I have been trying to get my arguments to be passed to my main method in C#. Mainly I just want to capture the file path that was double clicked. I have my files with custom extension and when it runs it open my program. That part works.
static string file = "";
[STAThread]
static void Main(string[] args)
{
Application.EnableVisualStyles();
if (args.Length > 0) file = args[0];
Application.Run(new Form1());
}
public Form1()
{
InitializeControls();
}
I also tried this way, which is not much different.
static string file = "";
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
string[] args = Environment.GetCommandLineArgs();
if (args.Length > 0) file = args[0];
Application.Run(new Form1());
}
public Form1()
{
InitializeControls();
}
Its worth mentioning that I have this in a partial class. I don't know if that effects it directly or not.
I don't really need to get the args if I can just get the file that was double clicked but I feel as that is the only way, and now I am curious.
What am I missing that is preventing me from being able to pass args to my main?
if you run "ftype" in the command prompt your program type should appear as:
YOURTYPE="yourProgram.exe" "%1"
If the "%1" doesn't appear in exactly that way, then the association is wrong (it won't pass the name of the file as an argument). Give it a try.
Related
I have 2 winform applications, say form1 and form2.
They are programmed through separate visual studio programs
form1 is programmed in WindowsFormsApplication1.sln
form2 is programmed in WindowsFormsApplication2.sln
I want to open form2(=WindowsFormApplication2.exe) by clicking a button in form1
I created a method in WindowsFormApplication1.sln
private void button3_Click(object sender, EventArgs e)
{
var p = new Process();
p.StartInfo.FileName ="WindowsFormsApplication2.exe";
p.StartInfo.Arguments = "10";
p.Start();
}
This method opens WindowsFormApplication2.exe
Then I need WindowsFormApplication2 MessageBox show the value got from WindowsFormApplication1.exe. Is this clear?
This should be clear... I cannot explain more simply than this
What other people have answered through comment or answerbox, is not what I want
If I want to pass a value from form1 to form2 that are in same .sln (That is, WindowsFormApplication1.sln has form1 and form2), this is so easy
I could just use
Form2 form2 = new Form2(textBox1.Text);
form2.Show();
Constructor Form2:
public Form2(string smth)
{
InitializeComponent();
label1.Text = smth;
}
But this is not what I want
I think everything is clear. Please tell me how to solve the problem
C# programs have a static void Main() method that is the entry point for the application. You should see something like this in your Program.cs file in your winform2 project:
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
If you want to enable your winform2 application to accept command-line arguments, you capture them from this method. But first you need to modify the method signature to take in a string[] of arguments:
// Add a string[] argument to the Main entry point method
static void Main(string[] args)
Now any command line arguments passed to this application will be in the args array.
Next, we need to modify your winform2 application's main form constructor to take in one or more string arguments, so we can pass them in the line that says Application.Run(new Form1()).
For example, you can modify your form's constructor to take in a string (I'm using Form1 as an example):
public partial class Form1 : Form
{
// Add a string argument to the form's constructor.
// If it's not empty, we'll use it for the form's title.
public Form1(string input)
{
InitializeComponent();
if (!string.IsNullOrEmpty(input)) this.Text = input;
}
}
After we enable the form to take a string input, we now modify the call to the constructor to pass a string to our form. In this case, I'm expecting a string like: /Title:"Some Form Title", so I'll look at the args array and try to find a match.
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
// Try to find the 'Title' argument
var titleArg = args?.FirstOrDefault(arg => arg.StartsWith("/Title:",
StringComparison.OrdinalIgnoreCase));
// Now strip off the beginning part of the argument
titleArg = titleArg?.Replace("/Title:", "");
// And now we can pass this to our form constructor
Application.Run(new Form1(titleArg));
}
Now you can launch your WinForm application from the command line and pass in a string, which will become the title. Here I'm running the .exe from the command line and passing /Title:"Custom Title From Command Line", but you could just assign this string to the Arguments property of your ProcessStartInfo instance if you're launching the application programmatically.:
I am programming, in Microsoft's Visual Studio 2015, in C#.
