We Keep Coding

Database varbinary(MAX) to RichText Box

Here i Saved .Doc files in Database and i used varbinary(MAX) Datatype. Now I want to bind the varbinary(MAX) field to Richtext box, Here i am used bellow code to Read binary format data to string type.
string Query = "Select Name, ContentType, DocFileText from <TableNAme> where Id=5";
SqlCommand cmd = new SqlCommand(Query, con);
SqlDataAdapter da = new SqlDataAdapter(cmd);
con.Open();
SqlDataReader sqlRead = cmd.ExecuteReader();
while (sqlRead.Read())
{
byte[] fileData = ((byte[])sqlRead["DocFileText"]);
Richtextbox1.Text = Encoding.ASCII.GetString(fileData);
}
but the data should be in unreadable format like :
PK!0?(r?[Content_Types].xml ?(??T?n?0?W??D?V??????[??0??z??l?I?Q?B? \"%?????????l ?w%?=???^i7+???%?g&??0?A?6?l4??L60#????S ????X??&??V$z?3??3 ??????%p)O5?????5}?:?`?e????V?DFK??)_:?K%?)?l??\?!??U?'?v?7?&j?X??*,??+W^.,???????W????k??D?????X?????>??N!??FZ??&0m??ly??)?q?9??d}???#??????????R??/??s???*&:t??g?????????8Y?O?[??&V0}?X????????>?#??;?F?io.????PK!???N_rels/.rels ?(????JA???a?}7? "???H?w"????w?????? ?P?^????O?????;?<?aY????`G?kxm??PY?[??g G??ino?/"f3??\???T??I S??????????W????Y ig?#??X6_?]7~ f?????ao?.b*lI?r?j)?,l0?%??b? 6?i???D?_???, ? ???|u?Z^t??y??;!Y,}{?C??/h>??PK!??? ?word/_rels/document.xml.rels ?(????J?0?????n????l?????v???$?j?????..??K`?????0??L'????YI?#[????????? D mK?9? ?Ooovo?i?G?i? ?? Q?,e(4:D?G?7??F????.>u?r?[???^x?C???{??s??????_\q4h?J?H?????FRpR"?ya?* ?p???d?x{49z??Dp?? ?kB?Nc)?3Ybx\??r?2?w3?????&?7??Vr&?#??oK??PK!??????2word/document.xml?Y[O?0~????r????BiCH????.???????_?s?84?-a-#??;>??|>N..??P?S.?u???5{l??}???{??5!I??#???Z#sl?}?????M??iuK??B?? ???]????=???O?F??o????ba?)??Nw8,Ht'pn6??P7??p)N?*97?tl???#'L???????se~??;?Y??;???}?K?????v???M??????K???j?>U????+g?^U|?????C N???M?~%????a???????H??m?/?&?M_?i=??????VQN?0?J?#??l??J?|!U??4[]S%??7?$?i7:?bB???Nl??{uH5""3%hA?:?g?????n???:????#??xi%?z_vZ?*U?m??u??2?Jq??'?3?h???1Q?, ??????'??;??g?? ?Ev?????0$??`XmtGr??!?e_?}v??#??????????dT?h+?j-,A?%#???6? ??w?????|UOQ4????E?ga?V???#?????w2?|????????~????WH??X????t?^^???O????????lK?=?K????? ?93?.????????????ev?j??????|?4?y0??e?????=FV ??^?r?Zh9#??_vvsN3?r????????\m?]??1Y n4?X/2?.??`?%O?a????A??l??????N?d???????PK!?????Pword/theme/theme1.xml?YOo?6??w toc'vu????-M?n?i???P?#?I}?????a??m?a[????4?:l???GR??X^?6???>$?????????!)O?^?r?C$?y#?????/?yH*??????)?????????UDb?`}"?q???J?????X^?)I`n?E???p)???li?V[]?1M???G?M?Ge???D?????3Vq%'#q??????$?8??K?????)f?w9:????? x}r?x????w???r?:\TZaG?*?y8I?j?bR??c|X??????I u3KG?nD1?NIB?s??? ??R??u???K>V?.EL+M2?#'?f??i~?V??vl?{u8??z??H? ?*????:?(W???? ~??J??T?e\O*?tHG??HY???}KN??P?*???????T???9/#??A7?qZ??$*c????qU??n??w?N??%??O??i??4=3??P?? ????1?P?m\\9?????????M???2a?D?]?;Yt?\????[x??????]?}Wr??|?]??g-??? eW? ?)6-r??CS?j?? i?d ?D??A???IqbJ#x????6k???#??A?Sh???&??t(Q?%??p%m??&]?caSl=?X???????\P?1?Mh?9?M???V?dDA??aV?B??[??fJ???P|8???A?V^???f ?H??n???-??"??d>?z???n????? ?????>??b???&?????2??v????Ky?????D:????,AGm??\nz??i?????.u??YC?6?OMf??3o?r??$??5?????NH?T[XF64?T,?????M0?E)`#?5?XY?`???;??%?1?U???m;???R>QD????D?cp?U?'??&LE?/p???m????%]?????8fi??r?S4?d7y\?`?J??n??????I?R???3U?~7+?????#??m?q?BiD??????????i*?L6?9??m?Y&?????i???HE??=(K&?N!V??.K?e?LD????{D ????vE???de??N????e?(?MN9??R??6????&3(??a????/D??U?z???)???D????_??k??wXXub?????(?9??8?????????????<4??u?>?p?? ???F????
Here i used
Encoding.UTF8.GetString(fileData);
Encoding.Unicode.GetString(fileData);
but these are also not working.
How can i read Doc file from database to richtextbox ?
And My Uploaded Code is:
string filename = Path.GetFileName(FileUpload1.PostedFile.FileName);
Stream str = FileUpload1.PostedFile.InputStream;
BinaryReader br = new BinaryReader(str);
Byte[] size = br.ReadBytes((int) str.Length);
using (SqlConnection con = new SqlConnection(Connstring))
{
using (SqlCommand cmd = new SqlCommand())
{
cmd.CommandText = "insert into Gtrans(Name, ContentType, DocFileText) values(#Name, #ContentType, #DocFileText)";
cmd.Parameters.AddWithValue("#Name", filename);
cmd.Parameters.AddWithValue("#ContentType", "application/word");
cmd.Parameters.AddWithValue("#DocFileText", size);
cmd.Connection = con;
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}

