Image rotated but thumbnail is not - c#

I am trying to rotate the image based on EXIF tag. I am able to handle the rotation of image successfully but the thumbnail in windows explorer is still upside down. The image when opened is absolutely fine. Verified the corrected orientation here. The problem with the following code is that the EXIF data does not seem to have any information about thumbnail orientation. What I want is:
If there is thumbnail orientation available, rotate the thumbnail and update image's metadata for thumbnail orientation.
If there is no thumbnail orientation information available, rotate the thumbnail and add image's metadata for thumbnail orientation.
The code I am using is:
public static RotateFlipType RotateImageByExifOrientationData(Image img, string oldFileName, string sourceFilePath, out string newFileName)
{
int orientationId = 0x0112;//Image orientation
int thumbnailOrientationId = 0x5029;//Thumbnail orientation
var fType = RotateFlipType.RotateNoneFlipNone;
if (img.PropertyIdList.Contains(orientationId))
{
var pItem = img.GetPropertyItem(orientationId);
//Get the orientation
fType = GetRotateFlipTypeByExifOrientationData(pItem.Value[0]);
if (fType != RotateFlipType.RotateNoneFlipNone)
{
img.RotateFlip(fType);
// Read orientation tag. Update to normal so that the other clients(image viewer or browser) will not rotate the rotated image.
// Force value to 1
pItem.Value = BitConverter.GetBytes((short)1);
img.SetPropertyItem(pItem);
PropertyItem thumbnailItem;
if (img.PropertyIdList.Contains(thumbnailOrientationId))
{
//If thumbnail metadata is available, update it.
thumbnailItem = img.GetPropertyItem(thumbnailOrientationId);
thumbnailItem.Value = BitConverter.GetBytes((short)1);
img.SetPropertyItem(thumbnailItem);
}
else
{
//If thumbnail metadata is not available, add appropriate metadata.
thumbnailItem = img.PropertyItems[0];
thumbnailItem.Id = thumbnailOrientationId;
thumbnailItem.Type = 2;
thumbnailItem.Value = BitConverter.GetBytes((short)1);
thumbnailItem.Len = thumbnailItem.Value.Length;
img.SetPropertyItem(thumbnailItem);
}
newFileName = "Rotated_" + oldFileName;
string targetFilePath = sourceFilePath + newFileName ;
ImageFormat targetFormat = ImageFormat.Jpeg;
img.Save(targetFilePath, targetFormat);
File.Delete(sourceFilePath + oldFileName);//Delete old file.
}
}
return fType;
}

is an old question, but after some research, I noticed that even after removing the orientation of the Image (0x0112) and the orientation of the thumbnail (0x5029), when trying to generate the thumbnail again, the same orientation remained. So I checked that some JPGs have the thumbnail "embedded" in bytes. so after removing the bytes (0x501B), I was able to generate the thumbnail correctly.
Simple code shows:
var rotateImage = Image.FromStream(fileStream);
switch (degree)
{
case eRotateImagem.Degree_90:
rotateImage.RotateFlip(RotateFlipType.Rotate90FlipNone);
break;
case eRotateImagem.Degree_180:
rotateImage.RotateFlip(RotateFlipType.Rotate180FlipNone);
break;
case eRotateImagem.Degree_270:
rotateImage.RotateFlip(RotateFlipType.Rotate270FlipNone);
break;
}
int orientationId = 0x0112; //Image orientation
int thumbnailOrientationId = 0x5029; //Thumbnail orientation
int thumbnailBytes = 0x501B; //Thumbnail bytes
if (rotateImage.PropertyIdList.Contains(orientationId))
{
rotateImage.RemovePropertyItem(orientationId);
}
if (rotateImage.PropertyIdList.Contains(thumbnailOrientationId))
{
rotateImage.RemovePropertyItem(thumbnailOrientationId);
}
if (rotateImage.PropertyIdList.Contains(thumbnailBytes))
{
rotateImage.RemovePropertyItem(thumbnailBytes);
}

Related

C# Image GPS location property disappears after resizing image [duplicate]

