I have a problem where I need to get the value of a specific node in c#
I have this sample XML-Code and here is my C# code
string xml = #"
<ChapterHeader>
<Text> I need to get the text here</Text>
</ChapterHeader>
";
XmlReader rdr = XmlReader.Create(new System.IO.StringReader(xml));
while (rdr.Read())
{
if (rdr.NodeType == XmlNodeType.Element)
{
Console.WriteLine(rdr.LocalName);
if (rdr.LocalName == "ChapterHeader")
{
Console.WriteLine(rdr.Value);
}
}
}
The desired output is
<Text> I need to get the text here</Text>
including the Text Node. How can i do that? thank you
I also need to loop a huge xml file
and I need to get the value of a specific node
and I need to skip some specific node also.
example I have a node. the program must not read that Node and its childen Node.
How can i do that?
<ChapterHeader>
<Text> I need to get the text here</Text>
</ChapterHeader>
<Blank>
<Not>
</Not>
</Blank>
The desired output is
<Text> I need to get the text here</Text>
Look for ReadInnerXml which reads all the content, including markup, as a string.
Console.WriteLine( rdr.ReadInnerXml());
In the following question, you want to deal with larger Xml. I prefer Linq to Xml when dealing with larger set.
The program must not read that Node and its childen Node
Yes, it is possible. You could do something like this.
XDocument doc = XDocument.Load("filepath");
var nestedElementValues =
doc.Descendants("ChapterHeader") // flattens hierarchy and look for specific name.
.Elements() // Get elements for found element
.Select(x=>(string)x.Value); // Read the value.
Check this Example
System.Xml.Linq is a newer library designed to get rid of undesired reader style.
var document = XDocument.Parse(xml);
var texts = document.Descendants("Text");
foreach (var text in texts)
{
Console.WriteLine(text);
}
You can use the same parsing style you're using (rdr.LocalName = "Text") and then use rdr.ReadOuterXml()
Related
This is my XML:
<?xml version="1.0"?>
<formatlist>
<format>
<formatName>WHC format</formatName>
<delCol>ID</delCol>
<delCol>CDRID</delCol>
<delCol>TGIN</delCol>
<delCol>IPIn</delCol>
<delCol>TGOUT</delCol>
<delCol>IPOut</delCol>
<srcNum>SRCNum</srcNum>
<distNum>DSTNum</distNum>
<connectTime>ConnectTime</connectTime>
<duration>Duration</duration>
</format>
<format>
<formatName existCombineCol="1">Umobile format</formatName> //this format
<delCol>billing_operator</delCol>
<hideCol>event_start_date</hideCol>
<hideCol>event_start_time</hideCol>
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>ConnectdateTimeAFcombine</name>
<combineDate>event_start_date</combineDate>
<combineTime>event_start_time</combineTime>
</afCombineName>
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>aaa</name>
<combineDate>bbb</combineDate>
<combineTime>ccc</combineTime>
</afCombineName>
<modifyPerfixCol action="add" perfix="60">bnum</modifyPerfixCol>
<srcNum>anum</srcNum>
<distNum>bnum</distNum>
<connectTime>ConnectdateTimeAFcombine</connectTime>
<duration>event_duration</duration>
</format>
</formatlist>
I want to find format with Umobile format then iterate over those two nodes.
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>ConnectdateTimeAFcombine</name>
<combineDate>event_start_date</combineDate>
<combineTime>event_start_time</combineTime>
</afCombineName>
<afCombineName dateType="DateTime" format="dd/MM/yyyy HH:mm:ss"> //node i want
<name>aaa</name>
<combineDate>bbb</combineDate>
<combineTime>ccc</combineTime>
</afCombineName>
and list all the two node's child nodes. The result should like this:
ConnectdateTimeAFcombine,event_start_date,event_start_time.
aaa,bbb,ccc
How can I do this?
foreach(var children in format.Descendants())
{
//Do something with the child nodes of format.
}
For all XML related traversing, you should get used to using XPath expressions. It is very useful. Even if you could perhaps do something easier in your specific case, it is good practice to use XPath. This way, if your scheme changes at some point, you just update your XPath expression and your code will be up and running.
For a complete example, you can have a look at this article.