Okay there are two problems with your approach.
Point 1 (If you are using winforms):
If you like to load rtf text into a RichTextBox then you have to use the Rtf property of the RichTextBox. Not the Text property. See this for more information.
Point 2:
You can't open .doc in rtf just by passing the .doc string to rtf. .doc is something other that rtf.
The good news: it is possible, the bad: you need MS Word.
Add reference to "Microsoft Word 15.0 Object Library" is under the 'Com' section of the references window
Use this code to convert the doc file to rtf file
.
byte[] yourDocData = null; // in your case (byte[])sqlRead["DocFileText"]
// Save your data as file so word can read it
var tmpFile = Path.GetTempFileName();
using (var fileStream = new FileStream(tmpFile, FileMode.Append, FileAccess.Write))
using (var writer = new BinaryWriter(fileStream)) {
writer.Write(yourDocData);
}
// Convert .doc to .rtf
var newWordFile = (object) tmpFile;
var newRtfFile = (object) Path.GetTempFileName();
var wordObject = new Microsoft.Office.Interop.Word.Application();
var docs = wordObject.Documents.Open(ref newWordFile);
docs.SaveAs(ref newRtfFile, WdSaveFormat.wdFormatRTF);
// This is your rtf code
var yourRtfCode = File.ReadAllText(newRtfFile.ToString());
// Dispose
docs.Close();
wordObject.Quit();
source
Important
Use the same Encoding for saving / loading your .doc from the database!
Set the yourRtfCode not to the text-property of your control but to the property accepting rtf-text