Yes yes... I've seen other posts related to this issue, and yes... I've googled about it.
But so far, I was not able to get to the result I need.
I'm loading a large image taken in 300 dpi, and I need to resize it.
I know... I know... dpi is relative and doesn't really matter... what matters are the dimensions in pixels:
DPI is essentially the number of pixels that correspond to an inch when the image is printed not when it is viewed on a screen. Therefore by increasing the DPI of the image, you do not increase the size of the image on the screen. You only increase the quality of print.
Even though the DPI information stored in the EXIF of an image is somewhat useless, it is causing me problems.
The image I'm resizing is losing the original exif information, including the horizontal and vertical resolution (dpi), and thus it is saving with a default of 96 dpi. Possible reason to this is that only JPEG and another format can hold metadata information.
The end image result is should look like this: 275x375 at 300dpi
Instead is looking like this: 275x375 at 96dpi
You can argue that they are they same, and I agree, but we have a corel draw script that used to load these images, and since this dpi information is different, it places it in different sizes on the document.
Here's what I'm using for resizing:
public System.Drawing.Bitmap ResizeImage(System.Drawing.Image image, int width, int height)
{
Bitmap result = new Bitmap(width, height);
// set the resolutions the same to avoid cropping due to resolution differences
result.SetResolution(image.HorizontalResolution, image.VerticalResolution);
//use a graphics object to draw the resized image into the bitmap
using (Graphics graphics = Graphics.FromImage(result))
{
//set the resize quality modes to high quality
graphics.CompositingQuality = System.Drawing.Drawing2D.CompositingQuality.HighQuality;
graphics.InterpolationMode = System.Drawing.Drawing2D.InterpolationMode.High;
graphics.SmoothingMode = System.Drawing.Drawing2D.SmoothingMode.HighQuality;
//draw the image into the target bitmap
graphics.DrawImage(image, 0, 0, result.Width, result.Height);
}
//return the resulting bitmap
return result;
}
That does the work very well, but loses the EXIF information.
Setting the SetResolution to SetResolution(300, 300) does not work!
I looked at reading and changing the EXIF information of an image, and I've tried:
public void setImageDpi(string Filename, string NewRes)
{
Image Pic;
PropertyItem[] PropertyItems;
byte[] bDescription = new Byte[NewRes.Length];
int i;
string FilenameTemp;
System.Drawing.Imaging.Encoder Enc = System.Drawing.Imaging.Encoder.Transformation;
EncoderParameters EncParms = new EncoderParameters(1);
EncoderParameter EncParm;
ImageCodecInfo CodecInfo = GetEncoderInfo("image/jpeg");
// copy description into byte array
for (i = 0; i < NewRes.Length; i++) bDescription[i] = (byte)NewRes[i];
// load the image to change
Pic = Image.FromFile(Filename);
foreach (PropertyItem item in Pic.PropertyItems)
{
if (item.Id == 282 || item.Id == 283)
{
PropertyItem myProperty = item;
myProperty.Value = bDescription;
myProperty.Type = 2;
myProperty.Len = NewRes.Length;
Pic.SetPropertyItem(item);
Console.WriteLine(item.Type);
}
}
// we cannot store in the same image, so use a temporary image instead
FilenameTemp = Filename + ".temp";
// for lossless rewriting must rotate the image by 90 degrees!
EncParm = new EncoderParameter(Enc, (long)EncoderValue.TransformRotate90);
EncParms.Param[0] = EncParm;
// now write the rotated image with new description
Pic.Save(FilenameTemp, CodecInfo, EncParms);
// for computers with low memory and large pictures: release memory now
Pic.Dispose();
Pic = null;
GC.Collect();
// delete the original file, will be replaced later
System.IO.File.Delete(Filename);
// now must rotate back the written picture
Pic = Image.FromFile(FilenameTemp);
EncParm = new EncoderParameter(Enc, (long)EncoderValue.TransformRotate270);
EncParms.Param[0] = EncParm;
Pic.Save(Filename, CodecInfo, EncParms);
// release memory now
Pic.Dispose();
Pic = null;
GC.Collect();
// delete the temporary picture
System.IO.File.Delete(FilenameTemp);
}
That didn't work either.
I tried looking and changing the EXIF information for DPI (282 and 283) later in the process as such:
Encoding _Encoding = Encoding.UTF8;
Image theImage = Image.FromFile("somepath");
PropertyItem propItem282 = theImage.GetPropertyItem(282);
propItem282.Value = _Encoding.GetBytes("300" + '\0');
theImage.SetPropertyItem(propItem282);
PropertyItem propItem283 = theImage.GetPropertyItem(283);
propItem283.Value = _Encoding.GetBytes("300" + '\0');
theImage.SetPropertyItem(propItem283);
theImage.Save("somepath");
But the program crashes saying that Property Cannot be Found.
If the property doesn't exist, apparently I can't add it:
A PropertyItem is not intended to be used as a stand-alone object. A PropertyItem object is intended to be used by classes that are derived from Image. A PropertyItem object is used to retrieve and to change the metadata of existing image files, not to create the metadata. Therefore, the PropertyItem class does not have a defined Public constructor, and you cannot create an instance of a PropertyItem object.
I'm stuck... all I need is a resized image with a dpi set to 300, it shouldn't be so hard.
Any help much appreciated. Thanks
The following code worked for me:
const string InputFileName = "test_input.jpg";
const string OutputFileName = "test_output.jpg";
var newSize = new Size(640, 480);
using (var bmpInput = Image.FromFile(InputFileName))
{
using (var bmpOutput = new Bitmap(bmpInput, newSize))
{
foreach (var id in bmpInput.PropertyIdList)
bmpOutput.SetPropertyItem(bmpInput.GetPropertyItem(id));
bmpOutput.SetResolution(300.0f, 300.0f);
bmpOutput.Save(OutputFileName, ImageFormat.Jpeg);
}
}
When I inspect the output file I can see EXIF data and the DPI has been changed to 300.

