
Process process = new Process();
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.FileName = "C:\\PowerISO\\piso.exe";
process.StartInfo.Arguments = str;
process.Start();

How can i get build/rebuild realtime output

I'm making Visual Studio package where i start devenv.exe and try to build other solution.I need to get building output in realtime, so user can see buiding progress(output), but i don't know how to do it and if it's even possible.
I tried such way :
string rebuildLog = string.Empty;
string logFileName = System.IO.Path.GetTempFileName();
System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo();
psi.FileName = #"devenv.exe";
psi.Arguments = "\"" + config.DmsPath + "\"" + #" /rebuild" + " Release|x64 " +" /out " + logFileName;
System.Diagnostics.Process process = new System.Diagnostics.Process();
process.StartInfo = psi;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.UseShellExecute = false;
process.Start();
while (!process.StandardOutput.EndOfStream)
{
string line = process.StandardOutput.ReadLine();
MessageBox.Show(line); // just to see if it works. It should go to log form
}
rebuildLog = GetRebuildLog(logFileName);
And rebuildLog has output.
Can anybody help ?

I found answer.
devenv.exe doesn't write simple console output, so i had to change
psi.FileName = #"devenv.exe"; to psi.FileName = #"devenv.com"; and it worked.