How to insert BLOB datatype

I'm using the following code to insert into a blob field:
MySql.Data.MySqlClient.MySqlConnection conn;
MySql.Data.MySqlClient.MySqlCommand cmd;
conn = new MySql.Data.MySqlClient.MySqlConnection();
cmd = new MySql.Data.MySqlClient.MySqlCommand();
string SQL;
int FileSize;
byte[] rawData;
FileStream fs;
conn.ConnectionString = "server=192.168.1.104;uid=root;" +
"pwd=root;database=cady234;";
fs = new FileStream(#"d:\Untitled.gif", FileMode.Open, FileAccess.Read);
FileSize = (int)fs.Length;
rawData = new byte[FileSize];
fs.Read(rawData, 0, FileSize);
fs.Close();
conn.Open();
string strFileName = "test name";
SQL = "INSERT INTO file (file_name, file_size, file) VALUES ('" + strFileName + "', "+FileSize+", '"+rawData+"')";
cmd.Connection = conn;
cmd.CommandText = SQL;
cmd.ExecuteNonQuery();
conn.Close();
The insertion is ok but the image is not getting displayed while using "Open value in viewer":

The binary data isn't being properly passed to your insert as you are using string concatenation - you'll get rawData.ToString() which probably just prints out the TypeName (hence your binary data being 13 bytes in length compared to the filesize of > 3000 bytes); try this instead:
byte[] rawData = File.ReadAllBytes(#"d:\Untitled.gif");
FileInfo info = new FileInfo(#"d:\Untitled.gif");
int fileSize = Convert.ToInt32(info.Length);
using(MySqlConnection connection = new MySqlConnection("server=192.168.1.104;uid=root;pwd=root;database=cady234;"))
{
using(MySqlCommand command = new MySqlCommand())
{
command.Connection = connection;
command.CommandText = "INSERT INTO file (file_name, file_size, file) VALUES (?fileName, ?fileSize, ?rawData);";
MySqlParameter fileNameParameter = new MySqlParameter("?fileName", MySqlDbType.VarChar, 256);
MySqlParameter fileSizeParameter = new MySqlParameter("?fileSize", MySqlDbType.Int32, 11);
MySqlParameter fileContentParameter = new MySqlParameter("?rawData", MySqlDbType.Blob, rawData.Length);
fileNameParameter.Value = "test name";
fileSizeParameter.Value = fileSize;
fileContentParameter.Value = rawData;
command.Parameters.Add(fileNameParameter);
command.Parameters.Add(fileSizeParameter);
command.Parameters.Add(fileContentParameter);
connection.Open();
command.ExecuteNonQuery();
}
}
I've introduced several concepts for you here; firstly, if you are going to load all of the binary data at once, simply use the static method File.ReadAllBytes - it's a lot less code.
Secondly, there is no need to use the fully qualified namespace each time - use the using directive
Thirdly, (slightly confusingly) there is a also a using statement in C#. This ensures that any object that implements IDisposable is properly cleaned up after itself. In the case of the connection, it will explicitly call Close and Dispose if you command succeeds or fails.
Finally, I've parameterized your query. Parameters are useful for many reasons; they help protect against SQL Injection, and, in this instance, they should also ensure that your data types are handled correctly. You can read more about SqlParameter (which, like, MySqlParameter is a database specific implementation but uses the same principles).
Tested as working with MySQL 5.5.15, MySQL Connector 5.2.7 running under .Net 4

How about this:
It works fine for me.
Exepte I found out that it is the wrong one for me.
<?php
// csv invoeren naar pos.
$CSV = "uitvoer.csv";
// The CSV file has only 2 colums; The "Reference" and the image name (in my case the barcode with "thumb_" in front of it.
$username = "Username";
$password = "Passwwoorrdd";
$database = "POS";
$counter = 0;
// Create connection
$conn = new mysqli("localhost", $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully <br>";
//$mysqli->select_db();
ini_set('max_execution_time', 1000); //300 seconds = 5 minutes
if (($handle = fopen($CSV, "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1050, ",")) !== FALSE) {
// this loops through each line of your csv, putting the values into array elements
$counter++;
$IDEE = $data[0];
// It seems that after opening the image the $data is mixed up.
$imag = "photos/".$data[1]; // where "photos/' the folder is where this php file gets executed (mostly in /var/www/ of /var/www/html/)
$fh = fopen($imag, "r");
$data = addslashes(fread($fh, filesize($imag)));
fclose($fh);
echo " Ref: ".$IDEE." ----".$counter."----<br>";
// If there will be a time-out. You could erase the part what is already done minus 1.
$sql = "UPDATE PRODUCTS SET IMAGE='".$data."' WHERE CODE=$IDEE";
// The table PRODUCTS with IMAGE. There are more data in that table. But i need only to update the IMAGE. The rest is already inserted.
if ($conn->query($sql) === TRUE) {
echo "Tabel <b>products</b> updated successfully<br>";
} else {
echo "<br>Error updating tabel <b>Products</b>: " . $conn->error;
Exit();
}
}
fclose($handle);
}
?>