ITextSharp Image getInstance rotates my image

I'm having a problem when fetching an image using Image.GetInstance. The photo is in portrait but when I did the Image.GetInstance(), my image is rotated.
string imagepath = AttachmentURL + answer.Attachment.AzureFileName;
Image image = Image.GetInstance(imagepath);
My image:
https://zensyd.blob.core.windows.net/fileattachments/f9ab6a11-13c1-421a-abdd-4b4a6d701033.jpg
This means 2016 width and 1512 height.
I found this answer regarding image orientation rotation via exif but I need to convert the uri first to a memory stream. I then found this solution that converts URI to a MemoryStream. Then MemoryStream to System.Drawing Image.
Here's my solution
BaseColor color = null;
string imagepath = AttachmentURL + answer.Attachment.AzureFileName;
var imgStream = GetStreamFromUrl(imagepath);
var tempImg = System.Drawing.Image.FromStream(imgStream);
ExifRotate(tempImg);
Image image = Image.GetInstance(tempImg, color);
GetStreamFromUrl is balexandre's answer here
ExifRotate is saucecontrol's answer here.

Resize existing image in DocX using OpenXML sdk

Got template docx with image placeholder which replaced by correct picture.
private void SetImagePartData(ImagePart imagePart, byte[] data)
{
if (imagePart != null)
{
using (var writer = new BinaryWriter(imagePart.GetStream()))
{
writer.Write(data);
}
}
}
but it preserves placeholder size. How to change it to actual image size? Byte array is aqquared from image on server, so size is known.
If you mean a content control with your placeholder you can use following code I once needed:
//Get SdtElement (can be a block, run... so I use the base class) with corresponding Tag
SdtElement block = doc.MainDocumentPart.Document.Body.Descendants<SdtElement>()
.FirstOrDefault(sdt => sdt.SdtProperties.GetFirstChild<Tag>()?.Val == contentControlTag);
//Get First drawing Element and get the original sizes of placeholder SDT
//I use SDT placeholder size as maximum size to calculate picture size with correct ratios
Drawing sdtImage = block.Descendants<Drawing>().First();
double sdtWidth = sdtImage.Inline.Extent.Cx;
double sdtHeight = sdtImage.Inline.Extent.Cy;
double sdtRatio = sdtWidth / sdtHeight;
*Calculate final width/height of image*
//Resize picture placeholder
sdtImage.Inline.Extent.Cx = finalWidth;
sdtImage.Inline.Extent.Cy = finalHeight;
//Change width/height of picture shapeproperties Transform
//This will override above height/width until you manually drag image for example
sdtImage.Inline.Graphic.GraphicData
.GetFirstChild<DocumentFormat.OpenXml.Drawing.Pictures.Picture>()
.ShapeProperties.Transform2D.Extents.Cx = finalWidth;
sdtImage.Inline.Graphic.GraphicData
.GetFirstChild<DocumentFormat.OpenXml.Drawing.Pictures.Picture>()
.ShapeProperties.Transform2D.Extents.Cy = finalHeight;
But you can use it if you are just using an image in your word document too. You just need to locate the correct Drawing element which contains the reference to your imagepart. Then you can use the bottom part of the code to adjust the image size. It's important you adjust both the Transform2D x and y as well as the Inline x and y or the image size won't be changed.