I am trying to make an Windows Forms application which would be used to open simple .txt, or other type files, and edit them.
But the point being is i want to open my program with : Right click on .txt file->Open with->My program.
The question I have is this, how am I supposed to do that, if I only have the solution file of my program?
And i don't really care, about opening the .txt files when my program is already running. I want to be able to start it, like i mentioned before.
I am using this program as a starting point, from where the next time i will be able to make a simple mp3 player, or such. And as far as i know, people don't usually start an mp3 player program, and then the mp3 player file they want to play. I hope that sheds some light on what i am trying to accomplish.
I have been searching for a solution, and i couldn't find it.
Perhaps it is really easy, but for me, for now, it isn't. Your help is appreciated.
My Program.cs looks like this :
static void Main(string[] args)
{
//with args(user open file with the program)
if(args != null && args.Length > 0)
{
string fileName = args[0];
//check file exists
if (File.Exists(fileName))
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Form1 MainForm = new Form1();
MainForm.OpenFile(fileName);
Application.Run(MainForm);
}
//the file does not exist
else
{
MessageBox.Show("The file does not exist!", "Error!", MessageBoxButtons.OK, MessageBoxIcon.Error);
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
//without args
else
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
If you're asking how to handle opening the file, try this:
-In your Form1.cs, overload your constructor by adding another definition.
public Form1(string fileName)
{
InitializeComponent();
openFileNow(fileName);
}
-Create the openFileNow method (async for extra goodness)
private async void openFileNow(string fileName)
{
try
{
if(fileName.EndsWith(".txt"))
{
//Obviously you'll do something different with an .mp3
using (StreamReader reader = new StreamReader(fileName))
{
txtEditBox.Text = await reader.ReadToEndAsync();
}
}
else
{
MessageBox.Show("Can't open that file.");
}
}
catch (IOException e)
{
Console.WriteLine(e.Message);
}
}
-Edit your Program.cs to simply:
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Form1 MainForm;
if (args != null && args.Length > 0)
{
MainForm = new Form1(args[0]);
}
else
{
MainForm = new Form1();
}
Application.Run(MainForm);
}
In Visual Studio, under the project's properties, you can add Command line arguments in the "Debug" section.
If you want to associate a file extension with your application, you do that in the registry. You can do it in C#, but the ClickOnce settings will be so much cleaner.
Go to your project properties -> Publish -> Options -> FileAssociations
Edit
- Note that if you intend to publish with ClickOnce, you'll need to change a few lines in your Program.cs:
string fileName = AppDomain.CurrentDomain.SetupInformation.ActivationArguments.ActivationData[0];
if (fileName != null && fileName.Length > 0)
{
MainForm = new Form1(fileName);
}
If you're simply looking to debug with file associations, try right-clicking a .txt file, Open With... (More Options) and navigate to your .exe from your project's debug folder, i.e.:
C:\VS Projects\MyProject\MyProject\bin\Debug\myProgram.exe
Obviously this is a temporary solution. Enjoy!
In your Form add a button1 (or change it to suit your need) and add the following logic.
whatever file you open, following logic will use your system default program to open them without further asking.
BTW, Form1 doesn't have OpenFile method , you may have gotten it from somewhere. you can remove it or add method definition.
MainForm.OpenFile(filename);
private void button1_Click(object sender, EventArgs e)
{
var fileDialog1 = new OpenFileDialog
{
InitialDirectory = "c:\\",
RestoreDirectory = true
};
if (fileDialog1.ShowDialog() == DialogResult.OK)
{
System.Diagnostics.Process.Start(fileDialog1.FileName);
}
}
if this is not what you are trying to do then you may have to write to Registry for file association. I gave the link in the comment above.
I'm an amateur at c# and I've been unable to locate the answer to this.
Perhaps I am not aware of the correct terms to use.
When a video file is dragged onto my exe application, I would like the application to know that it was launched with a file and be able to know the path and filename of that file. This way, the user does not have to use the file>open menu.
Hope that makes sense.
Thanks
You can check the command line arguments which were used to launch the application.