open word document (saved as binary) from database

I'm making a program with c# and sql server and I have a problem , I hope if anyone help me .
I will but the database on pc and the program will be installed in other PCs , and app pcs' program connected to that database.
the program saving documents (word -excel) as binary ,using this code:
byte[] ReadFile(string sPath)
{
//Initialize byte array with a null value initially.
byte[] data = null;
//Use FileInfo object to get file size.
FileInfo fInfo = new FileInfo(sPath);
long numBytes = fInfo.Length;
//Open FileStream to read file
FileStream fStream = new FileStream(sPath, FileMode.Open, FileAccess.Read);
//Use BinaryReader to read file stream into byte array.
BinaryReader br = new BinaryReader(fStream);
//When you use BinaryReader, you need to supply number of bytes to read from file.
//In this case we want to read entire file. So supplying total number of bytes.
data = br.ReadBytes((int)numBytes);
return data;
}
private void button1_Click(object sender, EventArgs e)
{
string dt = dateTimePicker1.Value.ToShortDateString();
byte[] red = ReadFile(textBox3.Text);
con.Open();
string qry = "insert into documents ([Account no],Name,[Phone number],Date,[Document name],Document,Type) values(#accon,#name,#phone,#date,#docname,#doc,#type)";
//Initialize SqlCommand object for insert.
SqlCommand SqlCom = new SqlCommand(qry, con);
//We are passing Original Image Path and Image byte data as sql parameters.
SqlCom.Parameters.Add(new SqlParameter("#accon", textBox1.Text));
SqlCom.Parameters.Add(new SqlParameter("#name", textBox2.Text));
SqlCom.Parameters.Add(new SqlParameter("#phone", textBox3.Text));
SqlCom.Parameters.Add(new SqlParameter("#date", dt));
SqlCom.Parameters.Add(new SqlParameter("#docname", textBox1.Text));
SqlCom.Parameters.Add(new SqlParameter("#doc", (object)red));
SqlCom.Parameters.Add(new SqlParameter("#type", (object)textBox2.Text));
SqlCom.ExecuteNonQuery();
con.Close();
MessageBox.Show("done");
}
the problem : that I don't know how to retrieve saved documents in database and open it with Microsoft word or Microsoft Excel according to their types.
I want to select specific document form database and open it
Thanks in advance

String connStr = "connection string";
// add here extension that depends on your file type
string fileName = Path.GetTempFileName() + ".doc";
using (SqlConnection conn = new SqlConnection(connStr))
{
conn.Open();
using (SqlCommand cmd = conn.CreateCommand())
{
// you have to distinguish here which document, I assume that there is an `id` column
cmd.CommandText = "select document from documents where id = #id";
cmd.Parameters.Add("#id", SqlDbType.Int).Value = 1;
using (SqlDataReader dr = cmd.ExecuteReader())
{
while (dr.Read())
{
int size = 1024 * 1024;
byte[] buffer = new byte[size];
int readBytes = 0;
int index = 0;
using (FileStream fs = new FileStream(fileName, FileMode.Create, FileAccess.Write, FileShare.None))
{
while ((readBytes = (int)dr.GetBytes(0, index, buffer, 0, size)) > 0)
{
fs.Write(buffer, 0, readBytes);
index += readBytes;
}
}
}
}
}
}
// open your file, the proper application will be executed because of proper file extension
Process prc = new Process();
prc.StartInfo.FileName = fileName;
prc.Start();