C# Image Resizing - Losing EXIF

Yes yes... I've seen other posts related to this issue, and yes... I've googled about it.
But so far, I was not able to get to the result I need.
I'm loading a large image taken in 300 dpi, and I need to resize it.
I know... I know... dpi is relative and doesn't really matter... what matters are the dimensions in pixels:
DPI is essentially the number of pixels that correspond to an inch when the image is printed not when it is viewed on a screen. Therefore by increasing the DPI of the image, you do not increase the size of the image on the screen. You only increase the quality of print.
Even though the DPI information stored in the EXIF of an image is somewhat useless, it is causing me problems.
The image I'm resizing is losing the original exif information, including the horizontal and vertical resolution (dpi), and thus it is saving with a default of 96 dpi. Possible reason to this is that only JPEG and another format can hold metadata information.
The end image result is should look like this: 275x375 at 300dpi
Instead is looking like this: 275x375 at 96dpi
You can argue that they are they same, and I agree, but we have a corel draw script that used to load these images, and since this dpi information is different, it places it in different sizes on the document.
Here's what I'm using for resizing:
public System.Drawing.Bitmap ResizeImage(System.Drawing.Image image, int width, int height)
{
Bitmap result = new Bitmap(width, height);
// set the resolutions the same to avoid cropping due to resolution differences
result.SetResolution(image.HorizontalResolution, image.VerticalResolution);
//use a graphics object to draw the resized image into the bitmap
using (Graphics graphics = Graphics.FromImage(result))
{
//set the resize quality modes to high quality
graphics.CompositingQuality = System.Drawing.Drawing2D.CompositingQuality.HighQuality;
graphics.InterpolationMode = System.Drawing.Drawing2D.InterpolationMode.High;
graphics.SmoothingMode = System.Drawing.Drawing2D.SmoothingMode.HighQuality;
//draw the image into the target bitmap
graphics.DrawImage(image, 0, 0, result.Width, result.Height);
}
//return the resulting bitmap
return result;
}
That does the work very well, but loses the EXIF information.
Setting the SetResolution to SetResolution(300, 300) does not work!
I looked at reading and changing the EXIF information of an image, and I've tried:
public void setImageDpi(string Filename, string NewRes)
{
Image Pic;
PropertyItem[] PropertyItems;
byte[] bDescription = new Byte[NewRes.Length];
int i;
string FilenameTemp;
System.Drawing.Imaging.Encoder Enc = System.Drawing.Imaging.Encoder.Transformation;
EncoderParameters EncParms = new EncoderParameters(1);
EncoderParameter EncParm;
ImageCodecInfo CodecInfo = GetEncoderInfo("image/jpeg");
// copy description into byte array
for (i = 0; i < NewRes.Length; i++) bDescription[i] = (byte)NewRes[i];
// load the image to change