You can use the System.Xml namespace APIs along with System.Xml.XPath namespace API. Here is a quick algorithm that will help you do your task:
Fetch the text node containing the string Umobile format using the below XPATH:
XmlNode umobileFormatNameNode = document.SelectSingleNode("//formatName[text()='Umobile format']");
Now the parent of umobileFormatNameNode will be the node that you are interested in:
XmlNode formatNode = umobileFormatNameNode.ParentNode;
Now get the children for this node:
XmlNodeList afCombineFormatNodes = formatNode.SelectNodes("afCombineName");
You can now process the list of afCombineFormatNodes
for(XmlNode xmlNode in afCombineNameFormtNodes)
{
//process nodes
}
This way you can access those elements:
var doc = System.Xml.Linq.XDocument.Load("PATH TO YOUR XML FILE");
var result = doc.Descendants("format")
.Where(x => (string)x.Element("formatName") == "Umobile format")
.Select(x => x.Element("afCombineName"));
Then you can iterate the result this way:
foreach (var item in result)
{
string format = item.Attribute("format").Value.ToString();
string name = item.Element("name").Value.ToString();
string combineDate = item.Element("combineDate").Value.ToString();
string combineTime = item.Element("combineTime").Value.ToString();
}
Here is what I have so far:
HtmlAgilityPack.HtmlDocument ht = new HtmlAgilityPack.HtmlDocument();
TextReader reader = File.OpenText(#"C:\Users\TheGateKeeper\Desktop\New folder\html.txt");
ht.Load(reader);
reader.Close();
HtmlNode select= ht.GetElementbyId("cats[]");
List<HtmlNode> options = new List<HtmlNode>();
foreach (HtmlNode option in select.ChildNodes)
{
if (option.Name == "option")
{
options.Add(option);
}
}
Now I have a list of all the "options" for the select element. What properties do I need to access to get the key and the text?
So if for example the html for one option would be:
<option class="level-1" value="1">Funky Town</option>
I want to get as output:
1 - Funky Town
Thanks
Edit: I just noticed something. When I got the child elements of the "Select" elements, it returned elements of type "option" and elements of type "#text".
Hmmm .. #text has the string I want, but select has the value.
I tought HTMLAgilityPack was an html parser? Why did it give me confusing values like this?
This is due to the default configuration for the html parser; it has configured the <option> as HtmlElementFlag.Empty (with the comment 'they sometimes contain, and sometimes they don't...'). The <form> tag has the same setup (CanOverlap + Empty) which causes them to appear as empty nodes in the dom, without any child nodes.
You need to remove that flag before parsing the document.
HtmlNode.ElementsFlags.Remove("option");
Notice that the ElementsFlags property is static and any changes will affect all further parsing.
edit: you should probably be selecting the option nodes directly via xpath. I think this should work for that:
var options = select.SelectNodes("option");
that will get your options without the text nodes. the options should contain that string you want somewhere. waiting for your html sample.
foreach (var option in options)
{
int value = int.Parse(option.Attributes["value"].Value);
string text = option.InnerText;
}
you can add some sanity checking on the attribute to make sure it exists.
When I load this XML node, the HTML within the node is being completely stripped out.
This is the code I use to get the value within the node, which is text combined with HTML:
var stuff = innerXml.Descendants("root").Elements("details").FirstOrDefault().Value;
Inside the "details" node is text that looks like this:
"This is <strong>test copy</strong>. This is A Link"
When I look in "stuff" var I see this:
"This is test copy. This is A Link". There is no HTML in the output... it is pulled out.
Maybe Value should be innerXml or innerHtml? Does FirstOrDefault() have anything to do with this?
I don't think the xml needs a "cdata" block...
HEre is a more complete code snippet:
announcements =
from link in xdoc.Descendants(textContainer).Elements(textElement)
where link.Parent.Attribute("id").Value == Announcement.NodeId
select new AnnouncmentXml
{
NodeId = link.Attribute("id").Value,
InnerXml = link.Value
};
XDocument innerXml;
innerXml = XDocument.Parse(item.InnerXml);
var abstract = innerXml.Descendants("root").Elements("abstract").FirstOrDefault().Value;
Finally, here is a snippet of the Xml Node. Notice how there is "InnerXml" within the standard xml structure. It starts with . I call this the "InnerXml" and this is what I am passing into the XDocument called InnerXml:
<text id="T_403080"><root> <title>How do I do stuff?</title> <details> Look Here Some Form. Please note that lorem ipsum dlor sit amet.</details> </root></text>
[UPDATE]
I tried to use this helper lamda, and it will return the HTML but it is escaped, so when it displays on the page I see the actual HTML in the view (it shows instead of giving a link, the tag is printed to screen:
Title = innerXml.Descendants("root").Elements("title").FirstOrDefault().Nodes().Aggregate(new System.Text.StringBuilder(), (sb, node) => sb.Append(node.ToString()), sb => sb.ToString());
So I tried both HTMLEncode and HTMLDecode but neither helped. One showed the escaped chars on the screen and the other did nothing:
Title =
System.Web.HttpContext.Current.Server.HtmlDecode(
innerXml.Descendants("root").Elements("details").Nodes().Aggregate(new System.Text.StringBuilder(), (sb, node) => sb.Append(node.ToString()), sb => sb.ToString())
);
I ended up using an XmlDocument instead of an XDocument. It doesn't seem like LINQ to XML is mature enough to support what I am trying to do. THere is no InnerXml property of an XDoc, only Value.