After you have retrieved your document from the database (or any type of storage you care to use on the server) you should save the document in the windows temporary folder (Path.GetSpecialFolder) and use the Word Interop library to start word (or excel using its own interop library) with the document you just saved.
var temporayFileName = Path.GetRandomFileName();
var temporaryFileStream = File.Open(temporaryFileName, FileMode.Create);
var memoryStream = documentRepository.Get(...);
memoryStream.CopyTo(temporaryFileStream);
// Word App
dynamic wordApp = new Application { Visible = true };
var doc = wordApp.Documents.Add(TemplateName);
templatedDocument.Activate();
(See this document for more information about starting and manipulating word:
http://msdn.microsoft.com/en-us/magazine/ff714583.aspx)
.

The crux is Response.ContentType:
Response.ContentType = "application/vnd.xls"; // for excel
Response.ContentType = "application/ms-word"; // for word
Response.ContentType = "image/jpg";//for jpg images
It is advised to store content type also in database so that your code will be generic and can display/store any type of file
System.Data.SqlClient.SqlDataReader rdr = null;
System.Data.SqlClient.SqlConnection conn = null;
System.Data.SqlClient.SqlCommand selcmd = null;
try
{
conn = new System.Data.SqlClient.SqlConnection(
System.Configuration.ConfigurationManager
.ConnectionStrings["ConnectionString"].ConnectionString);
selcmd = new System.Data.SqlClient.SqlCommand(
"select pic1 from msg where msgid=" + Request.QueryString["imgid"],
conn);
conn.Open();
rdr = selcmd.ExecuteReader();
while (rdr.Read())
{
Response.ContentType = "image/jpg";
Response.BinaryWrite((byte[])rdr["pic1"]);
}
if (rdr != null)
rdr.Close();
}
finally
{
if (conn != null)
conn.Close();
}

How to use Microsoft Access Database's Attachment Data Type?

I'm trying to use Microsoft access database's attachment data type.
but i don't know how to use it.
I want to insert image into access database using .Net Windows Form.
In SQL Server 2008 Image data type and byte is compatibility for that.
but i don't know how to insert image into access database.
is there need to change byte like SQL Server or can directly insert into access database.

using (var connection = new OleDbConnection(#"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\BlankDatabase.mdb"))
{
connection.Open();
// Create table
using (var command = connection.CreateCommand())
{
command.CommandText = #"
CREATE TABLE FileTable (
FileName VARCHAR(255),
File IMAGE)
";
command.ExecuteNonQuery();
}
var imageContent = File.ReadAllBytes(#"C:\logo.png");
// upload image to the table
using (var command = connection.CreateCommand())
{
command.CommandText = #"
INSERT INTO FileTable (FileName, File)
VALUES (#FileName, #File)
";
command.Parameters.AddWithValue("#FileName", "Logo");
command.Parameters.AddWithValue("#File", imageContent);
command.ExecuteNonQuery();
}
// retreive image from the table
using (var command = connection.CreateCommand())
{
command.CommandText = #"
SELECT File
FROM FileTable
WHERE FileName = 'Logo'
";
var readImageContent = (byte[])command.ExecuteScalar();
File.WriteAllBytes(#"C:\logo1.png", readImageContent);
}
// alter image from the table
using (var command = connection.CreateCommand())
{
command.CommandText = #"
UPDATE FileTable
SET File = #File
WHERE FileName = 'Logo'
";
command.Parameters.AddWithValue("#File", imageContent);
command.ExecuteNonQuery();
}
// delete image from the table
using (var command = connection.CreateCommand())
{
command.CommandText = #"
DELETE FROM FileTable
WHERE FileName = 'Logo'
";
command.ExecuteNonQuery();
}
}
In this code BlankDatabase.mdb is an empty MS Access database file.
[Edit]
When you saved image to the database, as shown above you can retrieve image bytes as shown above:
You can construct Image from image bytes like this:
var imageConverter = new ImageConverter();
pictureBox1.Image = (Image)imageConverter.ConvertFrom(fileContent);