Pic = Image.FromFile(Filename);
foreach (PropertyItem item in Pic.PropertyItems)
{
if (item.Id == 282 || item.Id == 283)
{
PropertyItem myProperty = item;
myProperty.Value = bDescription;
myProperty.Type = 2;
myProperty.Len = NewRes.Length;
Pic.SetPropertyItem(item);
Console.WriteLine(item.Type);
}
}
// we cannot store in the same image, so use a temporary image instead
FilenameTemp = Filename + ".temp";
// for lossless rewriting must rotate the image by 90 degrees!
EncParm = new EncoderParameter(Enc, (long)EncoderValue.TransformRotate90);
EncParms.Param[0] = EncParm;
// now write the rotated image with new description
Pic.Save(FilenameTemp, CodecInfo, EncParms);
// for computers with low memory and large pictures: release memory now
Pic.Dispose();
Pic = null;
GC.Collect();
// delete the original file, will be replaced later
System.IO.File.Delete(Filename);
// now must rotate back the written picture
Pic = Image.FromFile(FilenameTemp);
EncParm = new EncoderParameter(Enc, (long)EncoderValue.TransformRotate270);
EncParms.Param[0] = EncParm;
Pic.Save(Filename, CodecInfo, EncParms);
// release memory now
Pic.Dispose();
Pic = null;
GC.Collect();
// delete the temporary picture
System.IO.File.Delete(FilenameTemp);
}
That didn't work either.
I tried looking and changing the EXIF information for DPI (282 and 283) later in the process as such:
Encoding _Encoding = Encoding.UTF8;
Image theImage = Image.FromFile("somepath");
PropertyItem propItem282 = theImage.GetPropertyItem(282);
propItem282.Value = _Encoding.GetBytes("300" + '\0');
theImage.SetPropertyItem(propItem282);
PropertyItem propItem283 = theImage.GetPropertyItem(283);
propItem283.Value = _Encoding.GetBytes("300" + '\0');
theImage.SetPropertyItem(propItem283);
theImage.Save("somepath");
But the program crashes saying that Property Cannot be Found.
If the property doesn't exist, apparently I can't add it:
A PropertyItem is not intended to be used as a stand-alone object. A PropertyItem object is intended to be used by classes that are derived from Image. A PropertyItem object is used to retrieve and to change the metadata of existing image files, not to create the metadata. Therefore, the PropertyItem class does not have a defined Public constructor, and you cannot create an instance of a PropertyItem object.
I'm stuck... all I need is a resized image with a dpi set to 300, it shouldn't be so hard.
Any help much appreciated. Thanks
The following code worked for me:
const string InputFileName = "test_input.jpg";
const string OutputFileName = "test_output.jpg";
var newSize = new Size(640, 480);
using (var bmpInput = Image.FromFile(InputFileName))
{
using (var bmpOutput = new Bitmap(bmpInput, newSize))
{
foreach (var id in bmpInput.PropertyIdList)
bmpOutput.SetPropertyItem(bmpInput.GetPropertyItem(id));
bmpOutput.SetResolution(300.0f, 300.0f);
bmpOutput.Save(OutputFileName, ImageFormat.Jpeg);
}
}
When I inspect the output file I can see EXIF data and the DPI has been changed to 300.