Maybe someday I will be able to revert to LINQ. For now, I just had to get this off my plate. Here is my solution:
// XmlDoc to hold custom Xml within each node
XmlDocument innerXml = new XmlDocument();
try
{
// Parse inner xml of each item and create objects
foreach (var faq in faqs)
{
innerXml.LoadXml(faq.InnerXml);
FAQ oFaq = new FAQ();
#region Fields
// Get Title value if node exists and is not null
if (innerXml.SelectSingleNode("root/title") != null)
{
oFaq.Title = innerXml.SelectSingleNode("root/title").InnerXml;
}
// Get Details value if node exists and is not null
if (innerXml.SelectSingleNode("root/details") != null)
{
oFaq.Description = innerXml.SelectSingleNode("root/details").InnerXml;
}
#endregion
result.Add(oFaq);
}
}
catch (Exception ex)
{
// Handle Exception
}
I do think wrapping your details node in a cdata block is the right decision. CData basically indicates that the information contained within it should be treated as text, and not parsed for XML special characters. The html charaters in the details node, especially the < and > are in direct conflict with the XML spec, and should really be marked as text.
You might be able to hack around this by grabbing the innerXml, but if you have control over the document content, cdata is the correct decision.
In case you need an example of how that should look, here's a modified version of the detail node:
<details>
<![CDATA[
This is <strong>test copy</strong>. This is A Link
]]>
</details>
When I do
XPathSelectElement("/root/title").ToString()
I get for example <title>this is an <strong>example</strong></title>. But I don't want to get <title> around the text.
When I do
XPathSelectElement("/root/title").Value
then it gets only the text without <strong></strong>
How can I solve this?
From memory:
XPathSelectElement("/root/title/text()").ToString()
Alternatively, you might select all child nodes (/root/title/*) and join the their string representations
You can create an XmlReader and read the inner xml from it.
XElement element = doc.XPathSelectElement("/root/title");
XmlReader reader = element.CreateReader();
reader.MoveToContent();
string innerXml = reader.ReadInnerXml();
Hy,
I have for example this xml:
<books>
<book1 name="Cosmic">
<attribute value="good"/>
</book1>
</books>
How can I display it in a listBox control line by line, that the final result it will be a listbox with 5 rows in this case?
In this moment I am prasing the XML using LINQ to XML like this:
foreach (XElement element in document.DescendantNodes())
{
MyListBox.Items.Add(element.ToString());
}
But the final result puts every xml node in one list-box item (including child-nodes).
Does anyone has any idea how can I put the xml line by line in list-box items?
Thanks.
Jeff
A simple solution would use a recursive function like the following:
public void FillListBox(ListBox listBox, XElement xml)
{
listBox.Items.Add("<" + xml.Name + ">");
foreach (XNode node in xml.Nodes())
{
if (node is XElement)
// sub-tag
FillListBox(listBox, (XElement) node);
else
// piece of text
listBox.Items.Add(node.ToString());
}
listBox.Items.Add("</" + xml.Name + ">");
}
Of course, this one will print only the tag names (e.g. <book1> in your example) and not the attributes (name="Cosmic" etc.). I’m sure you can put those in yourself.
If you want to display your raw XML in a list box, use a text stream to read in your data.
using(StreamReader re = File.OpenText("Somefile.XML"))
{
string input = null;
while ((input = re.ReadLine()) != null)
{
MyListBox.Items.Add(input);
}
}
Jeff, maybe it would be much easier to implement (and to read/maintain) with a simple TextReader.ReadLine()?
I don't know what you are trying to achieve, just a suggestion.