Here is what I use to get the file attachments from an OleDB connection in .net code to a microsoft access database with attachment field types:
This method gets the file you want in Ordinal Position from the attachment field name "Pic" in my table.. you can store many files in the attachment field, so you have to specify which of the files you want.. hope this helps ( i use this as web url to take the image from the attachment field in the access database, but the COM calls will be the same in your winform app)..good luck
try
{
//You get your file in a byteArray fileType is just the ordinal file position in the fileattachment field..ex. 1, 2, 3 (shown in the access listbox)
Response.BinaryWrite(GetPicField(productID, fileType));
Response.ContentType = "image/bmp";
}
catch
{
//need to get missing product photo image here as well N/A
Response.BinaryWrite(GetNA_Image());
Response.ContentType = "image/bmp";
}
//getting from Database
private byte[] GetPicField(string productID,int fileToShow)
{
DBEngine dbe = new DBEngine();
Database db;
Recordset rs;
byte[] byteArray = null;
dbe = new DBEngine();
db = dbe.OpenDatabase(Application["DB_FileName"].ToString());
rs = db.OpenRecordset("SELECT PIC FROM PRODUCT WHERE PRODUCTID = " + productID, RecordsetTypeEnum.dbOpenForwardOnly, 0, LockTypeEnum.dbPessimistic);
if (rs.RecordCount > 0)
{
Recordset rs2 = (Recordset2)rs.Fields["Pic"].Value;
int i = 1;
while (i < fileToShow)
{
rs2.MoveNext();
i++;
}
//get the thubmnail
Field2 f2 = (Field2)rs2.Fields["FileData"]; //0 is first pic
byteArray = f2.GetChunk(20, f2.FieldSize - 20);
System.Runtime.InteropServices.Marshal.ReleaseComObject(f2);
rs2.Close();
System.Runtime.InteropServices.Marshal.ReleaseComObject(rs2);
f2 = null;
rs2 = null;
}
rs.Close();
db.Close();
System.Runtime.InteropServices.Marshal.ReleaseComObject(rs);
System.Runtime.InteropServices.Marshal.ReleaseComObject(dbe);
System.Runtime.InteropServices.Marshal.ReleaseComObject(db);
rs = null;
db = null;
dbe = null;
return byteArray;
}

Insert blob in oracle database with C#

I have to persist a .csv in my database, but for a more testable application I prefer don't use procedures.
Basically I just generate a file and the next instruction is put this in database.
Someone have some clue about best way to do this in code?