Create thumbnail in .NET C# by defining width

I am using the following code in my website, for thumbnail creation:
string furl = "~/images/thumbs/" + matchString;
lBlogThumb.ImageUrl = GetThumbnailView(furl, 200, 200);
private string GetThumbnailView(string originalImagePath, int height, int width)
{
//Consider Image is stored at path like "ProductImage\\Product1.jpg"
//Now we have created one another folder ProductThumbnail to store thumbnail image of product.
//So let name of image be same, just change the FolderName while storing image.
string thumbnailImagePath = originalImagePath.Replace("thumbs", "thumbs2");
//If thumbnail Image is not available, generate it.
if (!System.IO.File.Exists(Server.MapPath(thumbnailImagePath)))
{
System.Drawing.Image imThumbnailImage;
System.Drawing.Image OriginalImage = System.Drawing.Image.FromFile(Server.MapPath(originalImagePath));
imThumbnailImage = OriginalImage.GetThumbnailImage(width, height,
new System.Drawing.Image.GetThumbnailImageAbort(ThumbnailCallback), IntPtr.Zero);
imThumbnailImage.Save(Server.MapPath(thumbnailImagePath), System.Drawing.Imaging.ImageFormat.Jpeg);
imThumbnailImage.Dispose();
OriginalImage.Dispose();
}
return thumbnailImagePath;
}
public bool ThumbnailCallback() { return false; }
I would like to change this code, and be able to create a thumbnail defining width ONLY. What I have in mind is actually something like cropping/resizing image, using a static width, maintaining it's ratio. Is that possible;
You mention resizing and cropping. If you want the thumbnail heights to vary with a fixed width, the answers provided already will work for you.
The mention of cropping makes me think that you may want a fixed thumbnail size, with the width filled and any overflowing vertical portion cropped off. If that is the case, you'll need to do a bit more work. I needed something similar recently, and this is what I came up with.
This will create a thumbnail of the original that is sized and cropped in such a way that the source image completely fills the target thumbnail, cropping any overflow. There will be no borders within the thumbnail, even if the original and thumbnail aspect ratios are different.
public System.Drawing.Image CreateThumbnail(System.Drawing.Image image, Size thumbnailSize)
{
float scalingRatio = CalculateScalingRatio(image.Size, thumbnailSize);
int scaledWidth = (int)Math.Round((float)image.Size.Width * scalingRatio);
int scaledHeight = (int)Math.Round((float)image.Size.Height * scalingRatio);
int scaledLeft = (thumbnailSize.Width - scaledWidth) / 2;
int scaledTop = (thumbnailSize.Height - scaledHeight) / 2;
// For portrait mode, adjust the vertical top of the crop area so that we get more of the top area
if (scaledWidth < scaledHeight && scaledHeight > thumbnailSize.Height)
{
scaledTop = (thumbnailSize.Height - scaledHeight) / 4;
}
Rectangle cropArea = new Rectangle(scaledLeft, scaledTop, scaledWidth, scaledHeight);
System.Drawing.Image thumbnail = new Bitmap(thumbnailSize.Width, thumbnailSize.Height);
using (Graphics thumbnailGraphics = Graphics.FromImage(thumbnail))
{
thumbnailGraphics.CompositingQuality = CompositingQuality.HighQuality;
thumbnailGraphics.InterpolationMode = InterpolationMode.HighQualityBicubic;
thumbnailGraphics.SmoothingMode = SmoothingMode.HighQuality;
thumbnailGraphics.DrawImage(image, cropArea);
}
return thumbnail;
}
private float CalculateScalingRatio(Size originalSize, Size targetSize)
{
float originalAspectRatio = (float)originalSize.Width / (float)originalSize.Height;
float targetAspectRatio = (float)targetSize.Width / (float)targetSize.Height;
float scalingRatio = 0;
if (targetAspectRatio >= originalAspectRatio)
{
scalingRatio = (float)targetSize.Width / (float)originalSize.Width;
}
else
{
scalingRatio = (float)targetSize.Height / (float)originalSize.Height;
}
return scalingRatio;
}
To use with your code, you could replace your call to OriginalImage.GetThumbnailImage with this:
imThumbnailImage = CreateThumbnail(OriginalImage, new Size(width, height));
Note that for portrait images, this code will actually shift the thumbnail's viewport slightly higher on the original image. This was done so that portrait shots of people wouldn't result in headless torsos when the thumbnails were created. If you don't want that logic, simply remove the if block following the "portrait mode" comment.
let's have originalWidth=the original image width and thumbWidth. You can simply choose the thumbWidth to your desired value, and calculate the thumbHeigth=originalHeigth*thumbWidth/originalWidth
I got sick of needed to do this and created a lib that does this easily: Link To Documentation & Download
A basic example without rounding with a thumbnail width of 140, below the 'file' is a HttpPostedFile uploaded from an ASP.Net FileUpload control, the HttpPostedFile exposes a stream.
// Save images to disk.
using (System.Drawing.Image image = System.Drawing.Image.FromStream(file.InputStream))
using (System.Drawing.Image thumbnailImage = image.GetThumbnailImage(140, Convert.ToInt32((image.Height / (image.Width / 140))), null, IntPtr.Zero))
{
if (image != null)
{
image.Save(imageFilePath);
thumbnailImage.Save(thumbnailImagePath);
}
else
throw new ArgumentNullException("Image stream is null");
}

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