If your application was started by dropping a file on the .exe file, there will be a single command line argument with the path of the file.
string[] args = System.Environment.GetCommandLineArgs();
if(args.Length == 1)
{
// make sure it is a file and not some other command-line argument
if(System.IO.File.Exists(args[0])
{
string filePath = args[0];
// open file etc.
}
}
As your question title states, you want the path and the file name. You can get the file name using:
System.IO.Path.GetFileName(filePath); // returns file.ext
When you drag a file into a C# application, it will goes as an command-line argument to that application. Like console applications, you can catch it on the Main method on the Program class.
I'll explain it using Windows Forms application.
Open your Program class on the solution. Your program class should look like this.
static class Program
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
By default, when you create Windows Forms applications, they don't treat command line arguments. You have to make a tiny change on the signature of the Main method, so it can receive arguments:
static class Program
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
Now you can handle file name argument passed to the application. By default, Windows will put the file name as the first argument. Just do something like this:
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
// Before Application.Run method, treat the argument passed.
// I created an overload of the constructor of my Form1, so
// it can receive the File Name and load the file on some TextBox.
string fileName = null;
if (args != null && args.Length > 0)
fileName = args[0];
Application.Run(new Form1(fileName));
}
In case you want to know the constructor overload of my Form1, here it is. Hope it helps!
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
public Form1(string fileName) : this()
{
if (fileName == null)
return;
if (!File.Exists(fileName))
{
MessageBox.Show("Invalid file name.");
return;
}
textBox1.Text = File.ReadAllText(fileName);
}
}
You need your application's command-line arguments. When you drop a file on your application in Explorer, Explorer opens the application with the file you dropped on it. You can select as many files as you want, drop them on your application and using this line of code, files will be an array of those command line arguments.
string[] files = Environment.GetCommandLineArgs();
I'm new to C# and I'm not getting around this trouble. Here is what I wanted to achieve.
Whenever I drag and drop a file on the .exe file (on the icon itself), the application should capture the filepath of dragged file.
Thanks.
If I understand correctly, you want to drop a file onto an icon of an exe, not an application itself. If that is so, it can be achieved easily using the parameters passed into the application. If you check your original boilerplate code when you make a console application it has the application entry point:
static void Main(string[] args)
If you drag drop a file onto the icon of the application, the args[0] will hold the name of the file being dropped. If the goal is to drop the file onto an EXE file, there are numerous tutorials on SO about that.
If you make this following code, then when you drag your file onto the exe icon, the args[0] will hold the path of it as an argument:
(I added the if statement that if you start the program without dragging anything
it shouldn't crash)
class Program
{
static void Main(string[] args)
{
if (args.Length > 0)
{
Console.WriteLine(args[0]);
}
Console.ReadLine();
}
}
I was able to add drag and drop onto an executable/shortcut created using Windows Forms by adding in the default string[] args to the Main function in Program. And then, add the same parameter to Form1's constructor function, and pass in the same args gathered from Main.
Program.cs
static class Program
{
[STAThread]
//add in the string[] args parameter
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
//pass in the args to the form constructor
Application.Run(new Form1(args));
}
}
Form1.cs
//add in the string[] args parameter to the form constructor
public Form1(string[] args)
{
InitializeComponent();
//if there was a file dropped..
if (args.Length > 0)
{
var file = args[0];
//do something with the file now...
}
}
I created a text editor in C# and I use a special file extension for the XML file that my program uses. When I use "Open With..." from the Windows context menu, my program doesn't read the file and I get an error.
How do I fix this?
In your Main() method, you need to capture the file name:
static void Main(string args[])
{
string fileName;
if (args.Length > 0)
fileName = args[0];
...
}
Then you'll need to pass fileName to the code that opens the file. How you do that is up to you.
If your Main() method has no parameters, just add the string args[] parameter and the runtime will take care of populating the array with the commandline parameters.
If you are already doing that, then this is probably a SuperUser question.
but the Main like that
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
it doesn't have any parameters
you can use this simple code to answer me
private void button1_Click(object sender, EventArgs e)
{
richTextBox1.Text = File.ReadAllText(#"d:\wifi.txt");
}
the text viewed in the richtextbox1