Here is an example to insert blob data in oracle using c# and procedures (you said prefer that means you may).
using System;
using System.Data;
using Oracle.DataAccess.Client;
using Oracle.DataAccess.Types;
using System.IO;
using System.Text;
//Step 1
// Connect to database
// Note: Modify User Id, Password, Data Source as per your database setup
string constr = "User Id=Scott;Password=tiger;Data Source=orcl9i";
OracleConnection con = new OracleConnection(constr);
con.Open();
Console.WriteLine("Connected to database!");
// Step 2
// Note: Modify the Source and Destination location
// of the image as per your machine settings
String SourceLoc = "D:/Images/photo.jpg";
String DestinationLoc = "D:/Images/TestImage.jpg";
// provide read access to the file
FileStream fs = new FileStream(SourceLoc, FileMode.Open,FileAccess.Read);
// Create a byte array of file stream length
byte[] ImageData = new byte[fs.Length];
//Read block of bytes from stream into the byte array
fs.Read(ImageData,0,System.Convert.ToInt32(fs.Length));
//Close the File Stream
fs.Close();
// Step 3
// Create Anonymous PL/SQL block string
String block = " BEGIN " +
" INSERT INTO testblob (id, photo) VALUES (100, :1); " +
" SELECT photo into :2 from testblob WHERE id = 100; " +
" END; ";
// Set command to create Anonymous PL/SQL Block
OracleCommand cmd = new OracleCommand();
cmd.CommandText = block;
cmd.Connection = con;
// Since executing an anonymous PL/SQL block, setting the command type
// as Text instead of StoredProcedure
cmd.CommandType = CommandType.Text;
// Step 4
// Setting Oracle parameters
// Bind the parameter as OracleDbType.Blob to command for inserting image
OracleParameter param = cmd.Parameters.Add("blobtodb", OracleDbType.Blob);
param.Direction = ParameterDirection.Input;
// Assign Byte Array to Oracle Parameter
param.Value = ImageData;
// Bind the parameter as OracleDbType.Blob to command for retrieving the image
OracleParameter param2 = cmd.Parameters.Add("blobfromdb", OracleDbType.Blob);
param2.Direction = ParameterDirection.Output;
// Step 5
// Execute the Anonymous PL/SQL Block
// The anonymous PL/SQL block inserts the image to the
// database and then retrieves the images as an output parameter
cmd.ExecuteNonQuery();
Console.WriteLine("Image file inserted to database from " + SourceLoc);
// Step 6
// Save the retrieved image to the DestinationLoc in the file system
// Create a byte array
byte[] byteData = new byte[0];
// fetch the value of Oracle parameter into the byte array
byteData = (byte[])((OracleBlob)(cmd.Parameters[1].Value)).Value;
// get the length of the byte array
int ArraySize = new int();
ArraySize = byteData.GetUpperBound(0);
// Write the Blob data fetched from database to the filesystem at the
// destination location
FileStream fs1 = new FileStream(#DestinationLoc,
FileMode.OpenOrCreate, FileAccess.Write);
fs1.Write(byteData, 0,ArraySize);
fs1.Close();
Console.WriteLine("Image saved to " + DestinationLoc + " successfully !");
Console.WriteLine("");
Console.WriteLine("***********************************************************");
Console.WriteLine("Before running this application again, execute 'Listing 1' ");

private void btnSave_Click(object sender, EventArgs e)
{
try
{
//Read Image Bytes into a byte array
byte[] blob = ReadFile(txtPath.Text);
//Initialize Oracle Server Connection
con = new OracleConnection(conString);
//Set insert query
string qry = "insert into Imgpn (imgpath,photo) values('" + txtPath.Text + "'," + " :BlobParameter )";
OracleParameter blobParameter = new OracleParameter();
blobParameter.OracleType = OracleType.Blob;
blobParameter.ParameterName = "BlobParameter";
blobParameter.Value = blob;
//Initialize OracleCommand object for insert.
cmd = new OracleCommand(qry, con);
//We are passing Name and Blob byte data as Oracle parameters.
cmd.Parameters.Add(blobParameter);
//Open connection and execute insert query.
con.Open();
cmd.ExecuteNonQuery();
MessageBox.Show("Image added to blob field");
GetImagesFromDatabase();
cmd.Dispose();
con.Close();
//this.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
byte[] ReadFile(string sPath)
{
//Initialize byte array with a null value initially.
byte[] data = null;
//Use FileInfo object to get file size.
FileInfo fInfo = new FileInfo(sPath);
long numBytes = fInfo.Length;
//Open FileStream to read file
FileStream fStream = new FileStream(sPath, FileMode.Open, FileAccess.Read);
//Use BinaryReader to read file stream into byte array.
BinaryReader br = new BinaryReader(fStream);
//When you use BinaryReader, you need to supply number of bytes to read from file.
//In this case we want to read entire file. So supplying total number of bytes.
data = br.ReadBytes((int)numBytes);
return data;
}
void GetImagesFromDatabase()
{
try
{
//Initialize Oracle connection.
con = new OracleConnection(conString);
//MessageBox.Show("Connection Successfull");
//Initialize Oracle adapter.
OracleDataAdapter oda = new OracleDataAdapter("Select * from Imgpn", con);
//Initialize Dataset.
DataSet DS = new DataSet();
//Fill dataset with ImagesStore table.
oda.Fill(DS, "Imgpn");
//Fill Grid with dataset.
dataGridView1.DataSource = DS.Tables["Imgpn"];
//
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
here is the simple way to insert image into oracle database ane retrieve ane show in datagridview